Answer:
40 ft.
Step-by-step explanation:
Because James's yard is a square, we can take the square root of the area to find the side length. The square root of 100 is 10, so we know that one side of his yard will require 10 feet of fencing. Since the yard has 4 sides, we simply need to do 4 * 10 = 40 ft of fencing.
Hope this helps!
the height of each door on the plan is given 1,5cm but the height of each door is 1,92m is an actual size.show that the scale of the house is 1:128
Answer:
It is.
Step-by-step explanation:
1.5cm is in the plan.
1.92m is in real life.
We need to convert m to cm so 1.92m=192cm
The ratio is 1:128.
1.5cm in plan as is 192 cm in real life.We write that as the ratio of: 1.5 : 192.
We need to prove that it is the actual scale so we equal this ratio(1.5:192) and the other ratio(1:128):
1.5 : 192 = 1 : 128
Then we multiply the numbers that are in and out of the equation like this:
1.5 * 128 = 192 * 1
192 = 192 It is proven beacuse the numbers are equal. The scale of the house is 1:128
What is one root of this equation?
2x^-4x+9=0
9514 1404 393
Answer:
1 +i√3.5
Step-by-step explanation:
In vertex form, the equation is ...
2(x² -2x +1) +7 = 0
2(x -1)² +7 = 0
Then the solutions are ...
(x -1)² = -7/2
x = 1 ±i√3.5
One solution is 1+i√3.5.
What is the sum of -14
and -15?
Answer:
-29
Step-by-step explanation:
(-14) + (-15) =
-14 - 15 =
-29
Solve for r: 3r+2-r=-4
Answer:
r = -3
Step-by-step explanation:
3r + 2 - r = -4
2r + 2 = -4
2r = -6
r = -3
Answer:
r = -3
Step-by-step explanation:
3r + 2 - r = -4 (Given)
2r + 2 = -4 (Simplify)
2r + 2 - 2 = -4 - 2 (Subtract 2 on both sides)
2r = -6 (Simplify)
2r/2 = -6/2 (Divide 2 on both sides)
r = -3 (Simplify)
suppose an object traveling in a straight line has a velocity function given by v(t)= t^2 -8t+ 15 km/hr. Find the displacement and distance traveled by the object from t=2 to t=4 hours.
v=t^2-8t+15
It has upper limit 4 and lower limit 2[tex]\boxed{\sf {\displaystyle{\int}^b_a}x^ndx=\left[\dfrac{x^{n+1}}{n+1}\right]^b_a}[/tex]
[tex]\\ \sf\longmapsto s={\displaystyle{\int}}vdt[/tex]
[tex]\\ \sf\longmapsto s={\displaystyle{\int^4_2}}t^2-8t+15[/tex]
[tex]\\ \sf\longmapsto s=\left[\dfrac{t^3}{3}-8\dfrac{t^2}{2}+15t\right]^4_2[/tex]
[tex]\\ \sf\longmapsto s=\left[\dfrac{t^3}{3}-4t^2+15t\right]^4_2[/tex]
[tex]\\ \sf\longmapsto s=\left(\dfrac{4^3}{3}-4(4)^2+15(4)\right)-\left(\dfrac{2^3}{3}-4(2)^2+15(2)\right)[/tex]
[tex]\\ \sf\longmapsto s=\left(\dfrac{64}{3}-64+60\right)-\left(\dfrac{8}{3}-16+30\right)[/tex]
[tex]\\ \sf\longmapsto s=\left(\dfrac{64}{3}-4\right)-\left(\dfrac{8}{3}+14\right)[/tex]
[tex]\\ \sf\longmapsto s=\dfrac{64}{3}-4-\dfrac{8}{3}-14[/tex]
[tex]\\ \sf\longmapsto s=\dfrac{64}{3}-\dfrac{8}{3}-4-14[/tex]
[tex]\\ \sf\longmapsto s=\dfrac{46}{3}-18[/tex]
[tex]\\ \sf\longmapsto s=15.3-18[/tex]
Take it +ve[tex]\\ \sf\longmapsto s=|-2.7|[/tex]
[tex]\\ \sf\longmapsto s=2.7km[/tex]
[tex]7w+2=3w+94[/tex]
Answer:
7w+2=3w+94
Subtract 3w from both sides.
7w+2−3w=94
Combine 7w and −3w to get 4w.
4w+2=94
Subtract 2 from both sides.
4w=94−2
Subtract 2 from 94 to get 92.
