If cot Theta = Two-thirds, what is the value of csc Theta? StartFraction StartRoot 13 EndRoot Over 3 EndFraction Three-halves StartFraction StartRoot 13 EndRoot Over 2 EndFraction Eleven-thirds

Answer:

since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its off functions

Step-by-step explanation:

set = {0,1,2,3,4,5,6,7,8,9}

setting up a one-to-one correspondence between the set of real numbers between 0 and 1

The function : F(n)= {0,1} is equivalent to the subset (sf) of (n) , this condition is met if n belongs to the subset (sf) when f(n) = 1

hence The power set of (n) is uncountable and is equivalent to the set of real numbers given

since the set of functions expressed are uncountable and they are a subset of real numbers starting from N therefore the set {0,1,2,3,4,5,6,7,8,9} is uncountable as well as its offfunctions

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Explanation:

The piecewise function shows that we have two cases. Either x = 1 or [tex]x \ne 1[/tex].

If x = 1, then g(x) = 3 as shown in the bottom row. This is why g(1) = 3.

If [tex]x \ne 1[/tex], then g(x) = (1/4)x^2-4

Plug x = -5 into this second definition

g(x) = (1/4)x^2-4

g(-5) = (1/4)(-5)^2-4

g(-5) = (1/4)(25)-4

g(-5) = 25/4 - 4

g(-5) = 25/4 - 16/4

g(-5) = 9/4

Repeat for x = 4

g(x) = (1/4)x^2-4

g(4) = (1/4)(4)^2-4

g(4) = (1/4)(16)-4

g(4) = 4-4

g(4) = 0

The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

The functions are given below.

g(x) = (1/4)x² - 4, x ≠ 1

g(x) = 3, x = 1

The value of the function at x = -5 will be given as,

g(-5) = (1/4)(-5)² - 4

g(-5) = 25 / 4 - 4

g(-5) = 6.25 - 4

g(-5) = 2.25

The value of the function at x = 4 will be given as,

g(4) = (1/4)(4)² - 4

g(4) = 16 / 4 - 4

g(4) = 4 - 4

g(4) = 0

The value of the function at x = 1 will be given as,

g(1) = 3

The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.

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Answer:

cos 60° = 1/2 because the angles are complements.

Step-by-step explanation:

Answer: 37.1%

Step-by-step explanation:

2130/3120×100% = 68.3%

100% - 68.3%

=31.7%

37.1%

which makes that $460

May I have brainliest please? :)

Also, the person above me smells like how a diaper tastes

Answer:

Thomas should not reject the null hypothesis.

Step-by-step explanation:

The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. It is not necessary that all null hypothesis will be rejected at 10% level of significance. To determine the criteria for accepting or rejecting a null hypothesis we should also consider p-value.  Here in this question the test value is -1.73346 and p-value is 0.0830. The p value is greater than the test value therefore the null hypothesis should be accepted.

The width of the gym will be W=60 feet for the area of 6,960 square feet.

Area is defines as the space covered by a surface in the two dimensional plane.

It is given that

Area of the gym =6960 square feet

Width of the gym = ?

Length of the gym=116 feet

The width of the gym will be calculated as

[tex]A=\L\times W\\\\\\6960=116\times W\\\\\\w=\dfrac{6960}{116}=60\ \ Feet[/tex]

hence the width of the gym will be W=60 feet for the area of 6,960 square feet.

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Answer

arrange the element in increasing order

-1.9, -1.3, -0.8, 2.3, 5.8, 7.4, 8.5, 9.9

interquatile = Q3 - Q1

[tex] = \frac{7.4 + 8.5}{2} - \frac{ - 1.3 - 0.8}{2} [/tex]

[tex] = 7.95 + 1.05[/tex]

[tex] = 9[/tex]

Answer:

9.0

Step-by-step explanation:

i took the quiz

Answer:  3.79 litres

Step-by-step explanation:

1 litre is equivalent to about ‭1.05668821‬ American quarts.

4 quarts would therefore be;

= 4/‭1.05668821‬

= 3.78541178

= 3.79 litres

Answer:

x = sqrt(50) = 5sqrt(2) = 7.071 ft (to 3 decimals)

Step-by-step explanation:

referring to the diagram

theta (x) = atan(10/x) - atan(5/x)

differentiate with respect to x

theta'(x) = 5/(x^2+25) - 10/(x^2+100)

For x to have an extremum (max. or min)

theta'(x) = 0  ="

5/(x^2+25) - 10/(x^2+100) = 0

transpose and cross multiply

10(x^2+25) -5(x^2+100) = 0

expand and simplify

10x^2+250 - 5x^2-500 = 0

5x^2 = 250

x^2=50

x = sqrt(50) = 5sqrt(2) = 7.071 ft (to 3 decimals)

Since we know that if x becomes large, theta will decrease, so

x = 5sqrt(2) is a maximum.

