I need help with math pls

Answer:

8

Step-by-step explanation:

180=90+40+6x+2

180=132+6x

48=6x

x=8

Answer:

x=4 i think havent done this in a long time

Step-by-step explanation:

Answer:

Scale factor = 1.5

Step-by-step explanation:

Formula for the scale factor,

Scale factor = [tex]\frac{\text{Measure of one side of the Image}}{\text{Measure of one side of the preimage}}[/tex]

In this question, image is triangle Y and preimage is triangle X.

Scale factor of X to Y = [tex]\frac{15}{10}[/tex]

                                    = 1.5

Therefore, scale factor = 1.5 is the answer.

Answer:

46.2

Step-by-step explanation:

46.188= 46.2

Answer:

z = 25

Step-by-step explanation:

adjacent angles in a rhombus are supplementary

3z - 15 + 7z - 55 = 180

10z - 70 = 180

10z = 250

z = 25

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle ([tex]a[/tex], [tex]b[/tex], [tex]c[/tex]), but all angles are unknown ([tex]A[/tex], [tex]B[/tex], [tex]C[/tex]). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that [tex]a = 19[/tex], [tex]b = 16[/tex] and [tex]c = 11[/tex], then the missing angles are, respectively:

Angle A

[tex]a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A[/tex] (1)

[tex]A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)[/tex]

[tex]A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right][/tex]

[tex]A \approx 87.395^{\circ}[/tex]

Angle B

[tex]b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B[/tex] (2)

[tex]B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)[/tex]

[tex]B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right][/tex]

[tex]B\approx 57.271^{\circ}[/tex]

Angle C

[tex]C = 180^{\circ}-A-B[/tex]

[tex]C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}[/tex]

[tex]C = 35.334^{\circ}[/tex]

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.