I need the correct answers

Answer:

b < c < a < d

Explanation:

The weak acid with the lowest pKa will be the most acidic. In the other way, the conjugate base which the acid is weak will be strong.

The weak base with the lowest pKb will be the most basic. And the conjugate base of the weak base will be a strong acid.

Ka Acetic acid = 1.8x10-5

Ka HCN = 1.9x10-10

Kb pyridine = 1.7x10-9

Kb NH3 = 1.8x10-5

NH4Br is the conjugate base of a weak base. That means is a strong acid.

NH4Br has the lowest pH

NaBr is the conjugate base of a strong acid, HBr. That means NaBr is neutral

The most basic between the conjugate base of the acetic acid, NaCH3CO2 and KCN is KCN because the acetic acid is the stronger acid regard to HCN.

The rank is:

NH4Br < NaBr < NaCH3CO2 < KCN

Answer:

If reaction is taking place at room temperature and pressure(rtp)

= 360 litres of O₂ at rtp

If reaction is taking place at  standard temperature and pressure(stp):

= 336 litres of O₂ at stp

Explanation:

2C₂H₆ + 70₂ → 4CO₂ + 6H₂O

1 mole of C₂H₆ =  (12 × 2) + (1 × 6) = 24 + 6 = 30g

2 moles of C₂H₆ = 30 × 2 = 60g

From the equation:

1 mole of 0₂ reacts with 2 moles of C₂H₆

1 mole of 0₂ reacts with  60g  of C₂H₆

? moles of 0₂ react with 90g of C₂H₆

[tex]\frac{90}{60}[/tex]= 1.5 moles of O₂

Considering condition of reaction taking place whether room temperature and pressure(rtp) or standard temperature and pressure(stp)

If room temperature and pressure(rtp):

1 mole of 0₂ occupies 24 liters/24000 cm³/ 24 dm³ of O₂

1.5 moles of O₂ occupies (24 × 1.5)  litres of O₂

= 360 litres of O₂ at rtp

If standard temperature and pressure(stp):

1 mole of 0₂ occupies 22.4 liters/22400 cm³/ 22.4 dm³ of O₂

1.5 moles of O₂ occupies (22,4 × 1.5)  litres of O₂

= 336 litres of O₂ at stp

Explanation:

4NH3 + 502 - 6H20 + 4NO

How many grams of O2 are required to produce 0.3 mol of H20?

4NH3 + 5O2 --> 6H2O + 4NO

How mant grams of NO are produced from 1.55 mol of NH3?

4NH3 + 5O2 --> 6H2O + 4NO

How many grams of NO is produced if 12g of 02 is combined with ammonia?

Answer:

Creo que es D pero no tan segura

Explanation:

Answer: Hello the compound is missing but I was able to get the Full question and missing compound . ( compound = copper sulfate )

answer : statement ; 2 , 3 and 5

Explanation:

The true statements regarding the coordination compound ( copper sulfate ) are :

During the coordination of compounds dative bonds exits between the transition metals and the Ligands molecules

Answer:

Ni(NO₃)₂ + Na₂CO₃ ⇒ NiCO₃ + 2 NaNO₃

Explanation:

Let's consider the unbalanced equation for the reaction that occurs when aqueous solutions of nickel(II) nitrate and sodium carbonate are combined. This is a double-replacement precipitation reaction.

Ni(NO₃)₂ + Na₂CO₃ ⇒ NiCO₃ + NaNO₃

We will balance the equation using the trial and error method.

First, we will balance Na atoms by multiplying NaNO₃ by 2.

Ni(NO₃)₂ + Na₂CO₃ ⇒ NiCO₃ + 2 NaNO₃

As we can see, the equation is balanced.

Answer:

There are 20 electrons.

Explanation:

Chlorine has 17 electrons in its atom to begin with (you can tell from the proton number in the periodic table).

A charge of -3 means that the chlorine atom gained 3 electrons, and now needs to lose 3 electrons to return to its atom configuration.

Answer:

Oxygen and Silicon

Explanation:

Oxygen and Silicon are the most abundant elements in magma, SiO₂

-TheUnknownScientist

Answer:

[tex]Q_{sln}=-3219.25 J[/tex]

Explanation:

Hello there!