[tex]10[/tex] divisions between $20$ and $20.1$ so each division is $\frac{20.1-20.0}{10}=0.01$

A is 2nd division from $20.0$, so, A is $20.0+2\times 0.01=20.02$

similarly, C is one division behind $20.0$ so it is 19.99

and B is $20.14$

Answer:

0.0016

Step-by-step explanation:

Batting average, p = 0.26

n = 7

x = 6

With p = 0.26 as success rate

1-p is equal to failure rate which is = 0.74

We have to solve this by using the binomial distribution formula.

P(X= x)

= nCx * p^x * (1-p)^(n-x)

P(X = 6)

=7C6 × 0.26^6 ×(1-0.26)^(7-6)

= 7 × 0.0003089 × 0..74¹

= 0.0016

So probability that he has exactly 6 hits in his next 7 bats is equal to 0.0016.

Answer:

d. all of the above

Step-by-step explanation:

A one sample z test measures whether the mean of a population is greater, less or equal to a specific value. It is called one sampl z test since the standard normal distribution is used in calculation of critical values. It makes use of the null hypothesis and alternative hypothesis in determining if the mean is greater than or equal or less than the reference value. Variance and standard deviation is assumed to be known and at least one population is used

Answer:

It's 8.3

Step-by-step explanation:

Answer:

8.3

Step-by-step explanation:

Answer:

Step-by-step explanation:

1. The sum of one-third of a number and 27

= [tex]\frac{1}{3}\times x +27\\= 1/3x +27[/tex]

2. The product of a number squared and 4

[tex]Let\:the\:unknown\: number\: be \:x\\\\x^2\times4\\\\= 4x^2[/tex]

3.Write a verbal expression for 5n^3 +9.

The sum of the product and of 5 and a cubed number and 9

Answer:

[tex]3x^{2} +38x+80[/tex]

Step-by-step explanation:

Hello!

A trinomial is a expression consisting of three different terms

To turn this into a trinomial we multiply everything to each other

                    3x                    

3x * x = [tex]3x^{2}[/tex]

3x * 10 = 30x

                    8                      

8 * x = 8x

8 * 10 = 80

Now we put them all together in an equation

[tex]3x^{2} +30x+8x+80[/tex]

Combine like terms

[tex]3x^{2} +38x+80[/tex]

The answer is [tex]3x^{2} +38x+80[/tex]

Hope this helps!

Answer:

-16

Step-by-step explanation:

8q

Let q = -2

8*-2

-16

Answer:

y = 8x + 70

Step-by-step explanation:

Start with the third line.

x = 3, y = 94

Subtract 1 from x and 8 from y:

x = 2, y = 86; this is the second line

Subtract 1 from x and 8 from y:

x = 1, y = 78; this is the first line

Subtract 1 from x and 8 from y:

x = 0; y = 70

For selling 0 games, she earns $70.

y = mx + b

y = mx + 70

For each game she sells, her commission is $8.

y = 8x + 70

Answer:

[tex] \boxed{f(x) = 2 {x}^{9} - 4 {x}^{2} + 4}[/tex]

Option B is the correct option

Step-by-step explanation:

By looking at the end behavior , we can say that the degree of the polynomial must be odd and leading coefficient will be positive.

Thus , the correct choice is B.

Hope I helped!

Best regards!

The polynomial function that could have created the given curve on the xy-plane is [tex]f(x)= 2x^9-4x^2+4[/tex]

Polynomial functions aree function having a leading degrees of 3 and greater.

The nature of the curve on the xy-plane depends on its end behaviour. From the given graph, the end behaviour shows that the equivalnt function has a positive leading coefficient and an odd degree.

From the listed option, the function that satisfies both criteria is [tex]f(x)=2x^9-4x^2+4[/tex].

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Answer:

1/2 inch per month

Step-by-step explanation:

The average rate hair grows is about half an inch per month which is 6 inches per year.

Answer:

Step-by-step explanation:

[tex]3h\left(2\right)+2k\left(3\right)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=3h\times \:2+2k\times \:3\\\\\mathrm{Multiply\:the\:numbers:}\:3\times \:2=6\\\\=6h+2\times \:3k\\\\\mathrm{Multiply\:the\:numbers:}\:2\times \:3=6\\\\=6h+6k[/tex]

Answer:

Answers for E-dge-nuityyy

Step-by-step explanation:

(h + k)(2) = 5

(h – k)(3) = 9

Evaluate 3h(2) + 2k(3) = 17

Answer:

so first convert to fraction so

9 3/4 = 39/4

so it was spread among 3

so this is division so you do 39/4 divided by 3

so you keep switch flip

which is  39/4 *1/3

answer is 13/4

Answer:

Step-by-step explanation:

[tex]9\frac{3}{4}= \frac{(4 \times 9)+3}{4}= \frac{39}{4} \\\\\frac{39}{4} = 3 \:vegetable \: beds\\x \:\:\:= 1 \: vegetable \:bed\\\\3x = \frac{39}{4} \\\\\frac{3x}{3} = \frac{\frac{39}{4} }{3} \\\\x = \frac{13}{4} \\\\x = 3\frac{1}{4}[/tex]

Rewrite f in terms of the unit step function:

[tex]f(t)=\begin{cases}5&\text{for }0\le t<7\\-3&\text{for }t\ge7\end{cases}[/tex]

[tex]\implies f(t)=5(u(t)-u(t-7))-3u(t-7)=5u(t)-8u(t-7)[/tex]

where

[tex]u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t<0\end{cases}[/tex]

Recall the time-shifting property of the Laplace transform:

[tex]L[u(t-c)f(t-c)]=e^{-cs}L[f(t)][/tex]

and the Laplace transform of a constant function,

[tex]L[k]=\dfrac ks[/tex]

So we have

[tex]L[f(t)]=L[5u(t)-8u(t-7)]=5L[1]-8e^{-7s}L[1]=\boxed{\dfrac{5-8e^{-7s}}s}[/tex]

In this exercise you have to find the laplace transform:

[tex]L[f(t)]=\frac{5-8e^{-7s}}{s}[/tex]

Rewrite f in terms of the unit step function:

[tex]f(t)=\left \{ {{5, for 0\leq t\leq 7} \atop {-3, for t\geq 7}} \right. \\f(t)= 5(u(t)-u(t-7)-3u(t-7)=5u(t)-8u(t-7)[/tex]

Where:

[tex]u(t)= \left \{ {{1, t\geq 0} \atop {0, t<0}} \right.[/tex]

Recall the time-shifting property of the Laplace transform:

[tex]L[u(t-c)f(t-c)]= e^{-cs}L[f(t)][/tex]

and the Laplace transform of a constant function,

[tex]L[k]=\frac{k}{s}[/tex]

So we have:

[tex]L[f(t)]= L[5u(t)-8u(t-7)]= 5L[1]-8e^{-7s}L[1]= \frac{5-8e^{-7s}}{s}[/tex]

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Answer:

P(C|Y) = 0.5.

Step-by-step explanation:

We are given the following table below;

               X             Y               Z             Total

A             32           10             28              70

B              6             5              25              36

C             18            15              7                40

Total       56           30            60              146

Now, we have to find the probability of P(C/Y).

As we know that the conditional probability formula of P(A/B) is given by;

                    P(A/B) =  [tex]\frac{P(A \bigcap B)}{P(B)}[/tex]

So, according to our question;

P(C/Y) =  [tex]\frac{P(C \bigcap Y)}{P(Y)}[/tex]

Here, P(Y) = [tex]\frac{30}{146}[/tex] and P(C [tex]\bigcap[/tex] Y) =  [tex]\frac{15}{146}[/tex]  {by seeing third row and second column}

Hence, P(C/Y) =  [tex]\frac{\frac{15}{146} }{\frac{30}{146} }[/tex]

                       =  [tex]\frac{15}{30}[/tex]  = 0.5.

Answer: 0.5

Step-by-step explanation:

edge

Answer:

The probability that the assembly line will be shut down is 0.00617.

Step-by-step explanation:

We are given that a soda bottling company’s manufacturing process is calibrated so that 99% of bottles are filled to within specifications, while 1% is not within specification.

Every hour, 12 random bottles are taken from the assembly line and tested. If 2 or more bottles in the sample are not within specification, the assembly line is shut down for recalibration.

Let X = Number of bottles in the sample that are not within specification.

