All the experimental probabilities of the coin lands heads up 42 times and tails up 28 times as discuss below 5 points.
Define the term experimental probabilities?Experimental probability is the ratio of the number of times an event occurs to the total number of trials or experiments conducted. It is calculated by performing an experiment or observation and recording the outcomes, and then finding the ratio of the number of times the desired outcome occurred to the total number of trials.
The experimental probability of the coin landing heads up is 42/70, or 0.6.The experimental probability of the coin landing tails up is 28/70, or 0.4The theoretical probability of the coin landing heads up is 1/2, or 0.5.The theoretical probability of the coin landing tails up is 1/2, or 0.5.Liz is more likely to flip heads than tails, based on the experimental probability.To know more about probability, visit:
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As discussed in the next five paragraphs, the coin lands heads up 42 times and tails up 28 times in all experimental probability.
Define the term experimental probabilities?The ratio of the frequency of an occurrence to the total number of trials or experiments is known as the experimental probability. It is determined by carrying out an experiment or making an observation, noting the results, and then calculating the ratio of the number of times the desired result appeared to the total number of trials.
42/70, or 0.6, is the experimental likelihood that the coin will land facing up.
The experimental likelihood that the coin will fall tails up is 28/70, or 0.4.
Theoretically, there is a 0.5 percent chance that the coin will land with its head up.
Theoretically, there is a 0.5 percent chance that the coin will fall tails up.
According to the experimental probability, Liz is more likely to flip heads than tails.
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a) Find the approximations T8 and M8 for the integral Integral cos(x^2) dx between the limits 0 and 1. (b) Estimate the errors in the approximations of part (a). (C) How large do we have to choose n so that the approximation Tn and Mn to the integral in part (a) are accurate to within 0.0001?
(a) Using the Trapezoidal rule, T8 = (1/16)[cos(0) + 2cos(1/16) + 2cos(2/16) + ... + 2cos(7/16) + cos(1)].
Using the Midpoint rule, M8 = (1/8)[cos(1/16) + cos(3/16) + ... + cos(15/16)].
(b) The error in the Trapezoidal rule is bounded by (1/2880)(1-0)^3(max|f''(x)|), where f''(x) = -4x^2sin(x^2) and 0 <= x <= 1. Therefore, the error in T8 is approximately 0.00014. The error in the Midpoint rule is bounded by (1/1920)(1-0)^3(max|f''(x)|), which gives an approximate error of 0.00011 for M8.
(c) Let n be the number of intervals in the approximation.
Then, the error bound for the Trapezoidal rule is (1/2880)(1-0)^3(max|f''(x)|)(1/n^2), and the error bound for the Midpoint rule is (1/1920)(1-0)^3(max|f''(x)|)(1/n^2).
Setting these equal to 0.0001 and solving for n, we get n >= 129 and n >= 160 for the Trapezoidal and Midpoint rules, respectively. Therefore, we should choose n >= 160 to ensure that both approximations are accurate to within 0.0001.
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Theorem: "If a and m are relatively prime integers and m > 1, then an inverse of a modulo m exists. Furthermore, this inverse is unique modulo m. (That is, there is a unique positive integer a less than m that is an inverse of a modulo m and every other inverse of a modulo m is congruent to a modulo m.)"Question: Explain why the terms a and m have to be relatively prime integers?
The reason why the terms a and m have to be relatively prime integers is that it is the only way to make sure that ax≡1 (mod m) is solvable for x within the integers modulo m.
Theorem:"If a and m are relatively prime integers and m > 1, then an inverse of a modulo m exists. Furthermore, this inverse is unique modulo m. (That is, there is a unique positive integer a less than m that is an inverse of a modulo m and every other inverse of a modulo m is congruent to a modulo m.)"If a and m are relatively prime integers and m > 1, then an inverse of a modulo m exists. Furthermore, this inverse is unique modulo m. (That is, there is a unique positive integer a less than m that is an inverse of a modulo m and every other inverse of a modulo m is congruent to a modulo m.)The inverse of a modulo m is another integer, x, such that ax≡1 (mod m).
This theorem has an interesting explanation: if a and m are not co-prime, then there is no guarantee that ax≡1 (mod m) has a solution in Zm. The reason for this is that if a and m have a common factor, then m “absorbs” some of the factors of a. When this happens, we lose information about the congruence class of a, and so it becomes harder (if not impossible) to undo the multiplication by .This is the reason why the terms a and m have to be relatively prime integers.
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question 962946: if a triangle with all sides equal length has a perimeter of 15x 27, what is an expression for the length of one of it's sides?
If a triangle with all sides of equal length has a perimeter of 15x + 27, the expression for the length of one of the sides is (5x + 9).
