What is 18.5% of 500?
Answer:
92.5
Step-by-step explanation:
18.5% = 0.185
0.185 x 500 = 92.5
Hope that helps!
Answer: 92 1/2 or 92.5
Step-by-step explanation:
how to solve?
Put it into a percent proportion :D!
Percent proportion is is/of=%/100 or a/w=p/100
The a stands for "part"
and the w stands for "whole"
p stands for "percent"
Is/of=%/100 will help you figure it out if it's in a mathmatical sentence.
Since they did NOT give you what the "is" is, you put the variable "a"
a/ =
Next,
Since it said "of"
You put of underneath the unknown number "is" (a)
a/500=
Now put in the percent
a/500=18.5/100
Now cross multiply!
Then you should get 92.5!
HOPE THIS HELPS :DDD
Which equations represent exponential growth functions? Select all that apply.
Question 6 options:
f(x)=(2.6)x
g(x)=(52)x
h(x)=(0.4)x
m(x)=(13)x
I need help on this and I don't know how to do this.
Please Help
9514 1404 393
Answer:
-8, 36, -5Step-by-step explanation:
This sort of pattern is used in the factoring of trinomials. Typically, the top quadrant holds the product you're trying to factor. The bottom quadrant holds the sum of the factors. The factors appear on the left and right in no particular order.
__
1) You're looking for factors of -24 that have a sum of -5. It can be useful to simply list the factor pairs. Since you want a negative sum, you may want to start with the most negative factors and work up from there.
-24 = (-24)(1) = (-12)(2) = (-8)(3) = (-6)(4)
The sums of these factor pairs are -23, -10, -5, -2. Obviously, the pair we're interested in is the one with a sum of -5: (-8) +(3).
So, the left- and right-quadrants are filled with -8 and 3.
Blank 1 = -8
Blank 2 = 3
__
2) You are given the factors, so all you need to do is form the product and sum.
Blank 1 = (-3)(-2) = 6
Blank 2 = (-3) +(-2) = -5
_____
Additional comment
Any sort of factoring is much easier to do if you have memorized your multiplication tables, preferably through 12×12. It is also helpful if you're familiar with divisibility rules—at least for single-digit numbers. I've seen college students struggle trying to do factoring using a calculator. It's not pretty. Many folks learn their times tables up to 10×10 by the end of 3rd grade.
Answer:
Blank 1: -8
Blank 2: 3
Step-by-step explanation:
Sorry if i'm late on this but it is the same X method concept. -8 and 3 add up to get -5, and they multiply to get -24
I WILL GIVE BRAINLIEST !!!What is the product of 4 and 7?
7
O
o
8 9
14
9
14
7
8
Answer:
8? I think I'm not quite sure. lmk
Factorize 25 – x² =
m2
Answer:
(5 + x)(5 - x)
Step-by-step explanation:
[tex]25 - {x}^{2} \\ \\ = {5}^{2} - {x}^{2} \\ \\ = (5 + x)(5 - x)[/tex]
A fish tank has 10 goldfish, 6 tetras, 5 snails, and 2 platies. What is the ratio of tetras to platies?
A. 2/10
B. 6/2
C. 2/6
D. 10/6
Answer:
its B cuz there r six tetras and 2 platies so it is 6/2
15 Points, please give full equation on how you answer.
What is 5 + 2x + 7 + 4x
Answer:
12+8x
Step-by-step explanation:
By adding together alike values, 5 and 7, and 2x and 4x, you get 12+8x.
The cost to rent the school is $200. The student council has a goal to raise $350 after paying the rental fee. How many students will need to attend the activity night for the student council to par for the rental fee and reach their goal
Answer:
110 students
Step-by-step explanation:
Let the total money raised = R ($)
Let the number of student = x
Proposed ticket cost to activity night = $5
(a) R = 5x
x = R/5----------------------------------------------- (1)
(b) Total money to be raised to pay for rent of $200 and have a left over of $ 350 is = $(200 + 350)
R = $ 550
Substituting the value of R in equation (1), the number of student (x) can be found:
x = R/5
= 550/5
= 110 students
The student council must sell 110 tickets to students in order to achieve their goal.
jeremiah has a total of 144 pokemon cards 40 out of every 48 cards are not holographic cards at this rate how many of jeremiah cards are holographic
Answer:
120
Step-by-step explanation:
rate of a holographic card= 40/48=5/6.
Total number of holographic cards = 144*rate =144*5/6=120
In the elimination method would you add or subtract the following system? (Elimi
2x+5y=-2
-2x-7y=-6
(1 Point)
Add
Subtract
(Worth 10 points)
Answer:
You will add!
Step-by-step explanation:
Words words words
I WILL GIVE BRAINERLEST AND LIKE AND 5 STARS
For what number of days d will the
total charges for an overdue library
book be $2.40?
Answer:
You seem to have not posted the whole problem
You did not seem to say the problem
But mabye 30
Sonya paid $4.39 for a hero. She paid $0.95 for an orange and $1.67 for a drink. What is the total amount Sonya paid for all three items?
