I will give BRAINLIEST to the correct answer

Answer:

0.5

Step-by-step explanation:

First we need to find the total number of hats 4 green hats + 3 blue hats + 1 orange hat = 8 hats P( green hat) = green / total      

                                            = 4 / 8                    

                                              = 1/2  

Answer:

the answer choices oh uhm I think i

Answer:

i think its yz but not sure

Step-by-step explanation:

Answer:

38

Step-by-step explanation:

triangle

900Answer:900

Step-by-step explanation:

Answer:

$22.50

Step-by-step explanation:

Answer:

$95 is the markup

Step-by-step explanation:

Add 45+50=95

Answer:

A

Step-by-step explanation:

cos(71)x19=6.1

6.1 =6

Answer:

ladder is 20 feet long.So answer is option c.

Step-by-step explanation:

let the length of a ladder be x

take 71 degree as reference angle

using sin rule

sin 71 =opposite/hypotenuse

0.94=19/x

x=19/0.94

x=20.21

x=20 feet

Answer:

The missing parts of the proof includes;

1) ∠ABC = m∠CBD + m∠ABD = 90° (Angle addition postulate)

2) m∠CBD = m∠ABD (Definition of angle bisector)

3) m∠CBD + m∠ABD  = m∠CBD + m∠CBD (Substitution property of equality)

Step-by-step explanation:

The given details of the proof are;

∠ABC is a right angle = 90°

Line DB is a bisector of ∠ABC

Therefore;

1) ∠ABC = m∠CBD + m∠ABD = 90° by angle addition postulate

By the definition of angle bisector, we have;

The angles formed by line DB from ∠ABC are equal,

2) m∠CBD = m∠ABD by the definition of angle bisector

3) m∠CBD + m∠ABD = 90° = m∠CBD + m∠CBD = 2 × m∠CBD by substitution property of equality

2 × m∠CBD = 90°

∴ m∠CBD = 90°/2 = 45°

Answer:

A: Given

B: measure the angle ABC = 90

C: angle addition postulate

D: 2 times the measure of angle CBD = 90

Step-by-step explanation:

Hope this helps <3

[tex]\longrightarrow{\green{\frac{5}{6}}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex] \frac{1}{2} + \frac{1}{3} [/tex]

Since the denominators are unequal, we find the L.C.M (lowest common multiple) for both denominators.

The L. C. M for 2 and 3 is 6.

Now, multiply the L.C.M. with both numerator & denominator.

[tex] = \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} [/tex]

[tex]= \frac{3}{6} + \frac{2}{6} [/tex]

Now that the denominators are equal, we can add them.

[tex]= \frac{3 + 2}{6} \\ \\ = \frac{5}{6} [/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]

Answer:

Step-by-step explanation:

take 50 degree as reference angle

using sin rule

sin 50 = opposite/hypotenuse

0.766 = x /3

0.766*3 = x

2.298 = x

2.30  = x

Step-by-step explanation:

a) Since there are 2 #1 in the spinner, the probability of landing on a 1 is 2/8 or 1/4

b) Since there is only one #2, the probability is only 1/8.

c) Probability of landing on #3 is 2/8 or 1/4.

d) Probability of landing on a #4 is 1/8

e) Just like the case of #1 & #3, there are 2 chances out of eight that it will land on a #5 so the probability is 2/8 or 1/4

Answer:

16/49

Step-by-step explanation:

2/ 7÷ 7/8

Copy dot flip

2/7 * 8/7

Multiply the numerators

2*8 =16

Multiply the denominators

7*7 = 49

numerator over denominator

16/49

Answer:

[tex]\frac{16}{49}[/tex]

Step-by-step explanation:

Answer:

the number is 2

Step-by-step explanation:

5x2=10+9=19

Answer:

They are not similar

Step-by-step explanation:

Angles dont match

Answer:

it is 32

Step-by-step explanation:

the answer is 32 it is the answer

Answer:

32

Step-by-step explanation:

20% of 40 is 8

so 40-8=32

Answer:

The answer is h(x)=(1/4)x

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex](\sqrt{14}-\sqrt{3})(\sqrt{12}+\sqrt{7})=\sqrt{14}*\sqrt{12}+\sqrt{14}*\sqrt{7}-\sqrt{3} *\sqrt{12}-\sqrt{3} *\sqrt{7}\\\\=\sqrt{14*12} + \sqrt{14*7}-\sqrt{3*12}-\sqrt{3*7}\\\\=\sqrt{2*7*2*2*3} + \sqrt{2*7*7}-\sqrt{3*3*2*2}-\sqrt{3*7}\\\\=2\sqrt{2*7*3}+7\sqrt{2}-3*2-\sqrt{21}\\\\= 2\sqrt{42}+7\sqrt{2}-6-\sqrt{21}[/tex]

Answer:

yes

Step-by-step explanation:

Answer:

Step-by-step explanation:

1) Vertically opposite angles are equal.