In this case, for this calorimetry problem, it is possible for us to infer that the heat of the reaction of dissolution of KNO3 is absorbed by the solution composed by the former and water so that we can write:

[tex]Q_{rxn}=-Q_{sln}[/tex]

Thus, given the mass, specific heat and temperature of the solution, we plug in the data to obtain the heat absorbed, by the reaction:

[tex]Q_{rxn}=-m_{sln}C_{sln}\Delta T _{sln}\\\\Q_{rxn}=-(13.3+213)g(4.184\frac{J}{yg\°C} )(19.60-23.00)\°C\\\\Q_{rxn}=3219.25J[/tex]

Also, we can say the the heat released by the solution was -3219.25 J.

Best regards!

Answer:

A

Explanation:

Answer:

Option A

Explanation:

Addition of too much of solvent will make the solution dilute due to which the crystals will not form. Hence option D is incorrect

On the other hand adding a minimum amount of boiling solvent will give a saturated solution for recrystallization. Hence, option A is incorrect

Addition of cold solvent will lower the rate of formation of crystals. Hence, both option B and C are incorrect

Answer:

No

Explanation:

thats scientifically impossible

Answer:

I'll explain.

Explanation:

The molecules of two different elements, nitrogen and oxygen, make up about 99 percent of the air. The rest includes small amounts of argon and carbon dioxide. Oxygen is the life-giving element in the air. You can tell because they're on the periodic table which is a table for elements.

Explanation:

nitrogen and oxygen are the gases in the air which are elements you can simply say it by looking the periodic table

Answer:

Volume is reduced to half

Explanation:

Acid base titration are commonly used reactions in a lab, and are ofter used to get pH or different kind of solutions.

The neutralization of an acid base reaction is reached, when the solution (having added an indicator previously) changes its original color. chemically speaking, this occurs when the number of moles of the acid and the base are balanced and equal. In other words the following:

n₁ = n₂   (1)

This expression can also be expressed in function of concentration and volume:

M₁V₁ = M₂V₂   (2)

From here, solving for V₁:

V₁ = M₂V₂  / M₁

Now, this expression is true only when we have the same kind of substance that can lose or gain the same number of hydrogens.

Lets suppose that we have as base NaOH (Monoprotic base) and HCl (monoprotic acid), the titration reaction would be:

NaOH + HCl --------> NaCl + H₂O

As both of the species are monoprotic, the number of moles are the same  when they reach the equilibrium, so, expression  (2) can be used, and calculate volume or concentrations.

However, in this case, a partner made a mistake and use a diprotic acid, in this case, H₂SO₄, In this case, things chance because H₂SO₄ is diprotic, meaning that we need to dissociate two hydrogens in equilibrium, therefore, expression (2) would be something like this.

Acid: 1; Base: 2

H₂SO₄ + 2NaOH ------> Na₂SO₄ + H₂O

nH₂SO₄ = n₁ = 1

nNaOH = n₂ = 2

n₁/n₂ = 1/2

2n₁ = n₂   (3)

Writting this, in function of concentration and volume, it would be:

2M₁V₁ = M₂V₂   (4)

From here, if we solve for the volume of the acid (V₁):

V₁ = M₂V₂ / 2M₁

Therefore, according to this expression, we can see that the volume required of the acid would be half the volume required of the monoprotic acid. For example, if we need 50 mL of Chloridic acid to reach the equivalence point with NaOH, then, with H₂SO₄ it will only need 25 mL. This, of course, assuming that concentrations are the same, and volume of the base used, the same.

Hope this helps

Answer:

Generally, the first ionisation energy increases along a period. But there are some exceptions one which is not an exception

Answer:

Explanation:

Remark

Interesting que8stion. You have to figure out how many mols are present in each reactant. Since all periodic tables are different, I'm going to use rounded numbers. If it is too close, I will go further.

NaCl

Na = 23

Cl = 35.5

1 mol = 58.5 grams

given = 50.0 grams

Mols for the reaction = 50/58.5 = 0.855

H2SO4

H2       =    2*1        2

S          =   1 * 32   32

O4       =   4*16     64

1 mol  =               98   grams

mols  present = 50/98 = 0.510

MnO2

Mn     = 1 * 55    = 55

O2   =   2*16      = 32

1 mol =                  87 grams

mols available    = 50/87 = 0.5747

Discussion

Na Cl and H2SO4 both require 2 moles for every mol of Cl2 produces.

H2SO4  has 0.51 mols available for a reaction

NaCl has  0.855 moles available for a reaction

MnO2 has 0.575 moles available for a reaction.

Given those numbers 0.510 mols of H2SO4 will only produce 0.255 mols of chlorine and the rest will be reduced in a similar manner. H2SO4 is the limiting reagent (reactant).

In other words only 0.510 moles of NaCl will be used and 0.855 - 0.510 moles will be left over on the reactants side.

only 0.575 moles of MnO2 will be used and 0.065 moles will be left over.

The oddity in the result shows up because the balance numbers in the equation give a ratio of 2 to 1 for H2SO4 and NaCl The 2 belongs to the reactants and the 1 for the chlorine.

The partial pressure of Xe in the mixture is 1.850 atm. (partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar = 1.850 atm).

To find the partial pressure of Xe, we need to subtract the partial pressures of He and Ar from the total pressure.

Total pressure = partial pressure of He + partial pressure of Ar + partial pressure of Xe

Given:

Total pressure = 2.40 atm

Partial pressure of He = 0.300 atm

Partial pressure of Ar = 0.250 atm

Let's solve for the partial pressure of Xe:

Partial pressure of Xe = Total pressure - Partial pressure of He - Partial pressure of Ar

Partial pressure of Xe = 2.40 atm - 0.300 atm - 0.250 atm

Partial pressure of Xe = 1.850 atm

Therefore, the partial pressure of Xe in the mixture is 1.850 atm.

To learn more about partial pressure of Xe  here

https://brainly.com/question/34136076

#SPJ2

Answer:

C) pH=pKa+log[((0.0050×0.10)0.0150)/((0.0100×0.20)−(0.0050×0.10)0.0150)]

Explanation:

To find the pH of a buffer (The mixture of the weak acid and its conjugate base) we have to use Henderson-Hasselbalch equation:

pH = pKa + log [Base] / [Acid]

Where pKa is the pka of the buffer and [] is molar concentration of the species of the buffer

The [Base] is equal to the concentration of NaOH added:

0.10M * (0.005L / 0.015L)

And the concentration of the acid [Acid] is the initial concentration of the acid - the concentration of the NaOH added:

0.0100L * (0.20M)/0.0150L - 0.10M * (0.005L / 0.015L)

That means the pH of the buffer is:

Answer:

C) pH=pKa+log[((0.0050×0.10)0.0150)/((0.0100×0.20)−(0.0050×0.10)0.0150)]

Explanation:

The equilibrium for the acid ionization of HC2HO3 is represented by the equation above. If 10.0mL of 0.20MHC2HO3 reacts with 5.0mL of 0.10MNaOH, which of the following could be used to calculate the correct pH of the resulting solution. pH=pKa+log[((0.0050×0.10)0.0150)/((0.0100×0.20)−(0.0050×0.10)0.0150)]

Answer:

Far as I know coefficients are unitless. sorry if this don't help ;)

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

[tex]AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)[/tex]

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

[tex]Ksp=[Ag^+][Cl^-][/tex]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       [tex]\ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)[/tex]

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

[tex]Ksp=x^2[/tex]

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!

Answer:

H₂(g) + F₂(g) ⇒ 2 HF(g)   ΔH°rxn = -542 kJ

Explanation:

Let's consider the unbalanced equation that occcurs when H₂(g) reacts with F₂(g) to form HF(g).

H₂(g) + F₂(g) ⇒ HF(g)

In order to get the balanced equation, we will multiply HF(g) by 2.

H₂(g) + F₂(g) ⇒ 2 HF(g)

To convert a balanced equation into a thermochemical equation, we need to add the standard enthaply of the reaction, considering that 542 kJ of energy are evolved for each mole of H₂(g) and there is 1 mole of H₂(g) in the balanced equation. By convention, when energy is released, it takes a negative sign. The thermochemical equation is:

H₂(g) + F₂(g) ⇒ 2 HF(g)   ΔH°rxn = -542 kJ

Answer:

i'm pretty sure its the last answer and if not its the 2nd one

Answer:

29.5 days

Explanation:

orginally 27.3 days but 29.5 days is also correct

Answer:

The answer is B

Explanation:

The answer is B because representative particles can only be atoms.

Answer:

B. Eastern Europe

Explanation:

The economy of Eastern Europe depends on producing foods. For example, Poland and Belarus are two countries in Eastern Europe, and they both produce chocolates. Producing foods isn't the only detrimental part of the region's economic data. The other half depends on consumer goods. For example, Estonia and Latvia are good countries in packaging food. The answer to the question is B.