If you draw a card with a value of three or less from a standard deck of cards, I will pay you $41. If not, you pay me $11. (Aces are considered the highest card in the deck). If you played this game 877 times how much would you expect to win or lose?

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Explanation:

We undo the "minus 6" by adding 6 to both sides.

Also, we undo the "+s" by subtracting s from both sides

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So we have these steps

P = r+s-6

P+6 = r+s-6+6 .... adding 6 to both sides

P+6 = r+s

r+s = P+6

r+s-s = P+6-s ..... subtracting s from both sides

r = P + 6 - s

Answer:

P+6-s=r

Step-by-step explanation:

Hi there!

We are given the equation P=r+s-6 and we need to solve for r

To do that, we need to isolate r onto one side, and have everything else on the other.

Here is the equation:

P=r+s-6

start by adding 6 to both sides to clear it from the right side

P+6=r+s

now subtract s from both sides to clear it from the right side

P+6-s=r

now everything that isn't r is on the left side, and r is by itself on the right side. P+6-s=r is the answer.

Hope this helps!

Answer:

Area of the given regular pentagon is 61.5 cm².

Step-by-step explanation:

Area of a regular polygon is given by,

Area = [tex]\frac{1}{2}aP[/tex]

Here, a = Apothem of the polygon

P = Perimeter of the polygon

Apothem of the regular pentagon given as 4.1 cm.

Side of the pentagon = 6 cm

Perimeter of the pentagon = 5(6)

                                             = 30 cm

Substituting these values in the formula,

Area = [tex]\frac{1}{2}(4.1)(30)[/tex]

        = 61.5 cm²

Therefore, area of the given regular pentagon is 61.5 cm².

Answer:

[tex]\sigma = 121.53[/tex]

Step-by-step explanation:

Required

The population standard deviation

First, calculate the population mean

[tex]\mu = \frac{\sum x}{n}[/tex]

This gives:

[tex]\mu = \frac{148+ 329+ 491 +167+ 228+285+ 441}{7}[/tex]

[tex]\mu = \frac{2089}{7}[/tex]

[tex]\mu = 298.43[/tex]

The population standard deviation is:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]

So, we have:

[tex]\sigma = \sqrt{\frac{(148 - 298.43)^2 + ..........+ (441- 298.43)^2}{7}}[/tex]

[tex]\sigma = \sqrt{\frac{103387.7143}{7}}[/tex]

[tex]\sigma = \sqrt{14769.6734714}[/tex]

[tex]\sigma = 121.53[/tex]

Answer:

[tex]E(x) = 1.5\\[/tex]

Step-by-step explanation:

Given

[tex]n = 9[/tex] -- number of rolls

Required

The mean of 2's

The distribution follows binomial distribution where:

[tex]X \to Binomial(n,p)[/tex]

In this case:

[tex]p= \frac{1}{6}[/tex] ---- the theoretical probability of rolling 2

So, the mean of 2's is calculated using:

[tex]E(x) = np[/tex]

[tex]E(x) = 9 * \frac{1}{6}[/tex]

[tex]E(x) = \frac{9}{6}[/tex]

Simplify

[tex]E(x) = \frac{3}{2}[/tex] or

[tex]E(x) = 1.5\\[/tex]

Answer:

The answer is "sometimes".

Step-by-step explanation:

A one-way ANOVA was merely performed on one collected data and the null hypothesis was rejected after an ANOVA F test. Assume we could randomize ANOVA block design with the same information. This null hypothesis for full equality is sometimes rejected for the randomized complete block design ANOVA. Therefore we understand the use of randomized ANOVA block if the null hypothesis is denied of a one-way ANOVA but the rejection of a null RBD ANOVA hypothesis isn't conditional mostly on denial of the yet another ANOVA null.

Answer:

the magnitude of a real number without regard to its sign.

Step-by-step explanation:

For example, |-3| would just be a 3 in general, no negative sign in the front.

hope this answers your confusion.

Answer:

10. CD + DE = CE

11. BC + CE = BE

Step-by-step explanation:

10. CD and DE lie on a straight line, therefore, CD + DE = CE based on the segment addition postulate.

11. BC and CE lie on a straight line, therefore, BC + CE = BE based on the segment addition postulate.

Answer:

[tex](f + g)(4) = 191[/tex]

Step-by-step explanation:

Given

[tex]f(x) = 5x^2 - 5x + 15[/tex]

[tex]g(x) = 6x^2 + 7x - 8[/tex]

Required

[tex](f + g)(4)[/tex]

First, calculate [tex](f + g)(x)[/tex]

This is calculated as:

[tex](f + g)(x) = f(x) + g(x)[/tex]

So, we have:

[tex](f + g)(x) = 5x^2 - 5x + 15+6x^2 + 7x - 8[/tex]

Collect like terms

[tex](f + g)(x) = 5x^2 +6x^2 - 5x+ 7x + 15 - 8[/tex]

[tex](f + g)(x) = 11x^2 + 2x + 7[/tex]

Substitute 4 for x

[tex](f + g)(4) = 11*4^2 + 2*4 + 7[/tex]

[tex](f + g)(4) = 191[/tex]

Answer:

[tex]y = -\frac{3}{4}x + 5[/tex]

Step-by-step explanation:

Given equation  y = -3/4x  - 5

Step 1 : Find slope.

           Since the lines are parallel to each other, the slopes are same.

          [tex]therefore, m = \frac{-3}{4}[/tex]

Step 2 : Find the equation of the line.

           [tex]( y - y_1) = m ( x - x_ 1) \ \ \ where \ x_ 1 = 4 \ and \ y_ 1 = 2[/tex]

            [tex]( y - 2 ) = -\frac{3}{4}( x - 4)\\\\y - 2 = -\frac{3}{4}x + 3\\\\y = -\frac{3}{4}x + 3 + 2\\\\y = -\frac{3}{4}x + 5[/tex]

Answer:

[tex]T_n = \frac{1}{4^{n-1}}[/tex]

Step-by-step explanation:

Given

[tex]({)1, 1/4, 1/16, 1/64, 1/256, ... (})[/tex]

Required

The general term

The given sequence is geometric.

So first, we calculate the common ratio (r)

[tex]r = T_2/T_1[/tex]

So, we have:

[tex]r = 1/4 \div 1[/tex]

[tex]r = 1/4[/tex]

The function is then calculated using:

[tex]T_n =T_1 * r^{n-1}[/tex]

This gives

[tex]T_n =1 * 1/4^{n-1}[/tex]

[tex]T_n = \frac{1}{4^{n-1}}[/tex]

Answer:

Step-by-step explanation:

every thing looks good,  except the question says  "round"   and soooooo,  if you are rounding to the 2nd decimal place,  then the next two decimal places are  54,      or  50.2654   so, to round that, round up , so your final answer would look like   50.27   :)  see?

9514 1404 393

Answer:

  50.24 inches  (or 50.2 inches)

Step-by-step explanation:

The formula for circumference in terms of radius is ...

  C = 2πr

Using the given values for radius and for pi, the circumference is ...

  C = 2(3.14)(8 in) = 50.24 in

__

Additional comment

If you use a more accurate value of pi, the rounded value is 50.27 in. That is not the value requested by this problem. It helps to follow directions.

If you like, you can round to 50.2, since only one decimal place is required in the result.

Answer:

25

Step-by-step explanation:

x = distance of the hike

y = number of friends coming along

so, we are looking for a linear relationship between these two.

y = ax + b

we need to find the factor a and the constant offset b.

19 = a×3 + b

7 = a×5 + b

7 - b = a×5

a = (7-b)/5

19 = (7-b)×3/5 + b

19 = (21 - 3b)/5 + b

95 = 21 - 3b + 5b

74 = 2b

b = 37

a= (7-37)/5 = -30/5 = -6

so, the relationship is

y = -6x + 37

for 2km hiking

y = -6×2 + 37 = -12 + 37 = 25 friends

s hard and too long I'm only of class 13

Answer:

15ways

Step-by-step explanation:

This is a combination question since combination has to do with selection. Hence the number of ways sample of 6 keyboards can be selected so that exactly two have an electrical defect is expressed as;

6C2 = 6!/(6-2)!2!

6C2 = 6!/4!2!

6C2 = 6×5×4!/4!×2

6C2 = 6×5/2

6C2 = 30/2

6C2 = 15

Hence this can be done in 15ways

Step-by-step explanation:

The number of cases of a new disease may be modeled by the quadratic regression equation y=-2x^2+44x+8 , what is the best prediction for the number of cases after 20 years ( the carrot symbol (^) means the following number is the exponent)

Hello,

P(A)=0.4

P(B)=0.3

P(AUB)+P(A∩B)=P(A)+P(B)

P(AUB)=0.4+0.3-0.1=0.6

Answer C

The correct answer is option (C).

P(A ∪ B) = 0.6

If A, B are two different events then P(A U B) = P(A) + P(B) - P(A ∩ B)

We have been given, P(A) = 0.4, P(B) = 0.3

From given Venn diagram,

P(A ∩ B) = 0.10

Now, P(A U B) = P(A) + P(B) - P(A ∩ B)

⇒ P(A U B) = 0.4 + 0.3 - 0.10

⇒ P(A ∪ B) = 0.6

Therefore, the correct answer is option (C) .6

Learn more about here:

https://brainly.com/question/1605100

#SPJ2

9514 1404 393

Answer:

  66 m

Step-by-step explanation:

The perimeter is the sum of the measures of all of the sides. There are two side measures that are missing from the diagram.

The missing horizontal measure is ...

  17 m - 8 m = 9 m

The missing vertical measure is ...

  16m -7 m = 9 m.

If you add these to the sum you already calculated, you will get the correct answer:

  48 m + 9 m + 9 m = 66 m . . . perimeter of the figure

_____

If you're paying attention, you see that the sum of the measures of the two shorter horizontal segments is the same as the measure of the longer horizontal segment. Likewise, the sum of the measurements of the two shorter vertical segments is the same as that of the longer vertical segment.

In other words, the perimeter of this (and any) L-shaped figure is the same as the perimeter of a rectangle having the same horizontal and vertical dimensions as the long sides of the figure.

  P = 2(17 m +16 m) = 2(33 m) = 66 m

Complete Question

Complete is Attached  Below

Answer:

Option D

Step-by-step explanation:

From the question we are told that:

Sample size [tex]n=26[/tex]

Student scoring [tex]65-100 n'=12[/tex]

Generally the equation for probability of a student having score between 65 and 100 is mathematically given by

 [tex]P(65-100)=\frac{12}{26}[/tex]

 [tex]P(65-100)=12/26[/tex]

 [tex]P(65-100)=0.462[/tex]

Option D

Answer:

f(h(x)) = 2•(x²-1)² -4•(x²-1)

There are more compact cars (4*10 = 40) compared to trucks (2*10 = 20); however, the pictogram might make it appear that there are more trucks because the individual truck icon is larger compared to an individual compact car icon.

To anyone giving this image a quick glance, they may erroneously conclude that there are more trucks since their eye would notice the trucks first. Also, the person might think there are more trucks because bigger sizes tend to correspond to more proportion.

In real life, a truck is larger than a compact car, but the icons need to be the same size to have the figure not be misleading.

A very similar issue happens with the mid-size cars vs the compact cars as well. The three mid-size car icons span the same total width as the compact cars do, indicating that a reader might mistakenly conclude that there are the same number of mid-size cars compared to compact ones (when that's not true either).

Step-by-step explanation:

we cannot see the diagram, so we don't know how many layers of bricks are used. and therefore it is impossible to tell the height of the wall.

Answer:

a) r ⋀~p

b)(r⋀p)⟶q

c) ~r ⟶ ~q

d) (~p ⋀r) ⟶q

Step-by-step explanation:

To solve this question we will make use of logic symbols in truth table.

We are told that;

p means "The user enters

a valid password,”

q means “Access is granted,”

r means “The user has paid the

subscription fee”

A) The user has paid the subscription fee, but does not enter a valid

password.”

Fist part of the statement is correct and so it will be "r". Second part of the statement is a negation and will be denoted by ~p. Since both statements are joined together in conjunction, we will use the conjuction symbol in between them which is "⋀" Thus, we have; r ⋀~p

B) Still using logic symbols, we have;

(r⋀p)⟶q

⟶ means q is true when r and p are true.

C) correct symbol is ~r ⟶ ~q

Since both statements are negation of the question. And also, if ~r is true then ~q is also true.

D) Similar to answer A to C above, applying similar conditions, we have (~p ⋀r) ⟶q

Answer:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]

[tex]P(x < 70) = 0.225[/tex]

Step-by-step explanation:

Given

[tex]Lower = 30[/tex]

[tex]Width = 10[/tex]

Solving (a): The relative frequency table

First, we construct the frequency table using the given parameters.

[tex]\begin{array}{cc}{Class} & {Frequency} &{30-39} & {1} & {40-49} & {1} & {50 - 59} & {2} & {60 - 69} & {5} & {70 - 79} & {13} & {80 - 89} & {10} & {90 - 99} & {8} & {Total} & {40}\ \end{array}[/tex]

The relative frequency (RF) is calculated as:

[tex]RF = \frac{Frequency}{Total}[/tex]

Using the above formula to calculate the relative frequency, the relative frequency table is:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {Relative\ Frequency} &{30-39} & {1} & {0.025} & {40-49} & {1} & {0.025} & {50 - 59} & {2} & {0.050} & {60 - 69} & {5} & {0.125} & {70 - 79} & {13} & {0.325} & {80 - 89} & {10} & {0.250} & {90 - 99} & {8} & {0.200} &{Total} & {40} & {1}\ \end{array}[/tex]

Solving (b): [tex]P(x < 70)[/tex]

To do this, we add up the relative frequencies of classes less than 70.

i.e.

[tex]P(x < 70) = [30 - 39] + [40 - 49] + [50 - 59] + [60 - 69][/tex]

So, we have:

[tex]P(x < 70) = 0.025 + 0.025 + 0.050 + 0.125[/tex]

[tex]P(x < 70) = 0.225[/tex]