I really need help with this question as fast as possible​

Answer:

The first one with the sequence 0.25,1,4,16

Answer:

the first one

Step-by-step explanation:

Answer is C

✔✔✔✔✔✔✔✔✔✔✔✔✔✔✔✔✔

Answer:

x <2

Step-by-step explanation:

2.5 – 1.2x < 6.5 – 3.2x

Add 3.2x to each side

2.5 – 1.2x+3.2x < 6.5 – 3.2x+3.2x

2.5 +2x < 6.5

Subtract 2.5 from each side

2.5+2x-2.5<6.5-2.5

2x<4

Divide by 2

2x/2 < 4/2

x <2

Given:

The expression is:

[tex]13+23+12+7[/tex]

To find:

The value of the given expression by using Commutative and Associative properties of numbers.

Solution:

We have,

[tex]13+23+12+7[/tex]

Applying parenthesis and brackets, we get

[tex]=[13+(23+12)]+7[/tex]

[tex]=[13+(12+23)]+7[/tex]             [Commutative properties of numbers]

[tex]=[(13+12)+23]+7[/tex]             [Associative properties of numbers]

[tex]=(25+23)+7[/tex]

Using Associative properties of numbers, we get

[tex]=25+(23+7)[/tex]               [Associative properties of numbers]

[tex]=25+30[/tex]

[tex]=55[/tex]

Therefore, the value of the given expression 55.

Answer:

The vertex is (0,0)

Step-by-step explanation:

To find the x coordinate of the vertex

x = -b/2a  where ax^2 +bx +c

a=1 b=0 c=0

x = -0/2(1) = 0

The y value is found by substituting into the equation

y = (0)^2 =0

The vertex is (0,0)

Answer:

The equations are linearly independent in vector space R²

Step-by-step explanation:

The given vectors are;

V₁ = (1, 2, 3), V₂ = (1, 1, 1), V₃ = (1, 1, 0)

For the vectors to be linearly dependent, we have;

a₁·V₁ + a₂·V₂ + a₃·V₃ = 0

Where;

a₁, a₂, and a₃ are not all zero

We get;

[tex]\left[\begin{array}{ccc}1&2&3\\1&1&1\\1&1&0\end{array} \right][/tex]

The vectors are linear dependent, if the following system of equation has a unique set of solution

x + y + z = 0...(1)

2·x + y + z = 0...(2)

3·x + y = 0...(3)

From equation (1), we have;

x = -(y + z)

∴ y + z = -x

Plugging in the value of y + z in equation (2) gives;

2·x + y + z = 0

2·x + y + z = 2·x - x = x = 0

x = 0

From equation (3), we get;

3·x + y = 0, where x = 0, therefore;

3 × 0 + y = 0

∴ y = 0

From equation (1), we have;

x + y + z = 0

Where, x = 0, and y = 0, we get;

0 + 0 + z = 0

z = 0

The vectors, V₁, V₂, and V₃ are linear independent in R³

In two dimensional space, we have

x + y = 0...(1)

2·x + y = 0...(2)

x + y = 0...(3)

Subtracting equation (1) from equation (2) gives;

2·x + y - (x + y) = 2·x - x + y - y = x = 0

∴ x = 0

From equation (1), we get

x + y = 0

∴ 0 + y = 0

∴ y = 0

Therefore, the equations are also linearly independent in vector space R²

Answer:

Range: [-7, 8]

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

According to the graph, our y-values span from -7 to 8. Since both are closed dot, they are included in the range:

Range: [-7, 8]

Answer:

t= r-21

7

Step-by-step explanation:

r = 7(t+3)

expanding the bracket

r = 7t + 21

bringing t to the left hand side

7t = r - 21

divide both sides by seven

t= r-21

7

Answer:

t = (r/7) - 3

Step-by-step explanation:

Given equation,

→ r = 7(t + 3)

Now the value of t will be,

→ r = 7(t + 3)

→ r = 7t + 21

→ r - 21 = 7t

→ 7t = r - 21

→ t = (r - 21)/7

→ t = (r/7) - 3

Hence, value of t is (r/7) - 3.

