Answer:
The equation of a line, having inclination 120° with positive direction of x-axis, .of x-axis, which is at a distance of 3 units from the origin is. 1. See answer ... where α is the angle with the positive X-axis, made by the perpendicular line drawn Now, from equation the equation of the straight line will be.
Step-by-step explanation:
24×63_64
help me sll
Answer:
1448
Step-by-step explanation:
24 × 63-64
Multiply 24 and 63 to get 1512.
1512-64
Subtract 64 from 1512 to get 1448.
answer
1448
Based on the Pythagorean theorem , find the missing length for each of the given right triangles
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the right trianglea are not given. The general explanation is as follows.
Using Pythagoras Theorem, we have:
a² = b² + c²
Where:
a => hypotenuse
Assume that the opposite and the adjacent sides are given as 3 and 4, respectively.
The hypotension becomes
a² = 3² + 4²
a² = 9 + 16.
a² = 25
Take square roots.
a = 5
If any of the other side lengths is missing; you make that side the subject and then solve.
A customer buys a different book that has an original selling price of $38. The book is discounted 25%. The customer must pay a 6% sales tax on the discounted price of the book.
What is the total amount, in dollars, the customer pays for the discounted book? Explain and SHOW how you arrived at your answer.
Answer:
$30.21
Step-by-step explanation:
100% -25%= 75%
Discounted price of the book
= 75% ×$38
= $28.50
Since the customer must pay an additional 6% of the discounted price,
percentage of discounted price paid
= 100% +6%
= 106%
Total amount paid
= 106% × $28.50
= $30.21
_________________________________
Alternative working:
Original selling price= $38
Since the book is discounted 25%,
100% ----- $38
1% ----- $0.38
75% ----- 75 ×$0.38= $28.50
Since the sales tax is based on the discounted price, we let the discounted price be 100%.
100% ----- $28.50
1% ----- $0.285
106% ----- 106 ×$0.285= $30.21
∴ The total amount the customer pays for the discounted book is $30.21.
19. Which of the following would best be solved using factoring the difference of squares?
O x^3 + 5x^2 - 9x - 45 = 0
O 3x² + 12x = 8
O x^2 - 25 = 0
O x^2 + 3x – 10 = 0
Please hurry!
Answer:
x² + 3x - 10 = 0
x² - 25 = 0
*PLEASE HELP ASAP I WILL MARK BRAINLIST*
(Questions and Answers pictured)
Answer:
The first equation, sorry can’t explain.
Answer:
g(x)=3f(2x)
I think
Which of the following is the square of a binomial?
Answer:
[tex]16 {x}^{2} + 24xy + 9 {y}^{2} [/tex]
Step-by-step explanation:
U can reduce this into
[tex](4x + 3y) {}^{2} [/tex]
Which is a square.
Now,
16x^2 + 24xy + 9y^2
16x^2 + 12xy + 12xy + 9y^2
4x ( 4x + 3y ) + 3y ( 4x + 3y )
( 4x + 3y ) ( 4x + 3y )
( 4x + 3y )^2
I hope you understand...
Mark me as brainliest...
If 12 girls can sweep a room in 20hours, how many hours will it take 8 girls to perform the same task, assuming they are sweeping at the same rate?
Answer:
30 hour
Step-by-step explanation:
girls time
12 20 hour
8 x(let)
now,
12/8=x/20
12×20=8×x
240=8x
x=240/8
x=30,,
What’s the solution
Answer:
x ≥ 12
Step-by-step explanation:
-3/4x +2 ≤ -7
Subtract 2 from each side
-3/4x +2-2 ≤ -7-2
-3/4x ≤ -9
Multiply each side by -4/3, remembering to flip the inequality
-3/4x * -4/3 ≥ - 9 *(-4/3)
x ≥ 12
Answer:
x>=12
Step-by-step explanation:
-3/4x + 2<=-7
-3/4x <= -7 -2
-3/4x<=-9
cross multiply
-3x<=-36
dividing throughout by -3
x>=12
Neglecting air resistance and the weight of the propellant, determine the work done in propelling a five-ton satellite to a height of (a) 100 miles above Earth and (b) 300 miles above Earth.
