In the diagram below, the area of $\triangle BCD$ is 60. What is the length of side $\overline{BC}$?

Answer:

The answer is (x+4)

Step-by-step explanation:

Just write the expression as a product with the factor x and 4

x²+2×x×4+4+16

then write the number in the exponential form with an exponent of 2

x²+2×x×4+4²

then use a² +2ab +b² = (a+b)² yo factor the expression which you get (x+4)

Answer:

Step-by-step explanation:

f(x) = (x + 3)(x - 2​) has two zeros:  One stems from (x + 3) = 0 and is (-3, 0); the other stems from (x - 2) = 0 and is (2, 0).  

The axis of symmetry is a vertical line located halfway between -3 and 2:  

x =  -1/2.

The graph opens up because the given (x + 3)(x - 2) has a positive leading coefficient (+1).

With this information we can eliminate the last two possible answers.  Note that the x-intercepts of the first graph are -3 and 2,  Thus, the first graph is the correct one.

Answer:

reading books (458), science books (957), mathematics books (1054)

Step-by-step explanation:

458 is less than 957 and 1054, while 957 is less than 1054 but more than 458, and 1054 is more than 957 and 458.

458<957<1054

Answer:

11

Step-by-step explanation:

2(x + 1) - 3

Let x= 6

2(6+1) -3

Parentheses first

2(7) -3

Then multiply

14-3

Then subtract

11

Answer:

1190 m^3

Step-by-step explanation:

l = 1700 cm = 17 m

b = 14 m

h = 1000 cm = 10 m

Total volume = l × b × h

= 17 × 14× 10

= 2380 m^3

since it is half filled ,

Volume is half , so,

volume of water in pond = 2380 ÷ 2

= 1190 m^3

Answer/Step-by-step explanation:

The diagram of the circular track is missing, and so also its dimensions.

However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.

Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.

Circumference = πd

d = 20 m (we are assuming the diameter is 20 meters)

π = 3.14

Circumference of circular track = 3.14 × 20 = 62.8 m.

This means that 1 lap = 62.8 m that she would have to run.

Therefore,

6 laps would be = 6 × 62.8 = 376.8 m

Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.

Answer:

Option B

Step-by-step explanation:

By applying the converse theorem of corresponding angles,

"If corresponding angles formed between two parallel lines and the transversal line are equal then both the lines will be parallel"

Angle between line B and Y = 90°

Angle between line B and Z = 90°

Therefore, corresponding angles are equal.

By applying converse theorem, line Y and line Z will be parallel.

Option B will be the answer.

Answer:

C

Step-by-step explanation:

Given that the equation of the revenue is R=2x2+55x+10 and the equation of the cost is C=2x2 – 15x – 40, you will get the profit by subtracting the revenue from the cost: R-C=P. Therefore, P=(2x2+55x+10)-(2x2 – 15x – 40). You will get P=70x+50 where x is is the number of cellphones sold. If 240 cellphones are sold, then the profit is 16850 dollars.

The profit, if 240 cell phones are sold, is $16,850.

Profit = 70x + 50

Option C is the correct answer.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example: so

1 + 3x + 4y = 7 is an expression.com

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

The profit, in dollars, can be found by subtracting the cost from the revenue:

Profit = Revenue - Cost

= (2x² + 55x + 10) - (2x² - 15x - 40)

= 70x + 50

The expression for profit is 70x + 50.

To find the profit if 240 cell phones are sold, we substitute x = 240 into the expression for profit:

Profit = 70x + 50

= 70(240) + 50

= 16,850

Therefore,

The profit, if 240 cell phones are sold, is $16,850.

Learn more about expressions here:

https://brainly.com/question/3118662

#SPJ5

Answer:

x=6

Step-by-step explanation:

2x + 2y = 20

Let y=4

2x +2(4) = 20

Multiply

2x+8 = 20

Subtract 8 from each side

2x+8-8= 20-8

2x = 12

Divide by  2

2x/2 = 12/2

x = 6

Answer:

[tex]x=6\\[/tex]

Step-by-step explanation:

[tex]2x+2(4)=20[/tex]

[tex]2x+8=20[/tex]

Subtract both sides by 8

[tex]2x=12[/tex]

Divide both sides by 2 to get x alone

[tex]x=6[/tex]

Hope this is helpful

Answer: 280 km

Step-by-step explanation:

[tex]3\dfrac{1}{2} \: hours = 3.5 \: hours[/tex]

S = V × t

V = 80 km/h

t = 3.5 h

S = 80 × 3.5 = 280 km

Answer:

Rotated 90° counterclockwise, then reflected across the y-axis

Step-by-step explanation:

Answer:

hypotenuse = 7.3

Step-by-step explanation:

the length two legs of the given triangle are 7 and 2 respectively.

using pythagoras theorem

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.3 = c

Answer:

a

Step-by-step explanation:

Answer:

Associative property

Step-by-step explanation:

The associative property is a math rule that says that the way in which factors are grouped in a multiplication problem does not change the product.

Hope this helps

Answer:

3

Step-by-step explanation:

f(x) =2x+3

Let x=0

f(0) =2*0+3

Multiply

f(0) =0+3

Add

f(0) =3

Answer:

3

step-by-step explanation

f ( x ) = 2 x + 3

f ( 0 ) = 2 × 0 + 3 .. ( f ( x = 0 ) - given )

multiply

f ( 0 ) = 0 + 3

Add the numbers

f ( 0 ) = 3

Answer: 1/4

Step-by-step explanation:

Reword the problem. It says what is the probability of landing on 2 or 1. That is 2 possibilities out of 8 so 2/8 = 1/4

Answer:

Option A = 1/15 cubic meters

Step-by-step explanation:

Formule to find volume of rectangular prism:

Volume = width × height × length

V = w×h×l

V = 1/3 × 1/4 × 4/5

V = 1/15 cubic meters

Answer:

The surface charge density is [tex]7.8\times10^{-8} C/m^2[/tex].

Step-by-step explanation:

separation, d = 85 mm

Work, W = 6 x 10^-3 J

charge , Q = 8µC

The potential difference is given by

W = q V

[tex]V=\frac{6\times 10^{-3}}{8\times 10^{-6}}=750 V[/tex]

Let the charge on he capacitor is q.

[tex]q = CV\\\\q = \frac{\varepsilon oA}{d}\times V\\\\\frac{q}{A} = \frac{8.85\times 10^{-12}\times750}{0.085} =7.8\times10^{-8} C/m^2[/tex]

Answer:

3 * 45 = 135 which is NOT 180

45, 45, 90 would work

Step-by-step explanation:

hope it helps!

Answer:

3 < x

Step-by-step explanation:

3(8 – 4x) < 6(x – 5)

Divide each side by 3

3/3(8 – 4x) < 6/3(x – 5)

(8 – 4x) < 2(x – 5)

Distribute

8-4x < 2x-10

Add 4x to each side

8-4x+4x < 2x-10+4x

8 < 6x-10

Add 10 to each side

8+10 < 6x-10+10

18 < 6x

Divide by 6

18/6 < 6x/6

3 < x

Question options:

A. He should report them directly on form 1040

B. He should report them on form 8949 and then on schedule D

C. He should report them on schedule D

D. He is not required to report them until he sells the underlying securities

Answer:

B. He should report them on form 8949 and then on schedule D

Explanation:

John has shares which have capital gains from a mutual fund and a brokerage account. In order to report his taxes, he would need to use the Schedule D(form 1040) for his mutual fund capital gains and the form 8949 for his brokerage capital gains. The brokerage capital gains is then transferred to schedule D.

Answer:

31 batches

Step-by-step explanation:

Find how many batches of orange punch smoothies he can make by dividing 560 by 18:

560/18

= 31.11

Since we can only have a whole number answer, round down.

So, he can make 31 batches of orange punch smoothies.

Answer:

timely, timely,measurable

Step-by-step explanation:

Answer:

specific, timely, measurable

Step-by-step explanation:

i took the test on plato

Answer:

500000 cm2

Step-by-step explanation:

Answer:

The answer is D

Step-by-step explanation:

-x is n

Y=0

Answer:

D

Step-by-step explanation:

Basically....... graph shown in picture

Answer:

[tex] \displaystyle - \frac{1}{2} [/tex]

Step-by-step explanation:

we would like to compute the following limit:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{1}{ \ln(x + \sqrt{ {x}^{2} + 1} ) } - \frac{1}{ \ln(x + 1) } \right) [/tex]

if we substitute 0 directly we would end up with:

[tex] \displaystyle\frac{1}{0} - \frac{1}{0} [/tex]

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

now notice that after simplifying we ended up with a rational expression in that case to compute the limit we can consider using L'hopital rule which states that

[tex] \rm \displaystyle \lim _{x \to c} \left( \frac{f(x)}{g(x)} \right) = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)} \right) [/tex]

thus apply L'hopital rule which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \dfrac{d}{dx} \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1} - \frac{1}{ \sqrt{x + 1} } }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2} + 1 } } + \frac{ \ln(x + \sqrt{x ^{2} + 1 } }{x + 1} } \right) [/tex]

simplify which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1 } - x - 1 }{ (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \sqrt{ {x}^{2} + 1 } - x - 1 }{ \dfrac{d}{dx} (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{x}{ \sqrt{ {x}^{2} + 1 } } - 1}{ \ln(x + 1) + 2 + \frac{x \ln(x + \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } } \right) [/tex]

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

[tex] \displaystyle \frac{ \frac{0}{ \sqrt{ {0}^{2} + 1 } } - 1}{ \ln(0 + 1) + 2 + \frac{0 \ln(0 + \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } } [/tex]

simplify which yields:

[tex] \displaystyle - \frac{1}{2} [/tex]

finally, we are done!

9514 1404 393

Answer:

  -1/2

Step-by-step explanation:

Evaluating the expression directly at x=0 gives ...

  [tex]\dfrac{1}{\ln(\sqrt{1})}-\dfrac{1}{\ln(1)}=\dfrac{1}{0}-\dfrac{1}{0}\qquad\text{an indeterminate form}[/tex]

Using the linear approximations of the log and root functions, we can put this in a form that can be evaluated at x=0.

The approximations of interest are ...

  [tex]\ln(x+1)\approx x\quad\text{for x near 0}\\\\\sqrt{x+1}\approx \dfrac{x}{2}+1\quad\text{for x near 0}[/tex]

__

Then as x nears zero, the limit we seek is reasonably approximated by the limit ...

  [tex]\displaystyle\lim_{x\to0}\left(\dfrac{1}{x+\dfrac{x^2}{2}}-\dfrac{1}{x}\right)=\lim_{x\to0}\left(\dfrac{x-(x+\dfrac{x^2}{2})}{x(x+\dfrac{x^2}{2})}\right)\\\\=\lim_{x\to0}\dfrac{-\dfrac{x^2}{2}}{x^2(1+\dfrac{x}{2})}=\lim_{x\to0}\dfrac{-1}{2+x}=\boxed{-\dfrac{1}{2}}[/tex]

_____

I find a graphing calculator can often give a good clue as to the limit of a function.