By using the concept of differential equation, it can be calculated that
[tex]\\\begin{bmatrix} 3c_1e^{2t} +c_2e^{-5t} \\2c_1e^{2t} +3c_2e^{-5t} \end{bmatrix}[/tex] is the general solution
What is a differential equation?
A differential equation is an equation consisting of one or more unknown variables and their derivative.
This is a problem on differential equation
[tex]x^{'} = \begin{bmatrix} 4 & -3 \\ 6 & -7\end{bmatrix}x[/tex], [tex]x_1 = \begin{bmatrix} 3e^{2t} \\ 2e^{2t} \end{bmatrix}[/tex], [tex]x_2 = \begin{bmatrix} e^{-5t}\\3e^{-5t}\end{bmatrix}[/tex]
To show [tex]x_1 = \begin{bmatrix} 3e^{2t} \\ 2e^{2t} \end{bmatrix}[/tex] is a solution of [tex]x^{'} = \begin{bmatrix} 4 & -3 \\ 6 & -7\end{bmatrix}x[/tex]
[tex]x_1 = \begin{bmatrix} 3e^{2t} \\ 2e^{2t} \end{bmatrix}\\\\x_1^{'} = \begin{bmatrix} \frac{d}{dt}(3e^{2t}) \\ \frac{d}{dt}(2e^{2t})\end{bmatrix}\\\\x_1^{'} = \begin{bmatrix} 6e^{2t} \\ 4e^{2t}\end{bmatrix}\\\\ \begin{bmatrix} 4 & -3\\6 &-7\end{bmatrix}\begin{bmatrix} 3e^{2t} \\ 2e^{2t} \end{bmatrix} \\\\\begin{bmatrix} 12e^{2t}-6e^{2t} \\ 18e^{2t}-4e^{2t}\end{bmatrix}\\\\ = \begin{bmatrix} 6e^{2t} \\ 4e^{2t}\end{bmatrix}[/tex]
So, [tex]x_1 = \begin{bmatrix} 3e^{2t} \\ 2e^{2t} \end{bmatrix}[/tex] is a solution of [tex]x^{'} = \begin{bmatrix} 4 & -3 \\ 6 & -7\end{bmatrix}x[/tex]
To show [tex]x_2 = \begin{bmatrix} e^{-5t} \\ 3e^{-5t} \end{bmatrix}[/tex] is a solution of [tex]x^{'} = \begin{bmatrix} 4 & -3 \\ 6 & -7\end{bmatrix}x[/tex]
[tex]x_2 = \begin{bmatrix} e^{-5t} \\ 3e^{-5t} \end{bmatrix}\\\\x_2^{'} = \begin{bmatrix} \frac{d}{dt}(e^{-5t}) \\ \frac{d}{dt}(3e^{-5t})\end{bmatrix}\\\\x_1^{'} = \begin{bmatrix} -5e^{-5t} \\ -15e^{-5t}\end{bmatrix}\\\\ \begin{bmatrix} 4 & -3\\6 &-7\end{bmatrix}\begin{bmatrix} e^{-5t} \\ 3e^{-5t} \end{bmatrix} \\\\\begin{bmatrix} 4e^{-5t}-9e^{-5t} \\ 6e^{-5t}-21e^{-5t}\end{bmatrix}\\\\ = \begin{bmatrix} -5e^{-5t} \\ -15e^{-5t}\end{bmatrix}[/tex]
So, [tex]x_2 = \begin{bmatrix} e^{-5t} \\ 3e^{-5t} \end{bmatrix}[/tex] is a solution of [tex]x^{'} = \begin{bmatrix} 4 & -3 \\ 6 & -7\end{bmatrix}x[/tex]
W=
[tex]\begin{vmatrix} 3e^{2t} & e^{-5t} \\ 2e^{2t} & 3e^{-5t} \end{vmatrix}\\=9e^{-10t} - 2e^{-10t}\\=7e^{-10t}\\\neq 0[/tex]
[tex]x_1[/tex] and [tex]x_2[/tex] are linearly independent
The general solution is
[tex]c_1x_1+c_2x_2\\c_1\begin{bmatrix} 3e^{2t} \\ 2e^{2t} \end{bmatrix} +c_2\begin{bmatrix} e^{-5t} \\ 3e^{-5t} \end{bmatrix}\\\begin{bmatrix} 3c_1e^{2t} +c_2e^{-5t} \\2c_1e^{2t} +3c_2e^{-5t} \end{bmatrix}[/tex]
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Complete Question
The differential equation has been attached below
An animal shelter has cats and dogs available for adoption in a ratio of 3:5. If there are 25 dogs available for adoption, how many cats are available? Use a tape diagram to help organize your thinking. (1 point)
cats
Answer:
15 cats
Step-by-step explanation:
c:d
3:5
5=25
25/5=5
5*3=15
15 cats
======================================================
Explanation:
The tape diagram is shown below.
