I need help please and thank you

Answer:

42 ft 2 is the closest answer I got

Answer: C

Step-by-step explanation:

Answer:

4/6  8/12

Step-by-step explanation:

Answer:

√36/√16 is a rational number as it can be written as 6/4=3/2 which is rational

Answer:

volume = 4.5 in³

Step-by-step explanation:

V = L x W x H

V = 3 x 1.5 x 1 = 4.5

x=16/4=4 is the answer if u need any explanation please comment

hope it helps

Answer:

x=4

Step-by-step explanation:

4x = 16

Divide each side by 4:

x=4

Answer:

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

Step-by-step explanation:

Geometrically speaking, the area of a rectangle ([tex]A[/tex]), in square centimeters, is described by following expression:

[tex]A = w\cdot l[/tex] (1)

Where:

[tex]w[/tex] - Width, in centimeters.

[tex]h[/tex] - Height, in centimeters.

By Differential Calculus, we find an expression for the rate of change of the area of the rectangle ([tex]\dot A[/tex]), in square centimeters per second:

[tex]\dot A = \dot w\cdot l + w\cdot \dot l[/tex] (2)

Where:

[tex]\dot w[/tex] - Rate of change of the width of the rectangle, in centimeters per second.

[tex]\dot l[/tex] - Rate of change of the length of the rectangle, in centimeters per second.

If we know that [tex]w = 12\,cm[/tex], [tex]l = 15\,cm[/tex], [tex]\dot w = 4\,\frac{cm}{s}[/tex] and [tex]\dot l = 9\,\frac{cm}{s}[/tex], then the rate of change of the area of the rectangle is:

[tex]\dot A = \dot w\cdot l + w\cdot \dot l[/tex]

[tex]\dot A = 168\,\frac{cm^{2}}{s}[/tex]

The area of the rectangle is increasing at a rate of 168 square centimeters per second.

Answer:

[tex]\boxed {\boxed {\sf A \approx 3.3 \ in^2}}[/tex]

Step-by-step explanation:

Since we are given the central angle in degrees, we should use the following formula for sector area.

[tex]A= \frac {\theta}{360}* \pi r^2[/tex]

The angle is 42 degrees and the radius is 3 inches. Therefore,

[tex]\theta= 42 \\r=3 \ in[/tex]

[tex]A=\frac {42}{360} * \pi (3 \ in)^2[/tex]

Solve the exponent.

[tex]A=\frac {42}{360} * \pi (9 \ in^2)[/tex]

Multiply all three numbers together.

[tex]A= 0.116666666667* 3.14159265359 * 9 \ in^2[/tex]

[tex]A=3.29867228627 \ in^2[/tex]

Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.

[tex]A \approx 3.3 \ in^2[/tex]

The area of the sector is approximately 3.3 square inches.

Answer:

If youre looking for the value of y:

Step-by-step explanation:

4/5 y=32

y= 32/(4/5)

y=40

Answer:

Step-by-step explanation:

4/5y=32. y is a unknown number. How i solve these is i do 32 times 5 which is 160 and then 160 divided by 4 is 40. 4/5 of 40 is 32.

Answer:

1728

Step-by-step explanation:

if its a cube then all sides are the same length. you need to times to base width and height. so it will be 12 times 12 times 12 which is 1728.

Answer:

3 bookcases

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

2(54-6x)=73-7x

108-12x=73-7x

108-73=-7x+12x

35=5x

x=7

UW=73-7x=73-7(7) = 73-49 = 24

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Answer: 4.375

I hope this helped!

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Answer:

35/8 or 4 3/8

Step-by-step explanation:

Step 1. Convert the expression

7 can also be seen as 7/1

Step 2. Multiply the fractions

7/1 × 5/8

you do this step by multiplying the numerators together for your top number, and your denominators together for your bottom number.

7×5= 35 (numerator)

1×8=8 (denominator)

the answer is 35/8 or 4 3/8 as a mixed fraction.

Answer:

I will post 4,5 and 6 separately.

Answer:

B

Step-by-step explanation:

Answer:

∠ BDC = 30°

Step-by-step explanation:

The angle on the circle is half the measure of the central angle subtended by the arc BC

∠ BDC = [tex]\frac{1}{2}[/tex] × 60° = 30°

Examining the question:

We are given the expression:

[tex]\frac{1}{Sec(\alpha)-Tan(\alpha)}[/tex]

We know from Basic trigonometry that:

[tex]Sec(\alpha) = \frac{1}{Cos(\alpha)}[/tex]

[tex]Tan(\alpha) = \frac{Sin(\alpha)}{Cos(\alpha)}[/tex]

Simplifying the expression:

Replacing these values in the given expression, we get:

[tex]\frac{1}{\frac{1}{Cos(\alpha)} -\frac{Sin(\alpha)}{Cos(\alpha)} }[/tex]

Since the denominator of both the values in the denominator is the same:

[tex]\frac{1}{\frac{1-Sin(\alpha)}{Cos(\alpha)} }[/tex]

We know that [tex]\frac{1}{\frac{a}{b} }[/tex] = [tex]\frac{b}{a}[/tex], using the same property:

[tex]\frac{Cos(\alpha)}{1-Sin(\alpha)}[/tex]

and we are done!