How to find the expression for the length of one of the sides of a triangle?The perimeter of a triangle is the sum of the lengths of all three sides. If all the sides of the triangle are equal, you can find the length of one side by dividing the perimeter by 3. Here, the perimeter is given as 15x + 27.
Therefore, the length of one side will be (15x + 27) / 3 = 5x + 9. Hence, an expression for the length of one of the sides is (5x + 9).
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an offshore oil well is 5 kilometers off the coast. the refinery is 6 kilometers down the coast. laying pipe in the ocean is twice as expensive as on land. how many kilometers down the coast should the pipe be laid in order to minimize the cost?
An offshore oil well is 5 kilometers off the coast. The refinery is 6 kilometers down the coast. Laying pipe in the ocean is twice as expensive as on land. Kilometers down the coast should the pipe be laid in order to minimize the cost, the pipe should be laid approximately 8.62 km down the coast to minimize the cost.
How do we minimize the cost?Let the distance down the coast where the pipe is laid be x. Therefore, the distance from the refinery to the point where the pipe meets the shore will be (x + 5) km. The total distance of the pipe can be found using the Pythagorean Theorem.[tex]D = \sqrt{((x + 5)^2 + 6^2) } = \sqrt{(x^2+ 10x + 61)}[/tex] km
Let C(x) be the cost of laying the pipe down the coast at a distance x. Then
[tex]C(x) = 2[(x + 5) + 6] + 1.5[/tex][tex]D= 2(x + 11) + 1.5\sqrt{(x^2 + 10x + 61)}[/tex]Now, to minimize the cost, we have to find the value of x that minimizes C(x). The first derivative of C(x) is:[tex]C'(x) = 2 + 1.5 [x^2 + 10x + 61]^{-1/2} [2x + 10][/tex] After simplifying,[tex]C'(x) = [2(x^2 + 10x + 61) + 1.5(2x + 10)] [x^2 + 10x + 61]^{-1/2}= (3x^2 + 23x + 82) [x^2 + 10x + 61]^{-1/2}= 0[/tex] (at a minimum point)
Now we can solve for x using the above equation.[tex](3x^2 + 23x + 82) = 0[/tex] ⇒ [tex]3(x^2 + 7.67x + 27.33) = 0[/tex] Using the quadratic formula; x = {-b ± √(b² - 4ac)}/2 a We get, x = {-23 ± √(23² - 4(3)(82))}/2(3)x = {-23 ± √(529 - 984)}/6x = {-23 ± √(-455)}/6x = -3.03 or -8.62 Since x must be positive, x = -3.03 is not possible. Hence, the distance down the coast where the pipe should be laid in order to minimize the cost is :x = -8.62Therefore, the pipe should be laid approximately 8.62 km down the coast to minimize the cost.
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A relation contains the points (1, -4), (3, 2), (4, -3), (x, 7), and (-4, 6). For which values of x will the relation be a function?
In response to the stated question, we may state that To conclude, the function problem's relation is a function for all x values except x between 3 and 4.
what is function?In mathematics, a function is a connection between two sets of numbers in which each member of the first set (known as the domain) corresponds to a single element in the second set (called the range). In other words, a function takes inputs from one set and produces outputs from another. Inputs are commonly represented by the variable x, whereas outputs are represented by the variable y. A function can be described using an equation or a graph. The equation y = 2x + 1 represents a linear function in which each value of x yields a distinct value of y.
If and only if each input has precisely one output, a relation is a function. To determine whether the connection stated in the issue is a function, we must examine whether any x values have more than one output.
We may achieve this by putting the specified points on a graph and looking for vertical lines that cross the graph more than once. If so, the relationship is not a function.
We may create the following graph with the supplied points:
|
8 |
|
7 | ●
|
6 | ●
|
5 |
|
4 | ●
|
3 | ●
|
2 | ●
|
1 |
|
0 |
|
-1 |
|
-2 |
|
-3 |
|
-4 |
|
|_____________________
-4 -3 -2 -1 0 1 2 3 4
Apart for the line travelling through the points (3, 2) and (4, 2), there is no vertical line that intersects the graph in more than one spot (4, -3). As a result, if x is between 3 and 4, the relation specified in the issue is not a function.
To conclude, the problem's relation is a function for all x values except x between 3 and 4.
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The value of 5^2000+5^1999/5^1999-5^1997
Answer:
We can simplify the expression as follows:
5^(2000) + 5^(1999)
5^(1999) - 5^(1997)
= 5^(1999) * (1 + 1/5)
5^(1997) * (1 - 1/25)
= (5/4) * (25/24) * 5^(1999)
= (125/96) * 5^(1999)
Therefore, the value of the expression is (125/96) * 5^(1999).
Step-by-step explanation:
Triangle ABC has coordinates A(4,1), B(5,9),and C (2,7). If the triangle is translated 7 units to left, what are the coordinates of B'?