A store sold 6 fruit trees. Five of the trees were apple trees.
What fraction of the trees were apple trees?
In a Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were dissatisfied with the quality of education students receive in kindergarten through grade 12. Use the normal distribution to construct and interpret a 90% confidence interval for the proportion of U.S. adults who are dissatisfied with the education students receive in kindergarten through grade 12. The standard error is SE
Answer:
The standard error is 0.0157.
The 90% confidence interval for the proportion of U.S. adults who are dissatisfied with the education students receive in kindergarten through grade 12 is (0.5042, 0.5558). This means that we are 90% sure that the true proportion of U.S. adults who are dissatisfied with the education students receive in kindergarten through grade 12 is between 0.5042 and 0.5558.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm zs[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
[tex]s = \sqrt{\frac{\pi(1-\pi)}{n}}[/tex] is the standard error.
In a Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were dissatisfied with the quality of education students receive in kindergarten through grade 12.
This means that [tex]n = 1012, \pi = 0.53[/tex]
The standard error is:
[tex]s = \sqrt{\frac{\pi(1-\pi)}{n}} = \sqrt{\frac{0.53*0.47}{1012}} = 0.0157[/tex]
The standard error is 0.0157.
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
The lower limit of this interval is:
[tex]\pi - zs = 0.53 - 1.645*0.0157 = 0.5042[/tex]
The upper limit of this interval is:
[tex]\pi + zs = 0.53 + 1.645*0.0157 = 0.5558[/tex]
The 90% confidence interval for the proportion of U.S. adults who are dissatisfied with the education students receive in kindergarten through grade 12 is (0.5042, 0.5558). This means that we are 90% sure that the true proportion of U.S. adults who are dissatisfied with the education students receive in kindergarten through grade 12 is between 0.5042 and 0.5558.
write the fraction 4/9 as an equivalent fraction with the given denominator 45
Answer:
answer is in the picture
Which of the following modifications to an electromagnet would be most likely to
decrease the strength of its magnetic field?
Answer:
Fewer coils, lower voltage, alloyed core with less iron
Step-by-step explanation:
factor g(x) =6x^3 +13x^2 -2x -1 if (2x + 3) is a factor.
here is a tree diagram showing the sample independent events how many outcomes are there for the second event
8
1
2
4
Which range best describes the possible number of cells in one organism , from the very smallest organism to the very largest ?
Answer:
ant to a wale
Step-by-step explanation:
A novelist can write 3 1/2 pages in 1/3 of an hour. How many pages can she write in one hour?
Answer:
LG sjsjsjdjdbvebsjsuwknsnsbbskoejenndnd
Answer:
12 pages
Step-by-step explanation:
3 1/2 pages = 1/3 hour
? pages = 1 hr
; Cross multiply. Multiply 1 times 3 1/2 which is 4. Then, divide 4 by 1/3.
4/1 times 3/1 which equals 12 pages.
PLEASE HELP ME NO LINKS I AM BEGGING U !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
9514 1404 393
Answer:
x = 70
Step-by-step explanation:
The measure of the angle x° is half the sum of the intercepted arcs.
x° = (112° +28°)/2 = 140°/2
x° = 70°
How can I do this dudhhehrhr
Answer:
the answer is 30
Step-by-step explanation:
(6+4) * 3
Do what is in the parenthesis!
(6+4) = 10
Then do the *3
10*3 = 30!
Hope this help! Goodluck!
please help me for brqinliest im imed
Answer:
77°
Step-by-step explanation:
As we can see ABCD is a cyclic quadrilateral so opposite angles of a cyclic quadrilateral is supplementary.
< A + <B = 180° { being opposite angles of cyclic quadrilateral }
2x + 9° + 3x + 1° = 180°
5x + 10° = 180°
5x = 180° - 10°
5x = 170°
x = 170° / 5
x = 34°
Now
< A = 2x + 9°
= 2 * 34° + 9°
= 77°
Hope it will help :)❤
A machine used to fill beverage cans is supposed to supply exactly 16 ounces toeach can, but the actualamount supplied varies randomly from can to can. The machine is calibrated so that the population standard deviation is 0.04 ounces. How many filled cans must be sampled so that we estimate the mean fill volume within 0.015 ounces with 99% confidence
Answer:
48 cans must be sampled.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
The machine is calibrated so that the population standard deviation is 0.04 ounces.
This means that [tex]\sigma = 0.04[/tex]
How many filled cans must be sampled so that we estimate the mean fill volume within 0.015 ounces with 99% confidence?
n cans must be sampled, and n is found when M = 0.015. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.015 = 2.575\frac{0.04}{\sqrt{n}}[/tex]
[tex]0.015\sqrt{n} = 2.575*0.04[/tex]
[tex]\sqrt{n} = \frac{2.575*0.04}{0.015}[/tex]
[tex](\sqrt{n})^2 = (\frac{2.575*0.04}{0.015})^2[/tex]
[tex]n = 47.2[/tex]
Rounding up, 48 cans must be sampled.