The above situation can be represented through binomial distribution;

[tex]P(X=r)=\binom{n}{r} \times p^{r}\times (1-p)^{n-r};x=0,1,2,3,.....[/tex]

where, n = number of trials (samples) taken = 12 bottles

             x = number of success  = 2 or more bottles

            p = probabilitiy of success which in our question is probability that  

                 bottles are not within specification, i.e. p = 0.01

So, X ~ Binom (n = 12, p = 0.01)

Now, the probability that the assembly line will be shut down is given by = P(X [tex]\geq[/tex] 2)

  P(X [tex]\geq[/tex] 2) = 1 - P(X = 0) - P(X = 1)

                 = [tex]1-\binom{12}{0} \times 0.01^{0}\times (1-0.01)^{12-0}-\binom{12}{1} \times 0.01^{1}\times (1-0.01)^{12-1}[/tex]

                 = [tex]1-(1 \times 1\times 0.99^{12})-(12 \times 0.01^{1}\times 0.99^{11})[/tex]

                 = 0.00617

Answer: Multiply both sides by 2.

Step-by-step explanation:

g divided by 2  is equal to 4 .

We could represent that with the equation :

[tex]\frac{g}{2} = 4[/tex]     To solve for g  in this case multiply both sides by 2.

[tex]\frac{g}{2} * 2 = 4(2)[/tex]     2 cancels out on the left side so we will be left with g. On the right side will be left with 8  after multiplying.

g = 8    

Step-by-step explanation:

a2=a1+1/2=-1

a3=a2+1/2=-1/2, then we have common difference 0.5

a9=a1+(n-1)d

a9=-3/2+(8)0.5=5/2

Answer:

The null hypothesis is rejected and  research hypotheses is supported

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 30[/tex]

     The standard deviation is [tex]\sigma = 5[/tex]

      The sample size is  n =  1

      The  cutoff Z score for significance is  [tex]Z_{\alpha } = 1.96[/tex]

       The mean score is  [tex]\= x = 45[/tex]

Generally the test hypothesis is mathematically represented as

            [tex]t = \frac{\= x - \mu }{ \frac{ \sigma }{\sqrt{n} } }[/tex]

=>         [tex]t = \frac{45 - 30 }{ \frac{ 5}{\sqrt{1} } }[/tex]

=>         [tex]t = 3[/tex]

From the obtained value  we can see that [tex]t > Z_{\alpha }[/tex]

Hence the null hypothesis is rejected and  research hypotheses is supported

Answer:

The mean age is 48

The standard deviation is 4

Step-by-step explanation:

The answer is, (a) mean age is 48.

                          (b)  standard deviation is 4.

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Answer:

∠NMC  = 50°

Step-by-step explanation:

The interpretation of the information given in the question can be seen in the attached images below.

In ΔABC;

∠ A + ∠ B + ∠ C = 180°    (sum of angles in a triangle)

∠ A + 70°  + 50°  = 180°

∠ A = 180° - 70° - 50°

∠ A =  180° - 120°

∠ A =  60°

In ΔAMN ; the base angle are equal , let the base angles be x and y

So; x = y   (base angle of an equilateral  triangle)

Then;

x + x + 60° = 180°

2x +  60° = 180°

2x = 180° - 60°

2x = 120°

x = 120°/2

x = 60°

∴ x = 60° , y = 60°

In ΔBQC

∠a + ∠e + ∠b = 180°

50° + ∠e + 40° = 180°

∠e = 180° - 50° - 40°

∠e = 180° - 90°

∠e = 90°

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

∠i  = 50° - 40° = 10°

In ΔNQC

∠f + ∠i   + ∠j = 180°

90° + 10° + ∠j = 180°

∠j  = 180° - 90°-10°

∠j  = 180° - 100°

∠j  = 80°

From  line AC , at point N , ∠y + ∠c + ∠j = 180°   (sum of angles on a straight line)

60° + ∠c + ∠80° = 180°

∠c  = 180° - 60°-80°

∠c  = 180° - 140°

∠c  = 40°

Recall that :

At point Q , ∠e = ∠f = ∠g = ∠h = 90°  (angles at a point)

Then In Δ NMC ;

∠d + ∠h + ∠c = 180°   (sum of angles in a triangle)

∠d + 90° + 40° = 180°

∠d  = 180° - 90° -40°

∠d  = 180° - 130°

∠d  = 50°

Therefore, ∠NMC = ∠d  = 50°