Answer:
(-2,9)
Step-by-step explanation:
when moving it 5 units left on the x axis it would be 5-7
So in turn you would be given (-2,9)
Because the y stays the same you would still have (?,9)
Find the angle measures for m∠QRS and m∠SRT.
Answer:
its 126 and 54 hope this helps
kernel composition rules 2 1 point possible (graded) let and be two vectors of the same dimension. use the the definition of kernels and the kernel composition rules from the video above to decide which of the following are kernels. (note that you can use feature vectors that are not polynomial.) (choose all those apply. )
a. 1
b. x.x’
c. 1+ x.x’
d. (1+ x.x’)^2
e. exp (x+x’), for x.x’ ER
f. min (x.x’) for x.x’ E Z
Answer:
Step-by-step explanation:
kernel composition rules 2 1 point possible (graded) let and be two vectors of the same dimension. use the the definition of kernels and the kernel composition rules from the video above to decide which of the following are kernels. (note that you can use feature vectors that are not polynomial.) (choose all those apply. )
4. A parking lot in the shape of a trapezoid has an area of 2,930.4 square meters. The length of one base is 73.4 meters, and the length of the other base is 3760 centimeters. What is the width of the parking lot? Show your work.
The parking lot has a width of around [tex]0.937[/tex] meters.
Are meters used in English?This same large percentage of govt, company, and industry use metric measurements, but imperial measurements are still frequently used for fresh milk sales and are marked with the metric equiv for journey distances, vehicle speeds, and sizes of returnable milk canisters, beer glasses, and cider glasses.
How much in math are meters?100 centimeters make up one meter. Meters are able to gauge a building's length or a playground's dimensions. 1000 meters make up one kilometer.
[tex]3760 cm = 37.6 m[/tex]
Solve for the width,
[tex]area = (1/2) * (base1 + base2) * height[/tex]
where,
base1 [tex]= 73.4 m[/tex]
base2 [tex]= 37.6 m[/tex]
area [tex]= 2,930.4[/tex] square meters
Let's solve for the height first,
[tex]height = 2 * area / (base1 + base2)[/tex]
[tex]height = 2 * 2,930.4 / (73.4 + 37.6)[/tex]
[tex]height = 2 * 2,930.4 / 111[/tex]
[tex]height = 56.16 m[/tex]
We nowadays can apply the algorithm to determine the width.
[tex]width = (area * 2) / (base1 + base2) * height[/tex]
[tex]width = (2 * 2,930.4) / (73.4 + 37.6) * 56.16[/tex]
[tex]width = 5856.8 / 111 * 56.16[/tex]
[tex]width = 5856.8 / 6239.76[/tex]
[tex]width = 0.937[/tex]
Therefore, the width of the parking lot is approximately [tex]0.937[/tex] meters.
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Select the correct answer. A parabola declines through (negative 2, 4), (negative 1 point 5, 2), (negative 1, 1), (0, 0) and rises through (1, 1), (1 point 5, 2) and (2, 4) on the x y coordinate plane. The function f(x) = x2 is graphed above. Which of the graphs below represents the function g(x) = (x + 1)2? A parabola declines through (negative 2, 5), (negative 1 point 5, 3), (negative 1, 2), (0, 1) and rises through (1, 2), (1 point 5, 3) and (2, 5) on the x y coordinate plane. W. A parabola declines through (negative 2, 3), (negative 1 point 5, 1), (1, 0), (0, negative 1) and rises through (1, 1), (1 point 5, 1) and (2, 2) on the x y coordinate plane. X. A parabola declines through (negative 3, 4), (negative 2 point 5, 2), (negative 2, 1), (negative 1, 0), (0, 1), (0 point 5, 2) and (1, 4) on the x y coordinate plane. Y. A parabola declines through (negative 1, 4), (negative 0 point 5, 2), (0, 1) and (1, 0) and rises through (2, 1), (2 point 5, 2) and (3, 4) on the x y coordinate plane. Z. A. W B. X C. Y D. Z
The correct answer is (C) Y.
Define the term graph?Graphs are used to represent relationships between data points or to illustrate patterns or trends in data.
To determine which graph represents the function g(x) = (x+1)², we can start by plotting the given points and sketching the graph of f(x) = x²:
Based on the given points and the graph of f(x), we can see that the vertex of g(x) is shifted one unit to the left from the vertex of f(x), and the graph opens upward.
Choice A does not match the given points, as the parabola does not decline through the given point (-2, 4)
Choice B does not match the given points, as the parabola does not rise through the given point (1.5, 2)
Choice C does match the given points, as the parabola declines through (-2, 5), (-1.5, 3), (-1, 2), (0, 1), and rises through (1, 2), (1.5, 3), and (2, 5)
Choice D does not match the given points, as the parabola does not rise through the given point (2.5, 2)
Therefore, the correct answer is (C) Y.
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As the parabola rises through (1, 2), (1.5, 3), and (0, 1) and declines through (-2, 5), (-1.5, 3), (-1, 2), and (0, 1), Choice C does not fit the provided points. (2, 5)
Define the term graph?In graphs, relationships between data elements are depicted as well as patterns or trends in the data.
We can begin by plotting the given points and sketching the graph of
[tex]f(x)=x^2[/tex] to identify which graph corresponds to the function
[tex]g(x) = (x+1)^2[/tex]:
The vertex of g(x) is one unit to the left of the vertex of f(x), and the graph opens upward, as can be seen from the provided points and the graph of f(x).
Choice A does not correspond to the points provided because the parabola does not decelerate through the point. (-2, 4)
The parabola does not rise through the given point in Choice B, so it does not meet the points supplied. (1.5, 2)
As the parabola rises through (1, 2), (1.5, 3), and (0, 1) and declines through (-2, 5), (-1.5, 3), (-1, 2), and (0, 1), Choice C does not fit the provided points. (2, 5)
Because the parabola does not rise through the indicated point, Choice D does not match the points provided. (2.5, 2)
Therefore, (C) Y is the right response.
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In a certain class of 40students, 90% passed ssce mathematics examinations and 75% passed English. If 2 students failed both mathematics and English, what percentage of students passed both examinations
30% percent of the students passed both Mathematics and English.
What is Percentage?A rate, number, or amount in each hundred is known as a percentage
Let's use a Venn diagram to represent the information given in the problem. Let M be the set of students who passed Mathematics, E be the set of students who passed English, and F be the set of students who failed both.
We know that there are 40 students in the class, and 90% passed Mathematics, so the number of students who passed Mathematics is 0.9 × 40 = 36. Similarly, 75% passed English, so the number of students who passed English is 0.75 × 40 = 30.
We also know that 2 students failed both Mathematics and English, so we can label the F section with 2.
where the number in each section represents the number of students who passed the respective exam.
To find the percentage of students who passed both examinations (i.e., the intersection of M and E), we need to add the number of students in the M and E intersection to the F section, then subtract that from the total number of students (40), and finally divide by 40 to get the percentage. That is:
percentage of students who passed both exams = (M ∩ E + F) / 40 × 100%
= (28 + 2) / 40 × 100%
= 30%
Therefore, 30% of the students passed both Mathematics and English.
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what is the x? please help its very important
dayna writes the integers 1,2,3,4,5,6,7,8,9,10,11,12 on a chalkboard, then she erases the integers from 1 through 6, as well as their multiplicative inverse $\mod{13}$. what is the only integer dayna does not erase?
Dayna erases the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, and 11, and leaves only the integer 12 on the chalkboard, by the concept of multiplicative inverse and by using the extended Euclidean algorithm.
The integers from 1 through 6, as well as their multiplicative inverse [tex]$\mod{13}$[/tex], have been erased from the integers 1 through 12. We need to find the only integer that Dayna did not erase. We can find the multiplicative inverse of an integer a modulo 13 by using the extended Euclidean algorithm.
The integers from 1 through 6 are 1, 2, 3, 4, 5, and 6. We need to find their multiplicative inverses modulo 13.
The multiplicative inverse of 1 modulo 13 is 1, since
[tex]$1 \times 1 \equiv 1 \pmod{13}$[/tex].
The multiplicative inverse of 2 modulo 13 is 7, since
[tex]$2 \times 7 \equiv 1 \pmod{13}$[/tex].
The multiplicative inverse of 3 modulo 13 is 9, since
[tex]$3 \times 9 \equiv 1 \pmod{13}$[/tex].
The multiplicative inverse of 4 modulo 13 is 10, since
[tex]$4 \times 10 \equiv 1 \pmod{13}$[/tex].
The multiplicative inverse of 5 modulo 13 is 8, since
[tex]$5 \times 8 \equiv 1 \pmod{13}$[/tex].
The multiplicative inverse of 6 modulo 13 is 11, since
[tex]$6 \times 11 \equiv 1 \pmod{13}$[/tex].
Therefore, the only integer that Dayna does not erase is 12.
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Find the real part of the particular solution Find the real part of the particular solution to the differential equation dạy 3 dt2 dy +5 + 7y =e3it dt in the form y=Bcos(3t) + C sin(3t) where B, C are real fractions. = Re(y(t)) = = symbolic expression ?
The real part of the particular solution to the differential equation is [tex](1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]
The real part of the particular solution to the differential equation:
[tex]\frac{d^2y}{dt^2} +3\frac{dy}{dt} +7y = e^(3it)[/tex]
First, we assume a particular solution of the form:
[tex]y(t) = Bcos(3t) + Csin(3t)[/tex]
where B and C are real fractions.
Taking the first and second derivatives of y(t), we get:
[tex]\frac{dy}{dt} = -3Bsin(3t) + 3Ccos(3t)[/tex]
[tex]\frac{d^2y}{dt2} = -9Bcos(3t) - 9Csin(3t)[/tex]
Substituting these into the differential equation, we get:
[tex](-9Bcos(3t) - 9Csin(3t)) + 3(-3Bsin(3t) + 3Ccos(3t)) + 7(Bcos(3t) + Csin(3t)) = e^(3it)[/tex]
Simplifying and collecting terms, we get:
[tex](-9B + 21C)*cos(3t) + (-9C - 9B)*sin(3t) = e^(3it)[/tex]
Comparing the coefficients of cos(3t) and sin(3t), we get:
[tex]-9B + 21C = Re(e^(3it))[/tex]
[tex]-9C - 9B = 0[/tex]
Solving for B and C, we get:
[tex]B = -C[/tex]
[tex]C = (1/30)*Re(e^(3it))[/tex]
Therefore, the particular solution is:
[tex]y(t) = -Ccos(3t) + Csin(3t) = (1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]
A differential equation is a mathematical equation that relates a function to its derivatives. It is a powerful tool used in many fields of science and engineering to describe how physical systems change over time. The equation typically includes the independent variable (such as time) and one or more derivatives of the dependent variable (such as position, velocity, or temperature).
Differential equations can be classified based on their order, which refers to the highest derivative present in the equation, and their linearity, which determines whether the equation is a linear combination of the dependent variable and its derivatives. Solving a differential equation involves finding a function that satisfies the equation. This can be done analytically or numerically, depending on the complexity of the equation and the available tools.
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in fig. 8-25, a block slides along a track that descends through distance h.the track is frictionless except for the lower section. there the block slides to a stop in a certain distance d because of friction. (a) if we decrease h,will the block now slide to a stop in a distance that is greater than, less than, or equal to d? (b) if, instead, we increase the mass of the block, will the stopping distance now be greater than, less than, or equal to d?
a block slides along a track that descends through distance h. The track is frictionless except for the lower section. There the block slides to a stop in a certain distance d because of friction. If we decrease h, will the block now slide to a stop in a distance that is greater than, less than, or equal to d?As per the given information, when a block slides along a track that descends through a distance h, the track is frictionless except for the lower section. There the block slides to a stop in a certain distance d because of friction. Now if we decrease h, then the distance covered by the block before it comes to rest will also decrease. So the block will slide to a stop in a distance that is less than d. Hence the answer is less than d.If we increase the mass of the block, will the stopping distance now be greater than, less than, or equal to d?
As the mass of the block increases, the force of friction acting on the block will also increase. Hence the stopping distance will also increase. So the stopping distance now will be greater than d. Hence the answer is greater than d.In conclusion, the answer to (a) is less than d, and the answer to (b) is greater than d.
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cos(-180").tan 8.cos 690 sin (8-180) cos² (6-90) (5)
cos(-180°) = -1
tan 8° = 0.1425
cos 690° = 0
sin (8-180°) = - sin 172° = - 0.9997
cos² (6-90°) = cos(-84°) = 0.4997
Therefore, the answer to the expression is -0.4997.
If the volume of a hexagonal prism is 3,660 ft³, what is the volume of a hexagonal pyramid in cubic feet
with the same dimensions?
The volume of a hexagonal pyramid in cubic feet with the same dimensions = 1220 ft³
What is hexagonal pyramid?A hexagοnal pyramid is a three-dimensiοnal geοmetric shape that cοnsists οf a base that is a regular hexagοn (a six-sided pοlygοn with all sides and angles equal) and six triangular faces that meet at a single pοint abοve the base, called the apex. The six triangular faces fοrm a pyramid shape with the base, which is why it's called a hexagοnal pyramid.
This relatiοnship can be derived using the fοrmula fοr the vοlume οf a pyramid V = (1/3)Bh, where B is area οf base and h is height οf pyramid. Since the base οf the pyramid is a hexagοn inscribed within the hexagοnal base οf the prism, the area οf the base is (3√3/2)a², where a is the side length οf the hexagοn. The height οf the pyramid is the same as the height οf the prism, which we can call h.
Thus, the volume of pyramid is
[tex]\rm V_p[/tex] = (1/3)(3√3/2)a²h
= (√3/2)a²h, while the volume of prism is
[tex]\rm V_p[/tex]r = [tex]\rm B_p[/tex]r h = (3√3/2)a²h.
Dividing [tex]\rm V_p[/tex]r by 3 gives [tex]\rm V_p[/tex]
so we have [tex]\rm V_p[/tex] = [tex]\rm V_p[/tex]r/3, as claimed. so
[tex]\rm V_p[/tex] = 3360/3 ft³
[tex]\rm V_p[/tex] = 1220ft³
volume of a hexagonal pyramid in cubic feet 1220ft³
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If θ = 1 π 6 , then find exact values for the following: sec ( θ ) equals csc ( θ ) equals tan ( θ ) equals cot ( θ ) equals Add Work
If θ = 1π/6 then six trigonometric functions of θ are: sec(θ), cos(θ), tan(θ), cot(θ), is [tex]((2 \sqrt{(3)})[/tex], [tex]\sqrt(3)/2[/tex], [tex]\sqrt{(3)}/3[/tex], and [tex]\sqrt{(3)[/tex], respectively.
To find the exact values of sec(θ), cos(θ), tan(θ), and cot(θ) when θ = π/6 radians, we can use the unit circle and the basic trigonometric ratios.
First, we locate the point on the unit circle corresponding to θ = π/6, which has coordinates[tex](\sqrt{(3)}/2, 1/2).[/tex]
Then, we can use the definitions of the trigonometric ratios to calculate their exact values:
sec(θ) = 1/cos(θ) = [tex]2\sqrt3 = (2 \sqrt{(3)})[/tex]
cos(θ) = adjacent/hypotenuse =[tex]\sqrt{(3)}/2[/tex]
tan(θ) = opposite/adjacent = [tex]\sqrt{(3)}/3[/tex]
cot(θ) = adjacent/opposite = [tex]\sqrt(3)[/tex]
Therefore, the exact values of sec(θ), cos(θ), tan(θ), and cot(θ) when θ = π/6 are [tex]((2 \sqrt{(3)})[/tex], [tex]\sqrt(3)/2[/tex], [tex]\sqrt{(3)}/3[/tex], and [tex]\sqrt{(3)[/tex], respectively.
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5x-2=3(x+4)
What is the value of X
Answer:
[tex]\large\boxed{\textsf{x = 7}}[/tex]
Step-by-step explanation:
[tex]\textsf{For this problem, we are asked to find the value of x.}[/tex]
[tex]\textsf{We should simply isolate the x so that it's only on one side.}[/tex]
[tex]\large\underline{\textsf{How?}}[/tex]
[tex]\textsf{Simply use the Distributive Property for the right side of the equation.}[/tex]
[tex]\textsf{Simplify the equation to where x is by itself.}[/tex]
[tex]\large\underline{\textsf{What is the Distributive Property?}}[/tex]
[tex]\textsf{The Distributive Property is a Property that allow us to distribute expressions further.}[/tex]
[tex]\textsf{Commonly, the form is a(b+c); Where b and c are multiplied by a.}[/tex]
[tex]\large\underline{\textsf{Use the Distributive Property;}}[/tex]
[tex]\mathtt{5x-2=3(x+4)}[/tex]
[tex]\mathtt{5x-2=(3 \times x)+(3 \times 4)}[/tex]
[tex]\mathtt{5x-2=3x+12}[/tex]
[tex]\large\underline{\textsf{Add 2 to Both Sides of the Equation;}}[/tex]
[tex]\mathtt{5x-2 \ \underline{+ \ 2}=3x+12 \ \underline{+ \ 2}}[/tex]
[tex]\mathtt{5x=3x+14}[/tex]
[tex]\large\underline{\textsf{Subtract 3x from Both Sides of the Equation;}}[/tex]
[tex]\mathtt{5x-3x=3x-3x+14}[/tex]
[tex]\mathtt{2x=14}[/tex]
[tex]\large\underline{\textsf{Divide the Whole Equation by 2;}}[/tex]
[tex]\mathtt{\frac{2x}{2} = \frac{14}{2} }[/tex]
[tex]\large\boxed{\textsf{x = 7}}[/tex]
Answer:
[tex] \sf \: x = 7[/tex]
Step-by-step explanation:
Now we have to,
→ Find the required value of x.
The equation is,
→ 5x - 2 = 3(x + 4)
Then the value of x will be,
→ 5x - 2 = 3(x + 4)
→ 5x - 2 = 3(x) + 3(4)
→ 5x - 2 = 3x + 12
→ 5x - 3x = 12 + 2
→ 2x = 14
→ x = 14 ÷ 2
→ [ x = 7 ]
Hence, the value of x is 7.
this question has several parts that must be completed sequentially. if you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. tutorial exercise use the trapezoidal rule and simpson's rule to approximate the value of the definite integral for the given value of n. round your answers to four decimal places and compare the results with the exact value of the definite integral. integral 0 - 4 for x2 dx, n=4
The Simpson's rule gives a more accurate approximation of the definite integral.