There are 4 blood types, and not all are equally likely to be in blood banks. 49% of donations are type O blood, 27% of donations are type A blood, 20% of donations are type B blood, and 4% of donations are type AB blood. A person with type A blood can safely receive blood transfusions of type O and type A blood. If three donations are made, what is the probability that at least 1 of them can be safely used in a blood transfusion on someone with type A blood? 0.0138 0.4390 0.5610 0.9862
Answer:
0.9862.
Step-by-step explanation:
For each donation, there are only two possible outcomes. Either it can be safely used in a blood transfusion on someone with type A blood, or it cannot. The probability of a donation being safely used is independent of other donations, which means that we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
Type A blood:
Can receive from type O(49%) and from type A(27%), which means that:
[tex]p = 0.49 + 0.27 = 0.76[/tex]
If three donations are made, what is the probability that at least 1 of them can be safely used in a blood transfusion on someone with type A blood?
Three donations mean that [tex]n = 3[/tex]
This probability is:
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{3,0}.(0.76)^{0}.(0.24)^{3} = 0.0138[/tex]
[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0138 = 0.9862[/tex]
The answer is 0.9862.
The probability that at least 1 of them can be safely used in a blood is 0.9862.
Since, A person with type A blood can safely receive blood transfusions of type O and type A blood.
Given that,
49% of donations are type O blood
27% of donations are type A blood
So, [tex]p=0.49+0.27=0.76[/tex] and [tex]q=1-0.76=0.24[/tex]
Where p represent probability of success and q represent probability of unsuccessful.
Now use Binomial distribution,
[tex]P(X=r)=n_{C}_rp^{r} q^{n-r}[/tex]
Here three donations, it means that, n = 3
We have to find that the probability that at least 1 of them can be safely used in a blood.
So, [tex]P(X\geq 1)=1-P(X=0)[/tex]
[tex]P(X=0)=3_{C}_0(0.76)^{0} (0.24)^{3}=0.0138[/tex]
[tex]P(X\geq 1)=1-0.0138=0.9862[/tex]
Thus, The probability that at least 1 of them can be safely used in a blood is 0.9862.
Learn more about Binomial distribution here:
https://brainly.com/question/11388449
During July in Jacksonville florida
Answer:
yo i live in florida
Step-by-step explanation:
aylor states that 2,800,000 in scientific notation is 2.8 × 10-6 because the number has six places to the right of the 2. Is Taylor’s reasoning correct?
Answer:
2.8+1232adwasdf 232=999
Step-by-step explanation:
(x+6)/(x+1)=6/2
Solving proportions
Answer:
[tex]x = \frac{3}{2} [/tex]
Step-by-step explanation:
[tex] \frac{x + 6}{x + 1} = \frac{6}{2} [/tex]
[tex] \frac{6}{2} = 3[/tex]
so, the solution of the equation will be as follows:
[tex] \frac{x + 6}{x + 1} = 3[/tex]
3(x+1) = x + 6
3x + 3 = x + 6
3x - x = 6 - 3
[tex]x = \frac{3}{2} [/tex]
so, the answer will be x = 3/2
Biologists are interested in how temperature changes might affect the frequency of mating calls of frogs. Twenty gray tree frogs are randomly chosen for a study. For each frog, the temperature of its habitat (in degrees Celsius) and the frequency of its mating call (in tones per second) are recorded. The 96 percent confidence interval for estimating the population slope of the linear regression line predicting mating call frequency based on habitat temperature is given by 2.341±0.768. Assume that the conditions for inference for the slope of the regression line have been met. Which of the following is the correct interpretation of the calculated confidence interval?
a. We are 96 percent confident that the increase in mating call frequency of an individual frog when its habitat temperature increases by 1 degree Celsius is between 1.573 and 3.109 tones per second.
b. We are 96 percent confident that the average increase in mating call frequency in the sample of frogs when habitat temperature increases by 1 degree Celsius is between 1.573 and 3.109 tones per second.
c. We are 96 percent confident that the average increase in mating call frequency in the population of frogs when habitat temperature increases by 1 degree Celsius is between 1.573 and 3.109 tones per second.
d. We are 96 percent confident that the average increase in habitat temperature in the sample of frogs when mating call frequency increases by one tone per second is between 1.573 and 3.109 degrees Celsius.
e. We are 96 percent confident that the average increase in habitat temperature in the population of frogs when mating call frequency increases by one tone per second is between 1.573 and 3.109 degrees Celsius.
Answer:
c. We are 96 percent confident that the average increase in mating call frequency in the population of frogs when habitat temperature increases by 1 degree Celsius is between 1.573 and 3.109 tones per second.
Step-by-step explanation:
x% confidence interval:
A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.
The 96 percent confidence interval for estimating the population slope of the linear regression line predicting mating call frequency based on habitat temperature is given by 2.341±0.768.
This means that the 96% CI is between:
2.341 - 0.768 = 1.573
2.341 + 0.768 = 3.109
Which of the following is the correct interpretation of the calculated confidence interval?
We are 96% sure that the population mean(population of frogs) in mating call frequency is in this interval. So the correct answer is given by option c.