I only need the odd numbers answered

Answer:

59 / 71

Step-by-step explanation:

Given the data :

A B C Total

Male 20 10 13 43

Female 15 2 11 28

Total 35 12 24 71

The probability of randomly selecting a Student that got B ;

Probability = required outcome / Total possible outcomes

P(getting B) = number of students who got B / total number of students

P(getting B) = 12 / 71

Probability of getting B = 12 /71

Probability of not getting B = P(getting B)' = 1 - P(getting B)

Probability that student did not get "B" = 1 - 12/71 = 59 / 71

Answer:

(using the numbers youve prpvided) 3444544

Step-by-step explanation:

214 x 8 x 2012 = 3444544

Answer:

.20

Step-by-step explanation:

take the two digit % and move the decimal two places to the left

Answer: 0.2

Step-by-step explanation: 20/100 is 1/5 and 1/5 means 1 divided by 5 so the answer is 0.2

Answer:

13th term

Step-by-step explanation:

41 = 7n - 50

41 + 50 = 7n

91 = 7n

7n = 91

n = 91/7

n = 13

13th term has value 41

Answer:

n = 13

Step-by-step explanation:

7n - 50 = 41

Add 50 to both sides

7n = 41 + 50

7n = 91

Divide both sides by 7

n = 91/7

n = 13

Step-by-step explanation:

t8 = a1 + (n - 1)*d

t8 = 17

17 = a1 + 7*d

t12 = 25

25 = a1 + 11d

17 = a1 + 7d Subtract

8 = 4d Divide by 4

8/4 = 4d/4

2 = d

17 = a1 + 7d

17 = a1 + 7*2

17 = a1 + 14 Subtract 14

3 = a1

Sum 20 terms

The 20 term = a1 + 19*2

The 20 term = 3 + 38

= 41

Sum = (a1 + a20) * 20 / 2

Sum = (3 + 41)* 20/2

Sum = 44 * 10

Sum = 440

Hi!

√80 = √(16 • 5) = √(4² • 5) = 4√5

Answer:

hlo how are u?whats ur day is going

Answer:

467 muffins

Step-by-step explanation:

143 + 211 + 113 = 467

Answer: A

Step-by-step explanation:

The main parent functions are x, and x raised to the power of something (examples: [tex]x^2, x^3, x^4[/tex], etc)

Answer:

Step-by-step explanation:

[tex]\frac{34-40}{8}= -.75[/tex]

Hello,

[tex]f(x)=2x^4-x^3-18x+9x\\\\=x(2x^3-x^2-18x+9)\\\\=x(x^2(2x-1)-9(2x-1))\\\\=x(2x-1)(x^2-9)\\=x(2x-1)(x-3)(x+3)\\[/tex]

Zeros are : 0;  1/2; -3; 3.

The zeros of the function are -3, 0, 1/2 and 3.

The given function is [tex]f(x)=2x^{4} -x^{3} -18x^{2} +9x[/tex].

Zeros of a function are the points where the graph of the function meets the X-axis i.e., at the solutions of f(x) = 0.

Now, factorise the given function, that is f(x)=x(2x³-x²-18x+9).

=x[x²(2x-1)-9x(2x-1)]

=x(2x-1)(x²-9)

=x(2x-1)(x+3)(x-3)

= -3, 0, 1/2, 3

Therefore, the zeros of the function are -3, 0, 1/2 and 3.

To learn more about the zeros of the function visit:

https://brainly.com/question/16633170.

#SPJ2

Answer:

Q1 = 32.5

Q3 = 50

D2 = 29

D8 = 52

67th percentile = 46.5

Step-by-step explanation:

Given the ordered data:

13, 13, 13, 20, 26, 29, 32, 33, 34, 34, 35, 35, 36, 37, 38, 41, 41, 41, 45, 46, 47, 47, 48, 52, 54, 55, 56, 62, 67, 82

The first quartile :

Q1 = 1/4(n+1)th term

n = sample size = 30

Q1 = 1/4(31) = 7.75 = (7th + 8th) / 2 = (32+33) / 2 = 32.5

Q3 = 3/4(n+1)th term

n = sample size = 30

Q3 = 3/4(31) = 23.25 = (23rd + 24th) / 2 = (48+52) / 2 = 50

D2 = 2nd decile

2 * 10% = 20%

20% * n

0.2 * 30 = 6th = 29

D8 = 8th decile

8 * 10% = 80%

80% * 30 = 24th = 52

67th percentile :

0.67 * 30 = 20.1 th

(20th + 21th) / 2

(46 + 47) / 2

= 46.5

9514 1404 393

Answer:

  (t, u, w) = (1, -2, -2)

Step-by-step explanation:

A graphing calculator makes short work of this, giving the solution as ...

  (t, u, w) = (1, -2, -2)

__

There are many ways to solve this "by hand." Here's one of them.

Add the first and third equations. Their sum is ...

  -3t +4w = -11 . . . . . [eq4]

Add this to twice the second equation. That sum is ...

  (-3t +4w) +2(-4t -2w) = (-11) +2(0)

  -11t = -11

  t = 1

Substituting this into the second equation gives ...

  -4(1) -2w = 0

  w +2 = 0 . . . . divide by -2

  w = -2 . . . . add -2

Substituting for t in the third equation lets us find u.

  2(1) -2u = 6

  -1 +u = -3 . . . . . divide by -2

  u = -2 . . . . add 1

The solution is (t, u, w) = (1, -2, -2).

Answer:

D. No, there isn’t enough information because only two pairs of corresponding sides can't be used to prove that two triangles are congruent.

Answer:

it's and equilateral triangle because

all sides are equal

Answer:

equilateral triangle i have a math proffesor helping me

Step-by-step explanation:

I have a math proffesor helping me

[tex] {64}^{ \frac{2}{3} } \div {27}^{ \frac{5}{3} } \times 54 \\ = > \: {({2}^{3} )}^{ \frac{2}{3} } \div ({{3}^{3}})^{ \frac{5}{3} } \times 54 \\ = > \: {2}^{2} \div {3}^{5} \times 54 \\ = > \: 4 \div 243 \times 54 \\ = > \: 4 \div 13122 \\ = > \: \frac{4}{13122} \\ = > \: \frac{2}{6561} [/tex]

Hope it helps!!!!!!!!!!

Answer:

Step-by-step explanation:

Given function h(x).

Shift left:

Shift down:

Given function is,

→ h(x)

As we shift left,

→ h(x) = h(x + 3)

As we shift down,

→ h(x + 3) = h(x+3)-5

Then the equation is,

→ h(x+3)-5

It is correct answer.

Answer:

11.5

Step-by-step explanation:

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

Answer:

11.5

Step-by-step explanation:

Add all them all together.

7+9+10+12+15+16=69

Divide by the amount of numbers there are

69/6=11.5

11.5

Step-by-step explanation:

here is the answer to your question

Answer:

0.4204 probability, option b.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

[tex]f(x) = \mu e^{-\mu x}[/tex]

In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.

The probability that x is lower or equal to a is given by:

[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]

Which has the following solution:

[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]

The probability of finding a value higher than x is:

[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]

Children arrive at a house to do Halloween trick-or- treating according to a Poisson process at the unlucky rate of 13/hour

13 arrivals during an hour, which means that the mean time between arrivals, in minutes is of [tex]\mu = \frac{13}{60} = 0.2167[/tex]

What is the probability that the time between the 15th and 16th arrivals will be more than 4 minutes ?

This is P(X > 4). So

[tex]P(X > 4) = e^{-0.2167*4} = 0.4204[/tex]

So the correct answer is given by option b.

Answer:

Step-by-step explanation:

X+3 SO = Cymath can't further simplify this.

Please try another operation.

X-220= Cymath can't further simplify this.

Please try another operation.

y= AsymptotesFind the vertical, horizontal and slant asymptotes.

"Asymptotes y=x^2/(x+8)"

"Asymptotes y=1/x"

DifferentiateFind the derivative.

"Differentiate cos(x)^4"

"Differentiate x^5/y for x"

DomainFind the domain of a function.

"Domain y=2/x"

"Domain y=sqrt(x-3)"

Answer:

can you be more specific?

Step-by-step explanation:

Answer

a) chart

Step-by-step explanation:

a) chart best represents the following information about student results from a class assignment

Answer:

Kendriya z-score keva product

Answer:

30° and -1/2. This is pretty easy to do on a piece of paper but I recommend googling "unit circle" and clicking images, it tells you everything you need to know.

Step-by-step explanation:

Answer:

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Step-by-step explanation:

Given

[tex]n = 3[/tex]

[tex]B \to boys[/tex]

[tex]G \to girls[/tex]

[tex]P(G) = P(B) = 0.5[/tex] --- equal probability

See comment for complete question

Required:

[tex]P(At\ least\ one\ girl)[/tex]

To do this, we make use of complement rule:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

The event that there is no girl out of the 3 children is: B B B

And the probability is:

[tex]P(No\ Girl) = P(B) * P(B) * P(B)[/tex]

[tex]P(No\ Girl) = 0.5*0.5*0.5[/tex]

[tex]P(No\ Girl) = 0.125[/tex]

So:

[tex]P(At\ least\ one\ girl) = 1 - P(No\ girl)[/tex]

[tex]P(At\ least\ one\ girl) = 1 - 0.125[/tex]

[tex]P(At\ least\ one\ girl) = 0.875[/tex]

Answer:

C $13,220

Step-by-step explanation:

[tex] \sqrt[5]{32} \times 2 \sqrt[3]{81} \\ = {32}^{ \frac{1}{5} } \times 2 {(81)}^{ \frac{1}{3} } \\ = ({{2}^{5}})^{ \frac{1}{5} } \times {2({3}^{3})}^{ \frac{1}{3} } \\ = {2}^{1} \times 2({3}^{1}) \\ = 2 \times 2 \times 3 \\ = 4 \times 3 \\ = 12[/tex]

This is the answer.

Hope it helps!!