The question requires you to use both the trapezoidal rule and Simpson's rule to approximate the value of a definite integral for the given value of n. Then, you should round your answers to four decimal places and compare the results with the exact value of the definite integral.Integral: 0 - 4 for x^2 dx, n=4Using Trapezoidal Rule:The Trapezoidal rule is a numerical integration method used to calculate the approximate value of a definite integral. The rule involves approximating the region under the graph of the function as a trapezoid and calculating its area. The formula for Trapezoidal Rule is given by:∫baf(x)dx≈h2[f(a)+2f(a+h)+2f(a+2h)+……+f(b)]whereh=b−anUsing n = 4, we get, h = (b-a)/n = (4-0)/4 = 1Therefore,x0 = 0, x1 = 1, x2 = 2, x3 = 3 and x4 = 4f(x0) = 0, f(x1) = 1, f(x2) = 4, f(x3) = 9, and f(x4) = 16∫4.0x^2 dx = (1/2)[f(x0) + 2f(x1) + 2f(x2) + 2f(x3) + f(x4)](1/2)[0 + 2(1) + 2(4) + 2(9) + 16] = 37
Using Simpson's Rule:Simpson's rule is a numerical integration method that is similar to the Trapezoidal Rule, but the function is approximated using quadratic approximations instead of linear approximations. The formula for Simpson's Rule is given by:∫baf(x)dx≈h3[ f(a)+4f(a+h)+2f(a+2h)+4f(a+3h)+….+f(b)]whereh=b−an, and n is even.Using n = 4, we get, h = (b-a)/n = (4-0)/4 = 1Therefore, x0 = 0, x1 = 1, x2 = 2, x3 = 3 and x4 = 4f(x0) = 0, f(x1) = 1, f(x2) = 4, f(x3) = 9, and f(x4) = 16∫4.0x^2 dx = (1/3)[f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + f(x4)](1/3)[0 + 4(1) + 2(4) + 4(9) + 16] = 20Comparing the results with the exact value of the definite integral, we have:Integral 0 - 4 for x^2 dx = ∫4.0x^2 dx = [x^3/3]4.0 - [x^3/3]0 = 64/3 ≈ 21.3333Thus, using Trapezoidal Rule, we get an approximation of 37, which has an error of 15.6667, while using Simpson's Rule, we get an approximation of 20, which has an error of 1.3333. Therefore, Simpson's rule gives a more accurate approximation of the definite integral.
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A skating rink charges a group rate of $9 plus a fee to rent each pair of skates. A family rents 7 pairs of skates and pays a total of $30. Draw a tape diagram
Answer:
X = 3
Step-by-step explanation:
I can't really draw the diagram for you.
$9 is always charged so just add that to the end of your equation.
x is what they charge for skates and their are 7 skates so 7x
$30 is the total
7x + 9 = 30
subtract 9 from both sides
7x = 21
divide by 7 on both sides
x = 3
The equation and graph show the distance traveled by a covertible and a limousine in miles, y, as a function of time in hours, x.
The rate of change of the distance for limousine is less than the rate of change of the convertible.
What is rate of change?How much a quantity changes over a specific time period or interval is the subject of the mathematical notion of rate of change. Several real-world occurrences are described using this basic calculus notion.
In mathematics, the ratio of a quantity change to a time change or other independent variable is used to indicate the rate of change. For instance, the rate at which a location changes in relation to time is called velocity, and the rate at which a velocity changes in relation to time is called acceleration.
The equation of the distance travelled by the convertible is given as:
y = 35x
The equation of the limousine can be calculated using the coordinates of the graph (1, 30) and (2, 60).
The slope is given as:
slope = (change in y) / (change in x) = (60 - 30) / (2 - 1) = 30
Using the point slope form:
y - 30 = 30(x - 1)
y = 30x
So the equation of the limousine is y = 30x.
Comparing the rates, that is the slope we observe that, the rate of change of the limousine is lower than the rate of change of the convertible.
Hence, the rate of change of the limousine is less than the rate of change of the convertible.
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A sphere is to be designed with a radius of 72 in. Use differentials to estimate the maximum error when measuring the volume of the sphere if the possible error in measuring the radius is 0.5 in. 4 (Hint: The formula for the volume of a sphere is V(r) = ²³.) O 452.39 in ³ O 16,286.02 in ³ O 65,144.07 in ³ O 32,572.03 in ³
By using differentials to estimate the maximum error when measuring the volume of the sphere if the possible error in measuring the radius is 0.5. It will be 32,572.03 in³. Which is option (d).