4w=92
Divide both sides by 4.
w=492
Divide 92 by 4 to get 23.
w=23
Answer:
23
Step-by-step explanation:
7w + 2 = 3w + 94 Subtract 2 from both sides
7w = 3w + 94 - 2
7w = 3w + 92 Subtract 3w from both sides
4w = 92 Divide by 4
w = 92/4
w = 23
The product of 2 more than 5 times a number and 4 less than three times a number
Sorry I'm not sure if I'm right just my thinking...
set the number to be x so that (5x+2)(3x-4)??
what fraction of the Earth's surface would be covered by the surface of the moon,if the radius of the Earth is 6,378km and the radius of the moon is 1.741km?
Answer:
3031081 / 40678884
Step-by-step explanation:
To solve this, we can find the surface area of the moon and Earth, and then see how much the moon covers the Earth. The surface area of a sphere is equal to 4πr², so the radius of the Earth is
4πr² = 4 * π * 6378²
and the radius of the moon is
4πr² = 4 * π * 1741²
To figure out how much of the Earth's surface that the moon covers, we can implement a ratio of moons:Earth. This will give us an understanding of how many moons go inside one Earth. We thus have
(4 * π * 1741²) : ( 4 * π * 6378²) = (4 * π * 1741²) / ( 4 * π * 6378²)
cross out the 4 * π in the numerator and denominator
1741²/6378²
Next, we want to make the denominator 1, as that gives us 1 Earth. To do this, we can divide both the numerator and denominator by 6378². Because we are applying the same expression to both the numerator and denominator, this is essentially multiplying the fraction by 1, keeping it the same. We thus have
(1741²/6378²)/(6378²/6378²)
≈0.0745/1
≈ 0.0745
To put this in a fraction, we would have
(1741²/6378²)/1
= (1741²/6378²)
= 3031081 / 40678884
ans all these questions please
Answer:
the answer is in picture
Identify the equation of the circle that has its center at (9, 12) and passes through the origin.
Answer: [tex](x-9)^2 + (y-12)^2 = 225\\\\[/tex]
This is the same as writing (x-9)^2 + (x-12)^2 = 225
========================================================
Explanation:
Any circle equation fits the template of [tex](x-h)^2 + (y-k)^2 = r^2\\\\[/tex]
The center is (9,12) which tells us the values of h and k in that exact order.
h = 9
k = 12
To find the radius r, we need to find the distance from the center (9,12) to a point on the circle. The only point we know on the circle is the origin (0,0).
Apply the distance formula to find the distance from (9,12) to (0,0)
[tex]d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{ (9-0)^2+(12-0)^2}\\\\d = \sqrt{ (9)^2+(12)^2}\\\\d = \sqrt{ 81+144}\\\\d = \sqrt{ 225}\\\\d = 15\\\\[/tex]
The distance from (9,12) to (0,0) is 15 units. Therefore, r = 15
An alternative to finding this r value is to apply the pythagorean theorem. The distance formula is effectively a modified version of the pythagorean theorem.
---------------------
Since h = 9, k = 12 and r = 15, we can then say:
[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-9)^2 + (y-12)^2 = 15^2\\\\(x-9)^2 + (y-12)^2 = 225\\\\[/tex]
which is the equation of this circle.
I =∫▒dx/(x^2 √(x^2+4))
Which expression can be used to find the slope of a line containing the points (–3, 2) and (7, –1)?
A. (Image 092552)
B. (Image 092607)
C. (Image 092618
D. (Image 092630)
Answer:
C. (Image 092618
Step-by-step explanation:
[tex]slope = \frac{y_{2} - y_{1} }{x _{2} - x_{1} } [/tex]
y1 is 2
y2 is -1
x1 is -3
x2 is 7
substitute:
[tex]slope = \frac{ - 1 - 2}{7 - ( - 3)} [/tex]
The formula d=rt is used to calculate the distance traveled by an object moving at a constant average speed during an elapsed time . How long would it take a pilot to fly 1240 miles at an average speed of 220 mph?
Answer:
Approx 5.64 hours
Step-by-step explanation:
d=rt
t=d/r
To find the time, divide distance by velocity
1240 / 220 = approx 5.64 hours
Solve for x in the equation below.
-3x + 2 = -7
Answer:3
Step-by-step explanation:
-3x+2=-7
subtract 2 from both sides
-3x+2-2-(-7-2
simplify the arithmetic
-3x=-7-2
simplify the arithmetic aging
-3x=-9
=3
The arithmetic mean of ten numbers is 36. if one of the numbers is 18,What is the mean of the other nine?
My answer is in the picture
Reading - Word - Level 1
Vocabulary
Page 21
*
Safety is the number one priority at our trampoline parks.
That's why every session is supervised by our trained staff.
However, we cannot do it alone. We ask that parents and
guardians make sure their children follow our rules.
Informative
Persuasive
Answer:
crisp, clean, formal, readable
Step-by-step explanation:
which of these is right
Answer:
A
Step-by-step explanation:
For each point along it goes 1 point up, if it was 4x it'd go 4 points up
find the real numbers x&y so that (x^2+2xy)+i(y-1) = (x^2-2x+2y) - i(x+y)
Answer:
[tex]\displaystyle x_1 = 2-\sqrt{3} \text{ and } y_1 = \frac{\sqrt{3}-1}{2}[/tex]
Or:
[tex]\displaystyle x _ 2 = 2 + \sqrt{3} \text{ and } y _ 2 = -\frac{1+\sqrt{3}}{2}[/tex]
Step-by-step explanation:
We are given the equation:
[tex]\displaystyle (x^2 + 2xy) + i(y-1) = (x^2 -2x + 2y) - i(x +y)[/tex]
And we want to find the values of x and y such that the equation is true.
First, distribute:
[tex]\displaystyle (x^2 + 2xy) + i(y-1) = (x^2 -2x + 2y) +i(-x -y)[/tex]
If two complex numbers are equivalent, their real and imaginary parts are equivalent. Hence:
[tex]\displaystyle x^2 + 2xy = x^2 - 2x +2y \text{ and } y - 1 = -x -y[/tex]
Simplify:
[tex]\displaystyle 2xy = -2x +2y \text{ and }x = 1 - 2y[/tex]
Substitute:
[tex]\displaystyle 2(1-2y)y = -2(1-2y) + 2y[/tex]
Solve for y:
[tex]\displaystyle \begin{aligned} 2(y - 2y^2) &= (-2 + 4y) + 2y \\ 2y - 4y^2 &= 6y -2\\ 4y^2 + 4y - 2& = 0 \\ 2y^2 + 2y - 1 &= 0 \\ \end{aligned}[/tex]
From the quadratic formula:
[tex]\displaystyle \begin{aligned} y &= \frac{-(2)\pm\sqrt{(2)^2 - 4(2)(-1)}}{2(2)} \\ \\ &= \frac{-2\pm\sqrt{12}}{4} \\ \\ &= \frac{-2\pm2\sqrt{3}}{4}\\ \\ &= \frac{-1\pm\sqrt{3}}{2} \end{aligned}[/tex]
Hence:
[tex]\displaystyle y_1 = \frac{-1+\sqrt{3}}{2} \text{ or } y_2 = \frac{-1-\sqrt{3}}{2}[/tex]
Then:
[tex]\displaystyle x _ 1 = 1 - 2\left(\frac{-1+\sqrt{3}}{2}\right) = 1 + (1 - \sqrt{3}) = 2 - \sqrt{3}[/tex]
And:
[tex]\displaystyle x _ 2 = 1 - 2\left(\frac{-1-\sqrt{3}}{2}\right) = 1 + (1 + \sqrt{3}) = 2 + \sqrt{3}[/tex]
In conclusion, the values of x and y are:
[tex]\displaystyle x_1 = 2-\sqrt{3} \text{ and } y_1 = \frac{\sqrt{3}-1}{2}[/tex]
Or:
[tex]\displaystyle x _ 2 = 2 + \sqrt{3} \text{ and } y _ 2 = -\frac{1+\sqrt{3}}{2}[/tex]
x ^ 2 − 17x − 60
Which expression is equivalent to the expression above?
(Please explain in simple terms cause, it's usually hard for me to understand)
[tex] {x}^{2} - 17x - 60 \\ (x + 3)(x - 20)[/tex]
First we put parentheses and in each bracket we put (X) and then we put the signs x² is positive and the 17X before it is a negative q is positive with negative —> negative, and negative before 17X and negative before the 60 —> positive. And then the number that does not have (x) where did it come from, for example 60 came from 20 x 3 or 30 x 2...etc. We can verify this by multiplying the parentheses together and the same number comes out .
Or it can be checked by multiplying the first bracket 3 with x from the second parenthesis comes out 3X and negative 20 from the second parenthesis with X from the first parenthesis and subtract 3X from –20xcomes out –17X .
I hope I helped you^_^
PLssssssss helppppppppppppppppppppppp
Answer:
6 ft
Step-by-step explanation:
The shaded rectangle, which is the correct expression of its perimeter
Answer:
2x + 2y - 4
Step-by-step explanation:
The opposite sides are congruent so perimeter (P) is
P = 2(x + 2) + 2(y - 4)
= 2x + 4 + 2y - 8
= 2x + 2y - 4
PLS HELPP , i tried solving this and i wrote 56 but it was wrong so i don’t know anymore pls pls help
Answer:
y = 68
A = 44
Step-by-step explanation:
No matter what may be true, that doesn't look like an a to me.
x = y = 68 x and y are opposite equal sides and are therefore =.
68 + 68 + A = 180 all triangles are 180 degrees.
136 + A = 180 Subtract 136 from both sides
A = 180 - 136
A = 44
Point V is on line segment UW. Given VW = 5x - 4, UV = 2x, and UW = 5x, determine the numerical length of VW
Answer:
VW = 6
Step-by-step explanation:
To find x, set up the following equation:
(5x - 4) + (2x) = 5x
Solve out left side
7x - 4 = 5x
Subtract 5x from both sides
2x - 4 = 0
Add 4 to both sides
2x = 4
Divide both sides by 2
x = 2
Plug into 5x - 4
5(2) - 4
10 - 4
6
Answer:
6
Step-by-step explanation:
5x - 4 + 2x = 5x
7x - 4 = 5x
-4 = -2x
2 = x
5(2) - 4
10 - 4
6
Select the following statement that describes overlapping events.
A. Receiving a Jack of diamonds meets the requirement of getting both a Jack and a diamond
B. Amanda rolls a three when she needed to roll an even number
C. Amanda understands that she cannot get a black diamond when playing poker
D. Amanda wants a black card so she can have a winning hand, and she receive the two of hearts
Answer:
Step-by-step explanation:
Having a jack and also having a diamond, satisfies two sets in a Venn diagram. An overlapping set is the intersection of the two. So A is the only one that can be in an intersection of these two sets.
The statement from the given choices that describes an overlapping event is A. Receiving a Jack of diamonds meets the requirement of getting both a Jack and a diamond.
What are overlapping events in probability?Events that share one or more outcomes are said to be overlapping events.
How to solve the question?In the question, we are asked for the statements from the given options that describe overlapping events.
To check for overlapping events, we analyze each option as follows:-
A. Receiving a Jack of diamonds meets the requirement of getting both a Jack and a diamond. The receiving of a jack of diamond shows an overlapping event, with the overlapping of the events of getting a jack and getting a diamond.B. Amanda rolls a three when she needed to roll an even number. The rolling of a three when the requirement was to roll an even number doesn't show an overlapping event as three doesn't fall in even numbers.C. Amanda understands that she cannot get a black diamond when playing poker. The event of getting a black diamond is not overlapping as black cards are spades and clubs, and not diamonds.D. Amanda wants a black card so she can have a winning hand, and she receives the two of hearts. The event of receiving two of hearts when the requirement was of a black card is not an overlapping event as two of hearts is not a black card.Thus, the statement from the given choices that describes an overlapping event is A. Receiving a Jack of diamonds meets the requirement of getting both a Jack and a diamond.
Learn more about overlapping events at
https://brainly.com/question/17253921
#SPJ2
Is the function given by f(x)=3x-2 continuous at x=5?
Answer:
Yes the function is continuous f(5) = 13
Step-by-step explanation:
Replace the variable x with 5 in the expression
Simlify the results
f(5) = 3(5)-3
f(5) = 15=3
f(5) = 13
Plotting on a graph gives a coninous line with a positive gradient
y intercept (0,-2)
Please view the attached graph
2. Which type of variation is represented by the following equation?
indirect variation
Verification
[tex]\\ \rm\Rrightarrow s\propto \dfrac{1}{y}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{s_1}{t_2}=\dfrac{s_2}{t_1}[/tex]
[tex]\\ \rm\Rrightarrow s_1t_1=s_2t_2[/tex]
if M∠ ABD =64 and M∠CBD=30 then M∠ABC=
Need help
Answer:
[tex]\displaystyle m\angle ABC = 34^\circ[/tex]
Step-by-step explanation:
∠ABD is the sum of the angles ∠ABC and ∠CBD. In other words:
[tex]\displaystyle m\angle ABD = m\angle ABC + m\angle CBD[/tex]
Substitute in known values:
[tex]\displaystyle \left(64^\circ\right) = m\angle ABC + \left(30^\circ\right)[/tex]
And subtract. Hence:
[tex]\displaystyle m\angle ABC = 34^\circ[/tex]
In conclusion, ∠ABC measures 34°.
After subtracting 20% of a number from a number we get 12975.what was the number?
Answer:
Step-by-step explanation:
d
Find the area and the circumference of a circle with radius 7 ft.
Answer:
Area is 307.72 ft^2
Circumference is 43.96 ft
Step-by-step explanation:
Area is 2pir^2
Circumference is 2rpi
pi is about 3.14
A=2pi(7)^2
A= 98pi which is about 307.72 ft^2
C= 2(7)pi
C= 14pi which is about 43.96 ft
(I'm not sure whether they want the answer left in terms of pi or not)
Is the product of a rational number and an irrational number always irrational?
Answer:
The product of any rational number and any irrational number will always be an irrational number.
Step-by-step explanation:
