make a box-and-whisker plot for the data. numbers of colors in a country's flag :3,2,2,4,4,3,6,3,5,3,4,1
Answers
Answer: see attachment
Step-by-step explanation:
Put the numbers in order from smallest to biggest:
1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 6
↓ ∨ ↓
Q1 Median Q3
Q1 median = (2+3)/2 = 2.5 <---- left side of box plot
Median = (3+3)/2 = 3 <---- Vertical Line of box plot
Q3 median = (4+4)/2 = 4 <---- right side of box plot
Related Questions
A house m by m is surrounded by a walkway m wide. 27 9 1.8 a) Find the area of the region covered by the house and the walkway. b) Find the area of the walkway.
Answers
Answer:
A. 385.56 square meters.
B. 142.56 square meters.
Step-by-step explanation:
A house 27m by 9m is surrounded by a walkway 1.8m wide.
a) Find the area of the region covered by the house and the walkway.
b) Find the area of the walkway.
Let
Length of the house=l=27m
Width of the house=w=9m
Wideness of the walkway=x=1.8m
Area of the region covered by the house and the walkway
=( L + 2*x) * (w + 2*x)
= (27+2*1.8)*(9+2*1.8)
=(27+3.6)*(9+3.6)
=(30.6)*(12.6)
=385.56 square meters.
b) Area of the walkway
= (L + 2*x)*(w + 2*x) - l*w
= (27+2*1.8)*(9+2*1.8) - 27*9
=(27+3.6)*(9+3.6) - 243
=(30.6)*(12.6) - 243
=385.56 - 243
=142.56 square meters.
Please answer this correctly without making mistakes
Answers
Answer:
17/16 OR [tex]1\frac{1}{16}[/tex] minutes
Step-by-step explanation:
Since Jayla spent 1/16 of a minute AND one whole minute watching a millipede crawl, we'd need to first add the two numbers.
Since the given minute is out of 16, we can convert the one minute to 16/16. This means we can add the other 1/16 of a minute.
This leaves us with Jayla watching the millipede for 17/16 OR [tex]1\frac{1}{16}[/tex] minutes.
Hope this helps!! <3 :)
Blake bought two iced coffees from Dutch Bros. He originally had $13.50 and now has $9. Write and solve an equation to find out how much each iced
coffee cost.
Answers
Answer:
each ice coffee is $2.25
Step-by-step explanation:
13.50 - 9 = 4.50
4.50 / 2 = 2.25
If you move from zero to 15 on the number line, you are representing all of the following exce
the opposite of -15
the opposite of 15
the absolute value of 15
the distance between zero and 15
Answers
Answer: the opposite of 15
Step-by-step explanation:
Every number 'a' on number line is exactly opposite of '-a'.
So, 15 is the opposite of '-15'
Also absolute value for any number gives its positive value, soabsolute value of 15 = 15
Moving 0 to 15 gives the distance between zero and 15.
So all statements are true except "the opposite of 15".
Hence, the required statement is "the opposite of 15".
Consider the following. C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)
a. Find a piecewise smooth parametrization of the path C.
r(t) = { 0
b Evaluate
Integral of (x+2y^1/2)ds
Answers
Answer:
a.
[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]
[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]
[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]
b.
[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]
Step-by-step explanation:
Given that:
C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)
a. Find a piecewise smooth parametrization of the path C.
r(t) = { 0
If C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1),
Then:
[tex]C_1 = (0,0) \\ \\ C_2 = (1,0) \\ \\ C_3 = (0,1)[/tex]
Also:
[tex]\mathtt{r_1 = (0,0) + t(1,0) = (t,0) }[/tex]
[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]
[tex]\mathtt{r_2 = (1,0) + t(-1,1) = (1- t,t) }[/tex]
[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]
[tex]\mathtt{r_3 = (0,1) + t(0,-1) = (0,1-t) }[/tex]
[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]
b Evaluate :
Integral of (x+2y^1/2)ds
[tex]\mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \int \limits ^1_{0} \ (t + 0) \sqrt{1} } \\ \\ \mathtt{ \int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \begin {pmatrix} \dfrac{t^2}{2} \end {pmatrix} }^1_0 \\ \\ \mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \dfrac{1}{2}}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits (x+2 \sqrt{y} \sqrt{(\dfrac{dx}{dt})^2 + (\dfrac{dy}{dt})^2 \ dt } }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits 2- t + 2\sqrt{t-1} \ \sqrt{1+1} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} \int \limits^2_1 2- t + 2\sqrt{t-1} \ dt }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2t - \dfrac{t^2}{2}+ \dfrac{2(t-1)^{3/2}}{3} (2) \end {pmatrix} ^2_1}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{1}{2} (4-1)+\dfrac{4}{3} (1)^{3/2} -0 \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{3}{2} + \dfrac{4}{3} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{12-9+8}{6} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{11}{6} \end {pmatrix} }[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ \sqrt{2} }{6} \ (11 )}[/tex]
[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ 11 \sqrt{2} }{6}}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 0+2 \sqrt{3-t} \ \sqrt{0+1} }[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 2 \sqrt{3-t} \ dt}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits^3_2 \begin {pmatrix} \dfrac{-2(3-t)^{3/2}}{3} (2) \end {pmatrix}^3_2 }[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [(0)-(1)]}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [-(1)]}[/tex]
[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \dfrac{4}{3}}[/tex]
[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}}{6}+\dfrac{1}{2}+ \dfrac{4}{3}}[/tex]
[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+3+8}{6}}[/tex]
[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]
I need help with this
Answers
Answer:
The fraction that represents the heart in the diagram shown is 7/3
Step-by-step explanation:
For this problem, we have to find the fraction expressed by the number line in the diagram shown.
First off, we know that the fraction will be between 2 and 3. Second, we know that each little dash between 2 and 3 represents 1/6.So, let's use this information to find the fraction.
Since the heart is two dashes away from 2, then this part of the fraction is 2/6 which can also be simplified to 1/3.
2 1/3
Since we can not have a mixed fraction, then we are going to turn this mixed number into an improper fraction. We do this by multiplying 2 with the denominator (which is 3) and adding the numerator (which is 1) to that product. Our denominator will stay the same in the final fraction.
2 1/3 = 7/3
So, the fraction represented by the heart is 7/3
Answer:
16/7
Step-by-step explanation:
There are 7 divisions between the numbers 2 and 3
So the denominator is 7
The heart is at the second mark
We are past the 2 mark so it is
2 2/7
Changing this from a mixed number to an improper fraction
(7*2+2) /7
16/7
For an ordered pair (x,y) in a relation, the y element represents the
a.) range
b.) domain
c.) function
d.) input
Answers
Explanation:
x represents the domain
y represents the range
y represents the range for an ordered pair (x, y). Option A is correct.
For an ordered pair (x, y), What y represents is to determine.
Range of the function is the output value of the function.
Here, in ordered pair (x, y) x represents the values of independent variable terms as domain. And for every value of x their is exist or output values y this set of y values is called as range.
Thus, y represents the range for an ordered pair (x, y).
Learn more about range here:
https://brainly.com/question/17553524
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Help me I’m stuck please
Answers
Answer:
choice 1,2,4,5 from top to bottom
Step-by-step explanation:
1:the points given are in the line where both planes intersect
2:point H is not on any plane
3:in the diagram point F is on plane R so false
4:if you connect the points given they will intersect so not collinear
5:the points F and G are on the plane R
6:so F is on plane R but H is not on any do false
If Discriminant > 0 :
What is "m" in ( 2x^2 + 4x + 1 - 3m=0) ?
Answers
The given equation is in the form ax^2+bx+c = 0 with
a = 2b = 4c = 1-3mD = discriminant
D = b^2 - 4ac
D = 4^2 - 4(2)(1-3m)
D = 16 - 8(1-3m)
D = 16 - 8 + 24m
D = 24m + 8
D > 0
24m + 8 > 0
24m > -8
m > -8/24
m > -1/3
As long as m is larger than -1/3, then the discriminant is positive. There are infinitely many solutions to pick from.