x + 30 = 180 - 2x

Add '2x' to both sides

x + 30  +2x = 180

3x + 30 = 180

Subtract 30 from both sides

3x = 180 - 30

3x = 150

 x = 150/3

x = 50

2)  Let the angle be x

It's complement angle = 90 - x

[tex]x = \frac{2}{3}(90-x)\\\\x = \frac{2}{3}*90 - \frac{2}{3}*x\\\\x =2*30 - \frac{2}{3}x\\\\x +\frac{2}{3}x = 60\\\\\frac{3}{3}x+\frac{2}{3}x=60\\\\\frac{5}{3}x =60\\\\x = 60*\frac{3}{5}\\\\x = 12*3\\x = 36[/tex]

The angles are : 36 , 54

3) Let the angle be x

It's supplement = 180 - x

[tex]x = \frac{1}{5}(180-x)\\\\x =\frac{1}{5}*180 - \frac{1}{5}x\\\\x + \frac{1}{5}x= 36\\\\\frac{5}{5}x +\frac{1}{5}x = 36\\\\\frac{6}{5}x = 36\\\\x = 36*\frac{5}{6}\\\\x = 6*5 = 30\\[/tex]

Angles are  30 , 150

4) Ratio = 7 : 3

The angles are = 7x , 3x

7x + 3x = 180

10x = 180

x = 180/10

x = 18

7x = 7 * 18 = 126

3x = 3 * 18 = 54

Angles are 126 , 54

1. Intersecting lines are lines that cross each other. When two lines intersect, the opposite angles are equal.

Given: x + 30° and 180° - 2x are vertically opposite angles

⇒   x + 30° = 180° - 2x

⇒   3x = 150°

⇒   x = 50°

2. Let the complement be : C

Given : The other angle is two third of its complement

[tex]\sf{\implies Other \ angle = \dfrac{2}{3} \times C}[/tex]

Two angles are said to be Complementary if their sum is equal to 90°

[tex]\sf{\implies C + \dfrac{2C}{3} = 90}[/tex]

[tex]\sf{\implies \dfrac{5C}{3} = 90}[/tex]

[tex]\sf{\implies 5C = 270}[/tex]

[tex]\sf{\implies C = 54}[/tex]

[tex]\sf{\implies Other \ angle = \bigg(\dfrac{2}{3} \times C\bigg) = \bigg(\dfrac{2}{3} \times 54\bigg) = 36 }[/tex]

Answer: The size of the angle which is two third of its complement is 36°

3. Let the supplement be : S

Given : The other angle is one fifth of its supplement

[tex]\sf{\implies Other \ angle = \dfrac{1}{5} \times S}[/tex]

Two angles are said to be Supplementary if their sum is equal to 180°

[tex]\sf{\implies S + \dfrac{S}{5} = 180}[/tex]

[tex]\sf{\implies \dfrac{6S}{5} = 180}[/tex]

[tex]\sf{\implies 6S = 900}[/tex]

[tex]\sf{\implies S = 150}[/tex]

[tex]\sf{\implies Other \ angle = \bigg(\dfrac{1}{5} \times S\bigg) = \bigg(\dfrac{1}{5} \times 150\bigg) = 30 }[/tex]

Answer: The size of the angle which is one fifth of its supplement is 30°

4. Two supplementary angles are in the ratio 7 : 3

Let the supplementary angles be : 7S and 3S

Two angles are said to be Supplementary if their sum is equal to 180°

⇒   7S + 3S = 180°

⇒  10S = 180°

⇒   S = 18°

First Angle : 7S = (7 × 18) = 126°

Second Angle : 3S = (3 × 18) = 54°

Answer:

π =14 cm

Step-by-step explanation:

Given:

circumference of a circle =616 cm

pie(π)=22/7

circumference of a circle=πr^2

616=22/7 *r^2

616*7/22 =r^2

4312/22 =r^2

196=r^2

[tex]\sqrt{196}[/tex] =r

14 =r

Answer:

D

Step-by-step explanation:

7.17 x 10(4) = 71,700

8.17 x 10(5) = 817,000

Any numbers between 71,700 and 817,000 is obv the answer

I did the math

A 69,200

B 7,200,000,000

C 7,570

D 80,530

Pretty obv that D be the only one that is inbetween 71,700-817,000

(excuse my spelling pls)

210 IS THE POSSIBLE ANSWER

0Answer:

Angle PTR is 136*

Step-by-step explanation:

In Question, We Have Given

Line PS and RS are Two Tangent To Circle With Centre T & ∠PSR=44* .

Thus ∠SPT=90* & ∠SRT=90* (Property Of Tangent ↔ Tangent always Form 90* With Radius Of Circle)  

Now We Have A Quadrilateral SPTR & The Sum Of All Angle Of Quadrilateral is 360* .

Thus The Angle Of PTR is

∠PTR = 360* - ( 90*+90*+44*)

∠PTR = 360* - 224*

∠PTR = 136*

Diagram, Please Find In Attachment

Answer:

35º

Step-by-step explanation:

u = 180 - 145

u = 35

C. 270

Hope this helps! :)

Answer:

A.)90 degrees

Step-by-step explanation:

The total of the two cars is 0.46 + 0.34 = 0.8

The total of all probabilities needs to equal 1

The probability of not buying either car is 1 - the sum of the two probabilities

1-0.8 = 0.20

The probability of not buying either car is 0.20

Answer:

B

Step-by-step explanation:

In fact in this case there is only a value of y when x is equal to 0