"C" represents a sub-group of cats, and "D" represents a sub-group of dogs. Each sub-group has the same number of animals.
There are 3 copies of "C" and 5 copies of "D" to represent the ratio 3:5 of cats to dogs. For every 3 cats, there are 5 dogs.
We are told there are 25 dogs available for adoption. This consists of all five blocks of "D" combined. If each "D" is the same number of dogs, then there must be 25/5 = 5 dogs per "D" block. By extension, there are 5 cats per "C" block.
In short, each block has 5 animals.
3 blocks of C = 3*5 = 15 cats are available.
-----------------
Another approach:
C = number of cats available = unknown
D = number of dogs available = 25
C/D = 3/5
C/25 = 3/5
5C = 25*3 ... cross multiply
5C = 75
C = 75/5
C = 15 cats are available
-----------------
A third approach:
The ratio 3:5 scales up to 15:25 after multiplying both parts by 5. This is so the "5" in "3:5" becomes "25".
The ratio of cats to dogs of 15:25 reduces to 3:5 when you divide both parts by the GCF 5.
So this is another way to see how 15 cats are available.
Which of the following points lie on the line y = 2x - 3? (2, 3) (-2, -1) (4, 1) (0, -3)
Answer:(0,-3)
Step-by-step explanation:
Answer:
(0,-3)
Step-by-step explanation:
just fill in the coordinates to see if it’s true
3=2(2)-3
3=4-3
3-1
Not true
-1=2(-2)-3
-1=-4-3
-1=-7
Not true
1=2(4)-3
1=8-3
1=5
Not true
-3=2(0)-3
-3=0-3
-3=-3
True
Hopes this helps please mark brainliest
Solve it please I need this asap!
The angles ∠BCD and ∠BAD are opposite interior angles of a parallelogram. in which the alternate interior angles ∠BAC and ∠ACD and ∠BCA and ∠DAC are congruent, from which by angle addition property, ∠BCD ≅ ∠BAD
What are alternate interior angles?Alternate interior angles are angles formed by the transversal to two parallel lines on the inside of the parallel lines, and on opposite sides of the transversal.
The two column-method used to prove that ∠BCA is congruent to ∠DAC can be presented as follows;
Step [tex]{}[/tex] Statement Reason
1. [tex]\overline{BC}[/tex]║ [tex]\overline{AD}[/tex], [tex]\overline{AB}[/tex]║[tex]\overline{CD}[/tex] [tex]{}[/tex] Given
2. [tex]{}[/tex] ∠BCA ≅ ∠DAC ║ lines cut by a trans. form ≅ int. ∠s
3. [tex]{}[/tex] [tex]\overline{AC}[/tex]║[tex]\overline{CA}[/tex] [tex]{}[/tex] Reflexive Property
4. ∠BAC ≅ ∠ACD [tex]{}[/tex] Alternate interion angles
5. ∠BCA = ∠DAC[tex]{}[/tex] Definition of congruency
[tex]{}[/tex] ∠BAC = ∠ACD
6. ∠BCD = ∠BCA + ∠ACD[tex]{}[/tex] Angle addition property
∠BAD = ∠BAC + ∠DAC
7. ∠BCD = ∠BCA + ∠ACD [tex]{}[/tex] Substitution property
8. [tex]{}[/tex] ∠BCD = ∠BAD [tex]{}[/tex] Substitution property
9. ∠BCD ≅ ∠BAD [tex]{}[/tex] Definition of congruency
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Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant speed to get to the safe zone that was 160 meters away. After 3 seconds of driving, she was 85 meters away from the safe zone.