Jasmine is making 150 bracelets and she needs 26 cm of silver wire for each bracelet. She will buy either the 3.7 metre or the 10.5 metre packs. She wants to pay as little as possible for the silver wire. How much will she have to pay for the silver wire to make 150 bracelets? £
Answers
Answer:
The least possible price is p = £110
Step-by-step explanation:
From the question we are told that
The number of bracelets to be made is [tex]n = 150[/tex]
The length of silver require for on bracelet is [tex]x = 26 \ cm = 0.26 \ m[/tex]
The option of silver length packs that she buys is a = 10.5 m packs
b = 3.7 m packs
Generally
1 bracelet [tex]\to[/tex] 0.26 m
150 bracelet [tex]\to[/tex] z
=> [tex]z = \frac{150 * 0.26}{1}[/tex]
=> [tex]z = 39 \ m[/tex]
Now for option a i.e 10.5 m per pack
The number of packs require is
[tex]v = \frac{z}{a}[/tex]
=> [tex]v = \frac{39}{ 10.5}[/tex]
=> [tex]v = 3.7 1[/tex]
given that the number of packs cannot be a fraction but an integer hence she needs to purchase v = 4
and that 4 packs would equal t = 4 * 10.5 = 42 meters of silver
Now for option d i.e 3.7 meters per pack
The number of packs requires is
[tex]w = \frac{z}{b}[/tex]
=> [tex]w = \frac{39}{3.7}[/tex]
=> [tex]w = 10.54[/tex]
given that the number of packs cannot be a fraction but an integer hence she needs to purchase w= 11
and that 11 packs would equal t = 11 * 3.7 = 40.7 meters of silver
So the comparing the option and option b we see that for her to pay as little as possible she needs to go for option b since option be will produce the 150 bracelet with a little excess while option a will produce the 150 bracelet with much excess
Assuming the price for the 3.7 m pack is £10
And the price for the 10.7 pack is £30
The least possible amount she would pay is
[tex]p = 10 * 11[/tex]
p = £110
In the diagram, ∆ABC and ∆DBE are similar. What is the scale factor of the dilation that will map the preimage ΔABC onto the image ΔDBE? A. 1.33 B. 0.75 C. 0.66 D. 0.55
Answers
Answer:
B
Step-by-step explanation:
Calculate the ratio of corresponding sides, image to preimage, that is
scale factor = [tex]\frac{DE}{AC}[/tex] = [tex]\frac{12.09}{16.12}[/tex] = 0.75 → B
The scale factor of the dilation will be 1.33. Then the correct option is A.
What is dilation?Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.
There is no effect of dilation on the angle.
In the diagram, ∆ABC and ∆DBE are similar.
Then the scale factor of the dilation that will map the preimage ΔABC onto the image ΔDBE will be
⇒ 16.12 / 12.09
⇒ 1.33
Then the correct option is A.
More about the dilation link is given below.
https://brainly.com/question/2856466
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At a sale, dresses were sold for $39 each. This price was 65% of a dress's original price. How much did a dress originally cost?
Answers
Answer:
Hey there!
We can write the equation:
0.65x=39
x=60
The dress originally sold for 60 dollars.
Hope this helps :)
What is the biggest value of probability?
Answers
Answer:
1
Step-by-step explanation:
Answer:
Hello There!!
Step-by-step explanation:
The answer is 1 as that means its certain that the event will happen.
hope thus helps,have a great day!!
~Pinky~
how can i solve this factorial? A 6,2- P6- A 5,3 + P5
Answers
The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the other trinomial? 2x2 − x − 2 2x2 + x + 6 4x2 + 21x + 6 4x2 − 21x – 2
Answers
Answer: [tex]4x^2-21x-2[/tex] .
Step-by-step explanation:
Given: The difference of two trinomials is [tex]x^2 -10x + 2[/tex]. If one of the trinomials is [tex]3x^2 - 11x - 4[/tex].
Then, the other trinomial will be ([tex]3x^2 - 11x - 4[/tex] ) + ([tex]x^2 -10x + 2[/tex])
[tex]=3x^2-11x-4+x^2-10x+2\\\\=3x^2+x^2-11x-10x-4+2\\\\=4x^2-21x-2[/tex]
Hence, the other trinomial could be : [tex]4x^2-21x-2[/tex] .
Which is the ratio of the number of months that begin with the letter M to the total number of months in a year? 2 to 12 2 to 10 10 to 12 12 to 2
Answers
Answer:
the answer will be 2 to 12
Answer:
2 to 12
Step-by-step explanation:
just did a quiz got it right
The perimeter of a rectangle is 80 cm. Find the lengths of the sides of the rectangle giving the maximum area.Enter the answers for the lengths of the sides in increasing order.