Answer:
a) the work done in propelling a five-ton satellite to a height of 100 miles above Earth is 487.8 mile-tons
b) the work done in propelling a five-ton satellite to a height of 300 miles above Earth is 1395.3 mile-tons
Step-by-step explanation:
Given the data in the question;
We know that the weight of a body varies inversely as the square of its distance from the center of the earth.
⇒F(x) = c / x²
given that; F(x) = five-ton = 5 tons
we know that the radius of earth is approximately 4000 miles
so we substitute
5 = c / (4000)²
c = 5 × ( 4000 )²
c = 8 × 10⁷
∴ Increment of work is;
Δw = [ ( 8 × 10⁷ ) / x² ] Δx
a) For 100 miles above Earth;
W = ₄₀₀₀∫⁴¹⁰⁰ [ ( 8 × 10⁷ ) / x² ] Δx
= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{x}[/tex] [tex]]^{4100}_{4000[/tex]
= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{4100}[/tex] [tex]+\frac{1}{4000}[/tex] [tex]][/tex]
= (8 × 10⁷ ) [ 6.09756 × 10⁻⁶ ]
= 487.8 mile-tons
Therefore, the work done in propelling a five-ton satellite to a height of 100 miles above Earth is 487.8 mile-tons
b) For 300 miles above Earth.
W = ₄₀₀₀∫⁴³⁰⁰ [ ( 8 × 10⁷ ) / x² ] Δx
= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{x}[/tex] [tex]]^{4300}_{4000[/tex]
= (8 × 10⁷) [tex][[/tex] [tex]-\frac{1}{4300}[/tex] [tex]+\frac{1}{4000}[/tex] [tex]][/tex]
= (8 × 10⁷ ) [ 1.744186 × 10⁻⁵ ]
= 1395.3 mile-tons
Therefore, the work done in propelling a five-ton satellite to a height of 300 miles above Earth is 1395.3 mile-tons
A group of campers is going to occupy 6 campsites at a campground. There are 16 campsites from which to choose. In how many ways can the campsites be chosen?
Answer:
The campsites can be chosen in 5,765,760 different ways.
Step-by-step explanation:
Given that a group of campers is going to occupy 6 campsites at a campground, and there are 16 campsites from which to choose, to determine in how many ways the campsites can be chosen, the following calculation must be performed:
16 x 15 x 14 x 13 x 12 x 11 = X
240 x 182 x 132 = X
240 x 24,024 = X
5,765,760 = X
Therefore, the campsites can be chosen in 5,765,760 different ways.
Someone please help with the questions on this picture!! URGENT!!!
Answer:
A) Independent
B) Dependent
Step-by-step explanation:
A) If we take a marble out and put the marble back, it means we have restored the sample to what it was initially and thus it doesn't affect probability of making another selection.
Thus, this is an independent event.
B) A card is taken from a deck of cards without replacement and set aside. Then after that another card is taken from the first sample, this means that the first sample size has now reduced and thus the first card taken affects the probability of the second card to be picked. Thus, this is a dependent event.
Which of these four sets of side lengths will form a right triangle? set 1 set 2 set 3 set 4
Answer:
hey um I cant see the picture
Can someone please answer this
x( 3x - 2y + 4z)x = -2, y = 4, and z = -3
What is the cube root of -1,000p12q3?
O-1004
O - 10pta
O 1004
O 10pta
Answer:
Your options are not clear
Step-by-step explanation:
[tex]\sqrt[3]{-1000 \times p^{12} \times q^3} \\\\(-1 \times 10^3 \times p^{12} \times q^3)^{\frac{1}{3} }\\\\(-1^3)^{\frac{1}{3} }\times 10^{3 \times \frac{1}{3} } \times p^{12 \times \frac{1}{3}} \times q^{3 \times \frac{1}{3}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ (-1)^3 = - 1 \ ] \\\\- 1 \times 10 \times p^4 \times q\\\\-10p^4q[/tex]
12 Kendrick wants to build a slide for his son in the backyard. He buys a
slide that is 8 feet long. The height of the stairs is 5 feet. Find the
distance from the bottom of the stairs to the base of the slide.
Lydiagrace33
Image attached
A) 1 point Write an inequality for this graph . Use the shift key and the key or key to type the < or > symbol . *
B) Water boils when the temperature is at least 212 degrees F. Which inequality shows this situation ?
C) When the temperature drops below 50 degrees F , crickets usually stop chirping . Which inequality shows this situation ?
D) Explain the difference between the meaning of a closed
circle and an open circle on a graph of an inequality .
The senior classes at High School A and High School B planned separate trips to Yellowstone National Park. The senior class at High School A rented and filled 9 vans and 14 buses with 710 students. High School B rented and filled 13 vans and 5 buses with 371 students. Each van and each bus carried the same number of students. Find the number of students in each van and in each bus.
Answer:
Buses - 43 people
Vans - 12 people
The square below represents one whole.
What percent is represented by the shaded area?
%
The anwser is 6%
Answer:
the answer is 6%
hdhxbxcbxbxszznzj
please help me...........
Pa help po plssssss
Sana po meron Ang maka-sagot ☺️☺️
Answer:
The answer is below
Step-by-step explanation:
a) the volume of the pit = length * width * depth = 9 dm * 6 dm * 7 dm = 378 dm³
Hence to fil the pit, 378 dm³ of sand is needed.
b) Volume of the room = length * width * height = 2.3 m * 0.59 m * 3.74 m = 5.08 m³
The cabinet would occupy 5.08 m³ of space.
c) volume = length * width * height
210 dm³ = 3.5 dm * 6 dm * width
width = 210 dm³ / (3.5 dm * 6 dm) = 10 dm
d) Volume of the room = length * width * height = 15 m * 15 m * 15 m = 3375 m³
The stockroom has a space of 3375 m³
e) volume = length * width * height = 5 dm * 5 dm * 5 dm = 125 dm³
The container has a space of 125 dm³
f) volume = length * width * height = 41 cm * 13 cm * 24 cm = 12792 cm³
The box has a space of 12792 cm³
g) volume of prism = length * width * height
72 m³ = 4 m * 3 m * length
length = 72 m³ / (4 m * 3 m) = 6 m
h) volume = length * width * height = 8 cm * 8 cm * 8 cm = 512 cm³
The figure has a volume of 512 cm³
i) volume = length * width * height = 5 ft * 2 ft * 3 ft = 30 ft³
The cabinet has a space of 30 ft³
Help. Urgent. Skenekeks
Answer:
D
Step-by-step explanation:
Plug in the numbers for the x-value and solve the equation.
| 3(80/3)/4 + 1 | = 16
| 3(-40/3)/4 + 1 | = 16
Consider the following graph:
What is the limit as it is approaching -1 from the right, what is the limit?
Answer:
The limit is 0, and the answer is given by option E.
Step-by-step explanation:
Limit to the right:
The limit of a function approacing a value of x to the right is given by the value of the function quite close to the point, looking to the right.
In this question:
Approacing by the right(x quite close, but more than -1, that is, -0.9999...), y tends to 0, so the limit is 0, and the answer is given by option E.
Find the Value of x
Answer:
42
Step-by-step explanation:
(adjacent straight angles sum up to 180)
3x+54=180
x=42
. A population of rabbits oscillates 25 above and below an average of 129 during the year, hitting the lowest value in January (t = 0). a. Find an equation for the population, P, in terms of the months since January, t. b. What if the lowest value of the rabbit population occurred in April instead?
Answer:
Because we know that here we have an oscillation, we can model this with a sine or cosine function.
P = A*cos(k*t) + M
where:
k is the frequency
A is the amplitude
M is the midline
We know that at t = 0, we have the lowest population.
We know that the mean is 129, so this is the midline.
We know that the population oscillates 25 above and below this midline,
And we know that for t = 0 we have the lowest population, so:
P = A*cos(k*0) + 129 = 129 - 25
P = A + 129 = 129 - 25
A = -25
So, for now, our equation is
P = -25*cos(k*t) + 129
Because this is a yearly period, we should expect to see the same thing for t = 12 (because there are 12 months in one year).
And remember that the period of a cosine function is 2*pi
Then:
k*12 = 2*pi
k = (2*pi)/12 = pi/6
Finally, the equation is:
P = -25*cos(t*pi/6) + 129
Now we want to find the lowest population was in April instead:
if January is t = 0, then:
February is t = 2
March is t = 3
April is t = 4
Then we would have that the minimum is at t = 4
If we want to still use a cosine equation, we need to use a phase p, such that now our equation is:
P = -25*cos(k*t + p) + 129
Such that:
cos(k*4 + p) = 1
Then:
k*4 + p = 0
p = -k*4
So our equation now is:
P = -25*cos(k*t - 4*k) + 129
And for the periodicity, after 12 months, in t = 4 + 12 = 16, we should have the same population.
Then, also remembering that the period of the cosine function is 2*pi:
k*12 - 4*k = 2*pi
k*8 = 2*pi
k = 2*pi/8 = pi/4
And remember that we got:
p = -4*k = -4*(pi/4) = -pi
Then the equation for the population in this case is:
P = -25*cos( t*pi/4 - pi) + 129
I’ve been stuck on this problem I can’t seem to get 7 9/4 into the ABC form
Answer:
7 square root 9^4
Step-by-step explanation:
Discount Comics is running a special: 20 comics for $5.00. Seth purchases 30 comics for $7.50. What is the sale price per comic?
$ per comic?
Answer:
$0.25
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Defined the total variation distance to be a distance TV(P,Q) between two probability measures P and Q. However, we will also refer to the total variation distance between two random variables or between two pdfs or two pmfs, as in the following.
Compute TV(X,X+a) for any a∈(0,1), where X∼Ber(0.5).
TV(X,X+a) = ?
Answer:
1
Step-by-step explanation:
Computing Tv(X, X + a ) for any a∈(0,1)
Given that : X∼Ber(0.5)
∴ The probability mass function
P(X = 1 ) = 0.5
P(X = 0) = ( 1 - 0.5 )
and expectation E[X] = 0.5
hence ; TV ( X, X + a ) = 1
find the equation of the line passing through points A(3,4) and B(1,10)
Answer:
y = -3x + 13
Step-by-step explanation:
First, find the slope:
[tex]m=\frac{y_1-y_2}{x_1-x_2}\\\\m=\frac{4-10}{3-1}\\\\m=\frac{-6}{2}\\\\m=-3[/tex]
Finally, find the equation:
[tex]y-y_1=m(x-x_1)\\\\y-4=-3(x-3)\\\\y-4=-3x+9\\\\y=-3x+13[/tex]
On each trial of an experiment, a participant is presented with a constant soft noise, which is interrupted at some unpredictable time by a slightly louder sound. The time it takes for the participant to react to the louder sound is recorded. The following list contains the reaction times (in milliseconds) for trials of this experiment.
170, 206, 218, 232, 238, 248, 254, 264, 268, 281, 281, 281, 316, 320, 320, 329, 336, 365, 399, 400, 438, 438, 452, 524, 724, 806
1. measures of central tendency do not exist for this data set?
a. Mean
b. Median
c. Mode
d. None of these measures
2. Suppose that the measurement 806 (the largest measurement in the data set) were replaced by 1169. Which measures of central tendency would be affected by the change? Choose all that apply.
Answer:
1.d. None of these measures (do not exist interpreted as all of these exist)
2.The mean is increased from 346.8 to 361.32
Step-by-step explanation:
After calculations we find that all the measures of central tendency exist for this data. The mean , median and mode can be easily calculated .
The mean is 346.8
The mode is 281
The median is 316
Suppose that the measurement 806 (the largest measurement in the data set) were replaced by 1169. The mean would be affected by the change.
The mean is 361.32
The mode is 281
The median is 316
The mean is increased from 346.8 to 361.32