Let y represent the distance (in meters) from the safe zone after x seconds.
Complete the equation for the relationship between the distance and number of seconds.
y=, equals
If Kayden is a stunt driver and one time, during a gig where she escaped from a building about to explode . the equation for the relationship between the distance and number of seconds is : D(t) = -25t + 160.
How to find the distance equation?First step is to find kayden speed using this formula
Speed = Distance/Time
Speed = 85-160/3
Speed = -75/3
Speed = -25t
Hence, the equation for the relationship between the distance and number of seconds is
D(t) = -25t + 160
Therefore we can conclude that the equation is D(t) = -25t + 160.
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Margret has $32.00 in a savings account. Margret wants to have a balance of $40.00 in the account. How much money does Margret need to deposit to reach this amount?
The amount of money that Margret needs to deposit to reach this amount is $8.
What is an expression?Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both. Addition, subtraction, multiplication, and division are all possible mathematical operations.
Since Margret has $32.00 in a savings account. Margret wants to have a balance of $40.00 in the account, the amount needed will be:
= $40 - $32
= $8
She'll need $8 more.
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Pls help quick from hegarty maths
The mean lifetime of a bulb is 149.37 hours.
What is the meaning of mean?
By dividing the sum of the given numbers by the entire number of numbers, the mean—the average of the given numbers—is determined. Mean is equal to (Sum of All Observations/Total Observations).
The given table represents a continuous data.
The table attached in below. To get mean lifetime of a bulb, find the mean of the given table.
The formula for mean is = Σ fm/N
Where f is frequency and m is midpoint of the class.
N is total number of observation.
From the table, Σ fm = 53175
Total number of bulb is 356.
The mean lifetime is 53175/ 356 = 149.37 hours
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The surface area of the figure shown is 192 cm².
What is the value of x?
8 cm
6 cm
10 cm
X cm
The value of x = 6cm.
What is surface area?
The area is the area occupied by a two-dimensional flat surface. It has a square unit of measurement. The surface area of a three-dimensional object refers to the space occupied by its outer surface.
From the given figure,
Surface area(A) = [tex]192cm^{2}[/tex]
Height = 8cm
a base side = 6 cm
b base side = 10 cm
c base side = x cm
Therefore, TSA= 2B +Px = [tex]2 \times\frac{1}{2} \times8\times6 +(6+10+8)x[/tex]
=48+24x
Thus, 60+24x=192
[tex]x=\frac{192-48}{24}[/tex]
x= 6cm
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1. A painting crew bought 45 gallons of paint for a job. The crew members used 5 gallons of paint per hour until they used all the paint. Sketch a graph to represent the start to the end of the job, assuming all paint was used. Be sure to title your graph, label your axes, and label your intercepts. This must be graphed by hand or by using the tools in Word. You may not use a web-based graphing program.
The graph that shows the equation, y = -5x + 45, that represents the scenario given is shown in the attachment.
How to Graph a Linear Equation?Determine the slope (m) and the y-intercept (b), then input the values in the equation, y = mx + b, to write the equation of the line that would be graphed.
Given the information above, we have the following:
Let x = hours, and y = quantity of gallons of paint left
Slope (m) = -5
Y-intercept (b) = 45
Write the equation of the graph by substituting m = 5 and b = 45 into y = mx + b:
y = -5x + 45
The graph shown below for y = 5x + 45 would be labelled as follows:
x-axis = hours
y-axis = quantity of paint (in gallons)
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Lines l and m are parallel and intersect transversal p as shown in the diagram below
What is the value of n?
Answer: a
Step-by-step explanation:
The value of n from the given parallel lines is 6. Therefore, the option A is the correct answer.
What are angles of parallel lines?Angles in parallel lines are angles that are created when two parallel lines are intersected by another line called a transversal.
Given that, the angles from the parallel lines are (3n+16)° and (5n+4)°.
Here, (3n+16)°=(5n+4)° (Interior alternate angles are equal)
5n-3n=16-4
2n=12
n=6
Therefore, the option A is the correct answer.
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Unless specified, all approximating rectangles are assumed to have the same width. Evaluate the upper and lower sums for f(x) = 1 + cos cos($) -ISXS*, with n = 3, 4, and 6. Illustrate each case with a sketch similar to the figure shown below. (Round your answers to two decimal places.) n = 3: upper sum ll lower sum n = 4: upper sum II lower sum n = 6: upper sum IO lower sum
In this Trigonometric Functions F(x) = 1 + cos(1/X): n=3 (12.01, 8.10), n=4 (11.65,8.50), and n=6 (11.24, 9.12), with their upper and lower value
What is Trigonometric Functions?
Trigonometry uses six fundamental trigonometric operations. Trigonometric ratios describe these operations. The sine function, cosine function, secant function, co-secant function, tangent function, and co-tangent function are the six fundamental trigonometric functions. The ratio of sides of a right-angled triangle is the basis for trigonometric functions and identities. Using trigonometric formulas, the sine, cosine, tangent, secant, and cotangent values are calculated for the perpendicular side, hypotenuse, and base of a right triangle.
F(x) = 1 + cos(1/X)
for n=3
Upper sum = 12.01
Lower sum = 8.10
Δx = (b-a)/n = 2π / 3
for n=4
Upper sum = 11.65
Lower sum = 8.50
Δx = (b-a)/n = π / 2
for n=6
Upper sum = 11.24
Lower sum = 9.12
Δx = (b-a)/n = π / 3
Hence, n=3 (12.01, 8.10), n=4 (11.65,8.50), and n=6 (11.24, 9.12), with their upper and lower value.
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Assume that 40% of students at SCC receive A or B’s, 35% receive C’s, and 25% receive
D or F’s. A survey of 300 r/s UC Davis students indicates that 100 of them received A or
B’s, 130 received C’s, and 70 received D or F’s. Do these results provide strong evidence
that the overall percentages of the 3 grade categories at UC Davis are not all the same as
the ones at SCC? Perform a hypothesis test and use a p-value to draw and explain your
conclusion
We have sufficient evidence to conclude that the over all percentages of 3 categories are not same.
What is meant by percentage?The percentage refers to a specific percentage out of a hundred. It is a fraction with the denominator 100, and the sign for it is 1%.
The Latin word per centum, which means "hundred" or "by the hundred," is the source of the word "percent." The Italian phrase per cento, which means "for a hundred," gradually shrank to become the symbol for "percent," which is now used globally. It finally vanished totally. The word "per" was frequently shortened to "p." The contemporary "%" symbol was created by condensing the "cento" to two circles divided by a horizontal line.
Category Observed([tex]O_{i}[/tex]) Expected([tex]E_{i}[/tex]) ([tex]O_{i}[/tex]-[tex]E_{i}[/tex])²/[tex]E_{i}[/tex]
A or B 100 120 3.333
C 130 105 5.9524
D or F 70 75 0.056
Total 300 300 9.3417
H₀:over percentages are same at UC Davis and at SSC
H₁:They are not same
Test statistic
X²=∑ ([tex]O_{i}[/tex]-[tex]E_{i}[/tex])²/[tex]E_{i}[/tex]
=9.3417
P-value=P(X²(n-1)>9.3417)
=0.0094
Here we can see that the P-value is very low(<0.05 and <0.01)
So, we reject the null hypothesis H₀.
Therefore, we have sufficient evidence to conclude that the over all percentages of 3 categories are not same.
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Jamie is measuring the growth of a bean plant in her garden. On the first day, the plant is 2. 5 inches tall. On the fourth on the ninth day, it is 14. 5 inches tall. What will be the height of Jamie’s plant in the twenty-first day if it continues to
The height of Jamie's plant on the twenty-first day is 82.5 feet.
Here we have to find the height of Jamie's plant on the twenty-first day.
Data given:
First-day increase in the plant = 2.5 inches
On the fourth day increase in the plant = 14.5 inches
We can find the slope of the line:
m = (y2 - y1) / ( x2 - x1)
= (14.5 - 2.5) / (4 - 1)
= 12/3
= 4
Now we will find the equation of a line:
(y - y1) = m( x - x1)
( y - 2.5) = 4( x - 1)
y - 2.5 = 4x - 4
y = 4x - 1.5
Now substitute x = 21 in our equation.
y = 4(21) - 1.5
y = 84 - 1.5
= 82.5
Therefore we get the height of the plant as 82.5 feet.
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G-2/2-24 simplify the variable
On simplifying for variable, we get -
G = - 20
What is a expression? What is a mathematical equation? What is Equation Modelling?A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
We have the following equation -
(G-2)/(2-24) = 0
We have -
(G-2)/(2-24) = 0
G - 2 = 2 - 24
G - 2 = - 22
G = - 22 + 2
G = - 20
Therefore, on simplifying for variable, we get -
G = - 20
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and D are noncoplanar. △ABC,△ABC,△ACD, and △ABD are equilateral. X and Y are midpoints of AC¯¯¯¯¯¯¯¯ and and AD.Z is a point on AB¯¯¯¯¯¯¯¯. What kind of triangle is △XYZ? Explain.
ΔXYZ will also be an equilateral triangle.
What is equilateral triangle?
An equilateral triangle in geometry is a triangle with equal-length sides on all three sides. In the well-known Euclidean space, an equilateral triangle also is equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others. It's also referred to it as a regular triangle because it is a regular polygon.
As X,Y,Z are the midpoints of sides of equilateral triangle so when we will join the X,Y,Z we will find that distances XY=YZ=XZ are three are equal because this is proved by similarity of triangles which in itself is a detailed and vast topic
Hence XYZ will also be an equilateral triangle
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what is a line with a slope of 4 and passes through (2,4)
Answer: y = 4x - 4
Step-by-step explanation:
We already have our slope, which is 4
(x , y) (2, 4) -> 2 is x, 4 is y
Substitute y = mx + b with the right numbers
4 = 4(2) + b
Solve
4 = 8 + b
Subtract 8 on both sides
-4 = b
Then put it in slope-intercept form
y = 4x - 4
14. Triangle DEF and angle measurements are shown. Write and
solve an equation to find the value of h.
Answer:
[tex]\huge\boxed{\sf h = 24}[/tex]
Step-by-step explanation:
Statement:Interior angles of a triangle add up to 180 degrees.So,
2h + 8 + 3h - 3 + 31 + h = 180
Combine like terms
2h + 3h + h + 8 - 3 + 31 = 180
6h + 36 = 180
Subtract 36 to both sides
6h = 180 - 36
6h = 144
Divide 6 to both sides
h = 144/6
h = 24[tex]\rule[225]{225}{2}[/tex]
Solve and Graph.
[tex]\tt |4x+1|\:\le 6[/tex]
The value of x from the inequality equation | 4x + 1 | ≤ 6 , is
-7/4 ≤ x ≤ 5/4
What is an Inequality Equation?
Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
In an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.
Given data ,
Let the equation be A
The value of the equation A is | 4x + 1 | ≤ 6 be equation (1)
From the modulus function rule , we know
If , | x | ≤ a , then -a ≤ x ≤ a
So , on simplifying the equation , we get
-6 ≤ 4x + 1 ≤ 6
Now , the two values are
4x + 1 ≥ -6 be equation (2)
4x + 1 ≤ 6 be equation (3)
From equation (2) , 4x + 1 ≥ -6
Subtracting 1 on both sides , we get
4x ≥ -7
Divide by 4 , we get
x ≥ -7/4
And , From equation (3) , 4x + 1 ≤ 6
Subtracting 1 on both sides , we get
4x ≤ 5
Divide by 4 on both sides , we get
x ≤ 5/4
Therefore , the solution is -7/4 ≤ x ≤ 5/4 and the graph is given below
Hence , The value of x from the inequality equation | 4x + 1 | ≤ 6 , is
-7/4 ≤ x ≤ 5/4
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Nevaeh is working two summer jobs, making $14 per hour lifeguarding and making $25 per hour tutoring. In a given week, she can work no more than 11 total hours and must earn no less than $200. If x represents the number of hours lifeguarding and y represents the number of hours tutoring, write and solve a system of inequalities graphically and determine one possible solution.
The system of equations are
x + y < 1114x + 25y < 200The solution of the equation from the graph is
x = 6.8181y = 4.1818How to find the system of equationsThe system of equations is derived from the statements as interpreted below
If x represents the number of hours lifeguarding and y represents the number of hours tutoring
number of hours lifeguarding = x
number of hours tutoring = y
she can work no more than 11 total hours
x + y not more than 11 hours
x + y < 11
making $14 per hour lifeguarding and making $25 per hour tutoring and must earn no less than $200
$14x + $25y no less than $200
14x + 25y > 200
The required equations are
14x + 25y > 200
x + y < 11
The graph is attached
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A = 2(x + 3) y B = 3(13 + x)
what does cherry-picking mean in the context of data analytics
Answer:
In simple terms, it basically means to select the important parts of the data and take note of them. It's a very helpful technique.
On the cherry - picking mean in the context of data analytics is confirmation bias. The correct option is (B)
What is cherry picking mean in data analytics?Cherry picking is the selective use of evidence to support a claim while ignoring other data that is more likely to challenge that claim.
here, we have,
It's not always done with malicious purpose, but this behavior is extremely widespread. Probably even you have cherry-picked.
now, we know that,
cherry picking looks like as:
For instance, someone who cherry picks may only mention a few studies out of the many that have been published on a certain topic in an effort to make it appear as though the scientific consensus supports their position.
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review the video to determine whether each statement about the following equation is true or false. dndt
The statemet 2, the variable K represent carrying capacity and the variable N represent population size, is correct.
In the given question we have to review the video to determine whether each statement about the following equation is true or false.
The given equation is:
[tex]\frac{dN}{dt}=rN(\frac{K-N}{K})[/tex]
The given equation is used to find the annual growth of population.
In which, dN/dt = the annual increase for the population,
r = the annual growth rate,
N = the population size, and
K = the carrying capacity.
So the statemet two, the variable K represent carrying capacity and the variable N represent population size, is correct.
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Consider all right circular cylinders for which the sum of the height and circumference is 60 cm. What is the radius of the one with maximum volume?.
By using the concept of maxima, it can be calculated that
Volume is maximum if the radius of the cone is 40 cm
What is maxima of a function?
Maxima of a function gives the maximum value of the function on a certain interval or on the whole domain.
Let the height of the cylinder be h and radius be r
Sum of height and circumference = h + 2πr
By the problem,
h + 2πr = 60
h = 60 -2πr
Volume(V) = π[tex]r^2[/tex] h
= π[tex]r^2[/tex](60 - r)
= 60π[tex]r^2[/tex] - π[tex]r^3[/tex]
[tex]\frac{dV}{dr} = 120\pi r - 3 \pi r^2[/tex]
For maximum volume
[tex]\frac{dV}{dr} = 0[/tex]
[tex]120\pi r - 3 \pi r^2 = 0\\[/tex]
[tex]3 r^2 = 120 r\\3r = 120 [r \neq 0]\\r = \frac{120}{3}\\r = 40 \ cm[/tex]
[tex]\frac{d^2V}{dr^2} = 120 \pi - 6 \pi r\\[/tex]
Putting r = 40
[tex]\frac{d^2V}{dr^2} = 120 \pi - 6 \pi \times 40\\\frac{d^2V}{dr^2} =120\pi - 240 \pi\\\frac{d^2V}{dr^2} = -120\pi < 0[/tex]
Hence Volume is maximum
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a bar chart might be used for
When presenting chunks of information, bar charts should be used. As long as there aren't too many categories to contrast, vertical bar charts can be useful for comparing several discrete or categorical variables, such as age groups, courses, and schools. For time series data, they are also highly beneficial.
Why would one use a bar chart?
To show a frequency distribution for qualitative data, bar charts are frequently employed.
The axis used to measure the bars should always begin at zero, unless there is a valid reason for doing otherwise.
Otherwise, the axis can be stretched to magnify differences in the lengths of the bars. A title and the axis labels are required for bar charts.
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He creates paths through the garden along line segment a b, line segment x y, and line segment z y. Which correctly compares the lengths of the paths?the path along line segment x y is longer than the path along line segment z y, and the path along line segment z y is longer than the path along line segment a b. The path along line segment a b is longer than the path along line segment z y, and the path along line segment z y is longer than the path along line segment x y. The path along line segment z y is longer than the path along line segment x y, and the path along line segment x y is longer than the path along line segment a b. The path along line segment z y is longer than the path along line segment a b, and the path along line segment a b is longer than the path along line segment x y.
The journey along Line segment X Y is longer than the path along Line segment Z Y, and the path along Line segment Z Y is longer than the path along Line segment A B, hence Option-A is the correct answer.
Given that,
He makes paths that follow Line segments A and B, X and Y, and Z and Y through the garden.
We have to find which accurately compares the pathways' lengths.
We know that,
The length of the third side in a triangle is proportional to the angle Ф if the lengths of the two sides that make up the angle Ф are fixed.
XY > YZ because XY's opposing angle (79°) is greater than YZ's (65°).
As before, YZ > AB because the opposing angle of YZ (65°) is greater than that of AB (36°).
Since both sides of the angle are the same length (8 feet),
As a result, assertion A. is accurate. (Answer)
Therefore, The journey along Line segment X Y is longer than the path along Line segment Z Y, and the path along Line segment Z Y is longer than the path along Line segment A B, hence Option-A is the correct answer.
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Answer:
It's A
Step-by-step explanation:
I got 100 on the quiz
I can't theme to grasp these questions can someone please explain the steps ?
Answer:
(i) See below for proof.
(ii) x = 1.823, x = -0.823
Step-by-step explanation:
Part (i)Given equation:
[tex]\dfrac{x+2}{x+1}+\dfrac{3}{x}=3[/tex]
Make the denominators of the fractions the same:
[tex]\implies \dfrac{x+2}{x+1}\cdot \dfrac{x}{x}+\dfrac{3}{x}\cdot \dfrac{x+1}{x+1}=3[/tex]
[tex]\implies \dfrac{x(x+2)}{x(x+1)}+\dfrac{3(x+1)}{x(x+1)}=3[/tex]
[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]
[tex]\implies \dfrac{x(x+2)+3(x+1)}{x(x+1)}=3[/tex]
Multiply both sides of the equation by x(x + 1) to eliminate the denominator of the fraction on the LHS:
[tex]\implies x(x+2)+3(x+1)=3x(x+1)[/tex]
Expand the brackets:
[tex]\implies x^2+2x+3x+3=3x^2+3x[/tex]
[tex]\implies x^2+5x+3=3x^2+3x[/tex]
Subtract x² from both sides:
[tex]\implies 5x+3=2x^2+3x[/tex]
Subtract 5x from both sides:
[tex]\implies 3=2x^2-2x[/tex]
Subtract 3 from both sides:
[tex]\implies 0=2x^2-2x-3[/tex]
[tex]\implies 2x^2-2x-3=0[/tex]
Part (ii)[tex]\boxed{\begin{minipage}{3.6 cm}\underline{Quadratic Formula}\\\\$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\\\\when $ax^2+bx+c=0$ \\\end{minipage}}[/tex]
To solve the quadratic equation [tex]2x^2-2x-3=0[/tex], use the quadratic formula.
Therefore:
a = 2b = -2c = -3Substitute these values into the formula and solve for x:
[tex]\implies x=\dfrac{-(-2) \pm \sqrt{(-2)^2-4(2)(-3)}}{2(2)}[/tex]
[tex]\implies x=\dfrac{2 \pm \sqrt{4+24}}{4}[/tex]
[tex]\implies x=\dfrac{2 \pm \sqrt{28}}{4}[/tex]
[tex]\implies x=\dfrac{2 \pm \sqrt{4 \cdot 7}}{4}[/tex]
[tex]\implies x=\dfrac{2 \pm \sqrt{4} \sqrt{7}}{4}[/tex]
[tex]\implies x=\dfrac{2 \pm 2 \sqrt{7}}{4}[/tex]
[tex]\implies x=\dfrac{1 \pm \sqrt{7}}{2}[/tex]
Therefore, the solutions correct to 3 decimal places are:
[tex]x=1.823,\;\; x= -0.823[/tex]
Find the maximum profit and the number of units that must be produced and sold in order to yield the maximum profit. Assume that revenue, Upper R left parenthesis x right parenthesis, andcost, Upper C left parenthesis x right parenthesis, of producing x units are in dollars. R(x)=3x, C(x)=0.05x^2+0.04x+10
To maximize the profit 29.6 units must be produced.
What is the maxima or minima?
The maxima and minima of a function collectively referred to as extrema in mathematical analysis, are the highest and lowest values of the function, either on the whole domain or within a specific range.
We have given,
The revenue function is,
R(x)=3x
Cost function,
C(x)=0.05x^2+0.04x+10,
Where
x = number of units produced.
Thus, profit = revenue - cost
P(x) = 3x - (0.05x^2+0.04x+10)
= -0.05x^2 + 2.96x - 10
Differentiating with respect to x,
P'(x) = -0.1x + 2.96
Again differentiating with respect to x,
P''(x) = -0.1
For maxima or minima,
P'(x) = 0,
0 = -0.1x + 2.96
-0.1x = -2.96
x = 2.96/0.1
For x = 29.6,
P''(x) = negative,
Hence, to maximize the profit 29.6 units must be produced.
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(pythagorean theorem mc) a right triangle has a leg length of square root of 11 and a hypotenuse length of 9. determine the length of the other leg of the right triangle. square root of 18 square root of 81 square root of 70 22
The length of the other leg of the given right triangle is [tex]\sqrt{70}[/tex].
RIGHT TRIANGLE
A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called the hypotenuse. And, the other two sides are called legs.
The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.
The Pythagorean Theorem says (hypotenuse)²= (leg1)²+(leg2)². And the main trigonometric ratios are: sin (x) , cos (x) and tan (x) .
The question gives:
leg1=[tex]\sqrt{11}[/tex]hypotenuse = 9Therefore, from the Pythagorean Theorem, you will find the value of the other leg. See below.
[tex]9^2={\sqrt{11}^2 +{leg_2}^2[/tex]
[tex]81=11 +{leg_2}^2[/tex]
[tex]{leg_2}^2=81-11\\ \\ {leg_2}^2=70\\ \\ leg_2=\sqrt{70}[/tex]
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ANSWER FOR BRAINLY!! AND 20 POINTS please
(x+1)(2x-4)=0
rewrite the equation as a compound statement and find 2 solutions to the equation.
x=0
Step-by-step explanation:
4(x+1)=2x+4
Distribute
4x+4 = 2x+4
Subtract 4 from each side
4x+4-4 = 2x+4-4
4x= 2x
Subtract 2x from each side
4x-2x = 2x-2x
2x=0
Divide by 2
x =0
It has long been thought that the length of one's femur is positively correlated to the length of one's tibia. The following are data for a classroom of students who measured each (approximately) in inches. Femur Length Tibia Length 18.7 14.2 20.5 15.9 16.2 13.1 15.0 12.4 19.0 16.2 21.3 15.8 21.0 16.2 14.3 12.1 15.8 13.0 18.8 14.3 18.7 13.8 Regression Statistics Multiple R 0.9305 R Square 0.8659 Adjusted R Square 0.8510 Standard Error 0.5963 Observations ANOVA SS MS F Significance F Regression 1 20.6611 20.6611 58.0968 3.25116E-05 Residual 9 3.2007 0.3556 Total 10 23.8618 Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Intercept 3.5850 1.4137 2.5359 0.0319 0.3871 6.7830 Femur Length 0.5899 0.0774 7.6221 0.0000 0.4148 0.7650 A strong linear correlation was found between the two variables. Find the standard error of estimate. Round answer to 4 decimal places.
The linear correlation between the given two variables be,
4.5y + 5.2x = 168.34
Given, data for a classroom of students who measured each (approximately) in inches.
Femur Length 18.7 14.2 20.5 15.9 16.2 13.1 15.0 12.4 19.0 16.2 21.3
Tibia Length 15.8 21.0 16.2 14.3 12.1 15.8 13.0 18.8 14.3 18.7 13.8
we have to find a linear correlation between the two variables,
linear correlation be,
(y - 15.8)/(x - 18.7) = (15.8 - 21.0)/(18.7 - 14.2)
(y - 15.8)/(x - 18.7) = (- 5.2)/4.5
4.5y - 71.1 = -5.2x + 97.24
4.5y + 5.2x = 168.34
So, the linear correlation between the given two variables be,
4.5y + 5.2x = 168.34
Hence, the linear correlation between the given two variables be,
4.5y + 5.2x = 168.34
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use the image to answer the question what does the absolute vaule of the point labeled in the image if the number line represents temperature change.
Please help!!!
Answer:i don't know I just need the points
Step-by-step explanation: