If the distance between a neutral atom and a point charge is increased by a factor of six, by what factor does the force on the atom by the point charge change

Answers

Answer 1

Answer:

A neutral atom has no net charge and should not be affected by a point charge, and the distance of separation is not a factor.

Answer 2

The force will remain the same and is equal to zero.

We have a point charge and a neutral atom.

We have to investigate if the distance between a neutral atom and a point charge is increased by a factor of six, by what factor does the force on the atom by the point charge change.

State Coulomb's Law of Electrostatic force.

The Coulomb's law states that the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them. Mathematically -

[tex]$F=\frac{q _{1}\cdot q _{2}}{4\cdot \pi \cdot \varepsilon \cdot \varepsilon _{0}\cdot r^{2}}[/tex]

According to question, we have -

A point charge and a neutral atom.

If initially the distance between the point charge and neutral atom is r meters, then -

q(1) = Q (say)

q(2) = 0   ( Neutral atom has zero charge)

Using Coulomb's law -

[tex]$F=\frac{Q\times 0}{4\cdot \pi \cdot \varepsilon \cdot \varepsilon _{0}\cdot r^{2}}[/tex]

F = 0 Newtons.

Now, if you will increase the distance by the factor of six, still the force will remain zero as there is only one point charge and other is neutral atom. There is no electrostatic force between a charged and uncharged particle.

Hence, the force will remain the same and is equal to zero.

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Related Questions

Atoms of which two elements could combine with atoms of chromium (Cr) to
form ionic bonds?
O A. F.
B. Au
C. Se
D. Ti
E. Mg

Answers

Answer:

D and E

Ionic bonds are formed between metals and non-metals and both of those are metals

how many atoms are in a 4.7 g copper coin?​

Answers

3.11 is the answer I think

Answer:

x = 4.45 * 10 ^22  Note. Technically, this should be rounded to 4.5 * 10^22. There are only 2 sig digits.

Explanation:

You have to assume that the coin is pure copper, which I doubt.  What a coin is actually made of  depends on when it was minted. But for the sake of this question, we'll assume coins are pure copper.

Copper has an atomic mass of 63.546 grams / mol

So 4.7 g of copper = 4.7 / 63.545 mol

We have 0.07396 mol of copper

1 mol of anything = 6.02 * 10^23 atoms (in this case).

0.07396 mol        = x

Cross Multiply

               

1 * x = 0.07396 * 6.02 * 10^23

x = 4.45 * 10 ^22  atoms of copper

If it were to snow in Phoenix in July, which type of Earth scientist would be most
surprised?

Answers

Answer:

Economists, I guess.

Explanation:

Hạt mang điện q > 0 chuyển động trong từ trường của một dòng điện thẳng dài có cường độ I = 10A như hình. Hạt mang điện chuyển động song song với dây dẫn và cách dây một khoảng 5cm. Vẽ hình và:
a. Xác định cảm ứng từ do dòng điện gây ra tại điểm mà hạt mang điện đi qua.
b. Hạt mang điện chuyển động với tốc độ 104m/s, lực Lorentz tác dụng lên hạt là 8.10-4N. Tính độ lớn của điện tích.

Answers

Answer:

I dnt know that language

Explanation:

I provided the question above.

Answers

Answer:

Explanation:

since it is connected in parallel combination

use this formula

[tex]\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2}[/tex]

[tex]\frac{1}{R} = \frac{1}{2} + \frac{1}{4}[/tex]

[tex]\frac{1}{R} = \frac{4+2}{2}[/tex]

[tex]\frac{1}{R} = \frac{6}{2}[/tex]

[tex]\frac{1}{R} = 3[/tex] ohm

therefore resistence = 3 ohm

then we should find power

P = VI

P = 12*3

P = 24 watt

now to find current use formula power = current * voltage

24 = current * 12

24/12 = current

2 = current

therefore current is 2 ampere (A).

to find potential difference (emf) use formula

V = IR

V = current * resistence

V = 2 * 3

V = 6 volt .

therefore potential difference is 6 volt.

In the figure below, this “double” nozzle discharges water (at 10°C, density= 1000 kg/m3) into the atmosphere at a rate of 0.50 m3/s. The pressure at the inlet is to be 315612 Pa. If the nozzle is lying in a horizontal plane. Jet A is 10 cm in diameter, jet B is 12 cm in diameter, and the pipe (1) is 30 cm in diameter. The x-component of force (Rx) acting through the flange bolts is required to hold the nozzle in place is:

Answers

Answer:

gfxfhhnhgfhjjgfghjhffgkhfdcg

Which of the following situations would violate the second law of
thermodynamics?
O A. A heat engine feeling cold after running for an hour
B. A heat engine using heat to do work
O C. A heat engine losing some energy as heat
D. A heat pump being 80% efficient

Answers

Answer: it’s A.

Explanation: A pex

Why do some "people" still believe that the earth is "flat".
I called my brother in Australia and it was day here, and night there, HOW CAN THE EARTH POSSIBLY BE FLAT, i did a zo,om meeting to prove that it was live. WHAT ARE PE,OPLE TH,INKING!!!

Answers

Answer: Members of the Flat Earth Society claim to believe the Earth is flat. Walking around on the planet's surface, it looks and feels flat, so they deem all evidence to the contrary, such as satellite photos of Earth as a sphere, to be fabrications of a "round Earth conspiracy" orchestrated by NASA and other government agencies.

♛ Mark me as Brainliest if I’m right

THE ANSWER!!! Please

Answers

Answer:

I think -7 N. Netforce is 3N-10N= -7N

Explanation:

A student must use an object attached to a string to graphically determine the gravitational field strength near Earth's surface. The student attaches the free end of the string to the ceiling and pulls the object-string system so that the string makes an angle of 5 degrees from the object's vertical hanging position. The student then releases the object from rest and uses a stopwatch to measure the time it takes for the object to make one complete oscillation. Which of the following is the next step that will allow the student to determine the gravitational field strength?
А) Repeat the experiment by adding additional mass to the object for multiple trials
B) Repeat the experiment by changing the length of the string for multiple trials
C) Repeat the experiment by changing the angle that the string makes with the object's vertical hanging position
D) Repeat the experiment by measuring the time it takes to make two oscillations, three oscillations, and additional oscillations for multiple trials

Answers

Answer:

B) True. By changing the length get a different period and with a graph you can find the best value of the gravity pull

Explanation:

The student is reacting a simple pendulum experiment where he can determine the value of the relationship of gravity with the expression

              T = 2π [tex]\sqrt{\frac{L}{g} }[/tex]

let's analyze each statement

A) False. The mass is not a paramer of the period expression

B) True. By changing the length get a different period and with a graph you can find the best value of the gravity pull

C) False. The angle while it is small does not influence the period

D) True. By changing the number of oscillations the period does not change, so you can get the value of the pull of gravity.

We can see that the expressions B and d are true, the most exact value is obtained using procedure B since the graphs allow to reduce the errors

An object starts to rotate about an axis from rest wih a, uniform angular acceleration of 2pi rads-2 what is the no.of rotations it can complete in 5s

Answers

Answer:

θ = 12.5 rotations

Explanation:

The number of rotations can be found by using the second equation of motion:

[tex]\theta = \omega_i t + \frac{1}{2}\alpha t^2\\\\[/tex]

where,

[tex]\theta[/tex] = angular displacement = ?

ωi = initial angular speed = 0 rad/s

t = time = 5 s

α = angular acceleration = 2π rad/s²

Therefore,

[tex]\theta = (0\ rad/s)(5\ s)+\frac{1}{2}(2\pi\ rad/s^2)(5\ s)^2\\\\\theta = 78.54\ rad[/tex]

converting it to no. or rotations:

[tex]\theta = (78.54\ rad)(\frac{1\ rotation}{2\pi\ rad})[/tex]

θ = 12.5 rotations

A 50-kg copper block initially at 140°C is dropped into an insulated tank that contains 90 L of water at 10°C. Determine the final equilibrium tempera

Answers

Answer:

16.33°C

Explanation:

Applying,

Heat lost by copper = heat gained by water

cm(t₁-t₃) = c'm'(t₃-t₂).............. Equation 1

Where c = specific heat capacity of copper, m = mass of copper, c' = specific heat capacity of water, m' = mass of water, t₁ = initial temperature of copper, t₂ = initial temperature of water, t₃ = final equilibrium temperature.

From the question,

Given: m = 50 kg, t₁ = 140°C, m' = 90 L = 90 kg, t₂ = 10°C

Constant: c = 385  J/kg°C, c' = 4200J/kg°C

Substitute these values into equation 1

50(385)(140-t₃) = 90(4200)(t₃-10)

(140-t₃) = 378000(t₃-10)/19250

(140-t₃) = 19.64(t₃-10)

140-t₃ = 19.64t₃-196.6

19.64t₃+t₃ = 196.4+140

20.64t₃ = 336,4

t₃ = 336.4/20.6

t₃ = 16.33°C

Got it never mind. The only reason I'm typing more is to fill out the required space

Answers

Answer:

hey. i dont know what you tryna say but if u replying to someone else, you should use the comments section. in that way you won't lose points.

A test charge of -1.4 x 10-7 coulombs experiences a force of 5.4 x 10-1 newtons. Calculate the magnitude of the electric field created by the
negative test charge.
ОА.
1.4 x 106 newtons/coulomb
ОВ.
1.9 x 106 newtons/coulomb
OC. 5.4 x 10-1 newtons/coulomb
OD
3.6 x 106 newtons/coulomb

Answers

Answer:

3.86×10⁶ Newton/coulombs

Explaination:

Applying,

E = F/q....................... Equation 1

Where E = Electric Field, F  = Force, q = charge.

From the question,

Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs

Substitute these values into equation 1

E = 5.4×10⁻¹/ -1.4×10⁻⁷

E = -3.86×10⁶ Newtons/coulombs

Hence the magnitude of the electric field created by the

negative test charge is 3.86×10⁶ Newton/coulombs

In 1913 Niels Bohr formulated a method of calculating the different energy levels of the hydrogen atom.

a. True
b. False

Answers

They are right the answer is A true

When an AC source is connected across a 17.0 Ω resistor, the output voltage is given by Δv = (190 V)sin(50πt). Determine the following quantities. (a) maximum voltage V (b) rms voltage V (c) rms current A (d) peak current A (e) Find the current when t = 0.0045 s.

Answers

Explanation:

the answer is in the above image

(a) The maximum voltage V is  190 Volts.

(b) The rms voltage V is 95√2 Volts.

(c) The rms current in Amperes is  7.9 A.

(d) The peak current Amperes is  11.18 A.

(e)The current when t = 0.0045 s is 7.26 A.

What is current?

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

Given is an AC source is connected across a 17.0 Ω resistor, the output voltage is given by Δv = (190 V)sin(50πt).

(a) From the given voltage equation, maximum voltage V is 190 Volts.

(b) rms voltage =Vmax/√2

Put the values, we get

Vrms = 190/√2 = 95√2 Volts

(c) rms current = Vrms/Resistance

Put the values, we get

Irms =  95√2 /17

Irms = 7.9 Amperes.

(d) peak current  =√2 Irms

Substitute the values, we get

Peak current = 7.9 √2 = 11.18 A

(e) The current when t = 0.0045 s is written as

I =  (190 V)sin(50πt)/R

Substitute the values, we have

I =  (190 )sin(50π x0.0045)/17

I = 7.26 A.

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What is the magnitude of a vector that has the following components: x = 32 m y = -59 m

Answers

Answer:

Explanation:

Since the x and y components are given

The vectors Magnitude = √32²+(-59)²

=67.12m

An Na ion has a charge of +1 and an Oion has a charge of -2. How many Na ions does one Oion need to balance
charges?

Answers

Mark Brainliest please

Answer : 2 (two)
For every O ion, two Na ions are needed to balance charges.

An iron nail floats in mercury and sinks in water. explain why?​

Answers

Answer:

because density of iron is more than that of water but less then that of Mercury

hope it's helpful


40 ohms
1.2 A
40 ohms
12 V


Calculate the total energy developed in 5
minutes by the system above.​

Answers

Answer:

17280 J and 1080 J

Explanation:

Given :

R= 40 ohm

I=1.2A

t= 5 min=60×5=300 sec

Now,

Total energy can be calculated as:

[tex]E=I^{2} Rt\\E=(1.2)^{2} *40*300\\E=17280 J[/tex]

Now,

V=12V

R=40 Ohm

[tex]E=\frac{V^{2} }{R} *t\\E=\frac{(12)^{2} }{40} *300\\E=1080 J[/tex]

Total energy  is 17280 J and 1080 J

Which of the following phenomenon odd called photoelectric effect?

A. High energy electrons impinge on a metallic Annie which emits electrons

B. A high energy photon emits photons as it slows down

C. A metal absorbs a quanta of light and then emits electrons

D. Two electrons are created from a quanta of light.

Answers

two electrons are created from a quanta of kight

1. An AAMU basketball player is 2.03 meters tall. What is his height given in US customary units of feet and
inches?

Answers

Answer:

His height is 6.66 feet or 79.92 inches.

Explanation:

Given that,

An AAMU basketball player is 2.03 meters tall.

Let h is the height.

We know that,

1 m = 3.28 feet

So,

2.03 m = 6.66 feet

Also,

1 m = 39.37 inches

2.03 m = 79.92 inches

Hence, this is the required solution.

If a rock displaces 7 ml of water, what is the volume of the rock?

Answers

Answer:

if i am not mistaken the volume is 7, because it only took that much space

Two oppositely charged objects are separated by a small distance. The objects are then moved three times farther apart from each other. Which of the following statements best describes what happens to the electrical force between the objects?

A: The force of attraction increases
B: The force of attraction decreases
C: The force of attraction stays the same
D: The force of attraction becomes a force of repulsion

Answers

Force is indirectly proportional to the distance. Therefore when the distance increases the force of attraction increases and the answer would be B

The statement best describes what happens to the electrical force between the objects when moved three times farther apart from each other is the force of attraction decreases. The correct option is B.

What is force of attraction?

The objects when placed at a distance, they are attracted by the gravitational force of attraction.

Gravitational force of attraction is directly proportional to the product of masses and inversely proportional to the square of distance between them.

Two oppositely charged objects are separated by a small distance. The objects are then moved three times farther apart from each other.

Force is indirectly proportional to the distance. So, when the distance increases the force of attraction decreases.

Thus, the correct option is B.

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A caterpillar climbs up a one-meter a wall. For every 2 cm it climbs up, it slides down 1 cm. It takes 10 minutes for the
caterpillar to climb to the top. What is the distance traveled? (Round the number to the nearest hundred.)
cm

Answers

Answer:

1.5 m is ur answer

Explanation:

What must a plant need to produce 4 molecules of sugar?
What must a plant need to produce 4 molecules of sugar?

Answers

Answer:

To produce a single sugar molecule a plant must use a molecule of water (H2O) and carbon dioxide (CO2) and sunlight. To get 4 molecules, you simple use 4 molecules of water and 4 molecules of carbon dioxide

Carbon dioxide and water to produce glucose.

A given wave has a wavelength of 1.4 m and a frequency of 2.0 Hz. How fast
is the wave moving?
O A. 0.6 m/s
O B. 3.4 m/s
O C. 0.7 m/s
D. 2.8 m/s

Answers

Answer:

The wave speed is 2.8 m.

Explanation:

Wavelength = 1.4 m

frequency, f = 2 Hz

the wave speed is given by

wave speed = wavelength x frequency

wave speed = 1.4 x 2 = 2.8 m

option (D) is correct.  

Record the lengths of the sides of ABC and ADE.

Answers

Can you show the rest of the problem

A 500 Kg block is attached with a rope of length 5m, having area 0.4× 10-4 m2. If final length is 6m, Calculate the Stress, Strain and Young's Modulus?

Answers

Answer:

stress = 1.225 x 10^8 N/m^2

strain = 1/5

Young's modulus = 6.125 x 10^8 N/m^2

Explanation:

mass, m = 500 kg

length, L = 5 m

Area, A = 0.4 x 10^-4 m^2

Final length, L' = 6 m

extension, x = L'-L= 6 - 5 = 1 m

Stress is defined as force per unit area.

[tex]stress =\frac{Force}{Area}\\\\stress =\frac{500\times 9.8}{0.4\times 10^{-4}}\\\\stress = 1.225\times 10^8 N/m^2[/tex]

Strain is defined as the ratio of change in length to the original length.

[tex]strain =\frac{x}{L}\\\\strain = \frac{1}{5}[/tex]

Young's modulus is given by the ratio of stress to the strain.

[tex]Y = \frac{1.225 \times 10^8}{\frac{1}{5}}\\\\Y = 6.125\times 10^8 N/m^2[/tex]

What is the weight on Earth of an object with mass 45 kg. Hint gravity = 10 N/kg *
1 point
45 N
450 N
450 kg
10N

Answers

Answer:

450N

Explanation:

weight= m*g

weight=45*10

weight=450N

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