Answer:
[tex]\boxed{\sf Distance_{AB}= 8.24 \ units }[/tex]
Step-by-step explanation:
Here two points are given to us and we need to find the distance between the two points . The given points are , A(0,0) and B(8,2) . The distance between the two points can be found out using the Distance Formula , which is ,
Distance Formula:-
[tex]\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}[/tex]
Therefore on substituting the respective values ,we can find the Distance as ,
[tex]\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2} [/tex]
Simplify the brackets ,
[tex]\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}[/tex]
Square the numbers inside the squareroot ,
[tex]\sf\longrightarrow Distance =\sqrt{ 64 + 4} [/tex]
Add the numbers inside the squareroot ,
[tex]\sf\longrightarrow Distance = \sqrt{68} [/tex]
Find the value of squareroot,
[tex]\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}[/tex]
Hence the distance between the two points is 8.24 units .
10-7+12 dived (2^3-6) hope you can answer
Answer:
The answer is 7.5
A motorboat travels 81 miles in 3 hours going upstream. It travels 135 miles going downstream in the same amount of time. What is the rate of the boat in still water and what is the rate of the current?
Answer:
27, 18
Step-by-step explanation:
Here's why
what is the ordered pair to (-4,2)
Answer:
(1,2) is ordered pair to (-4,2).
Step-by-step explanation:
(1,2)
hora khoi thaha vayena hai
Cinco litros de agua se divide en cuatro partes iguales, me tomo 2 partes ¿Cuánto me queda?
Answer:
2 [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
5 ÷ 4 = 1 [tex]\frac{1}{4}[/tex]
1 [tex]\frac{1}{4}[/tex] × 2 = 2 [tex]\frac{2}{4}[/tex] = 2 [tex]\frac{1}{2}[/tex]
5 - 2 [tex]\frac{1}{2}[/tex] = 2 [tex]\frac{1}{2}[/tex]
respuesta: 2 [tex]\frac{1}{2}[/tex]
How do I solve this problem?
9514 1404 393
Answer:
see attached
Step-by-step explanation:
Short answer: to solve this problem, follow directions.
a. Write the inequalitiesLet c and p represent numbers of cakes and pies produced daily. Then the constraints are ...
2c +3p ≤ 108 . . . . . . . . available hours of preparation time
1c +0.5p ≤ 20 . . . . . . . available hours of decoration time
p ≥ 0, c ≥ 0 . . . . . . . . . negative numbers of cakes or pies cannot be produced
__
b. Sketch the feasible regionIt works well to let a graphing calculator do this.
The feasible region is the doubly-shaded area with vertices ...
(0, 0), (0, 36), (3, 34), (20, 0)
__
c. Write the profit functionProfit is $25 per cake and $12 per pie, so is ...
p = 25c +12p
__
d. Determine maximum profitThe attached table shows the profit for the various mixes of cakes and pies in the feasible region. The most profit is had by production of cakes only.
The maximum profit is $500 per day for production of 20 cakes.
_____
Additional comment
We have used x for cakes and y for pies in the attachment, because those are variables that the Desmos calculator prefers.
As is sometimes the case, the production point giving maximum profit leaves one of the resources (preparation time) only partially utilized.
Simplify : -2a(a-d)+2a(2a-3D) pls help.
-2a(a - d) + 2a(2a - 3d)
(-2a * a) + (-d * -2a) + (2a * 2a) + (2a * -3d)
-2a^2 + 2ad + 4a^2 - 6ad
(4a^2 - 2a^2) + (2ad - 6ad)
2a^2 - 4ad
---The above expression is simplified, though not fully. The below expression is fully simplified.
2a(a - 2d)
Hope this helps!
Find the value of the trigonometric ratio, Make sure to simplify the fraction if needed
Answer:
Cos Z = 7/25
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
cos theta = adj / hyp
cos Z = 14/50
Cos Z = 7/25
▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓
As the [tex]\triangle\sf{XYZ}[/tex] is a right angle traingle.
we know that,
[tex]\boxed{\underline{\sf{cos\blue{\theta}=\dfrac{adjacent}{hypertension} }}}[/tex]
According to the question,
[tex]cosZ=\dfrac{adjacent}{hypertension}\\\\cosZ=\dfrac{14}{50}\\\\\pmb{\green{\sf{cosZ}=\frak{\dfrac{7}{25}}}}[/tex]
▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓
Write each decimal as a fraction or mixed number in simplest form -0.4
Answer:
-2/5
Step-by-step explanation:
The one-to-one functions g and h are defined as follows.
g={(-9, 2), (-1, -3), (2, 3), (9, 4)}
h(x) = 3x-4
Find the following.
g^-1 (2) =?
h^-1 (x) =?
(h • h^-1) (2) =?
Answer:
Hello,
Step-by-step explanation:
[tex]g(-9)=2\Longrightarrow\ g^{-1}(2)=-9\\\\y=h(x)=3x-4\\x=3y-4\\\\y=\dfrac{x+4}{3} \\\\h^{-1}(x)=\dfrac{x+4}{3}\\\\h(h^{-1}(x))=(h^{-1}o\ h)(x)=1_\pi(x) \ (identical\ permutation\ of\ plane) \\\\h(h^{-1}(2))=2[/tex]
Two thirds of the students in a class have pets. There are
36 students in the class. How many of the students have pets?
Hi!! Can you please help with this question and explain how to solve it??
Find the height in centimeters of a square pyramid with a volume of 144 cm3 and a base edge length equal to the height. Give the approximate answer rounded to 2 decimal places.
9514 1404 393
Answer:
7.56 cm
Step-by-step explanation:
The volume is given by the formula ...
V = 1/3b²h . . . . where b is the base edge length, and h is the height.
Here we have V = 144 cm³, and b = h. Filling in these values and solving for h, we get ...
144 cm³ = 1/3h³
432 cm³ = h³
h = ∛432 cm ≈ 7.55953 cm
The height of the pyramid is about 7.56 cm.
Answer:
[tex]7.56cm[/tex]
Step-by-step explanation:
Given that,
base length = Height
so,
[tex]volume = \frac{1}{3} {b}^{2} h \\ [/tex]
We can also write this as( according to this question)
[tex]v = \frac{1}{3} \times {b}^{2} \times b \\ v = \frac{ {b}^{3} }{3} [/tex]
let's solve
[tex]v = \frac{ {b}^{3} }{3} \\ 144 = \frac{ {b}^{3} }{3} \\ 144 \times 3 = {b}^{3} \\43 2 = {b}^{3} \\ \sqrt[3]{432} = b \\ b = 7.55[/tex]
[tex]base = height = 7.55cm \\ [/tex]
= 7.56cm
Zoe walks at a speed of 10 miles/h and jogs at a speed of 20 miles/h. She goes to the park to walk 2 miles on a Monday. How long will she take to walk 2 miles?
Answer:
12 minutes
Step-by-step explanation:
Given
[tex]s_1 = 10mi/h[/tex] --- walk speed
[tex]s_2 = 20mi/h[/tex] --- jog speed
[tex]d = 2\ miles[/tex] --- distance
Required
The time to walk the given distance
Time is calculated as:
[tex]Time = \frac{distance}{speed}[/tex]
In this case, the speed is the speed at which she walks.
So, we have:
[tex]Time = \frac{d}{s_1}[/tex]
Substitute known values
[tex]Time = \frac{2mi}{10mi/h}[/tex]
[tex]Time = 0.2hr[/tex]
Convert to minutes
[tex]Time = 0.2 * 60mins[/tex]
[tex]Time =12mins[/tex]
Help me pls
Find the missing segment in the image below
Answer:
The answer is 12
Step-by-step explanation:
You see its because.
Answer:
?=12
Step-by-step explanation:
Using the Thalès's theorem:
[tex]\dfrac{6}{6+4}=\dfrac{?}{20} \\\\?*10=6*20\ (cross\ products)\\\\?=\dfrac{6*20}{10} \ dividing\ by\ 10\\\\?=12[/tex]
David has a part-time job. He earns $9.40 per hour. How much will he earn when he works 9 hours?
Answer:
$84.60
Step-by-step explanation:
$84.60 is what david will earn in 9 hours becuz 9.40 times 9 is 84 dollars and 60 cents
The baseball team has a double-header on Saturday. The probability that they will win both games is 34%. The probability that they will win the first game is 75%, What is the probability that the team will win the second game given that they have already won the first game?
A. 45%
B. 74%
C. 90%
D. 26%
Answer:
A. 45%
Step-by-step explanation:
34/75=45 = 45%
Select the correct answer from the drop-down menu.
