I need help please anyone

Answer:

after 10 months

Step-by-step explanation:

Let x be the number of months and y be the amount they still owe.

Sin Ian borrows $1000 from his parents, then the y-intercept b= 1000 since he owes $1000 when x = 0. He pays them back $60 each month The slope is then m = -60 . Substituting in b = 1000 and m = -60 into the slope-intercept form of a line then gives y= mx + b=-60x +1000.

Sin Ken borrows $600 from his parents, then the y-intercept b = 600 since he owes $600 When x= 0. He pays them back $20 per month so the amount he owes decreases $20 each month. The slope is then m = -20 . Substituting in

b= 600 and m = -20 into the slope-intercept form then gives y = mx +b = -20x + 600.

They will owe the same amount when they have the same y-coordinate. Therefore -60x+ 1000= y= -20x+600. Solve this equation for x:

-60x+ 1000 = -20x+ 600

1000 = 40x+ 600

400 = 40x

10=x

They will then owe the same amount after 10 months.

Answer:

[tex]4(3x)^{\frac{3}{2} }[/tex]

Step-by-step explanation:

Answer:

27.3

Step-by-step explanation:

27.3

Answer:

Plays a musical instrument

Top left

Plays a sport: 0.46

Plays a musical instrument

Top right

Does not Play a sport: 0.54

Does not play a musical instrument

Bottom Left

Plays a sport: 0.73

Does not play a musical instrument

Bottom right

Does not Play a sport: 0.27

Step-by-step explanation:

I hope this helps you! :D

Answer:

y - 2 = 1/3(x - 3)

Step-by-step explanation:

Point slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Plug in the slope:

y - y1 = m(x - x1)

y - y1 = 1/3(x - x1)

Plug in the given point:

y - y1 = 1/3(x - x1)

y - 2 = 1/3(x - 3)

So, the correct answer is y - 2 = 1/3(x - 3)

Answer:

y - 10 = -1/2(x + 4)

General Formulas and Concepts:

Algebra I

Coordinates (x, y)

Point-Slope Form: y - y₁ = m(x - x₁)

Step-by-step explanation:

Step 1: Define

Identify variables

m = -1/2

Point (-4, 10) → x₁ = -4, y₁ = 10

Step 2: Find

Answer: [tex]y=-\frac{1}{2} x+8[/tex]

Step-by-step explanation:

An equation of a line can be in slope intercept form which is y=mx+b

m is the slope, b is the y intercept, x it the x coordinate, and y is the y coordinate. Since we know the slope is -1/2 and we know a x coordinate is -4 and a y coordinate is 10 we can sub them in and solve for the value of b.

[tex]y=mx+b\\10=(-\frac{1}{2})(-4)+b\\10=2+b\\10-2=2+b-2\\8=b[/tex]

The value of b is 8. We can now sub it in for our equation of the line. This time with x and y as variables.

y=-1/2x+8

Step-by-step explanation:

we can simplify the stuff inside the parentheses to

[tex] \frac{ {x}^{3} }{2y} [/tex]

now we need to multiply it with itself, giving us

[tex] \frac{ {x}^{6} }{4 {y}^{2} } [/tex]

so yeah, D is the correct answer

Step-by-step explanation:

Given: [∀x(L(x) → A(x))] →

[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for

arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof

technique.

Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

We need to show that the above expression is unsatisfiable (False).

¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))

∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))

E.I with respect to x,

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))

E.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b

U.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Since P ∧ Q is P, drop L(a) from the above expression.

(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Apply distribution

(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))

Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to

(L(b) ∧ H(a, b) ∧ ¬A(b))

U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace

¬A(b) in the above expression with ¬L(b). Thus, we get,

(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.

This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows

from the premise.

15

Answer:

Your answer would be B

Step-by-step explanation:

So right away you can get rid of a and d since they are positive numbers, there is no positive numbers in the graph were the line is.

So we know that the y-intercept is -2 (as you can see the line pass through (0,-2))

And we know the y intercept is -8 (since the line pass through (-8,0))

so you are left with b and c, c is incorrect because the -2 goes through the y-intercept not the x.

The right choice is b, it states that the x-intercept -8 pass through the line, the y-intercept is -2

Your welcome and hoped this helped!

Answer:

The length is 8 cm. Since its a square, so the length of both its sides are equal.

l^2=64

where l=length of side

square root both sides

then, l=8

Answer:

8cm is the length of its side.

Step-by-step explanation:

Answer:

x - 8>-4-x

Step-by-step explanation:

Looking at x - 8>-4-x

Collect the like terms;

x+x > -4 + 8

2x < 4

x > 4/2

x < 2

Since the values of x are greater than 2,this shows that they are positive values and will be farther from -8 than -4

Given:

The stem and leaf plot of a data set is given.

Legend:1|0 represents 10.

To find:

The original data set for the given stem and leaf plot.

Solution:

It is given that 1|0 represents 10 in the given stem and leaf plot. Using this, the original data set from the given stem and leaf plot is:

10, 11, 14, 21, 24, 24, 27, 29, 33, 35, 35, 35, 37, 38, 40, 41.

These values are in ascending order.

Therefore, the original set of data is 10, 11, 14, 21, 24, 24, 27, 29, 33, 35, 35, 35, 37, 38, 40, 41.

Answer:

Hi, there the answer is

These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Hope This Helps :)

Step-by-step explanation:

First degree equations

A first degree equation has the form

ax + b = 0

There are some special cases where the equation can have one, infinitely many or no solution

If , the equation has exactly one solution

If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0

If a=0 and  the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.

We have been given some equations, we only need to put them in standard form

-5x + 12 = –12x – 12

Rearranging

7x + 24 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x + 12

Rearranging

-10x + 0 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x – 5

Rearranging

-10x + 17 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = -5x – 12

Rearranging

0x + 24 = 0

It has no solution, no matter what the value of x is, it's impossible that 24=0

Answer: These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

9514 1404 393

Answer:

  x = 8/7

Step-by-step explanation:

The only real zero of this linear function is the value of x that makes y=0:

  0 = -7x +8

  7x = 8 . . . . . . add 7x

  x = 8/7 . . . . . .divide by 7

9514 1404 393

Answer:

  5/8

Step-by-step explanation:

Since the ratio is common, it can be found from the ratio of any pair of adjacent terms.

  r = 480/768 = (5·96)/(8·96) = 5/8

The common ratio is 5/8.

Answer:

Step-by-step explanation:

Given that:

[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]

at point (0, -2)

[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]

Taking the differential from the equation above with respect to x;

[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]

Collect like terms

[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

Hence, the slope of the tangent line m can be said to be:

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

At point (0,-2)

[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]

[tex]\dfrac{dy}{dx}= 0[/tex]

m = 0

So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:

(y - y₁ = m(x - x₁))

y + 2 = 0(x - 0)

y + 2 = 0

y = -2

Answer:

No choices listed.

Step-by-step explanation:

Answer:

63.44degrees

Step-by-step explanation:

Given that;

tan(A-45) = 1/3

A-45 = arctan(1/3)

A - 45 = 18.44

A = 18.44+45

A = 63.44degrees

Hence the value of A is 63.44degrees

Hi there!  

»»————-　★　————-««

I believe your answer is:  

Option B: [tex]y=-5x-6[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Slope-Intercept Form:}}\\\\------------\\y=mx+b\\\\\boxed{\text{\underline{Key}}}\\\\\rightarrow\text{m - slope}\\\\\rightarrow\text{b - y-intercept}[/tex]

⸻⸻⸻⸻

We are given the information of:

⸻⸻⸻⸻

[tex]\boxed{\text{Replace The Variables with The Appropriate Values:}}\\\\y=mx+b\\\\\rightarrow\text{-5 would replace 'm', -6 would replace 'b'.}\\\\\text{\underline{Therefore:}}\\\\y=mx+b\rightarrow\boxed{y=-5x-6}[/tex]

⸻⸻⸻⸻

Option B should be the correct answer.

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

First find the SA of the triangular figure

4 x 3 = 12 cm^2 (the triangles on the sides)

2 x 3 = 6 cm^2 (the back square)

2 x 5 = 10 cm^2 (the slanted square)

*I'm not sure if this question includes the bottom of the triangle but here it is anyways

4 x 2 = 8 cm^2

Including the bottom the SA of the triangular figure is:

12 + 6 + 10 + 8 = 36 cm^2

Find the SA of the rectangular shape

4 x 2 = 8 cm^2 (the bottom square)

2 x 6 = 12 x 2 = 24 cm^2 (the sides)

4 x 6 = 24 x 2 = 48 cm^2 (the front and back)

Add them up

8 + 24 + 48 = 80 cm^2

If you wanted to find the SA of the whole figure it would be:

12 + 6 + 10 + 8 + 24 + 48 = 108 cm^2

Hope this helps!

Answer: B

Step-by-step explanation:

Answer:

-5ºC < 5ºC is an inequality that compares temperatures.

B is the correct answer for the multiple choice question.

Answer:

The smallest possible length is 0.83m

Step-by-step explanation:

Given

[tex]Volume = 565L[/tex]

Required

The smallest length of the tank

Since the tank is cubical, then the volume is:

[tex]Volume = Length^3[/tex]

This gives:

[tex]565L= Length^3[/tex]

Express as [tex]m^3[/tex]

[tex]\frac{565m^3}{1000} = Length^3[/tex]

[tex]0.565m^3 = Length^3[/tex]

Take cube roots of both sides

[tex]0.8267m = Length[/tex]

Rewrite as:

[tex]Length = 0.8267m[/tex]

Approximate

[tex]Length = 0.83m[/tex]

Answer:

7x - 8

Step-by-step explanation:

Hope this helps!

Answer:

The answer is C

Hope this helped!

9514 1404 393

Answer:

  40

Step-by-step explanation:

The "initial value" is the value when x=0.

  [tex]f(x)=\dfrac{800}{1+19e^{-0.402x}}\\\\f(0) =\dfrac{800}{1+19e^0}=\dfrac{800}{1+19}=\dfrac{800}{20}\\\\=\boxed{40}[/tex]

The initial value is 40.

Answer:

b. $0.02[tex]/in^3[/tex]

Step-by-step explanation:

Given

[tex]r =1in[/tex]

[tex]h = 10in[/tex]

[tex]Cost_{1pk} =\$3[/tex]

[tex]Cost_{2pk} =\$5[/tex]

Required

The difference in the price per [tex]in^3[/tex]

First, calculate the volume (V) of the cylinder

[tex]V = \pi r^2h[/tex]

[tex]V = 3.14 *1^2 * 10[/tex]

[tex]V = 31.4[/tex]

The unit cost of 1 pack is:

[tex]Unit_{1pk} = \frac{Cost_{1pk}}{V}[/tex]

[tex]Unit_{1pk} = \frac{\$3}{31.4in^3}[/tex]

The unit cost of 2 packs is:

[tex]Unit_{2pk} = \frac{Cost_{2pk}}{2*V}[/tex]

[tex]Unit_{2pk} = \frac{\$5}{2*31.4}[/tex]

[tex]Unit_{2pk} = \frac{\$5}{62.8in^3}[/tex]

The difference (d) is:

[tex]d = |Unit_{2pk} - Unit_{2pk}|[/tex]

[tex]d = \frac{\$3}{31.4in^3} - \frac{\$5}{62.8in^3}[/tex]

Take LCM

[tex]d = \frac{\$6 - \$5}{62.8in^3}[/tex]

[tex]d = \frac{\$1}{62.8in^3}[/tex]

[tex]d = \$0.0159/in^3[/tex]

Approximate

[tex]d = \$0.02/in^3[/tex]

Answer:

b)

Step-by-step explanation:

had it on my quiz also give other dude brainliest.

Answer:

F(-2)= g(-2)

Step-by-step explanation:

F(-2)= g(-2), both function have the same points of intersect.