Identify the similar triangle. Then find each measure (round to the nearest tenth).

Answer:

Step-by-step explanation:

Answer:

the above is the answer

hope this is helpful

Answer:

The quadrilateral is a parallelogram

Step-by-step explanation:

If you plot the points on the graph it resembles the shape of a parallelogram. It prove this you need to check if the lengths are correct. The slope between point A and point B is 1/3 and the slope between point C and point D is also 1.3. The slope between point B and D is 1/2 and the slope between point A and point C is also 1/2

hope this helps

The quadrilateral is a parallelogram from the graph and the coordinates formed are parallel and the opposite sides have equal length.

A parallelogram is a quadrilateral whose opposite sides are parallel and equal in length. The opposite angles of a parallelogram are equal. The diagonals of a parallelogram bisect each other.

For the given situation,

The coordinates are A(2, 3) B(-1, 4) C(0, 2) D(-3, 3).

The graph below shows these points on the coordinates and the points ABDC forms the parallelogram.

This can be proved by finding the distance between these points.

The formula of distance between two points is

[tex]AB=\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}}[/tex]

Distance AB is

⇒ [tex]AB=\sqrt{(-1-2)^{2}+ (4-3)^{2}}[/tex]

⇒ [tex]AB=\sqrt{(-3)^{2}+ (1)^{2}}[/tex]

⇒ [tex]AB=\sqrt{9+ 1}[/tex]

⇒ [tex]AB=\sqrt{10}[/tex]

Distance BD is

⇒ [tex]BD=\sqrt{(-3+1)^{2}+ (3-4)^{2}}[/tex]

⇒ [tex]BD=\sqrt{(-2)^{2}+ (-1)^{2}}[/tex]

⇒ [tex]BD=\sqrt{4+ 1}[/tex]

⇒ [tex]BD=\sqrt{5}[/tex]

Distance DC is

⇒ [tex]DC=\sqrt{(0+3)^{2}+ (3-2)^{2}}[/tex]

⇒ [tex]DC=\sqrt{(3)^{2}+ (1)^{2}}[/tex]

⇒ [tex]DC=\sqrt{9+ 1}[/tex]

⇒ [tex]DC=\sqrt{10}[/tex]

Distance CA is

⇒ [tex]CA=\sqrt{(2-0)^{2}+ (3-2)^{2}}[/tex]

⇒ [tex]CA=\sqrt{(2)^{2}+ (1)^{2}}[/tex]

⇒ [tex]CA=\sqrt{4+ 1}[/tex]

⇒ [tex]CA=\sqrt{5}[/tex]

Thus the lengths of the opposite sides are equal, the given points forms the parallelogram.

Hence we can conclude that the quadrilateral is a parallelogram from the graph and the coordinates formed are parallel and the opposite sides have equal length.

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Answer:

4

Step-by-step explanation:

We can find the slope using the slope formula

m = ( y2-y1)/(x2-x1)

   = ( 9 - -7)/( 3 - -1)

   = (9+7)/(3+1)

   =16/4

   = 4

Answer: The answer is C the one you chose

Lets do

[tex]\\ \sf\longmapsto 2x + 24 = 30 \\ \\ \sf\longmapsto 2x = 30 - 24 \\ \\ \sf\longmapsto 2x = 6 \\ \\ \sf\longmapsto x = \frac{6}{2} \\ \\ \sf\longmapsto x = 3[/tex]

9514 1404 393

Answer:

  x = (17/2)√2

Step-by-step explanation:

The ratios of sides of an isosceles right triangle are ...

  1 : 1 : √2

In this problem, that is identical to ...

  x : x : 17

That is, ...

  [tex]x=\dfrac{17}{\sqrt{2}}=\boxed{\dfrac{17}{2}\sqrt{2}}\qquad\text{after rationalizing the denominator}[/tex]

Answer:

you forgot to add an image I dont know what angles your talking about

Answer:

[tex]a= \frac{9}{B+Q^2}[/tex]

Step-by-step explanation:

Given;

-Ba+9=Q²a

To solve for "a", make "a" the subject of the formula.

First, collect similar terms together;

-Ba - Q²a = -9

multiply through by "-1" to remove the negative sign;

Ba + Q²a = 9

factor out a;

a(B + Q²) = 9

divide both sides of the equation by "(B + Q²) ";

[tex]\frac{a(B+Q^2)}{B+Q^2} = \frac{9}{B+Q^2} \\\\a = \frac{9}{B+Q^2}[/tex]

Therefore, the value of "a" in the given expression is [tex]\frac{9}{B+Q^2}[/tex]

Answer:

[tex]M = \log(10000)[/tex]

Step-by-step explanation:

Given

[tex]M = \log(\frac{I}{I_o})[/tex]

[tex]I = 10000I_o[/tex] ---- intensity is 10000 times reference earthquake

Required

The resulting equation

We have:

[tex]M = \log(\frac{I}{I_o})[/tex]

Substitute the right values

[tex]M = \log(\frac{10000I_o}{I_o})[/tex]

[tex]M = \log(10000)[/tex]

The equation that calculates the magnitude of an earthquake with an intensity 10,000 times that of the reference earthquake is A. M = ㏒10000

Since the magnitude of an earthquake on the Richter sscale is M = ㏒(I/I₀) where

Since we require the magnitude when the intensity is 10,000 times the reference intensity, we have that I = 10000I₀.

So, substituting these into the equation for M, we have

M = ㏒(I/I₀)

M = ㏒(10000I₀./I₀)

M = ㏒10000

So, the equation that calculates the magnitude of an earthquake with an intensity 10,000 times that of the reference earthquake is A. M = ㏒10000

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Answer:

A

Step-by-step explanation:

-5+10(y+2) is a factor

The factor in the expression is (y³ + 2)

The expression is given as:

7z⁴ - 5 + 10 (y³ + 2)

The terms of the expressions are:

7z⁴ , -5 and 10 (y³ + 2)

The factors are

Hence, the factor in the expression is (y³ + 2)

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Given:

The formula is:

[tex]C=\dfrac{1}{2}e\cdot p[/tex]

To find:

The formula for e.

Solution:

We have,

[tex]C=\dfrac{1}{2}e\cdot p[/tex]

Multiply both sides by 2.

[tex]2C=e\cdot p[/tex]

Divide both sides by p.

[tex]\dfrac{2C}{p}=\dfrac{e\cdot p}{p}[/tex]

[tex]\dfrac{2C}{p}=e[/tex]

Interchange the sides.

[tex]e=\dfrac{2C}{p}[/tex]

Therefore, the required formula for e is [tex]e=\dfrac{2C}{p}[/tex].

Answer:

yes

Step-by-step explanation:

grehrehshbrenjt5rahtrere

I'm not sure about this one..

Answer:

I think true

Step-by-step explanation:

like and mark brainlist

trả :lờingu

Step-by-step explanation:

Answer:

[tex]f { - 1}^{ } = \frac{x}{4} [/tex]

Step-by-step explanation:

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Answer:

3/2 or 1.5

Step-by-step explanation:

(3/4) / (1/2) = (3/4) * (2/1)

                 = 6/4

                 = 3/2

It is given that,

→ 3/4 ÷ 1/2

We can divide the given values,

→ 3/4 ÷ 1/2

→ 3/4 × 2/1

→ 6/4

→ 3/2 (or) 1.5

Thus, 3/2 (or) 1.5 is the answer.

Answer: 13.5 Okay! Here's the method count the legs of the right triangle

The formula we'll use will be

A^2 + B^2 = C^2

In this case we're counting by twos

The base is 11 so we times it by itself =110

The leg is 8.5 so we going to times itself to make 72.25 add those together so 110+ 72.25 = 182.25 then we \|-----

182.25

Then you have got ur answer of 13.5

Step-by-step explanation:

Answer:

3.14

Step-by-step explanation:

First find the circumference of the circle:

[tex]2\pi r[/tex] = Circumference.

[tex]2 * \pi * 6[/tex] = [tex]12\pi[/tex]

Find the ratio of the angle in relation to the entire circle:

[tex]30^o[/tex] is what we have. So:

[tex]\frac{30^o}{360^o} = \frac{1}{12}[/tex]

Use the ratio and multiply the circumference to find the length:

[tex]12\pi * \frac{1}{12}[/tex] = [tex]\pi[/tex]

Round answer to the hundredth:

[tex]\pi = 3.14[/tex]

Answer:

80/3

Step-by-step explanation:

same distance is covered at different speed , avg speed= 2ab/a+b

= 2*20*40/60

= 80/3

Answer:

[tex]\frac{80}{3}\text{ mph}[/tex]

Step-by-step explanation:

We can use the formula [tex]d=rt[/tex] (distance  = rate * time) to solve this problem.

If the motorist is travelling 90 miles to and back on a trip, he has travelled [tex]90+90=180[/tex] miles total. This represents [tex]d[/tex] in our formula.

Now we need to find the total time.

On the first trip, it's given that the motorist travels at a rate of 20 mph. Therefore, the time this trip took to travel 90 miles is:

[tex]90=20t,\\t=\frac{90}{20}=\frac{9}{2}=4.5[/tex] hours

On the second trip back, he travels the same distance (90 miles) at a rate of 40 mph. Therefore, the time the trip took is:

[tex]90=40t,\\t=\frac{90}{40}=\frac{9}{4}=2.25[/tex] hours

Therefore, the total time is [tex]4.5+2.25=6.75[/tex] hours.

Now can calculate the average speed of the entire trip:

[tex]180=6.75r,\\r=\frac{180}{6.75}=\frac{180}{\frac{27}{4}}=180\cdot \frac{4}{27}=\boxed{\frac{80}{3}\text{ mph}}[/tex]

Answer:

supplementary angle is whose is mesure is 180

Answer:

O Subtract 9 from both sides of the equation.

Step-by-step explanation:

Notice that on the left hand side of the equation, you have two parts: X and 9. The variable is X, so we must do something to the 9 to remove it. Remember that we can cancel things by adding the negative of it. For example, 47+(-47)=0. Therefore, the opposite of 9 is -9. That essentially means subtracting 9.

Answer:

B (-2,2)

Step-by-step explanation:

Point C starts at (1,-2).

Reflect over the x axis: Point C becomes (1,2)

Translate 3 units left: Subtract 3 from x to make Point C (-2,2)

The new coordinates of C is (-2,2).

option (B) is correct.

It is required to find the  new co-ordinate of C.

Coordinates are distances or angles, represented by numbers, that uniquely identify points on surfaces of two dimensions (2D) or in space of three dimensions ( 3D ).

In the given figure ABCDE is reflected over X-axis and then translated 3 units left.

So, Point C starts at (1,-2).

Reflect over the x axis: Point C becomes (1,2).

Finally  Reflect over the x axis: Point C becomes (-2,2).

                                        OR

Translate 3 units left: Subtract 3 from x to make Point C  IS (-2,2).

Thus, the new coordinates of C is (-2,2).

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Answer:

4 is E, 5 is A

Step-by-step explanation:

4) Divide both sides by 5 to get |2x + 1| = 11, then solve for x to get 5 and -6.

5) Add 7 to both sides to get ½|4x - 8| = 10. Multiply both sides by 2 to get |4x - 8| = 20, then solve for x to get 7 and -3.

Answer:

t = 1 ... one day

Step-by-step explanation:

3 x [tex]10^{18}[/tex] * [tex](.5)^{t}[/tex] = 6 x [tex]10^{18}[/tex] * [tex](.5)^{2t}[/tex]

3 x [tex]10^{18}[/tex]     =   [tex](.5)^{2t}[/tex] / [tex](.5)^{t}[/tex]  

6 x [tex]10^{18}[/tex]      

1/2 = [tex].5^{t}[/tex]

ln( 1/2)  = t ln( [tex].5[/tex]  )

t = ln( .5)/ln( [tex].5[/tex]  )

t = 1

Saving percentage=100-80=20%

Saving amount:-

[tex]\\ \sf\longmapsto 4300\times 20\%[/tex]

[tex]\\ \sf\longmapsto 4300\times \dfrac{20}{100}[/tex]

[tex]\\ \sf\longmapsto 43\times 20[/tex]

[tex]\\ \sf\longmapsto 860[/tex]

[tex]\\ \sf\longmapsto 12\times 860[/tex]

[tex]\\ \sf\longmapsto Rs10320[/tex]

Step-by-step explanation:

i think this will be help you

Answer:

f^-1(x) = 4x-3

Step-by-step explanation:

f(x) = (x+3)/4

y = (x+3)/4

Exchange x and y

x = (y+3)/4

Solve for y

4x = y+3

Subtract 3

4x-3 = y

The inverse

f^-1(x) = 4x-3