Land costing $140,000 was sold for $173,000 cash. The gain on the sale was reported on the income statement as other income. On the statement of cash flows, what amount should be reported as an investing activity from the sale of land?

Answer:

d.

Step-by-step explanation:

Here is an answer I found on the internet (kudos to investopedia.com)

If a Z-score is 0, it indicates that the data point's score is identical to the mean score.

In other words, it's saying that a z-score of zero has a standard deviation of zero.

Answer:

The slope is the cost per hour.

$5 per hour

Answer:

False

Step-by-step explanation:

Sorry for the lat reply hopefully you still have that question ready. But basically in order for these equations to be considered inverses of one another it has to map its domain value and switch it to the range value and in this case it does not match the inverse when graphed.

Given :-

To Find :-

Solution :-

We know that the circumference of the Circle with radius r is given by ,

=> C = 2πr .

=> C = 2 × 3.14 × 50 cm

=> C = 314 cm .

Hence the required answer is 314 cm .

Answer:

Step-by-step explanation:

b 75

Answer:

t = 1

Step-by-step explanation:

16 - 2t = 5t + 9

7 = 7t

t = 1

9514 1404 393

Answer:

  $10

Step-by-step explanation:

Price is proportional to the number of rings, so Zack will spend D dollars, where ...

  dollars/rings = D/50 = 1/5

  D = 50/5 = 10

Zack will spend $10 to buy 50 toy rings.

Answer:

The answer is "sometimes".

Step-by-step explanation:

A one-way ANOVA was merely performed on one collected data and the null hypothesis was rejected after an ANOVA F test. Assume we could randomize ANOVA block design with the same information. This null hypothesis for full equality is sometimes rejected for the randomized complete block design ANOVA. Therefore we understand the use of randomized ANOVA block if the null hypothesis is denied of a one-way ANOVA but the rejection of a null RBD ANOVA hypothesis isn't conditional mostly on denial of the yet another ANOVA null.

Answer:

the number of flight lines needed is approximately 72

Step-by-step explanation:

Given the data in the question;

Aerial photography is to be taken of a tract of land that is 8 x 8 mi²

L × B = 8 x 8 mi²

Flying height H = 4000 ft = ( 4000 × 12 )inches = 48000 in

focal length f = 6 in

[tex]l[/tex] × b = 9 × 9 in²

side overlap = 30% = 0.3

meaning remaining side overlap = 100% - 30% = 70% = 0.7

{ not end to end overlap }

we take 100% { remaining overlap }

[tex]l[/tex]' = 9 × 100% = 9 in

b' = 9 × 70% = 6.3 in

Now the scale will be;

Scale = f/H

we substitute

Scale = 6 in /  48000 in = 1 / 8000

so our scale is; 1 : 8000

⇒ 1 in = 8000 in

⇒ 1 in = (8000 / 63360)mi

⇒ 1 in = 0.126 mi

so since

L × B = 8 x 8 mi²

[tex]l[/tex]' = ( 9 × 0.126 mi ) = 1.134 mi

b' = ( 6.3 × 0.126 mi ) = 0.7938 mi

Now we get the flight lines;

N = ( L × B ) / ( [tex]l[/tex]' × b' )

we substitute

N = ( 8 mi × 8 mi ) / ( 1.134 mi × 0.7938 mi )

N = 64 / 0.9001692

N = 71.0977 ≈ 72

Therefore, the number of flight lines needed is approximately 72

Answer:

Consider points (-1, 0) and (0, 1) :

[tex]{ \tt{slope = \frac{y _{2} - y _{1} }{x _{2} - x _{1} } }} \\ { \tt{slope = \frac{1 - 0}{0 - ( - 1)} }} \\ { \boxed{ \bf{slope = 1}}}[/tex]

Answer:

slope 1

Step-by-step explanation:

above ANS is correct mark it as branliest ANS

Answer:

45 miles per hour

Step-by-step explanation:

d=distance in miles

r=rate miles/hr

t = time in hours

t = 352/(r+3)

330/r = 352/(r+3)

352r = 330r + 990

22r = 990

r = 45

Answer:

4.48 years

Step-by-step explanation:

The formula for simple interest is

A = P(1+r*t), with A being the final amount, P being the initial amount, r being the interest rate, and t being the time. Plugging our values in, we get

1750 = 1500(1+0.0372 * t)

Note that 3.72 was translated into 0.0372 as changing percents to decimals requires dividing by 100

Expanding our equation, we get

1750 = 1500 + 55.8 * t

subtract 1500 from both sides to isolate the t and its coefficient

250 = 55.8 * t

divide both sides by 55.8 to get t

t = 4.48

====================================================

Explanation:

We have an octagon because there are n = 8 sides. The diagram below shows one way to number the sides so you can count them efficiently (without missing any or double counting any).

----------------

Plug n = 8 into the formula below

S = 180(n-2)

S = 180(8-2)

S = 180(6)

S = 1080

The 8 interior angles add up to 1080 degrees.

Answer:

not true....

assume $100 start.

in year 1 you are at $108 (up 8%)

in year 2  $108(.98) ... that is 2% down = 105.84...

thus your profit is up only 5.84% over the two years

Step-by-step explanation:

Answer:

x = 69

Step-by-step explanation:

m<M = x

From the triangle we know that

m<M + m<MNQ + m<MQN = 180

From the parallel lines we know that

m<MNQ = m<UQN = x

x + x + 42 = 180

2x + 42 = 180

2x = 138

x = 69

Answer:

the degree is the value of the biggest exponent = 5 (fifth degree)

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Since the highest power of x is 5, the degree of the polynomial x

3

−9x+3x

5

is 5.

Answer:

[tex]y = - 9 + 2x[/tex]

Step-by-step explanation:

Objective: Use the rules of Algebra to isolate y.

[tex]4x - 2y = 18[/tex]

[tex] - 2y = 18 - 4x[/tex]

[tex]y = \frac{18 - 4x}{ - 2} [/tex]

[tex]y = - 9 + 2x[/tex]

Answer:

C

Step-by-step explanation:

The triangles are similar and the scale factor can be find out by computing 18/6=15/5=9/3=3

Answer:

23 + b ≤ -276

Step-by-step explanation:

In this exercise, you're required to write an algebraic expression for the word problem. Thus, you'll write out a mathematical equation using the given values and unknown variable.

Translating the word problem into an algebraic expression, we have;

23 + b ≤ -276

Simplifying further, we have;

b ≤ -276 - 23

b ≤ -299

Answer:

The answer is 10, hope this helps!

Step-by-step explanation:

Answer:

[tex]x^2 + 4x + y^2 +8y = 0[/tex]

Step-by-step explanation:

Given

[tex]A = (-1,-2)[/tex]

[tex]B = (2,4)[/tex]

[tex]AP:BP = 1 : 2[/tex]

Required

The locus of P

[tex]AP:BP = 1 : 2[/tex]

Express as fraction

[tex]\frac{AP}{BP} = \frac{1}{2}[/tex]

Cross multiply

[tex]2AP = BP[/tex]

Calculate AP and BP using the following distance formula:

[tex]d = \sqrt{(x - x_1)^2 + (y - y_1)^2}[/tex]

So, we have:

[tex]2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}[/tex]

[tex]2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}[/tex]

Take square of both sides

[tex]4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2[/tex]

Evaluate all squares

[tex]4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16[/tex]

Collect and evaluate like terms

[tex]4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20[/tex]

Open brackets

[tex]4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20[/tex]

Collect like terms

[tex]4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0[/tex]

[tex]3x^2 + 12x + 3y^2 +24y = 0[/tex]

Divide through by 3

[tex]x^2 + 4x + y^2 +8y = 0[/tex]

Answer:

95.73%

Step-by-step explanation:

Given data:

mean μ= 95

standard deviation, σ = 11

to calculate, the probability that a randomly selected firm will earn less than 114 million dollars;

Use normal distribution formula

[tex]P(X<114)=P(Z<\frac{X-\mu}{\sigma} )[/tex]

Substitute the required values in the above equation;

[tex]P(X<114)=P(Z<\frac{114-95}{11} )\\P(X<114)=P(Z<1.7272)\\P(X<114)=0.9573[/tex]

Therefore, the probability that a randomly selected firm will earn less than 114 million dollars = 95.73%

Answer:

The correct answer is 3x-2

Step-by-step explanation:

It gives you the expression for JM and LM, and it asks for JL. Therefore, if you take away LM from JM, you are left with JL. You must subtract 2x-6 from 5x-8.

∴5x-8-(2x-6)

Do not forget to distribute the negative since you are subtracting, so instead of subtracting 6 from 8, you will be adding 6 to 8 because two negatives make a positive.

Answer:

She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.

Step-by-step explanation:

Let x represent the number of times that she travels using the train and let y represent the number of times she travels using the bus. Since she makes at least 8 trips to the place, hence:

x + y ≥ 8

Also, she plans to spend no more than 9 hr in travel time. Hence:

x + 1.5y ≤ 9

x ≥ 0, y ≥ 0.

Plotting the above equations on geogebra online graphing tool, the solution is (6, 2), (8, 0) and (9, 0).

If a train trip costs ​$6 and a bus trip costs ​$5, The cost equation (C) is:

C = 6x + 5y

At point (6, 2): C = 6(6) + 5(2) = $46

At point (8, 0): C = 6(8) + 5(0) = $48

At point (9, 0): C = 6(9) + 5(0) = $54

Therefore the minimum cost is at (6, 2). She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.

9514 1404 393

Answer:

  no

Step-by-step explanation:

We assume you are concerned with the cubic

  x³ -9x² -14x +24

Its factors are all irrational, as shown in the attached graph. x-3 is not a factor.

__

x-3 is a factor if the expression evaluates to zero when x=3. Here, it does not.

  ((x -9)x -14)x +24 for x=3 is ...

  ((3 -9)(3) -14)(3) +24 = (-18 -14)(3) +24 = -96 +24 = -72

The remainder from division by x-3 is not zero, so x-3 is not a factor.

Answer:

The responses to these question can be defined as follows:

Step-by-step explanation:

For point a:

[tex]\to P(1) = 0.73[/tex]

For point b:

[tex]\to P(2\ or\ 3) = P(2) + P(3)[/tex]

                    [tex]= 0.27 \times 0.73 + 0.27\times 0.27\times0.73\\\\=0.1971+0.1971\times 0.27\\\\=0.1971+0.053217\\\\=0.250317[/tex]

Given:

The graph that represents the enrollment for college R between 1950 and 2000.

To find:

The average rate of increase in enrollment per decade between 1950 and 2000?

Solution:

The average rate of change of function f(x) over the interval [a,b] is:

[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]

So, the average rate of increase in enrollment per year between 1950 and 2000 is:

[tex]m=\dfrac{f(2000)-f(1950)}{2000-1950}[/tex]

[tex]m=\dfrac{7-4}{50}[/tex]

[tex]m=\dfrac{3}{50}[/tex]

[tex]m=0.06[/tex]

It is given average rate of increase in enrollment per year between 1950 and 2000 is 0.06.

We need to find the average rate of increase in enrollment per decade between 1950 and 2000, So, multiply the average rate of increase in enrollment per year by 10.

[tex]0.06\times 10=0.6[/tex]

Therefore, the average rate of increase in enrollment per decade between 1950 and 2000 is 0.6.

Answer:

Step-by-step explanation:

It’s G