if the area of the quadrilateral ABCS is 924cm^2 and the length of the diagonal AC is 33cm,find the sum of lengths of the perpendicular from points B and D to AC.

please answer with full steps asap​

The correctness of the student's solution, we need to have the equations of the system.

A system of equations is graphed on the coordinate plane. A student concludes that the solution of the system is (-0.5, 1.5). Is this correct? Justify your response.To conclude that a system of equations has a solution in the coordinate plane, a set of ordered pairs (x, y) should satisfy both equations in the system of equations. That is, the system of equations should have a point (x, y) that is a solution of both equations.Only by testing the solution in the given system of equations can we know if the student's conclusion is correct. If the solution is satisfied by the system of equations, then the answer is true. Otherwise, it is false. However, since no system of equations is provided in the question, we cannot test the student's solution.To justify the correctness of the student's solution, we need to have the equations of the system.

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The three examples of contracts are:

Contracts are legal agreements between two or more parties that involve the exchange of goods, services, or money. They can be classified as unilateral or bilateral, express or implied, executed or executory.

Here are three examples of contracts that a person can be a part of:

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To perform matrix multiplication in MIPS, we can use nested loops to iterate over the rows and columns of the matrices.

The outer loop iterates over the rows of the first matrix, while the inner loop iterates over the columns of the second matrix. We then perform the dot product of the corresponding row and column, which involves multiplying the elements and summing the products.

To perform multiplication efficiently, we can use MIPS registers to store intermediate values and avoid accessing memory unnecessarily. We can also use assembly instructions like "lw" and "sw" to load and store values from memory, and "add" and "mul" to perform arithmetic operations.

In summary, matrix multiplication in MIPS involves nested loops, efficient use of registers and assembly instructions, and arithmetic operations.

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both containers have the same surface area and neither has a smaller surface area than the other.

Container 1:

Surface area of a single ball = π x (54/2)^2 = 3,092.62 mm^2

Total surface area of 4 balls = 12,370.48 mm^2

Container 2:

Surface area of a single ball = π x (54/2)^2 = 3,092.62 mm^2

Total surface area of 4 balls = 12,370.48 mm^2

Both containers have the same surface area.

To calculate the surface area of the two containers, I first calculated the surface area of one ball by using the formula π x (diameter/2)^2. I then multiplied this by 4 to get the total surface area of 4 balls. I repeated this process for both containers and found that both containers had the same surface area of 12,370.48 mm^2. both containers have the same surface area and neither has a smaller surface area than the other.

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(a) The eigenvalues of the coefficient matrix is  [-1,3]  and for λ=42, we get the eigenvector [1,5].

Itcan be found by solving the characteristic equation |A-λI|=0, where A is the coefficient matrix and λ is the eigenvalue. Solving for λ, we get λ=0 and λ=42.

o find the eigenvectors, we substitute each eigenvalue into the equation (A-λI)x=0 and solve for x. For λ=0, we get the eigenvector [-1,3]. For λ=42, we get the eigenvector [1,5].

(b) The solution is y(t) = c1e^(0t)[-1,3] + c2e^(42t)[1,5].

To find the real-valued solution to the initial value problem, we can use the eigenvectors and eigenvalues to diagonalize the coefficient matrix. We have A = PDP^-1, where P is the matrix whose columns are the eigenvectors and D is the diagonal matrix with the eigenvalues on the diagonal.

Using the initial condition y2(0) = 15, we can solve for the constants c1 and c2.

The solution is y(t) = c1e^(0t)[-1,3] + c2e^(42t)[1,5]. Solving for c1 and c2 using the initial condition, we get

y(t) = [-15e^(42t) + 3e^(0t), 15e^(42t) + 5e^(0t)].

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TU is a perpendicular bisector.

A line that divides a line segment into two equal halves and forms a 90-degree angle at the point of intersection is called a perpendicular bisector.

To put it another way, a perpendicular bisector separates a line segment at its midpoint, creating a 90-degree angle.

A line or line segment that divides a given line segment into two equal portions is known as a perpendicular bisector.

The word "bisect" refers to dividing equally.

The line segment that perpendicular bisectors overlap forms four 90° angles on either side.

A line or line segment is said to be perpendicular when it forms a 90° angle with another line or line segment.

Hence, TU is a perpendicular bisector.

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If the two removed squares have the same color, then it is possible to cover the truncated checkerboard with non-overlapping dominoes. If they have different colors, then it will be impossible to cover the truncated checkerboard with non-overlapping dominoes.

To prove that the chess board can be completely covered by non-overlapping dominoes, where each domino covers exactly two squares, we can color the board alternatively in black and white. The two colors will make the board have 32 black squares and 32 white squares. Each domino will cover one white and one black square. Since there are the same number of black and white squares, there is an equal number of squares that each domino can cover so it is possible to cover the entire board with dominoes without overlap.

To determine whether the cut checkerboard can be covered by non-overlapping dominoes, note that we have 62 squares, 31 of which are black, and 31 white. This means that one color will have one extra square, in this case black. Therefore, if the two removed squares are of different colors, it will be impossible to cover the cut checkerboard with non-overlapping dominoes.However, if the two removed squares have the same color, then it will be possible to cover the checkerboard with non-overlapping dominoes. This is because we will still have an equal number of black and white squares even after the removal of the two squares.The same logic applies to the truncated checkerboard.

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When the minimum volume of a clown is 60,000 cm³ and the volume of a car is 3 million cm³, 55 is an upper bound on the maximum number of clowns that can fit in a car. The correct answer is Option A.

Bounds are the maximum and minimum limits that are permitted, within which something can or must be performed. Bounds are used to refer to an acceptable range of values that provide safe operation or performance. In mathematics, a set of bounds can define the limits of the amount of things or objects.

The minimum volume of a clown is 60,000 cm³, so to fit 55 clowns in a car we need:

55 clowns × 60,000 cm³/clown = 3,300,000 cm³

This is lower than the volume of the car. Therefore, 55 is an upper bound on the maximum number of clowns that can fit in the car.

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The intensity of the beam 17 feet below the surface is 0.440265 times the initial intensity i0 of the incident beam is I(17) ≈ 0.002678.

It can be calculated as:

Let I(t) be the intensity of the beam at a depth of t feet below the surface, and

let k be a constant of proportionality.

Then we have:

[tex]dI/dt = -kI[/tex]

This equation says that the rate of change of intensity with respect to depth is proportional to the intensity itself, and the negative sign indicates that intensity decreases as depth increases.

We can solve this differential equation using separation of variables:

[tex]dI/I = -k dt[/tex]

[tex]\int\ dI/I = \int\ -k dt[/tex]

[tex]ln(I) = -kt + C[/tex]

[tex]I = e^{(C - kt)}[/tex]

where C is the constant of integration.

Now we can use the given information to find the value of k and the constant of integration C.

We know that at a depth of 3 feet below the surface, the intensity is 25% of the initial intensity i0:

[tex]I(3) = 0.25 i0[/tex]

[tex]e^{(C - 3k)} = 0.25 i0[/tex]

We also know that the depth at which we want to find the intensity is 17 feet below the surface:

t = 17

Now we can use the equation we derived earlier to find the intensity at a depth of 17 feet:

[tex]I(17) = e^{(C - 17k)}[/tex]

To find the constant of integration C and the constant of proportionality k, we can use the fact that we have two equations with two unknowns. First, we can solve the equation for C:

[tex]e^{(C - 3k)} = 0.25 i0[/tex]

[tex]C - 3k = ln{(0.25 i0)}[/tex]

[tex]C = ln{(0.25 i0)} + 3k[/tex]

Now we can substitute this expression for C into the equation for I(17):

[tex]I(17) = e^{(C - 17k)}[/tex]

[tex]I(17) = e^{(ln(0.25 i0) + 3k - 17k)}[/tex]

[tex]I(17) = e^{(ln(0.25 i0) - 14k)}[/tex]

Finally, we can solve for k using the fact that we know the intensity decreases by a factor of 0.25 when the depth increases from 0 to 3 feet:

[tex]dI/dt = -kI[/tex]

[tex]ln(I) = -kt + C[/tex]

[tex]I(3) = 0.25 i0[/tex]

[tex]e^{(C - 3k)} = 0.25 i0[/tex]

Taking the natural logarithm of both sides, we have:

[tex]C - 3k = ln{(0.25 i0)}[/tex]

Substituting the expression for C we derived earlier, we have:

[tex]ln{(0.25 i0)} + 3k - 3k = ln{(0.25 i0)}[/tex]

[tex]ln{(0.25 i0)} = ln{(0.25 i0)}[/tex]

This equation is true for all values of k, so we can choose any value for k that satisfies the differential equation.

For simplicity, we can choose[tex]k = ln(4)/3[/tex], which makes the constant of proportionality equal to[tex]-ln(4)/3.[/tex]

Now we can substitute this value of k into our expression for I(17) and simplify:

[tex]I(17) = e^{(ln(0.25 i0) - 14k)}[/tex]

[tex]I(17) = e^{(ln(0.25 i0) - 14ln(4)/3)}[/tex]

[tex]I(17) = 0.25 i0 e^{(-14ln(4)/3)}[/tex]

[tex]I(17) \approx 0.002678[/tex]

The intensity of the beam 17 feet below the surface is approximately 0.002678.

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Answer:

Correct choices

[tex]\csc (\theta) = - \dfrac{5}{3} \quad \quad \text{2nd option}\\\\\cot(\theta) = \dfrac{4}{3} \quad \quad \text{3rd option}\\\\\cos(\theta) = -\dfrac{4}{5} \quad \quad \text{4th option}\\\\[/tex]

Step-by-step explanation:

[tex]\text{If \;$ \tan\theta = \dfrac{3}{4} $}} \\\\\text{then }\\\theta = \tan^{-1} \left(\dfrac{3}{4}\right)\\\\= 36.87^\circ \text{ in Q1}\\[/tex]

But since tan θ is periodic it will also be 3/4 in Q3 which is 180° + 36.87 = 216.87°

The probability of the disk drive being in a normal state is 0.5, and the probability of the disk drive being in a failed state is 0.3.

The given table represents the joint probability mass function of the random variables, pxyc (r, y, c). r, y, and c denote the temperature, shock sensor, and health status of the disk drive. The values of r, y, and c are binary.The joint probability mass function of three random variables r, y, and c can be represented as follows:pxyc (r, y, c)= P(r, y, c)Here,P(r=0, y=0, c=0)= 0.1, P(r=0, y=1, c=0)= 0.2, P(r=1, y=0, c=0)= 0.2,P(r=0, y=0, c=1)= 0, P(r=0, y=1, c=1)= 0, P(r=1, y=0, c=1)= 0,P(r=0, y=0, c=0)= 0, P(r=0, y=1, c=0)= 0, P(r=1, y=1, c=0)= 0.05,P(r=0, y=0, c=1)= 0.25, P(r=0, y=1, c=1)= 0, P(r=1, y=0, c=1)= 0.From the given table, the probability of the disk drive being in a normal state, C=0, is P(C=0)=P(r=0, y=0, c=0)+P(r=0, y=1, c=0)+P(r=1, y=0, c=0)=0.1+0.2+0.2=0.5Hence, the probability of the disk drive being in a failed state, C=1, is:P(C=1)=P(r=0, y=0, c=1)+P(r=0, y=1, c=1)+P(r=1, y=0, c=1)+P(r=1, y=1, c=0)=0.25+0+0+0.05=0.3Therefore, the probability of the disk drive being in a normal state is 0.5, and the probability of the disk drive being in a failed state is 0.3.

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In Bitcoin, when a merchant waits for n confirmation of a payment transaction before providing the product, there is a risk of a double-spend attack. In this situation, the network is aware of a branch crediting the merchant, which has n blocks on top of the one in which the fork started.

      By simulating m as a negative binomial variable, P(m) = (m + n - 1m)pnqm can be used to more precisely compute this probability for a given value of m.

           The attacker, on the other hand, has a branch with only m additional blocks. If we assume the honest network and the attacker have a proportion of p and q of the total network hash power, respectively, the probability of the attacker catching up when he is currently z blocks behind is given by az = paz+1 + qaz−1, where a is a constant.

          To calculate the probability more accurately, we can model m as a negative binomial variable.

          This is the number of successes (blocks found by the attacker) before n failures (blocks found by the honest network), with a probability q of success.

          The probability for a given value m is then given by P(m) = (m + n - 1m)pnqm.

         Thus, when dealing with a double-spend attack in Bitcoin, the probability that the attacker will be able to catch up is given by az = paz+1 + qaz−1, where a is a constant.

              This probability can be more accurately calculated by modeling m as a negative binomial variable, with the probability for a given value m given by P(m) = (m + n - 1m)pnqm.

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A linear transformation matrix is a square matrix that represents a linear transformation of a vector space. The composition of linear transformation matrices is equivalent to the composition of linear transformations they represent.

In general, the composition of two linear transformations A and B can be represented by the matrix product AB. Therefore, the composition of two linear transformation matrices, say A and B, would be the matrix product AB.

Linear transformations are functions that map vectors from one vector space to another in a linear way. These transformations can be represented by matrices, which can be composed to represent the composition of linear transformations.

The composition of two linear transformations represented by matrices involves multiplying the matrices together. To perform this multiplication, we need to ensure that the number of columns in the first matrix matches the number of rows in the second matrix. The resulting matrix will have the same number of rows as the first matrix and the same number of columns as the second matrix.

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In response to the stated question, we may state that As a result, the area final polynomial in standard form is: -25pi + 50

The size of a surface area can be represented as an area. The surface area is the area of an open surface or the border of a three-dimensional object, whereas the area of a planar region or planar region refers to the area of a shape or flat layer. The area of an item is the entire amount of space occupied by a planar (2-D) surface or form. Make a square with a pencil on a sheet of paper. A two-dimensional character. On paper, the area of a form is the amount of space it takes up. Assume the square is made up of smaller unit squares.

To calculate the area of the darkened areas, subtract the area of the circle from the area of the square.

Then, determine the square's side length. Because the circle's diameter is ten, the radius is five. Because the diagonal of a square equals the diameter of a circle, we can use the Pythagorean theorem to calculate the side length:

[tex]s^2 + s^2 = 10^2\\2s^2 = 100\\s^2 = 50\\s = \sqrt(50) = 5 * \sqrt(2)[/tex]

The square's area is then:

[tex]A_{square} = s^2 = (5 * \sqrt(2))^2 = 50[/tex]

The circle's area is:

[tex]A_{circle} = pi * r^2 = pi * 5^2 = 25 * pi[/tex]

The shaded region's area is:

[tex]A_{shaded} = A_{square} - A_{circle} = 50 - 25 * pi[/tex]

As a result, the final polynomial in standard form is:

-25pi + 50

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Answer:

Step-by-step explanation:

(52 divided by 80) multiplied by 100
that will give you the answer

To estimate the difference between the giving rates of school A and school B, we must first identify the missing value. It is not given in the statement.

1. However, it can be assumed that the giving rate of school B is 0%, as the difference between the two figures should be expressed as a percentage.

2. If we learn that schools A and B have identical student-to-faculty ratios, the answer to the previous question would not change. The student-to-faculty ratio has no bearing on the graduation and giving rates of the school.

3. The question does not provide a list of 123 schools to choose from. It is not possible to determine the school with the highest or lowest giving rate without this information.

4. To calculate whether the school's giving rate is greater or lesser than 8%, we must first estimate the value of the giving rate. The problem statement does not provide a clue to the school's giving rate.

Therefore, it is not possible to calculate the school's giving rate without more information.

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the triangles are similar, corresponding parts of the triangles are equal in measure. Thus, it is reasonable to conclude that [tex]AB ≅ DE.[/tex]

It is reasonable to conclude that [tex]AB ≅ DE[/tex]because triangles ABC and DEF are similar.

This means that corresponding parts of the two triangles are equal in measure. Specifically, ∠A and ∠D are equal in measure, as are ∠B and ∠E.

Therefore, the corresponding sides AB and DE are equal in measure.

A way to show that the two triangles are similar is by using the AA Similarity Postulate.

This postulate states that if two angles of one triangle are equal in measure to two angles of a second triangle, then the two triangles are similar. In this case, [tex]∠A ≅ ∠D and B ≅ ∠E[/tex], which means the two triangles are similar.

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Answer:

$2300

Step-by-step explanation:

$1610 is 7/10 the original cost. Multiplying by 10/7 reverses that, and we get the starting cost of $2300

Hope this helps!

Answer: $22.50

Step-by-step explanation:

Let x be the cost per pound of the secret-formula coffee beans.

The total cost of the secret-formula beans is 12x dollars.

The total cost of the other beans is 15 × 18 = 270 dollars.

The total cost of the mix is (12 + 15) × 20 = 540 dollars.

Since the barista mixed 12 pounds of the secret-formula beans with 15 pounds of the other beans, the total weight of the mix is 12 + 15 = 27 pounds.

We can set up an equation based on the total cost of the mix:

12x + 270 = 540

Subtracting 270 from both sides:

12x = 270

Dividing both sides by 12:

x = 22.5

Therefore, the barista's secret-formula coffee beans cost $22.50 per pound.

When a researcher draws conclusions about a population based on the results of a test on a sample, he or she is most likely using inferential statistics. Therefore Option A is correct.

Inferential statistics: It involves using sample data to make inferences or draw conclusions about a population. In this case, the researcher is using the results from the sample to make inferences about the population from which the sample was drawn.

Deductive statistics, inductive statistics, and descriptive statistics are other branches of statistics that are used for different purposes.

Therefore the researcher draws a conclusion to use inferential statistics about a population based on test of sample.Option A is correct.

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Answer:

  10.309 in²/s

Step-by-step explanation:

Given A³ = 36πV² and V' = 18 in³/s, you want to know A' when A=153.24 in² and V=178.37 in³.

Using implicit differentiation, we have ...

  3A²·A' = 36π·2V·V'

  A' = (36π·2)/3·V/A²·V' = 24πV/A²·V'

  A' = 24π·(178.37 in²/(153.24 in²)²·18 in³/s

  A' ≈ 10.309 in²/s

The surface area is increasing at about 10.309 square inches per second.

__

Additional comment

There are at least a couple of ways a calculator can be used to find the rate of change. The first attachment shows evaluation of the expression we derived above. The second attachment shows the rate of change when the area is expressed as a function of the volume.

The result rounded to 5 significant figures is the same for both approaches.

Answer:

To find the point that partitions the line segment AB in a ratio of 1:3, we can use the following formula:

P = (3B + 1A) / 4

where P is the point that partitions the line segment in a ratio of 1:3, A and B are the endpoints of the line segment, and the coefficients 3 and 1 represent the ratio of the segment we are dividing.

Substituting the values, we get:

P = (3*(-1, -5) + 1*(-5, 3)) / 4

P = (-3, -7)

Therefore, the point that partitions the line segment AB in a ratio of 1:3 is (-3, -7).

Step-by-step explanation:

Answer:

5 cm

Step-by-step explanation:

Opposite sides are equal in a rectangle.

So, Area of missing length = 16-11 = 5 cm

Keenan's z-score is 0.71, rounded to the nearest hundredth.

The z-score measures how many standard deviations an individual's score is from the mean, and can be calculated using the formula:

z = (x - μ) / σ

where x is the individual's score, μ is the mean score, and σ is the standard deviation.

For Keenan's exam:

z = (80 - 77) / 4.2

z = 0.71

Therefore, Keenan's z-score is 0.71, rounded to the nearest hundredth.

Rounding to the nearest hundredth means the rounding of any decimal number to its nearest hundredth value. In decimal, hundredth means 1/100 or 0.01. For example, the rounding of 2.167 to its nearest hundredth is 2.17.

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The given expression is

[tex]15 + c = 17.50[/tex]

We can use this expression to model the cost for a service.

Let's say that your gardener charges an initial amount of $15, and an additional per hour. If the gardener worked only for one hour, and the total cost charged was $17.50, how much was the additional cost?

So, the given expression models this real life situation, we can answer the problem by just solving the equation for [tex]c[/tex]

[tex]15 + c = 17.50[/tex]

[tex]c=17.50-15[/tex]

[tex]c=2.50[/tex]

Answer: Well C equals 2.5. You could use...

You have 3 sticks. one stick is 15 inches long and the other is 17.50. You want to get a small stick to add to the first one so that the first and last stick is equal to the 2nd stick.  C is the third stick.  15+C = 17.50. What is the length of C?

Step-by-step explanation:

EASY

Move all terms not containing C to the right side of the equation. C = 2.5

Answer:

To find out how much Gary's backpack will weigh with the math and science textbooks in it, we need to add the weight of the textbooks to the weight of the backpack:

Total weight = backpack weight + math textbook weight + science textbook weight

Total weight = 1.2 + 3.75 + 2.85

Total weight = 7.8 pounds

Therefore, Gary's backpack will weigh 7.8 pounds with the math and science textbooks in it.

Answer: His backpack will weigh 7.8 pounds

Step-by-step explanation:

Gary's backpack already weights 1.2 pounds without the science and math textbook, now we add the weights of both the math and science textbook.

1.2 + 3.75 = 4.95

4.95 is the weight with only his math textbook in his bag

now we add the science textbooks weight to 4.95

4.95 + 2.85 = 7.8

7.8 is the weight of his backpack with both his science and math textbook in his bag

Answer:

9

Step-by-step explanation:

The correct answer is option (C).

Sine (sin), cosine (cos), tangent (tan), cosecant (csc), secant (sec), and cotangent are the six functions (cot).

The equation t = Q - P, where Q and P are the specified locations, can be used to determine the components of the vector t. Therefore:

t = (–18, 2) – (–13, 11) = (–18 + 13, 2 – 11) = (–5, –9) (–5, –9)

The vector's magnitude is given by:

|t| = √(–5)^2 + (–9)^2 = √106 ≈ 10.296

The formula = tan1 (y/x), where x and y are the vector's components, can be used to determine the direction of the vector t. The direction must be expressed in terms of sine and cosine functions because we are required to represent the vector in trigonometric form.

θ = tan⁻¹ (–9/–5) ≈ 60.945°

In trigonometric form, the vector t is thus represented as follows:

t = [t|cos|i] + [t|sin|j]

We get the following by altering the values of |t| and:

t = 10.296 cos I + 10.296 sin j of angle 60.945

As a result, the following is the proper trigonometric representation of the vector t:

t = 10.296 cos I + 10.296 sin j of angle 60.945

Thus, alternative is the right response (C).

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Answer:

A. x = -2 or x = 8

Good luck!!

Step-by-step explanation:

(x - 3) - 10 = -5

x - 3 = - 5 + 10

x - 3 = 5

x = 5 + 3

x = 8