A
The diagram shows a stage in the construction of a line perpendicular to GH through point A.
The next step in this construction is
Reset
Next
2021 Edmentum. All rights reserved.
The diagram is missing and so i have attached it.
Answer:
Next step is;
to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.
Step-by-step explanation:
A perpendicular line is to be drawn to line GH through point A.
The steps are;
1. Identification of the two end points of the line which has been done.
2. Place one leg of the compass at point G and draw a small arc above the line GH. This has been done.
3. Without changing the span of the compass, place the same leg of the compass at point H and draw another small arc above the line GH to intersect the previously drawn small arc.
4. Make use of a straight object to connect the point of intersection of the two small arcs to the point A.
This line is the perpendicular line to GH.
In the figure attached, they have just finished point 2 I wrote above. Thus, the next step is point 3.
Answer:
to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.
Step-by-step explanation:
An airplane flies a distance of 800km from A to B. If its average speed is 600km/h, how long does it take to cover that distance?
Answer:
1 hour 33 minutes
Step-by-step explanation:
distance/speed= time
d =800/600
d=1.33
The aeroplane takes 1.33 hours to traverse a distance of 800 km.
What is the speed of an object?Speed is the rate at which an object's position changes, measured in meters per second. For example, if an object starts at the origin, and then moves three meters in three seconds, its speed is one meter per second. The equation for speed is simple: distance divided by time
Given here: An airplane flies a distance of 800 km with an average speed of 600 km/h
Thus the time taken by the aeroplane to cover that distance is
t=800/600
t=4/3
t=1.33 hours
Hence, The aeroplane takes 1.33 hours to traverse a distance of 800 km.
Learn more about the speed of an object here:
https://brainly.com/question/28224010
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CAN A KIND SOUL PLEASE HELP ME OUT??!!!!!!!!!!!!!!
The translation (x, y)->(x + 10, y – 6) is applied to triangle ABC to create a new image triangle A’B’C’. Graph triangle A’B’C’ on the coordinate plane.
please show how you got it so I can see if the answer makes sense!!!!
Answer:
First find the coordinates of the vertices. A=(-8,8), B=(-8,3) and C=(-4, 4). Next apply transformation, A'=(2, 2), B=(2, - 3) and C=(6, - 2). Next map this and join them to get the required triangle
A car accelerates from rest at 1.0 m/s2 for 20.0 seconds along a straight road. It then moves at a constant speed for half an hour. It then decelerates uniformly to a stop in 30.0 s. Find the total distance covered by the car.
HELP
Answer:
50m
Step-by-step explanation:
speed (m/s2) = distance (m) ÷ time (s)
distance = speed (m/s2) x time (s)
1x20 =20m.
30s = 30m because they do 1 meter per second (every second)
50m in total if not counting the constant for half a hour.
Please explain how you got the answer!
Answer:
One of the scenarios:
Reflection over y-axis, then Translation 1 unit right and 9 units downsolue for x
X(3 + X) = 3x + x²
Answer:
here,
3x-3x=
[tex] {x}^{2} - {x}^{2} [/tex]
x=0
By which angle must turn about point A in the clockwise direction so that it coincides with ?
https://cdn.ple.platoweb.com/EdAssets/6168ddce5d8545b692cd00c2eaaf2f05?ts=635385675311870000
A. 90°
B. 180°
C. 270°
D. 360°
When a line is rotated, it is rotated about a fixed point to its new position. Line AB must turn 180 degrees about point A to coincide with line AE.
The complete question is that we determine the angle which AB will turn to, about point A to align with AE (see attachment for the figure)
Line AB and AE form a straight line. This means that the angle between these two lines on either side of point A is [tex]180^o[/tex]
So for line AB to coincides with line AE, the line AB must turn 180 degrees about point A.
Hence, option (B) is correct.
Read more about rotation of points at:
https://brainly.com/question/22363471
need help with this !!
Answer:
1
5
4
2
3
Step-by-step explanation:
1 combines the sets A and B. that symbol there stands for U like "union". so, all values of x, where x is either < 1 or >= 5.
2 is again a union. A and C are combined. C contains only one element : x=5.
3 is again a union. B and C are combined. but the element of C (x=5) is already part of B (x>=5), so the union does not change anything, the result is simply B again.
