In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on the final exam. There are 100 points available for each score. However, the lab score is worth 21% of your total grade, each major test is worth 25%, and the final exam is worth 29%. Compute the weighted average for the following scores: 60 on the lab, 81 on the first major test, 69 on the second major test, and 79 on the final exam. Enter your answer as a whole number.

Answer:

0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean per capita consumption of milk per year is 131 liters with a variance of 841.

This means that [tex]\mu = 131, \sigma = \sqrt{841} = 29[/tex]

Sample of 132 people

This means that [tex]n = 132, s = \frac{29}{\sqrt{132}}[/tex]

What is the probability that the sample mean would be less than 133.5 liters?

This is the p-value of Z when X = 133.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{133.5 - 131}{\frac{29}{\sqrt{132}}}[/tex]

[tex]Z = 0.99[/tex]

[tex]Z = 0.99[/tex] has a p-value of 0.8389

0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.

Answer:

the answer is x = 2 or B, hope this helps

Step-by-step explanation:

Answer:

200 test tubes will fill the container

Step-by-step explanation:

Hi there!

We need to find out how many 5 milliliter tubes will fill a 1 liter container

First, let's convert everything to the same unit, as the tubes and the container are in different units.

Let's do milliliters, as those are smaller than liters and we will avoid having decimals.

there are 1,000 milliliters in a liter (the unit prefix "milli-" means "thousand")

Let's say the number of test tubes needed to fill the container is x

As each tube has 5 milliliters of water, 5x milliliters will equal 1,000 milliliters (1 liter)

as an equation, that's

5x=1,000

divide both sides by 5

x=200

So that means 200 test tubes will fill the container

Hope this helps! :)

Answer:

Here is how to start

Step-by-step explanation:    7  2  13  42

1 milliliter is one one thousands of a liter      1 milliliter  = 0.001 liter

1000 milliliter is equal to 1 liter

How many 5 milliliter test tubes are in 1 liter?

1000 milliliter / 5 milliliter per test tube   =  ________  test tubes

Answer:

Step-by-step explanation:

Given,

Total no. of cards = 52

No. of 2 of spades cards = 1

Therefore,

Probability of getting 2 of spades

[tex] = \frac{no. \: of \: required \: outcomes}{total \: outcomes} [/tex]

[tex] = \frac{1}{52} (ans)[/tex]

Answer:

D. The y-intercept of the new graph would shift down 2 units.

Step-by-step explanation:

y = -9x + 3 has a y-intercept of 3 (0, 3).

y = -9x + 1 has a y-intercept of 1 (0, 1).

3 - 1 = 2

So, down two units.

Answer:

Let's solve for k.

x2−y2=k

Step 1: Flip the equation.

k=x2−y2

Answer:

k=x2−y2

Step-by-step explanation:

Answer:

A is the equation in standard form

Step-by-step explanation:

Answer:

(2k, k)

Step-by-step explanation:

x + y = 3k

x - y = k

Add the equations.

2x = 4k

x = 2k

2k + y = 3k

y = k

Answer: (2k, k)

Answer:

P

Step-by-step explanation:

It's where the altitudes meet

Answer:

1/4 *1/4*1/2 =0.03125

which as a fraction is 1/32

so the minimuim number of passes that will get him a goal is 1 since he could get it on the first try

Hope This Helps!!!

Answer:

f(6)=-42

f(0)=0

f(-1)=7

Step-by-step explanation:

since f(x) =-7x

it implies that f(6),f(0) and f(-1) are all equal to f(x)

which is equal to -7x .

so wherever you find x you out it in the

function

Answer:

Option A, 7b

Step-by-step explanation:

a/b=7/2

or, 2a=7b

Answered by GAUTHMATH

Answer:

A)7b

its yr ans.

hope it helps.

Answer:

251.33

Step-by-step explanation:

C=3.14(d)

C=3.14(80)

9514 1404 393

Answer:

  D.  f^-1(x) = 3 -7x

Step-by-step explanation:

Solve x = f(y) for y to find the inverse function.

  x = f(y)

  x = (3 -y)/7 . . . . . . use the function definition

  7x = 3 -y . . . . . . . .multiply by 7

  y = 3 -7x . . . . . . . add y-7x to both sides

Then the inverse function is ...

  [tex]\boxed{f^{-1}(x)=3-7x}[/tex]

Answer:

14 to 132

Step-by-step explanation:

We are given that there are 132 boys and 14 adults. Since the question is only asking for the ratio of adults to boys, we don't have to worry about the number of girls in this question. From here, we see that the question is asking for the ratio of adults to boys, so we put it in that exact order. Our answer is 14 to 132. I hope this helps and please don't hesitate to reach out with more questions!

Answer:

[tex]d_2=-8.32ft[/tex]

Step-by-step explanation:

From the question we are told that:

Height of first draw down [tex]h=30[/tex]

Pump Discharge [tex]Q=250gallons/day[/tex]

Well 1 depth [tex]d_1=10ft[/tex]

Transmissivity[tex]\=T 10.0 ft2/day[/tex]

Radius[tex]r=0.5[/tex]

Well 2 depth [tex]d_2=50ft[/tex]

Generally the Thiem's equation for Discharge is mathematically given by

 [tex]Q=\frac{2\piT(h_2-h_1)}{ln(\frac{r_2}{r_1})}[/tex]

 [tex]250=\frac{2*\pi 10 (10-d_2)}{ln(\frac{50}{0.5})}[/tex]

 [tex]1151.293=2*\pi 10 (10-d_2)[/tex]

 [tex]d_2=-8.32ft[/tex]

Answer:

(1) Ordinal

(2) Such data should not be used for calculations such as an average.

Step-by-step explanation:

Given

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

[tex]Average = 1.3[/tex]

Solving (a): The level of measurement

When observations are presented in ranks such as:

[tex]1 \to Low[/tex]

[tex]2 \to Medium[/tex]

[tex]3 \to High[/tex]

The level of measurement of such observation is ordinal

Solving (b): What is wrong with the computation?

Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.

Hence, (a) is correct

Answer:

B

Step-by-step explanation:

B is the only one that doesnt share x-values

Answer:

Evaluación de expresiones y polinomios

Purplemath

"Evaluación" significa principalmente "simplificar una expresión a un solo valor numérico". A veces se le dará una expresión numérica, donde todo lo que tiene que hacer es simplificar; esa es más una cuestión de orden de operaciones. En esta lección, me concentraré en el aspecto de la evaluación de "conectar y tragar": introducir valores para las variables y "avanzar" hasta llegar a la respuesta simplificada.

(Por cierto, sí, "plug-n-chug" es una terminología bastante estándar. No es un término "técnico", por lo que probablemente no lo verá en su libro de texto, pero seguramente lo escuchará de otros estudiantes. , y quizás también su instructor.)

MathHelp.com

Evaluar expresiones en MathHelp.com

Evaluar expresiones

Por lo general, la única parte difícil de la evaluación es hacer un seguimiento de los signos "menos". Le recomiendo encarecidamente que utilice los paréntesis libremente, especialmente cuando recién está comenzando.

Evalúe a2b para a = –2, b = 3, c = –4 y d = 4.

Anuncio publicitario

Para encontrar mi respuesta, simplemente conecto los valores dados, teniendo cuidado de usar paréntesis, particularmente alrededor de los signos "menos". Especialmente cuando recién estoy comenzando, dibujar los paréntesis primero puede ser útil:

a2 b

() 2 ()

(–2) 2 (3)

(4) (3)

12

Observe cómo el uso de paréntesis me ayudó a realizar un seguimiento del signo "menos" en el valor de a. Esto era importante, porque de otro modo podría haber elevado al cuadrado solo el 2, terminando con –4, lo que habría estado mal.

Por cierto, resultó que no necesitábamos los valores de las variables c y d. Cuando se le da un gran conjunto de expresiones para evaluar, debe esperar que a menudo haya una u otra de las variables que no se incluirán en ningún ejercicio en particular del conjunto.

Evalúe a - cd para a = –2, b = 3, c = –4 y d = 4.

En este ejercicio, me dieron información adicional. No hay una b en la expresión que quieren que evalúe, por lo que puedo ignorar este valor en mi trabajo:

(–2) - (–4) (4)

–2 - (–16)

–2 + 16

16 - 2

14

Step-by-step explanation:

hola

Answer:

Step-by-step explanation:

A.

[tex] \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} [/tex]

which equation has the steepest graph ?

[tex] \red{ \bold{ \textit{STANDARD \: EQUATION}}}[/tex]

[tex]y = mx + c[/tex]

[tex]WHERE \\ m = SLOPE \\ c = Y - INTERCEPT[/tex]

[tex] \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]

[tex] \blue{A.T.Q}[/tex]

PART A:-

[tex]y = mx + c \sim y= -14x+1 [/tex]

[tex] \orange{SO}[/tex]

m= (-14)

which is equal to the slope of the equation .

PART B:-

[tex]y = mx + c \sim y= ¾x-9 [/tex]

[tex] \orange{SO}[/tex]

m= (¾)

PART C:-

[tex]y = mx + c \sim y= 10x-5[/tex]

[tex] \orange{SO}[/tex]

m= (10)

PART D:-

[tex]y = mx + c \sim y= 2x+8[/tex]

[tex] \orange{SO}[/tex]

m= (2)

Negative shows Slope is in negative direction.

[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]

Answer:

x=5

y=3/2

Step-by-step explanation:

Take it or leave it, that's what the computer said.

Answer:

0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

The mean points obtained in an aptitude examination is 167 points with a standard deviation of 20 points

This means that [tex]\mu = 167, \sigma = 20[/tex]

Sample of 76:

This means that [tex]n = 76, s = \frac{20}{\sqrt{76}}[/tex]

What is the probability that the mean of the sample would differ from the population mean by less than 3.8 points?

P-value of Z when X = 167 + 3.8 = 170.8 subtracted by the p-value of Z when X = 167 - 3.8 = 163.2. So

X = 170.8

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{170.8 - 167}{\frac{20}{\sqrt{76}}}[/tex]

[tex]Z = 1.66[/tex]

[tex]Z = 1.66[/tex] has a p-value of 0.9515

X = 163.2

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{163.2 - 167}{\frac{20}{\sqrt{76}}}[/tex]

[tex]Z = -1.66[/tex]

[tex]Z = -1.66[/tex] has a p-value of 0.0485

0.9514 - 0.0485 = 0.9029

0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled

can you show a picture of the symbols

Answer:

option (B) is the answer

Answer:

"x" cantidad de personas, que será igual a

f(x) = $10x   Si   x < 30

f(x) = $9.5x si x ≥ 30

Si tenemos que son 29 personas entonces el costo es de:

f(x) = $10*29 = $290

Si incluye un miembro adicional

f(x) = $9.5*30 = $285

Ahorra un total de: $290 - $285 = $5

Answer:

Step-by-step explanation:

-2

Answer:

$637.50

Step-by-step explanation:

According to the Question,

Thus, the first months interest is

$200,000 list price x 0.90 = $180,000 contract sales price.

Since lender always uses the less of the appraised value or the contract sales price, use $180,00 for the remainder of the calculations.

Answer:

$637.50

Step-by-step explanation:

The appraised value is irrelevant. The lender will consider the lower of the appraised value or the agreed purchase price.

The term of the loan is also irrelevant. It is not an amortization problem.

The first month’s interest is $637.50.