If the specific heat of iron = 0.46J C, how much heat is needed to warm 50 g of iron from 20C to 100C

Answers

Answer 1

Answer:

1840 J

Explanation:

From the question given above, the following data were obtained:

Specific heat capacity (C) = 0.46 J/gºC

Mass (M) = 50 g

Initial temperature (T₁) = 20 °C

Final temperature (T₂) = 100 °C

Heat (Q) required =?

Next, we shall determine the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 20 °C

Final temperature (T₂) = 100 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 20

ΔT = 80 °C

Finally, we shall determine the heat required. This can be obtained as follow:

Specific heat capacity (C) = 0.46 J/gºC

Mass (M) = 50 g

Change in temperature (ΔT) = 80 °C

Heat (Q) required =?

Q = MCΔT

Q = 50 × 0.46 × 80

Q = 1840 J

Thus, 1840 J of heat energy is required.


Related Questions

What is the average speed of a car that travelled 400 miles in 6 hours?

Answers

Answer:

About 66 miles per hour

Explanation:

Based on the information given we can assume the car traveled the same number of miles every hour meaning all we need to do is divide.

400/6 ≈ 66 miles per hour

Answer

66 mph

Explanation:

400 ÷ 6 = 66.666666666666666.......

a simple mobile is made by attaching 4 small balls(0.1 kg each)

Answers

I’m guessing you do 4x0.1 and then get your answer

If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass of 86.3 g?

Answers

Answer:

Time = 6 years

Explanation:

First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:

[tex]m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}[/tex]

where,

n = no. of half-life periods = ?

m = initial mass = 86.3 g

m' = remaining mass = 10.8 g

Therefore,

[tex]2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3[/tex]

Since the bases are the same. Therefore equating powers:

n = 3

Now we calculate the time:

[tex]Time = (n)(Half-Life)\\Time =(3)(2\ years)[/tex]

Time = 6 years


What is the force required to accelerate an object with a mass of 5 kg and an acceleration of
2 m/s22

Answers

10 Newton. See the picture below

The weight of a luggage is 69.3 N on the moon. Find its weight on the Earth.​

Answers

Answer:

415.8N

Explanation:

Given:

weight of a luggage = 69.3 N

But

✓(weight on the Earth) is equivalent to 6 times weight if the moon.

✓Then, weight on the Earth) =( 69.3N × 6)

✓weight on the Earth) = 415.8N

When light hits a second transparent medium, light-

A. Reflects and Refracts
B. Refracts only
C. Reflects only

Answers

Answer:

C. Reflects only

Determine whether a moving tennis ball and a racket held by the player have the same momentum or different momentum. If different, determine which object has more momentum.

Answers

Answer:

key points:1.momentum and impulse

2.condition for conservation of momentum and why

3.how to solve collision problems

4.centre of mass

Explanation:

momentum is a vector

force of a tennis ball

for a top player,a tennis ball may leave the racket on the with a speed of 55m/s(about 120mi/h).if the ball has a mass of 0.060kg and is in contact with the racket for about 4ms(4×10)s.estimate the average force on the ball

When the Asthenosphere transfers heat, what happens?

Convection Currents, Earthquakes, volcanic eruptions, or weathering?

Answers

The hot rock flows along the bottom of the lithosphere, transferring its heat to the cold rocks by conduction.

how to find a cow

write a 4-5 sentence answer

Answers

Answer:

Go out into the country. Look on a farm. Look in a barn. Listen for, "MOOOOO." You found a cow.

Explanation:

A car traveling at 65 mph is an example of its

Answers

Answer:

Speed

Explanation:

The distance traveled by an object in a unit of time is speed

Which law best describes contact force
A.
second law
B.
third law
C.
law of gravity
D.
first law

Answers

Answer: the third law

Explanation:

Objects A and B are brought close to each other. Object A will soon become positively charged. Identify the charge that must transfer for
this
situation to occur.

Answers

B because that’s why they are going out of the circle

If the vehiche has a speed of 24.0 m/s at point a what is the force of the track on the vehicle at this point?

Answers

Question:

A roller-coaster vehicle has a mass of 500 kg when fully loaded with passengers.  If the vehicle has a speed of 20.0 m/s at point A, what is the force exerted by the track on the vehicle at this point?

See attachment

Answer:

33700 Newton

Explanation:

Given

[tex]m = 500kg\\v = 24.0m/s\\r=10m[/tex]

First, we determine the forces acting on mass m.

They are: the force exerted by the track (Fn) and the weight of the vehicle (W)

So, the net force is:

[tex]F_{net} = F_n - W[/tex]

[tex]W=mg[/tex]

So:

[tex]F_{net} = F_n - mg[/tex]

Make Fn the subject

[tex]F_n = F_{net} + mg[/tex]

Fnet is calculated as:

[tex]F_{net} = F_c = \frac{mv^2}{r}[/tex] --- i.e. the centripetal force

So:

[tex]F_n = F_{net} + mg[/tex]

[tex]F_n = \frac{mv^2}{r} + mg[/tex]

[tex]F_n = \frac{500 * 24^2}{10} + 500 * 9.8[/tex]

[tex]F_n = 28800 + 4900[/tex]

[tex]F_n = 33700N[/tex]

a
400 12
M
b
290 12
с
The question below refers to the circuit shown in the image
--
12.0 y
If the voltage across the 400 resistor is 7 V, what is the voltage across the 290 Q resistor?
O 5V
O 7V
O 9V
O 12 V
1
2
3
4
5

Answers

Answer:

i would think c

Explanation:

Un acróbata de masa M, se impulsa hacia arriba con una velocidad v0 desde un

trampolín. Mientras sube, a una altura h sobre el trampolín, recoge a un mono entrenado de masa m. ¿Cuál es la altura máxima que alcanzan el mono y el acróbata?

Answers

Answer:

La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].

Explanation:

Asumamos que tanto el acróbata, el mono y el sistema acróbata-mono son conservativos y que el acróbata comienza su acción a una altura de cero. El estudio se divide en dos etapas: (i) El acróbata se dirige al mono, (ii) El acróbata recoge al mono y alcanzan una altura máxima.

Para resolver esta cuestión, nos valemos del Principio de Conservación de la Energía.

Parte I

La energía cinética traslacional inicial ([tex]K_{1,a}[/tex]) es igual a la suma de la energía cinética traslacional final ([tex]K_{2, a}[/tex]) y la energía potencial gravitacional final ([tex]U_{g,2,a}[/tex]).

[tex]K_{1,a} = K_{2,a} + U_{g,2,a}[/tex] (1)

[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex] (1b)

Donde:

[tex]M[/tex] - Masa del acróbata.

[tex]g[/tex] - Constante gravitacional.

[tex]v_{o}[/tex] - Rapidez inicial del acróbata.

[tex]v_{1}[/tex] - Rapidez del acróbata justo antes de recoger al mono.

[tex]h[/tex] - Altura inicial del mono.

Parte II

La suma de las energías iniciales cinética traslacional ([tex]K_{2, a}[/tex]) y potencial gravitacional de acróbata ([tex]U_{g,2,a}[/tex]) y la energía inicial potencial gravitacional del mono ([tex]U_{g,2,m}[/tex]) es igual a la suma de las energías potenciales gravitacionales iniciales del sistema acróbata-mono ([tex]U_{g,3,a+m}[/tex]), es decir:

[tex]K_{2,a} + U_{g,2,a}+U_{g,2,m} = U_{g,3,a+m}[/tex] (2)

[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex] (2b)

Donde:

[tex]m[/tex] - Masa del mono.

[tex]z[/tex] - Altura máxima del sistema acróbata-mono.

De (1b) tenemos que la rapidez del acróbata justo antes de recoger al mono es:

[tex]\frac{1}{2}\cdot M \cdot v_{o}^{2} = \frac{1}{2}\cdot M\cdot v_{1}^{2} + M\cdot g \cdot h[/tex]

[tex]v_{o}^{2} = v_{1}^{2}+2\cdot g\cdot h[/tex]

[tex]v_{1} = \sqrt{v_{o}^{2}-2\cdot g\cdot h}[/tex]

Finalmente, la altura máxima alcanzada por el sistema acróbata-mono es:

[tex]\frac{1}{2}\cdot M\cdot v_{1}^{2} + (M+m)\cdot g \cdot h = (M+m)\cdot g \cdot z[/tex]

[tex]z = \frac{M\cdot v_{1}^{2}}{2\cdot (M+m)\cdot g}+h[/tex]

[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot (v_{o}^{2}-2\cdot g\cdot h)+ h[/tex]

[tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex]

La altura máxima que alcanzan el mono y el acróbata es [tex]z = \frac{1}{2}\cdot \left(\frac{M}{M+m} \right)\cdot v_{o}^{2}+\left(1-\frac{M\cdot g}{M+m} \right)\cdot h[/tex].

What are two ways fusion is used in the real world.

Answers

Answer:

The main application for fusion is in making electricity. Most fusion reactors make less radiation than the natural background radiation we live with in our daily lives. ... Clean - No combustion occurs in nuclear power (fission or fusion), so there is no air pollution.

A sound wave is produced by a musical instrument for 0.40 second. If the frequency of the wave is 370 hertz, how many complete waves are produced in that time period? *
A) 200 waves
B)150 waves
C)100 waves
D) 50 waves

Answers

E⁣⁣⁣xplanation i⁣⁣⁣s i⁣⁣⁣n a f⁣⁣⁣ile

bit.[tex]^{}[/tex]ly/3a8Nt8n

The number of waves produced by the musical instrument during the given time is 148 waves.

What is meant by frequency of a wave ?

Frequency of a wave is defined as the number of oscillations completed by the wave in one second.

Here,

The frequency of the wave, f = 370 Hz

That means the wave completes 370 oscillations in 1 second. Or 370 waves are produced by the musical instrument in 1 second.

The time taken by the instrument to produce waves, t = 0.4 s

Therefore,

The number of waves produced by the musical instrument during this time is,

n = f x t

n = 370 x 0.4

n = 148

Hence,

The number of waves produced by the musical instrument during the given time is 148 waves.

To learn more about frequency of a wave, click:

https://brainly.com/question/3693482

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A 5kg book is slid across the floor with an initial velocity of 3m/s. It slows and stops due to the friction with the floor. How man joules of work did friction do?

Answers

Answer:

SUP DAD i love cookies

Explanation:

yuh

Which two types of energy are being produced in the picture?
A
electrical energy and light energy
B
electrical energy and sound energy
C
mechanical energy and light energy
D
mechanical energy and sound energy

Answers

Answer:

dion sanders

Explanation:c

how does the input distance of a third-class lever compare to the output distance​

Answers

Answer:

A first-class lever: fulcrum is between input and output force; second-class lever: output force is between input force and fulcrum; third-class lever: input force is between fulcrum and output force

Are women sports underpaid compared with man? (Example: Women's USA soccer team is paid way less then Men's USA soccer team)

DO NOT PUT LINKS!!

Answers

Answer:

Yeah of course

Explanation:

Its obvious because more people are attracted to men soccer

I would say yes and no at the same time whatever way you are looking at it . Cause in a article it says men’s viewer ship in 2018 soccer is 3.5 billion views on television compared to the woman’s which was 1.1 billion views . So the more views the woman’s and men’s soccer gets the more they get paid . In which in a way that’s sets the woman’s pay way lower compared to the men’s.

So what is 27+22? Is it
A 8338
B 8282
C 8228
D 8234

Answers

Answer:

You put the add sign, so it would be 49. I don't believe that is what you meant to put though.

Explanation:

i gotchu, 27+22 so you take the 8 and multiply that by the number of times you blink every 2 minutes and then divide that by 0×1 and carry the 3 and that gives you -7

6
Which of these statements is true?
А
Acceleration in the direction of motion slows you down
B.
Acceleration in the direction of motion speeds you up
C
Acceleration against the direction of motion has no effect
on your speed
D
Acceleration against the direction of motion speeds you up

Answers

Answer:

B. Acceleration in the direction of motion speeds you up

Explanation:

Acceleration is defined as when something gains speed. For example, when a car speeds up. Deceleration is when the car slows down, and looses speed. When defining these terms, think of a car going faster, then slowing down at a red light.

The bones of the middle ear cause which structure in the inner ear to vibrate and change the sound into signals?
a) eardrum
b) cochlea
c) hammer
d) auricle

Answers

Answer:

B

Explanation:

The cochlea is the part of the inner ear involved in hearing. It is a spiral-shaped cavity in the bony labyrinth, in humans making 2.75 turns around its axis, the modiolus.

Answer:

the answer is the cochlea

Explanation:

the eardrum receives the sounds and the cochlea "decifers them" so you know what words people are saying or what sound is playing.

A car travels at uniform velocity at a distance of 100 m in 4 seconds what is the velocity of the car

Answers

100/4 = 25. velocity = distance divided by time. Hope this helps!!

Answer:

the answer is 25

Explanation:

because the formula for velocity is distance divided by time.  

Which of the following is the best
definition of tissue?
1 Pt
A
B
A. what organs are made of
B. your skin and muscles
C. parts of cells
D. a group of similar cells working together
E. None of the above

Answers

Kid stop giving links

3. A warehouse employee is pushing a 30.0 kg desk across a floor at a
constant speed of 0.50 m/s. How much work must the employee do on
the desk to change the speed to 1.00 m/s?

Answers

Answer: The employee must do 11.2308 Joules of work

Explanation:

Work done = force × distance

But  

Force = ma(mass x acceleration due to gravity)

F = 30×9.8

F = 294N

Also distance moved can be found using  the equation  

v² = u² +2gS

1.00 ² = 0.50²+2(9.8)S

1 =0.25+19.6S

1-0.25 =19.6S

0.75=19.6S

S=0.75/19.6

S = 0.0382m

Work done = force × distance = FS

Work done = 294 N X 0.0382m

Workdone =11.2308Nm = 11.2308 Joules

Work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.

What is work done?

Work done is the force applied on a body to move it over a distance. Work done by a body can be given as,

[tex]W=Fd[/tex]

Here (F) is the magnitude of force and (d) is the distance traveled.

From the second law of motion, the force is product of mass time acceleration. Thus the above formula can be given as,

[tex]W=(ma)d[/tex]

For the gravitational acceleration, it can be written as,

[tex]W=(mg)d\\W=mgd[/tex]

The constant speed by which, the warehouse employee is pushing the desk across a floor is 0.50 m/s and the the final speed of the desk is 1 m/s.

Thus, the distance traveled by it can be find out using the third law of motion as,

[tex]v^2-u^2=2gd\\1^2-0.25^2=2\times9.8\times d\\d=0.0382\rm m[/tex]

As the mass of the desk is 30 kg and the distance moved is 0.382 meters. Thus, put the values in the above formula as,

[tex]W=30\times9.81\times0.0382\\W\cong11.3\rm J[/tex]

Thus the work done required by the employee to do on the desk to change the speed to 1.00 m/s is 11.3 J.

Learn more about the work done here;

https://brainly.com/question/25573309

Decribe what must happen inside of an aluminum can in order for it to be attracted to a positively-charged and to a negatively-charged object

Answers

Answer:

The PROTONS in the can attract to the negatively charged object, so then the can becomes polarized and the ELECTRONS in the can attract the positively charged object.

Explanation:

The PROTONS inside the can entice to the negatively charged object, so then the can will become polarized and the ELECTRONS in the can appeal to the undoubtedly charged item.

How are proton and electron associated?

The number of protons within the nucleus of the atom is identical to the atomic range. The variety of electrons in an impartial atom is identical to the number of protons. The mass range of the atom (M) is equal to the sum of the wide variety of protons and neutrons inside the nucleus.

Protons definitely charged subatomic particles that live in the nucleus. Neutrons: Neutrally charged subatomic particles that are living in the nucleus. Electrons: Negatively charged subatomic debris found inside the electron shells surrounding the nucleus.

An electron is a negatively charged factor of an atom while the proton is an undoubtedly charged frame. The electrons are present out of doors the nucleus inside the orbiting shells. But the protons alongside neutrons shape the nucleus of the atom and are gifted in the middle of the atomic nuclei.

Learn more about electron and proton here: https://brainly.com/question/4894505

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How do I solve this arithmetic sequence?

Answers

Answer:

The 16ᵗʰ term of this sequence is 82

Step-by-step explanation:

Here,

First Term = a₁ = 9

Common Difference = (d) = 2

Now, For 16ᵗʰ term, n = 16

aₙ = a + (n - 1)d

a₁₆ = 7 + (16 - 1) × 2

a₁₆ = 7 + 15 × 5

a₁₆ = 7 + 75

a₁₆ = 82

Thus, The 16ᵗʰ term of this sequence is 82

-TheUnknownScientist

Would the following reaction be endothermic or exothermic? Why?
CH4 + 02 --> CO2 + H2O + Energy
A. Exothermic because energy is a reactant
B. Endothermic because energy is a reactant
C. Endothermic because energy is a product
D. Exothermic because energy is a product

Answers

Answer:

D. Exothermic because energy is a product

Explanation:

ENDOTHERMIC REACTION: A chemical reaction is considered endothermic if the energy is absorbed during the reaction. In other words, if the energy is required by the reactants to proceed with the reaction, then the reaction is endothermic.

EXOTHERMIC REACTION: A chemical reaction is considered exothermic if the energy is released during the reaction. In other words, if the energy is produced as a product of the reaction, then the reaction is exothermic.

Hence, the correct answer for this question will be:

D. Exothermic because energy is a product

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