4 is doing a "cross section" between the sets A and B. only elements that are in both sets are in the result. but x < 1 and x >= 5 don't have any elements in common. so, the result is an empty set.
5 is again a cross section. the only shared element between B and C is x=5.
Mr lim had just enough money to buy 6 similar lamps. However, he bought 3 such lamps and had $950 left. How much money did mr lim have at first?
Let the cost of a lamp = x
6 lamps would cost 6x
He bought 3 lamps at 3x plus Thad 950 left.
3 lamps plus the 950
Would be the same amount as 6 lamps:
Set up an equation and solve for x:
3x + 950 = 6x
Subtract 3x from both sides:
950 = 3x
Divide both sides by 3:
X = 316.67
Each lamp was $316.67
Multiply the price of a lamp by 6:
316.67 x 6 = 1900
He had $1900
Answer: $1900
Step-by-step explanation:
Mr Lim had enough money to buy 6 similar lamps. However he only bought 3 such lamps. That means he had only spent half of his money (6-3=3).
So, if he take money remaining with him = x = $950
Amount of money he first had = 2x =$950×2 = $1900
If l || m, classify the marked angle pair and give their relationship, then solve for x.
Answer:
14. x=16, 15. x=9
Step-by-step explanation:
14.
4x+4=7x-44 by alternate exterior angles
3x=48
x=16
15.
15x-26=12x+1 by alternate exterior angles
3x=27
x=9
150 students
110 studied mathematies
95 studied physics
question 1
-The students took mathematics and physics.
the students took math and physics = 55
¿Qué valor de m creará un sistema de líneas paralelas sin solución? y = mx - 6 8 x - 4 y = 12 Una cuadrícula de coordenadas con una línea etiquetada como 8 x menos 4 y es igual a 12. La línea pasa por un punto en (0, menos 3), (1, menos 1) y un punto en (1,5, 0). - 2 - 2
Answer:
Hello,
m=2
(0,-3) True
(1,-1) True
(1.5,0) True
(-2,-2) False
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}y&=&mx-6\\8x-4y&=&12\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&mx-6\\y&=&2x-3\\\end{array}\right.\\\\\\The\ slope\ must\ be\ the\ same:\ m=2\\\\\\\begin{array}{c|c}&y=2x-3\\---&--------\\x&y\\0&2*0-3=-3\\1&2*1-3=-1\\1.5&2*1.5-3=0\\-2&2*(-2)-3=-7\\\end{array}[/tex]
7. solve for x!
please help
(3x/6) + 2 = 8
=> 3x/6 = 8 - 2
=> 3x/6 = 6
=> 3x = 6 × 6
=> 3x = 36
=> x = 36/3
=> x = 12
Answer:
x=12
Step-by-step explanation:
3x/6+2=8
3x/6=8-2
=6
3x/6(6)=6(6)
3x=36
x=12
Delta math need help
Answer:
2.6
Step-by-step explanation:
We'll use the Pythagoras theorem to solve this, which states that in a right angle triangle:
h^2 = a^2 + b^2
4^2 = 3^2 +b^2
16= 9 +b^2
16-9= b^2
7= b^2
(take square root in both sides)
b= 2.65
round to nearest 10th = 2.6
answer by Gauthmath
Answer:
Missing side is 2.6
3^2 + x^2 = 4^2
9 + x^2 = 16
-9 -9
x^2 = 7
([tex]\sqrt{x}[/tex])^2 = [tex]\sqrt{7}[/tex]
x = 7
Find the approximation o the square root of 7 in fractions then carry out the long division.
Or
Approx. is 2 3/5 which equals 2 6/10 which equals 2.6
A transformation of AKLM results in AK'L'M'.
Which transformation maps the pre-image to the image?
O dilation
O translation
O reflection
O rotation
K
K
M
M
The transformation that maps the pre-image to the image is given as follows:
Dilation.
How to identify the transformation?The four types of transformation listed in this problem cause these following changes:
Translation: only the position of the figure changes, the orientation, the inclination and the side lengths remain constant.Reflection: The orientation of the figure changes.Rotation: The inclination of the figure changes.Dilation: The side lengths of the figure change, while the angle measures remain constant.From the image, we get that the side lengths were doubled, while the angle measures remained constant, meaning that the transformation is a dilation and the first option is the correct option.
More can be learned about transformations at https://brainly.com/question/28792248
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Answer:
dilation
Step-by-step explanation:
took the test