Answer:

x = [tex]\sqrt{26}[/tex]

Step-by-step explanation:

using pythagoras theorem

here [tex]\sqrt{13}[/tex] and [tex]\sqrt{13}[/tex] are the legs of the right angled triangle and x is hypotenuse.

a^2 + b^2 = c^2

[tex](\sqrt{ 13 })^2 + (\sqrt{13})^2 = x^2[/tex]

13 + 13 = x^2

26 = x^2

[tex]\sqrt{26}[/tex] = x

Answer:

answer would be c

Step-by-step explanation:

hope this helps

Answer:

x = 1, -5.56

Step-by-step explanation:

x^2 = -7x - 8

shift -7x and -8 to the other side . Remember when u shift minus changes into plus.

x^2 + 7x + 8 = 0

using quadratic equation formula

in quadratic equation one value comes positive and other comes in negative

a = 1  , b = 7 and c = 8

taking positive sign

x = (-b + [tex]\sqrt{b^2 - 4*a*c}[/tex]) /2*a

x = (-7 + [tex]\sqrt{7^2 - 4*1*8}[/tex] ) /2*1

x = (-7 + [tex]\sqrt{49 + 32}[/tex] ) /2

x = (-7 + [tex]\sqrt{81}[/tex] )/ 2

x = -7 + 9 / 2

x = 2/2

x = 1

taking negative sign

(-b - [tex]\sqrt{b^2 - 4*a*c}[/tex] ) /2*a

x = (-7 - [tex]\sqrt{7^2 - 4*1*8}[/tex] ) /2*1

x = (-7 - [tex]\sqrt{49 - 32}[/tex] ) /2

x = -7 - [tex]\sqrt{17}[/tex] / 2

x = -7 - 4.12 / 2

x = -11.12/2

x = -5.56

therefore x = 1 , - 5.56

Answer:

[tex]x = \frac{- 7 + \sqrt{17}}{2} \ , \ x = \frac{-7 - \sqrt{17}}{2}[/tex]

Step-by-step explanation:

[tex]x^2 = - 7x - 8\\\\x^2 + 7x + 8 = 0 \\\\[/tex]

[tex]x = \frac{- b \pm \sqrt{b^2 - 4ac}}{2a}\\\\[/tex]               [tex][ \ a = 1 , \ b = 7 , \ c = 8 \ ][/tex]

[tex]x = \frac{-7 \pm \sqrt{49 - (4\times 8)}}{2} \\\\x = \frac{-7 \pm \sqrt{17}}{2} \\\\x = \frac{-7 + \sqrt{17}}{2} , \ , \frac{-7 - \sqrt{17}}{2}[/tex]

Answer:

maybe like 12

Step-by-step explanation:

I would think 12 because because it is 2 of the square so I think 6 + 6 correct me of I'm wrong.

Answer:

x = 0

Step-by-step explanation:

-2(x-4)=4x+2x+8

Distribute

-2x +8 =4x+2x+8

Combine like terms

-2x+8 =6x+8

Add 2x to each side

-2x+2x+8 =6x+2x+8

8 = 8x+8

Subtract 8 from each side

8-8 = 8x+8-8

0 = 8x

Divide by 8

0=x

Answer:

x = 0

Step-by-step explanation:

-2(x-4) = 4x+2x+8

-2x+8 = 6x+8

8-8 = 6x+2x

0 = 8x

x = 0

Hope this will help and if so, then please mark me as brainliest.

Answer:

Step-by-step explanation:

If ABC i.e angle of centra = 124°Then, we know that angle at any where of Circle is 1/2 if central angle So, ADC = 124/2 => ⛰ ADC = 62

Given:

[tex]m=0.56x-0.25[/tex]

[tex]n=0.20x-0.03[/tex]

To find:

The sum of m and n.

Solution:

We have,

[tex]m=0.56x-0.25[/tex]

[tex]n=0.20x-0.03[/tex]

The sum of m and n is:

[tex]m+n=(0.56x-0.25)+(0.20x-0.03)[/tex]

Combining the like terms, we get

[tex]m+n=(0.56x+0.20x)+(-0.25-0.03)[/tex]

[tex]m+n=(0.76x)+(-0.28)[/tex]

[tex]m+n=0.76x-0.28[/tex]

Therefore, the sum of m and n is [tex]m+n=0.76x-0.28[/tex].

[tex]\longrightarrow{\green{x\:=\:6}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

➝[tex] \:\frac{3x + 2}{4} = \frac{x + 4}{2} [/tex]

➝[tex] \: 2(3x + 2) = 4(x + 4)[/tex]

➝[tex] \: 6x + 4 = 4x + 16[/tex]

➝[tex] \: 6x - 4x = 16 - 4[/tex]

➝[tex]\:2x = 12[/tex]

➝[tex] \: x = \frac{12}{2} [/tex]

➝[tex] \: x = 6[/tex]

Therefore, the value of [tex]x[/tex] is 6.

[tex]\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}[/tex]

➪ [tex] \: \frac{3x + 2}{4} = \frac{x + 4}{2} [/tex]

➪ [tex] \:\frac{3 \times 6 + 2}{4} = \frac{6 + 4}{2} [/tex]

➪ [tex] \:\frac{18 + 2}{4} = \frac{10}{2} [/tex]

➪ [tex] \:\frac{20}{4} = 5[/tex]

➪ [tex] \: 5 = 5[/tex]

➪ [tex] \: L.H.S.=R. H. S[/tex]

Hence verified.

[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{❦}}}}}[/tex]

Answer:

893

Step-by-step explanation:

To the right of the decimal, the number 8 is greater than 4 so you have to round up the number to the left. So 2 becomes 3 in the ones place.

Hope this helps.

[tex]$\mathcal{WHOLE \ \ NUMBERS:}$[/tex]

The closest number is 893

Saludos ten lindo día uwu

Answer:

d -x=y the awnssr may not be correct but I tried so

Answer:

7

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

4 1/5 ÷ 3/5

Change to improper fractions

4 1/5 = ( 5*4+1) /5 = 21/5

21/5 ÷ 3/5

Copy dot flip

21/ 5 * 5/3

Rewriting

21/ * 5/5

7 * 1

7

Step-by-step explanation:

my answer is in the image above

Answer:

(x - 5)² + (y - 5)² = 18

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (5, 5) , then

(x - 5)² + (y - 5)² = r²

r is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (5, 5) and (x₂, y₂ ) = (8, 8)

r = [tex]\sqrt{(8-5)^2+(8-5)^2}[/tex]

  = [tex]\sqrt{3^2+3^2}[/tex]

   = [tex]\sqrt{9+9}[/tex]

   = [tex]\sqrt{18}[/tex] ⇒ r² = ([tex]\sqrt{18}[/tex] )² = 18

Then

(x - 5)² + (y - 5)² = 18 ← equation of circle

Answer: The answer is 7.

1) 7/12= 0.58, 4/7= 0.57

they are about 1/2

2) 7/12 + 4/7 = 97/84= 1.15 approximately 1

which is 1m from the option

Answer:

hey, i think it's the first alternative

Step-by-step explanation:

Answer:

1 / 7

Step-by-step explanation:

Number of sections on spinner = 7

Section is numbered 1 to 7

Since the probability of landing on each section is the same:

Probability that spinner lands on 4 :

Probability, p = Required outcome / Total possible outcomes

Required outcome = landing on 4 = 1

Total possible outcomes = (1 to 7) = 7

P(landing on 4) = 1 /7

Answer:

hello the function graph is turned 90 degree like clock way.

All the plotted graphs represent functions whose inverse is also a function.

A function is a relation between a dependent and independent variable. We can write the examples of functions as -

y = f(x) = ax + b

y = f(x, y, z) = ax + by + cz

Given is to find the function whose inverse is also a function.

A one to one function is a type of function whose inverse is also a function. The linear equations are one to one functions. They are of the form {y} = ax + b. This means that all of the graphs plotted represent a  function whose inverse is also a function. So, we can conclude that all the plotted graphs represent the straight line, and all of them represent functions whose inverse is also a function.

Therefore, all the plotted graphs represent functions whose inverse is also a function.

To solve more questions on functions, visit the link below-

https://brainly.com/question/30194223

#SPJ7

Answer:

8 chocolates

Step-by-step explanation:

im not really good at math and didnt use an equation but if you add 5 and 2 together until 28 and then count up how many 2's you added, you should get the answer! sorry if this isnt helpful <3

Answer:

C

Step-by-step explanation:

Answer:

4628

I hope it will help you all

Answer:

[tex]{ \tt{ \sqrt[3]{24 {n}^{2} } \times \sqrt[3]{36 {n}^{2} } }} \\ = { \tt{( {n}^{ \frac{2}{3} })( \sqrt[3]{864}) }}[/tex]