Given:
The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.
To find:
The expected enrollment in 2010.
Solution:
Percentage decrease formula:
[tex]\%\text{ decrease}=\dfrac{\text{Initial value - New value}}{\text{Initial value}}\times 100[/tex]
The percentage decrease in between 1950 and 1960 is:
[tex]\%\text{ decrease}=\dfrac{4-3.5}{4}\times 100[/tex]
[tex]\%\text{ decrease}=\dfrac{0.5}{4}\times 100[/tex]
[tex]\%\text{ decrease}=\dfrac{50}{4}[/tex]
[tex]\%\text{ decrease}=12.5[/tex]
The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.
The expected enrollment in 2010 is:
[tex]\text{Expected enrollment}=7+\dfrac{12.5}{100}\times 7[/tex]
[tex]\text{Expected enrollment}=7+0.875[/tex]
[tex]\text{Expected enrollment}=7.875[/tex]
Therefore, the expected enrollment in 2010 is 7.875 thousands.
1. A set is said to be a singleton set,ig
a) n (A)=1
b) n (A)=0
Find the equation of the line that is parallel to f(x) and goes through point (-1,7).
Answer:
y=(3/7)*x+52/7
Step-by-step explanation:
The slope of the line will be (3/7). The equation of line will be y=(3/7)*x+52/7
A powerful women's group has claimed that men and women differ in attitudes about sexual discrimination. A group of 50 men (group 1) and 40 women (group 2) were asked if they thought sexual discrimination is a problem in the United States. Of those sampled, 11 of the men and 19 of the women did believe that sexual discrimination is a problem. Construct a 90% confidence interval estimate of the difference between the proportion of men and women who believe that sexual discrimination is a problem. What is the lower limit?
Answer:
the lower limit is 35% women believed and 65% of men believed in serial discrimination
If you only have a
1
6
cup measuring cup and a recipe calls for
15
1
6
cups of flour, how many 1/6 cups would you need to use?
Hi! I'm happy to help!
To solve this problem, we need to divide the recipe amount in 1/6 amounts. So, we will do a fraction division problem like this:
15[tex]\frac{1}{6}[/tex]÷[tex]\frac{1}{6}[/tex]
This problem is hard to do with mixed numbers, so we need to turn 15[tex]\frac{1}{6}[/tex] into an improper fraction. To do that we need to multiply 15 by 6, because that is our denominator, then add the extra [tex]\frac{1}{6}[/tex].
(15×6)+1
90+1
91
So, our improper fraction would be[tex]\frac{91}{6}[/tex], now, let's solve.
[tex]\frac{91}{6}[/tex]÷[tex]\frac{1}{6}[/tex]
It is difficult to do division problems on their own, so we can change this into an easier problem. We can do the inverse operation and turn this into multiplication. We do this by changing it to multiplication (obviously), then flip the second fraction.
[tex]\frac{91}{6}[/tex]×[tex]\frac{6}{1}[/tex]
Now, we just multiply the top by the top, and bottom by the bottom.
[tex]\frac{546}{6}[/tex]
We could end it here, but we want a whole number, so, we simplify the number by dividing both the top and bottom by 6.
[tex]\frac{91}{1}[/tex]
Anything over 1, is just a whole number
91.
Therefore, the recipe should require 91 uses of the 1/6 cup.
I hope this was helpful, keep learning! :D
1. Find the distance between the points A(1,0) and B(0,0).
Answer:
1
Step-by-step explanation:
Since the y value is the same, we only need to find the distance between the x points
1-0 = 1
The distance between the point is 1
Answer : 1 unit.
Explanation: Since ( 0,0 ) is at 0 on the x axis, ( 1,0 ) is one unit to the right of 0, 1.
The length of a rectangle is five times its width. If the perimeter of the rectangle is 108 in, find its area.
Answer:
Step-by-step explanation:multiple 5 times 108 and that gives you your answer..
What is the constant of variation, k, of the direct variation, y = kx, through (–3, 2)?
k = –k equals negative StartFraction 3 Over 2 EndFraction.
k = –k equals StartFraction 2 Over 3 EndFraction.
k = k equals StartFraction 2 Over 3 EndFraction.
k = k equals StartFraction 3 Over 2 EndFraction.
Answer: k = 2/-3
Step-by-step explanation: Option (B)
Taking the test as we speak
if 12 +2 =2 orderly what is 6 +3 orderly
Answer:
3
Step-by-step explanation:
Please Mark me brainliest
Answer:
aren't one of the numbers in the equations supposed to be negative?
What is the value of…
–13
–12
12
13
Answer:
-12
Step-by-step explanation:
that is b
Find the value of x on this triangle
Answer:
x = 35
Step-by-step explanation:
We can use the Pythagorean theorem since this is a right triangle
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
x^2 + 12^2 = (x+2)^2
FOIL
x^2+144=x^2+4x+4
Subtract x^2 from each side
144= 4x+4
Subtract 4 from each side
140 = 4x
Divide by 4
35 =x
Complete the statement. A critical value is _____________. Choose the correct answer below. A. A critical value is how far away our sample statistic can be from the true population parameter with a certain level of confidence. B. A critical value is the probability of obtaining a sample statistic like the one obtained from the sample or something more unusual if the null hypothesis is true. C. A critical value is the number of standard errors (or standard deviations) to move from the mean of a sampling distribution to correspond to a specified level of confidence. D. A critical value is the value that best estimates a population parameter.
Answer:
A. A critical value is how far away our sample statistic can be from the true population parameter with a certain level of confidence.
Step-by-step explanation:
Test of a hypothesis:
When we are testing a hypothesis, we have a null hypothesis and an alternative hypothesis, and the conclusion depends on the test statistic, given by:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
The test statistic measures the number of standard errors that we have to move away from the sample mean, and the critical value is how much we can be far from the population parameter with a certain level of confidence, that is, before a certain value we do not reject the null hypothesis, after the value we reject, and this value is the critical value, and thus the correct answer is given by option a.
A restaurant is doing a special on burgers. If the home team get a sack, the next day, burgers will cost$1
Normally, they cost $3,99. If every fan who attended the game (86,047 people) buys a $1.00 burger, how™
money did the restaurant lose with this discount?
ans: 257,256.59
if it was sold for $3.99
it would have been 86,047 × $3.99 = 343,303.59 and it was sold for $1 instead so automatically it's $86,047
therefore
343, 303.59
-86, 047 which is equal to a loss of $257, 256.59
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!!
At the grand opening of a store, the owner gave away stickers and T-shirts to some of the customers.
* A total of 180 customers visited the store at the grand opening.
* Every 10th customer received a free sticker.
* Every 25th customer received a free T-shirt.
a. What is the total number of customers who received a free sticker? Show or explain how you got your answer.
b. What is the total number of customers who received a free T-shirt? Show or explain how you got your answer.
c. What is the total number of customers who received a free sticker and a free T-shirt? Show or explain how you got your answer.
Answer:
[tex]thank \: you[/tex]
Approximately how many times greater is
7.4 x 10^8
than
2.5 x 10^7
0.3
3
30
300
Answer:
30
Step-by-step explanation:
To compare the numbers, divide the first number by the second number.
(7.4 x 10^8)/(2.5 x 10^7) = (74 x 10^7)/(2.5 x 10^7) = 74/2.5 = 29.6
Answer: 30
(07.04 MC)
Jim is designing a seesaw for a children's park. The seesaw should make an angle of 30' with the ground, and the maximum height
to which it should rise is 2 meters, as shown below:
1
2 meters
30
What is the maximum length of the seesaw? (6 points)
Select one:
a. 3.00 meters
b. 3.5 meter
C. 4,00 meters
d 4.5 meters
The maximum length of the seesaw is option c 4.00 meters.
What is a right-angled triangle?A right-angled triangle is one in which one of the angles is equal to 90 degrees. A 90 degree angle is called a right angle, which is why a triangle made up of right angle is termed a right angled triangle.
What are hypotenuse, height of a right-angled triangle?A right-angled triangle has three sides- hypotenuse, base and height. Hypotenuse is the longest and also the opposite side of the right angle of the triangle, base and height of a right triangle are always the sides adjacent to the right angle.
How to measure the hypotenuse of a right-angled triangle?The formula for measuring the hypotenuse is,
Height / Hypotenuse = Sinθ , where θ is the angle opposite to the height of the triangle.
In the given question, the seesaw should make an angle of 30° with the ground and the maximum height it should rise is 2 meters so the height here is 2 meters. So the seesaw will make a right angled triangle.
Height = 2 meters, θ = 30°,
Now using the formula,
2 / Hypotenuse = Sin30°
Rearranging we get,
Hypotenuse = 2 / Sin30°
The value of Sin30° is 1/2 and putting the value we get,
Hypotenuse = 2 / (1/2)
= 2 × 2
= 4 meters.
Therefore, the maximum length of the seesaw (that is the hypotenuse ) is 4 meters.
To learn more about right-angled triangles and finding sides of it click here-brainly.com/question/10331046
#SPJ2
A phone company offers two monthly plans. Plan A costs $21 plus an additional $0.11 for each minute of calls. Plan B costs $29 plus an additional $0.09 for each minute of calls. A. For what amount of calling do the two plans cast the same? ____minutes B. What is the cost when the two plans cost the same? $____
$121 and $12 ok isn't available in your ma er bishal bishal bishal
Match each sequence below to statement that BEST fits it.
Z. The sequence converges to zero;
I. The sequence diverges to infinity;
F. The sequence has a finite non-zero limit;
D. The sequence diverges.
_______ 1. ns in (1/n)
_______2. ln(ln(ln(n)))
_______3. (ln(n))/n
_______4. n!/n^1000
Answer: hello your question is poorly written attached below is the complete question
answer:
1 ) = I (
2) = F
3) = Z
4) = D
Step-by-step explanation:
attached below is the required solution.
1 ) = I ( The sequence diverges to infinity )
2) = F ( The sequence has a finite non-zero limit )
3) = Z ( The sequence converges to zero )
4) = D ( The sequence diverges )
I have a final for summer schoollll due midnight and it’s 10:23!!!!!!!!!!!!
Simplify the radical expression.
3^√0.125b^3
A. -5b
B. -0.5b
C. 0.5b
D. 5b
Anyone knows the answer?
Please!
Answer:
C
Step-by-step explanation:
sin(theta)=7/8, theta=arcsin(7/8)=61
According to the number line, what is the distance between points A and B?
А
B
VX
- 16 - 14 -12 -10 -8 -6 4-2
0 2
4
6
8 10 12 14 16
U6 units
X 7 units
12 units
14 units
Answer:
Below!
Step-by-step explanation:
Please provide the two points (A & B) so I can help you out with the question or...
use the distance formula: [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
where the first point = [tex](x_1,y_1)[/tex] & the second point: [tex](x_2,y_2)[/tex]
What is the key difference between simple interest and compound interest, and how does this difference affect the effectiveness of each? PLSSS HELP I HAVE ONE DAY LEFT
Answer:
The key difference between simple interest and compound interest is that in simple interest, the interest is calculated based on the principal amount of the loan.
The formula is principal multiplied by time by rate divided by 100.
Compound interest on the other hand, has to do with the principal amount and accumulated interest on previous periods.
The difference affects the effectiveness of each because in SI, interest is calculated once, while in CI, there's accumulated interest.
write your answer in simplest radical form
Answer:
please tell me the complete question
Change to cylindrical coordinates. 3∫−3 9-x^2∫0 9−x^2-y^2∫x^2+y^2 dz dy dx
I think the given integral reads
[tex]\displaystyle \int_{-3}^3 \int_0^{9-x^2} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
In cylindrical coordinates, we take
x ² + y ² = r ²
x = r cos(θ)
y = r sin(θ)
and leave z alone. The volume element becomes
dV = dx dy dz = r dr dθ dz
Then the integral in cylindrical coordinates is
[tex]\displaystyle \boxed{\int_0^\pi \int_0^{(\sqrt{35\cos^2(\theta)+1}-\sin(\theta))/(2\cos^2(\theta))} \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta}[/tex]
To arrive at this integral, first look at the "shadow" of the integration region in the x-y plane. It's the set
{(x, y) : -3 ≤ x ≤ 3 and 0 ≤ y ≤ 9 - x ²}
which is the area between a paraboloid and the x-axis in the upper half of the plane. So right away, you know θ will fall in the first two quadrants, so that 0 ≤ θ ≤ π.
Next, r describes the distance from the origin to the parabola y = 9 - x ². In cylindrical coordinates, this equation changes to
r sin(θ) = 9 - (r cos(θ))²
You can solve this explicitly for r as a function of θ :
r sin(θ) = 9 - r ² cos²(θ)
r ² cos²(θ) + r sin(θ) = 9
r ² + r sin(θ)/cos²(θ) = 9/cos²(θ)
(r + sin(θ)/(2 cos²(θ)))² = 9/cos²(θ) + sin²(θ)/(4 cos⁴(θ))
(r + sin(θ)/(2 cos²(θ)))² = (36 cos²(θ) + sin²(θ))/(4 cos⁴(θ))
(r + sin(θ)/(2 cos²(θ)))² = (35 cos²(θ) + 1)/(4 cos⁴(θ))
r + sin(θ)/(2 cos²(θ)) = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))]
r = √[(35 cos²(θ) + 1)/(4 cos⁴(θ))] - sin(θ)/(2 cos²(θ))
Then r ranges from 0 to this upper limit.
Lastly, the limits for z can be converted immediately since there's no underlying dependence on r or θ.
The expression above is a bit complicated, so I wonder if you are missing some square roots in the given integral... Perhaps you meant
[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{9-x^2-y^2} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
or
[tex]\displaystyle \int_{-3}^3 \int_0^{\sqrt{9-x^2}} \int_{x^2+y^2}^{\sqrt{9-x^2-y^2}} \mathrm dz\,\mathrm dy\,\mathrm dx[/tex]
For either of these, the "shadow" in the x-y plane is a semicircle of radius 3, so the only difference is that the upper limit on r in either integral would be r = 3. The limits for z would essentially stay the same. So you'd have either
[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{9-r^2} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]
or
[tex]\displaystyle \int_0^\pi \int_0^3 \int_{r^2}^{\sqrt{9-r^2}} r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]
Multiply and simplify the following complex numbers (-4-5i)•(1-i)
Answer:
Step-by-step explanation:
(-4 - 5i)⋅(1 - i) = (-4)(1) + (-4)(-i) + (-5i)(1) + (-5i)(-i)
= -4 + 4i - 5i + 5i²
= -4 - i -5
= -9 - i
Solve 3-(2x-5)<-4(x+2)
Answer:
Step-by-step explanation:
3-(2x-5)=-4(x+2)
We simplify the equation to the form, which is simple to understand
3-(2x-5)=-4(x+2)
Remove unnecessary parentheses
3-2x+5=-4*(x+2)
Reorder the terms in parentheses
3-2x+5=+(-4x-8)
Remove unnecessary parentheses
+3-2x+5=-4x-8
We move all terms containing x to the left and all other terms to the right.
-2x+4x=-8-3-5
We simplify left and right side of the equation.
+2x=-16
We divide both sides of the equation by 2 to get x.
x=-8
Answer:
x < - 8
Step-by-step explanation:
Given
3 - (2x - 5) < - 4(x + 2) ← distribute parenthesis on both sides
3 - 2x + 5 < - 4x - 8
- 2x + 8 < - 4x - 8 ( add 4x to both sides )
2x + 8 < - 8 ( subtract 8 from both sides )
2x < - 16 ( divide both sides by 2 )
x < - 8
Two years ago the population of a town was 40000. The population of the town at present has reached 44100. Calculate the population growth rate of the city.
Answer:
5% annual population growth rate
Step-by-step explanation:
Let the percent the population grows by be [tex]X\%[/tex]. The total population, [tex]f(x)[/tex], after [tex]t[/tex] years can be modeled by the function:
[tex]f(x)=40,000\cdot (\frac{X}{100}+1)^t[/tex]
Why?
Let's take a look at a simple example. If we said a number [tex]n[/tex] grew by 10%, we could represent the number after it grew by multiplying [tex]n[/tex] by [tex]1.10[/tex]. This is because growing by 10% is equivalent to taking [tex]100\%+10\%=110\%[/tex] of that number and we convert a percentage to a decimal by dividing by 100.
Therefore, if the population grew [tex]X\%[/tex], we would divide it by 100 to convert it to a decimal, then add 1 (100%) and raise to the power of [tex]t[/tex] (number of years) to multiply by the initial population of 40,000 to get the total population after [tex]t[/tex] years.
Since the population of the town after two years is 44,100, substitute [tex]f(x)=44,100[/tex] and [tex]t=2[/tex] into [tex]f(x)=40,000\cdot (\frac{X}{100}+1)^t[/tex]:
[tex]44,100=40,000\cdot (\frac{X}{100}+1)^2,\\\\(\frac{X}{100}+1)^2=\frac{44,100}{40,000},\\\\(\frac{X}{100}+1)^2=1.1025,\\\\(\frac{X}{100}+1)^2=\pm \sqrt{1.1025},\\\\\begin{cases}\frac{X}{100}+1=1.05,\frac{X}{100}=0.05, X=\boxed{5\%},\\*\text{negative case is extraneous since X must be positive}\end{cases}[/tex]
Therefore, the city has an annual population growth rate of 5%.
find the missing segment below brainly
Let missing side be x
Using basic proportionality theorem
[tex]\\ \sf\longmapsto \dfrac{6}{4}=\dfrac{x}{20-x}[/tex]
[tex]\\ \sf\longmapsto 6(20-x)=4x[/tex]
[tex]\\ \sf\longmapsto 120-6x=4x[/tex]
[tex]\\ \sf\longmapsto 120=6x+4x[/tex]
[tex]\\ \sf\longmapsto 120=10x[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{120}{10}[/tex]
[tex]\\ \sf\longmapsto x=20[/tex]
Roulette is a casino game that involves spinning a ball on a wheel that is marked numbered squares that are red, black, or green. Half of the numbers 1 - 36 are colored red and half are black and the numbers 0 and 00 are green. Each number occurs only once on the wheel. What is the probability of landing on a green space
Answer:
1/19
Step-by-step explanation:
There are a total of 36+2 = 38 spaces
2 are green
P(green) = green / total
= 2/38
=1/19
.052631579
PLEASE HELP
2/3x =10
Show your work in details if you can, I have a hard time understanding this.
[tex]\\ \sf\longmapsto \dfrac{2}{3}x=10[/tex]
[tex]\\ \sf\longmapsto \dfrac{2x}{3}=10[/tex]
[tex]\\ \sf\longmapsto 2x=3(10)[/tex]
[tex]\\ \sf\longmapsto 2x=30[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{30}{2}[/tex]
[tex]\\ \sf\longmapsto x=15[/tex]
[tex] \begin{cases}\large\bf{\red{ \implies}} \tt \frac{2}{3} x \: = \: 10 \\ \\ \large\bf{\red{ \implies}} \tt \frac{2x}{3} \: = \: 10 \\ \\ \large\bf{\red{ \implies}} \tt 2x \: = \: 3 \: \times \: 10 \\ \\ \large\bf{\red{ \implies}} \tt 2x \: = \: 30 \\ \\ \large\bf{\red{ \implies}} \tt \: x \: = \:\frac{ \cancel{30} \: \: ^{15} }{ \cancel{2}} \\ \\ \large\bf{\red{ \implies}} \tt \: x \: = \: 15 \end{cases}[/tex]