How to measure the maximum error while measuring the volume of a sphere?The possible error in measuring the radius of the sphere is 0.5 in
The formula for the volume of a sphere is given by V(r) = 4/3πr³
The volume of the sphere when r=72 in is given by V(72) = 4/3π(72)³
When r= 72 + 0.5 in= 72.5 in, the volume of the sphere can be calculated using the formula:
V(72.5) = 4/3π(72.5)³
The difference between these two volumes, V(72) and V(72.5), gives us the maximum error while measuring the volume of a sphere. It can be calculated as follows:
V(72.5) - V(72) = 4/3π(72.5)³ - 4/3π(72)³= 4/3π [ (72.5)³ - (72)³ ]= 4/3π [ (72 + 0.5)³ - 72³ ]= (4/3)π [ 3(72²)(0.5) + 3(72)(0.5²) + 0.5³ ]≈ (4/3)π [ 777.5 ]= 3.28 × 10⁴ in³
Therefore, the maximum error while measuring the volume of a sphere with a radius of 72 in, where the possible error in measuring the radius is 0.5 in, is approximately 3.28 × 10⁴ in³ or 32,572.03 in³. Therefore coorect option is (D).
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7. A medical technologist notes after observation under the microscope that in one of the samples to be tested, many red blood cells are crenated. Give a possible explanation for this observation.
8. Tugor pressure results one plant cells are placed in hypotonic solution. Why don't the cells burst?
9. A red blood cell is placed in a hypotonic solution. what is the fate of the cell?
7. Possible explanation for the observation is that the cells were in a hypertonic environment and lost water by osmosis. This may be due to exposure to a high concentration of salts, sugars or urea. Cells may also become crenated when exposed to low temperatures
.8. The cells don't burst due to the pressure of the cell wall that counteracts the force exerted by the water trying to get in the cells. The cell wall is made up of cellulose, which is strong enough to maintain the shape of the cell.
9. The red blood cell will expand due to water moving into the cell, resulting in the cell being ruptured or lysed, ultimately killing it in a hypotonic environment.
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A right triangle is describe as having an angle of measure six less than negative two times a number, another angle measure that is three less than negative one-fourth the number, and a right angle. What are the measure of the angles in degree
The angles measure 90°, -2x - 6, and -1/x - 3. ⇒ x = -44. Therefore, the required measures of the angles are 90°, 82°, and 8° in the given triangle.
A right triangle is a type of triangle where one of the angles measures exactly 90 degrees. This angle is known as the right angle, and it is formed by the intersection of the two sides of the triangle that are perpendicular to each other. The other two angles of the right triangle are acute angles, meaning they measure less than 90 degrees.
The side opposite the right angle is called the hypotenuse, and it is always the longest side of the right triangle. The other two sides are called legs, and they can be of different lengths. This theorem is one of the most important and useful tools in geometry, and it allows us to solve many practical problems involving right triangles, such as finding the height of a building.
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Find the roots of the polynomial equation.
x^3-x^2+x+39=0
Answer:
-3, 2+3i, and 2-3i.
Step-by-step explanation:
To find the roots of x^3-x^2+x+39=0, we use the Rational Root Theorem and synthetic division to test possible rational roots. We find that -3 is a root, and divide by (x+3) to get the quadratic factor x^2-4x+13=0. Solving this using the quadratic formula gives us the remaining roots of 2+3i and 2-3i. Therefore, the roots of the equation are -3, 2+3i, and 2-3i.
Two numbers have a sum of 1022. They have a difference of 292. What are the two numbers
Answer:
The answer is 657 and 365.
Step-by-step explanation:
Let the two numbers be x and y respectively
In first case,
x+y=1022
x=1022-y----------- eqn i
In second case
x-y=292
1022-y-y=292 [From eqn i]
1022-2y=292
1022-292=2y
730=2y
730/2=y
y=365
Substituting the value of y in eqn i
x=1022-y
x=1022-365
x=657
Hence two numbers are 657 and 365.
Pls mark me as brainliest if you got the answer
I need some help with this
Answer:
12
Step-by-step explanation:
i think its right
Find the surface area of the solid
The solid has a surface area of about 401.92 cm2.
How can you figure out surface area?A three-dimensional shape's surface area is the sum of all of its faces. The surface area of a shape can be calculated by finding the area of each face and combining them.
The surface areas of the cylinder and the hemisphere must be added to determine the solid's surface area.
The cylinder's surface area is equal to 2rh + 2r2, where r is the cylinder's radius and h is its height.
The hemisphere's surface area is equal to 2r2, where r is the hemisphere's radius.
As the cylinder's and hemisphere's radiuses are equal, we can sum their two surface areas as follows:
The solid's surface area is equal to 2rh plus 2r2 plus 2r2.
= 2πrh + 4πr²
Solid's surface area is equal to 2(4)(8) + 4(4)(2).
= 64π + 64π
= 128π
≈ 401.92 cm²
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