if you start with .235 g nickel, tell me how much of the compound product will be produced.
Please show work

Answers

Answer 1

Answer:

Explanation:

There are many compounds that are produced from Nickel.

Molar mass of Ni = 58.7g

So for 0.235g Ni, there are 0.004M.

By conservation of mass, the compound produced will contain 0.04M of Ni.

Answer 2

Molar mass of nickel=58g/mol

Given mass=0.235g

[tex]\\ \sf\longmapsto No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}[/tex]

[tex]\\ \sf\longmapsto \dfrac{0.235}{58}[/tex]

[tex]\\ \sf\longmapsto 0.004mol[/tex]

Using law of conservation of mass the compound will contain 0.04moles of Ni


Related Questions

Can you help ASAP? Thanks you.

Answers

Answer:

ok

Explanation:

Ok I can tutor you if you’d like

Given the balanced reaction: Zn + 2HCl → H2 + ZnCl2
If 5 grams of each reactant are available for the reaction and HCl is known
to be the limiting reactant, which of the following is correct?
O Both reactants will be completely used up.
O There will be excess of both reactants remaining.
O HCl will be completely used up while Zn will remain in excess.
O Zn will be completely used up while HCl will remain in excess.

Answers

Answer:

O HCl will be completely used up while Zn will remain in excess.

Explanation:

Zn + 2HCl → H₂ + ZnCl₂

In reactions involving two reactants, if one of them is the limiting reactant then the other one has to be the reactant in excess.

Meaning that in this case, the reaction will proceed until HCl is completely used up, and a certain amount of Zn will remain (thus being the reactant in excess).

what climate zone is asia?

Answers

Answer:

The Tundra Climate

Explanation:

:) hope this helps

The answer is As the aggregate result of those various meteorological patterns, the following types of climate may be distinguished in Asia: the tundra climate (associated with the cold, treeless plains of the Arctic lowlands of Asia); the cold, sharply continental climate of eastern Siberia; the cold, moderately humid western

Name the following ketone:

Answers

There is no picture or anything

The element tin has the following number of electrons per shell: 2, 8, 18, 18, 4. Notice that the number of electrons in the outer shell of a tin atom is the same as that for a carbon atom. Therefore, what must be true of tin

Answers

The question is incomplete, the complete question is:

The element tin has the following number of electrons per shell: 2.8. 18, 18, 4. Notice that the number of electrons in the outer shell of a tin atom is the same as that for a carbon atom. Therefore, what must be true of tin? Tin is a polar atom and can bind to other polar atoms. Tin has a high molecular weight to give tin-containing molecules greater stabilty. All of the above Tin conform single covalent bonds with other elements, but not double or triple covalent bonds Tincan bind to up to four elements at a time

Answer:

Tin can bind to up to four elements at a time

Explanation:

Certain important points were made in the question about tin and one of them is that tin is an element in the same group as carbon hence it has the same number of valence electrons as carbon.

Carbon is always tetra valent. The tetra valency of carbon is the idea that carbon forms four bonds.

If tin has the same number of valence electrons as carbon, then, tin can bind to up to four elements at a time

An elementary step is defined as a chemical collision in a reaction mechanism. A collection of different types of collisions makes up the reaction mechanism, so elementary steps provide a molecular view of the overall reaction.

a. True
b. False

Answers

The answer is A. True
A. True is your answer hope this helps

Increasing the temperature of a particular liquid from 298 K to 318 K causes its vapor pressure to double. What is the enthalpy of vaporization of this liquid

Answers

Answer:

27.3 kJ/mol

Explanation:

Step 1: Given data

Temperature 1 (T₁): 298 KVapor pressure 1 (P₁): P₁Temperature 2 (T₂): 318 KVapor pressure 2 (P₂): 2 P₁

Step 2: Calculate the enthalpy of vaporization of this liquid

We will use the Clausius–Clapeyron equation.

ln (P₂/P₁) = -ΔHvap/R × (1/T₂ - 1/T₁)

ln 2 = -ΔHvap/(8.314 J/K.mol) × (1/318 K - 1/298 K)

ΔHvap = 2.73 × 10⁴ J/mol = 27.3 kJ/mol

At 258C, Kp 5 2.9 3 1023 for the reactionNH4OCONH21s2m 2NH31 g21 CO21 g2In an experiment carried out at 258C, a certain amount of NH4OCONH2 is placed in an evacuated rigid container and allowed to come to equilibrium. Calculate the total pressure in the container at equilibrium.

Answers

Answer:

0.27 atm

Explanation:

At 25ºC, Kp = 2.9 x 10⁻³ for the reaction NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g). In an experiment carried out at 25ºC, a certain amount of NH₄OCONH₂ is placed in an evacuated rigid container and allowed to come to equilibrium. Calculate the total pressure in the container at equilibrium.

Step 1: Make an ICE chart

Solid and liquids are ignored in ICE charts.

       NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g)

I                                            0             0

C                                        +2x           +x

E                                          2x             x

Step 2: Write the pressure equilibrium constant expression (Kp)

Kp = [NH₃]² × [CO₂]

Kp = (2x)² × x

2.9 × 10⁻³ = 4 x³

x = 0.090 atm

Step 3: Calculate the pressures at equilbrium

pNH₃ = 2x = 2(0.090 atm) = 0.18 atm

pCO₂ = x = 0.090 atm

The total pressure is:

P = 0.18 atm + 0.090 atm = 0.27 atm

Francine makes several measurements of the mass of a metal block. The data set is shown in the table below.

Measurement
Mass of metal block (g)
1
20.73
2
20.76
3
20.68
4
20.75

After analyzing this data set, Francine calculates a value of 20.73 g.

Which of these characteristics has been calculated?
mean
median
mode
range

Answers

Answer:

Mean

Explanation:

The mean of a series of measurements is calculated when all the measurements are added up and then divided by the number of measurements taken, as follows:

Sum of Measurements = 20.73 + 20.76 + 20.68 + 20.75 = 82.92

As there are 4 measurements, the mean is:

Mean = 82.92 / 4 = 20.73

Answer:

A

Explanation:


Which is the correct Lewis structure for carbononitridic chloride (CNCl)?

Answers

Answer:

A.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to figure out the correct Lewis dot structure, by realizing chlorine has seven valence electrons, carbon has four of them and nitrogen five, it means that C and Cl form a single a bond and C and N form a triple bond for allowing the three of them to complete the octet; it means Cl remains with three lone pairs, N with one lone pair and C with no lone pairs; therefore, the answer is A.

Regards!

1,500 grams is equal to:
1.5 kg
1.5L
1.5 cm
all of the above

Answers

1kg is 1,000 grams plus .5 is 1.5 kg

A rod “X”, has a positive charge of 5. An otherwise identical rod, “Y”, has a negative charge of 12.
The rods are touched together and then separated.
a) When they touched, what particles moved between them?
b) Did the particles move from “X” to “Y” or from “Y” to “X”.

Answers

Answer:

a) electrons

b) from Y to X

Explanation:

positive protons are the cores of atoms in relative to electrons very, very heavy.

the outer electrons of atoms can move, under certain conditions, away from the atom, leaving it electrically unbalanced -> positively charged

there can also be a surplus of electrons on many surfaces, leading to a static negative charge. you know this when you are charged and you discharge with an object or another person, electrically balancing the two bodies charge.

electrons are also much smaller. they are the "things" to move, let it be trough the air or trough a wire, while the heavy protons will stay in place (unless the materials is melted of course, extreme heat brakes the bounds between atoms relatively well)

If 0.5 L of O2(g) reacts with H, to produce 1 L of H2O(g), what is the volume of
H2O(g) obtained from 1 L of O2(g)?
-
0.5 L
2.5 L
2 L
1.5 L

Answers

Answer:

2 L

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2H₂ + O₂ —> 2H₂O

From the balanced equation above, we can see clearly that 1 L of O₂ reacted to 2 L of H₂O.

This implies that 2 L of H₂O can be obtained by the reaction of 1 L of O₂.

Thus, option 3 gives the correct answer to the question.

Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The half-life of phosphorus-32 is 14.3 days. What mass of phosphorus-32 is left from an original sample of 175 mg of Na332PO4 after 35.0 days

Answers

Answer: The mass of P-32 left from the original sample is 32.07 mg

Explanation:

All radioactive decay processes follow first-order reactions.

Calculating rate constant for first order reaction using half life:

[tex]t_{1/2}=\frac{0.693}{k}[/tex] .....(1)

[tex]t_{1/2}[/tex] = half life period = 14.3 days

k = rate constant = ?

Putting values in equation 1:

[tex]k=\frac{0.693}{14.3days}\\\\k=0.0485days^{-1}[/tex]

The integrated rate law equation for first-order kinetics:

[tex]k=\frac{2.303}{t}\log \frac{a}{a-x}[/tex] ......(2)

Given values:

a = initial concentration of reactant = 175 mg

a - x = concentration of reactant left after time 't' = ? mg

t = time period = 35.0 days

Putting values in equation 2:

[tex]0.0485days^{-1}=\frac{2.303}{35.0 days}\log (\frac{175}{a-x})\\\\\log (\frac{175}{a-x})=\frac{0.0485\times 35.0}{2.303}\\\\\log (\frac{175}{a-x})=0.737\\\\\frac{175}{a-x}=10^{0.737}\\\\a-x=\frac{175}{5.457}=32.07mg[/tex]

Hence, the mass of P-32 left from the original sample is 32.07 mg

If the initial amount of indium-117 is 5.2 g, how much indium-117 is left in the body after 86 min

Answers

i need to go home and play on the game

The degree of ionization of a weak acid ________ I. varies with the concentration of the acid. II. depends on which weak acid it is. III. is 100%. IV. is greater than 50% but less than 100%.

Answers

Answer: The degree of ionization of a weak acid is greater than 50% but less than 100%.

Explanation:

An acid which dissociates partially or weakly when dissolved in water is called a weak acid.

For example, acetic acid [tex](CH_{3}COOH)[/tex] is a weak acid.

Hence, the degree of ionization of a weak acid is greater than 50% but less than 100%.

Thus, we can conclude that the degree of ionization of a weak acid is greater than 50% but less than 100%.

the density of gold is 19.3 g/ml. if you had a cube made of pure gold that weighs 58.1 pounds what would be the lengh of a side of this cube

Answers

Answer:

11.1 cm

Explanation:

First we convert 58.1 pounds into grams:

58.1 lb * [tex]\frac{453.592g}{1lb}[/tex] = 26353.69 g

Then we calculate the volume of the gold cube, using the given density:

26353.69 g ÷ 19.3 g/mL = 1365.48 mL

1365.48 mL is equal to 1365.48 cm³.

With the volume of a cube we can calculate the side length:

Length = ∛(1365.48 cm³) = 11.1 cm

a solution that contains a large amount of solute would be described as what

Answers

Answer:

A concentrated solution is one that has a relatively large amount of dissolved solute. A dilute solution is one that has a relatively small amount of dissolved solute.

5
The
(1 Point)
can change when describing motion. It is just the chosen starting point.
displacement
distance
reference point
speed

Answers

The correct answer is Reference Point

What is reduction potential?​

Answers

a measure of the tendency of a chemical species to acquire electrons from or lose electrons to an electrode and thereby be reduced or oxidised respectively. Redox potential is measured in volts

In which of the following molecules is hydrogen bonding likely to be the most significant component of the total intermolecular forces??

a. C6H13NH2
b. CH3OH
c. CH4
d. C5H11OH
e. CO2

Answers

Answer:

The given molecules are:

a. C6H13NH2

b. CH3OH

c. CH4

d. C5H11OH

e. CO2

Explanation:

The hydrogen bond is a weak electrostatic force of attarction that exists between covalently bonded hydrogen (of -OH or -NH2 or HF) with a highly electronegative atom like N,O and F.

Hydrogen bonding is of two types:

Intermolecular hydrogen bond (exists between two molecules)

Intramolecular hydrogen bond(exists within a molecule).

For example intermolecular hydrogen bond in water is shown below:

Among the given options,

a. C6H13NH2 has -NH2 linkage which leads to hydrogen bond formation.

b. CH3OH has -OH bond and it leads to hydrogen bond fomation.

d. C5H11OH has also -OH bond and it leads to hydrogen bond fomation.

Reamining molecules, CH4 and CO2 do not form hydrogen bond.

Hence, answer is:

options a,b,d.

A solid cylinder having a diameter of 1.50 cm and a height of 5.15 cm has a mass of 95.56 g. Show the equations needed to calculate the density of a solid.

Answers

Answer:

you can solve the rest of the equation. I only reduced it to that much to show you how to derive it

The density of the solid cylinder given the data from the question is 10.5 g/cm³

What is density?

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

How to determine the volume of the cylinderDiameter = 1.50 cm Radius (r) = Diameter / 2 = 1.5 / 2 = 0.75 cmPi (π) = 3.14Height (h) = 5.15 cmVolume (V) = ?

V = πr²h

V = 31.4 × 0.75² × 5.15

V = 9.1 cm³

How to determine the density

Mass = 95.56 gVolume = 9.1 cm³Density =?

Density = mass / volume

Density = 95.56 / 9.1

Density = 10.5 g/cm³

Learn more about density:

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Question 13 of 32

The pH of a sample of seawater is 8.0. What is the hydrogen ion concentration of seawater?

A. 8.0 M
B. 1 x 108 M
C. 6.0 M
D. 1 x 10-8 M​

Answers

Answer:

D

Explanation:

Mark Brainliest please

Answer is D

Explanation

We know that pH=−log[H^+]

pH=8

Thus, 8= −log[H^+]

Hence [H+]=10^−8

Thus, concentration of H^+ is 10^−8M

The limiting reactant in a chemical reaction is the reactant __________ Select one: A. for which you have the lowest mass in grams. B. which has the lowest coefficient in the balanced equation. C. which has the lowest molar mass. D. which is left over after the reaction has gone to completion. E. None of the above.

Answers

Answer:

i think its A

When Justin added deionized water to the volumetric flask, he accidentally filled the flask so that the water level was slightly above the mark. He still assumed that the flask was holding 100.0 mL when he calculated the density of the solution, however. How will this procedural error affect his calculated density value

Answers

Answer:

The actual value of density will be less than the calculated value of density

Explanation:

Density is defined as mass per unit volume. This means that the value of the density of the substance depends on both its mass and its volume.

Since the volume of the water used in the experiment is greater than the required 100mL yet a volume of 100mL was used in the calculation, the actual density of the substance is less than the calculated value of density.

Which pair of compounds has the same empirical formula?
1.
C2H2 and C6H6
2
C2H6 and C3H8
3.
CH3OH and C2H5OH
4.
CH3CHO and CH3COOH

Answers

Explanation:

Correct option is

B

CH

3

COOH

Empirical formula of Glucose C

6

H

12

O

6

= C

1

H

2

O

1

Now, Empirical formula of CH

3

COOH=C

1

H

2

O

1

As empirical formula is the simplest whole number ratio of number of different types of atoms present in the given molecular formula.

Answer : B

Explanation:

To make a 0.500 M solution, one could take 0.500 moles of solute and add Group of answer choices enough solvent to make 1.00 kg of solution. enough solvent to make 1.00 L of solution. 1.00 L of solvent. 1.00 kg of solvent.

Answers

Answer: The correct option is enough solvent to make 1.00 L of solution

Explanation:

A solution consists of solute and solvent. A solute is defined as the component present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

[tex]Molarity=\frac{Moles}{Volume}[/tex] .......(1)

We are given:

Molarity of solution = 0.500 M

Moles of solute = 0.500 moles

Putting values in equation 1, we get:

[tex]0.500mol/L=\frac{0.500mol}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.500mol}{0.500mol/L}=1.00L[/tex]

Hence, the correct option is enough solvent to make 1.00 L of solution

if the radius of a potassium atom is 2.27 x 10-7 mm what is the radius in μm

Answers

Explanation:

the answer is in the Image above

The radius of the potassium atom is [tex]2.27\times 10^{-4} \mu m[/tex].

Explanation:

Given:

The radius of potassium atom =[tex]2.27\times 10^{-7} mm[/tex]

To find:

The radius of potassium atom in micrometers.

Solution:

The radius of potassium atom =[tex]2.27\times 10^{-7} mm[/tex]

In 1 millimeter there are 1000 micrometers.

[tex]1 mm = 1000 \mu m[/tex]

Then in [tex]2.27\times 10^{-7} mm[/tex]:

[tex]=2.27\times 10^{-7} \times 1000\\=2.27\times 10^{-4} \mu m[/tex]

The radius of the potassium atom is [tex]2.27\times 10^{-4} \mu m[/tex].

Learn more about conversions here:

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1.20 × 104) × (2.152 × 102) = × 10^6 203/5.3=

Answers

I hoped that helped by the way I went on https://doyourmath.com/web-algebrator/#c=solve&v1=1.2%255C%2520x%255C%2520104%255C%2520x%255C%25202.152%255C%2520x%255C%2520102%253D10%255E%257B6%255C%2520%257D%255Cleft%2528%255Cfrac%257B203%257D%257B5.3%257D%255Cright%2529%255Cnl%2520&v2=solve&v3=x To get the answer.

A chemist must prepare 900.0 mL of potassium hydroxide solution with a pH of 12.20 at 25°C.
He will do this in three steps:
• Fill a 900.0 mL volumetric flask about halfway with distilled water.
• Weigh out a small amount of solid potassium hydroxide and add it to the flask.
. Fill the flask to the mark with distilled water.
Calculate the mass of potassium hydroxide that the chemist must weigh out in the second step. Round your answer to 2 significant digits and put your answer in grams (g).

Answers

Answer:

0.80 g

Explanation:

First we calculate the required pOH from the given pH value:

pOH = 14 - pHpOH = 14 - 12.20 = 1.80

Then we calculate the required concentration of OH⁻, using the pOH:

pOH = -log[OH⁻][OH⁻] = [tex]10^{-1.80}[/tex] = 0.0158 M

As the concentration of OH⁻ species is the sames as the concentration of KOH, we need to prepare 900 mL of a 0.0158 M KOH solution:

We calculate how many KOH moles are required, using the concentration and volume:

Converting 900 mL ⇒ 900 / 1000 = 0.900 Lmoles = 0.0158 M * 0.900 L = 0.01422 mol

Finally we convert 0.01422 moles of KOH to grams, using its molar mass:

0.01422 mol * 56 g/mol = 0.80 g
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