Answer:

cos a

---------------------

1  -sin (a)

Step-by-step explanation:

We know that sec a = 1/ cos (a)  and tan a = sin (a) / cos (a)

1

---------------------

1/ cos (a)  -sin (a) / cos (a)

Multiply the top and bottom by cos (a)

1* cos a

---------------------

( 1/ cos (a)  -sin (a) / cos (a)) * cos a

cos a

---------------------

1  -sin (a)

Answer:

=2−i

Step-by-step explanation:

Hope this helps :)

BRAINLIEST PLSSS I HAVE A LITTLE BIT POINTS :|

Answer:

35

Step-by-step explanation:

Answer:

Yes, they can only have acute angles (all measure 60°)

Step-by-step explanation:

Answer:

B) (1/2, -8)

Step-by-step explanation:

(1, -6) and (0, -10)

Midpoint formula:

((x1+x2)/2, (y1+y2)/2)

Solving for x:

(x1+x2)/2

(1 + 0)/2

1/2

Solving for y:

(y1+y2)/2

(-6-10)/2

(-16)/2

-8

Answer:

8 weeks

Step-by-step explanation:

Given data

Matteo

Amount= $400

Spending per week= $10

Hence his balance after x weeks is given as

y=400-10x-------------1

Luca

Amount= $200

Spending per week= $15

Hence his balance after x weeks is given as

y=200+15x-------------2

Equate 1 and 2

400-10x=200+15x

collect like terms

400-200=15x+10x

200=25x

x= 200/25

x= 8 weeks

Hence it will take 8 weeks

Answer:

area = 138 m²

Step-by-step explanation:

radius of large circle = 12 m

radius of small circle = 10 m

large circle area = πr² = (3.14)(12²) = 452.16 m²

small circle area = πr² = (3.14)(10²) =314 m²

452.16 - 314 = 138.16 m²

Answer:

a) The standard score associated with a gestation period of 13.8 months is of [tex]Z = -1[/tex]

b) 34% of whale pregnancies will have a gestation period between 13.8 and 15 months.

c) Since when [tex]X = 21[/tex], [tex]Z = 5 \geq 2[/tex], it would be unusual for a whale to have a gestation period of 21 months.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If [tex]Z \geq 2[/tex] or [tex]Z \leq -2[/tex], the measure X is considered to be unusual.

According to a website, the mean gestation period for a whale is 15 months. Assume the distribution of gestation periods is Normal with a standard deviation of 1.2 months.

I corrected to 1.2 because it is what makes sense considering the questions.

This means that [tex]\mu = 15, \sigma = 1.2[/tex]

a. Find the standard score associated with a gestation period of 13.8 months

This is Z when X = 13.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{13.8 - 15}{1.2}[/tex]

[tex]Z = -1[/tex]

The standard score associated with a gestation period of 13.8 months is of [tex]Z = -1[/tex]

b. Using the Empirical Rule and your answer to part a, what percentage of whale pregnancies will have a gestation period between 13.8 and 15 months?

The standard score associated with a gestation period of 13.8 months is of [tex]Z = -1[/tex], which means that it is one standard deviation below the mean.

The normal distribution is symmetric, which means that of the approximately 68% of measures within one standard deviation of the mean, 68%/2 = 34% are within one standard deviation below the mean(in this case, 13.8) and the mean(in this case 15), and 34% are within the mean and one standard deviation above the mean.

So 34% of whale pregnancies will have a gestation period between 13.8 and 15 months.

c. Would it be unusual for a whale to have a gestation period of 21 months? Why or why not?

Let's find the z-score

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{21 - 15}{1.2}[/tex]

[tex]Z = 5[/tex]

Since when [tex]X = 21[/tex], [tex]Z = 5 \geq 2[/tex], it would be unusual for a whale to have a gestation period of 21 months.

Answer:

No, the table is not linear.

Step-by-step explanation:

Between the x and y there has to be a constant rate. There is no constant rate.

Answer:

The t-distribution is used, as we have the standard deviation of the sample.

The 95% confidence interval for the population mean time wasted is between 7.12 hours and 8.88 hours.

Step-by-step explanation:

We have the standard deviation for the sample, which meas that the t-distribution should be used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 81 - 1 = 80

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 80 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 1.99

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.99\frac{4}{\sqrt{81}} = 0.88[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 8 - 0.88 = 7.12 hours.

The upper end of the interval is the sample mean added to M. So it is 8 + 0.88 = 8.88 hours.

The 95% confidence interval for the population mean time wasted is between 7.12 hours and 8.88 hours.

Answer:

okokokokokoo9i876t5rew

Step-by-step explanation:

4s3a468

Answer:

the answer is 5/6

Step-by-step explanation:

1/2 + 1/3

1 =3   +   2=1          5

        x

--       +        ---  =   ---

2       x        3 =     6