Answers
Answer:
The lengths of the sides are 20 cm and 20 cm
Step-by-step explanation:
Given
Perimeter, P = 80cm
Represent the length and width with L and W, respectively;
[tex]P= 2*(L + B)[/tex]
Substitute 80 for P
[tex]80 = 2 * (L + B)[/tex]
Divide through by 2
[tex]40 = L + B[/tex]
[tex]L + B = 40[/tex]
Make L the subject of formula
[tex]L = 40 - B[/tex]
Area of a rectangle is calculated as thus;
[tex]Area = L * B[/tex]
Substitute 40 - B for L
[tex]Area = (40 - B) * B[/tex]
Express this as a function
[tex]A(B) = (40 - B)* B[/tex]
[tex](40 - B)* B = A(B)[/tex]
Set A(B) = 0 to determine the roots
Hence;
[tex](40 - B)* B = 0[/tex]
[tex]40 - B = 0[/tex] or [tex]B = 0[/tex]
[tex]40 = B[/tex] or [tex]B = 0[/tex]
[tex]B = 40[/tex] or [tex]B = 0[/tex]
The maximum area of a rectangle occurs at half the sum of the roots;
So;
[tex]B= \frac{B_1 + B_2}{2}[/tex]
[tex]B= \frac{40+0}{2}[/tex]
[tex]B= \frac{40}{2}[/tex]
[tex]B = 20[/tex]
Recall that [tex]L = 40 - B[/tex]
[tex]L = 40 - 20[/tex]
[tex]L = 20[/tex]
Hence the lengths of the sides are 20 cm and 20 cm
Can you wiggle your ears? Use the students in your statistics class (or a group of friends) to estimate the percentage of people who can wiggle their ears. How can your result be thought of as an estimate for the probability that a person chosen at random can wiggle his or her ears? Comment: National statistics indicate that about 13% of Americans can wiggle their ears (Source: Bernice Kanner, Are You Normal?, St. Martin's Press, New York). The resulting relative frequency can be used as an estimate of the true probability of all Americans who can wiggle their ears. The resulting relative frequency can be used as an estimate of the true probability of all Americans who cannot wiggle their ears. The resulting relative frequency is the true probability of all Americans who can wiggle their ears. The resulting relative frequency cannot be used as an estimate of the true probability of all Americans who can wiggle their ears.
Answers
Answer:36
Step-by-step explanation:
Find the center, vertices, and foci of the ellipse with equation 4x2 + 9y2 = 36. Center: (0, 0); Vertices: (-3, 0), (3, 0); Foci: Ordered pair negative square root 5 comma 0 and ordered pair square root 5 comma 0 Center: (0, 0); Vertices: (-9, 0), (9, 0); Foci: Ordered pair negative square root 65 comma 0 and ordered pair square root 65 comma 0 Center: (0, 0); Vertices: (0, -3), (0, -3); Foci: Ordered pair 0 comma negative square root 5 and ordered pair 0 comma square root 5 Center: (0, 0); Vertices: (0, -9), (0, 9); Foci: Ordered pair 0 comma negative square root 65 and ordered pair 0 comma square root 65
Answers
Answer:
Option A.
Step-by-step explanation:
The given equation of ellipse is
[tex]4x^2+9y^2=36[/tex]
Divide both sides by 36.
[tex]\dfrac{4x^2}{36}+\dfrac{9y^2}{36}=1[/tex]
[tex]\dfrac{x^2}{9}+\dfrac{y^2}{4}=1[/tex]
[tex]\dfrac{x^2}{3^2}+\dfrac{y^2}{2^2}=1[/tex] ...(1)
The standard form of an ellipse is
[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex] ...(2)
where, (h,k) is center, (h±a,k) are vertices and (h±c,k) are foci.
On comparing (1) and (2), we get
[tex]h=0,k=0,a=3,b=2[/tex]
Now,
Center [tex]=(h,k)=(0,0)[/tex]
Vertices [tex]=(h\pm a,k)=(0\pm 3,0)=(3,0),(-3,0)[/tex]
We know that
[tex]c=\sqrt{a^2-b^2}=\sqrt{3^2-2^2}=\sqrt{5}[/tex]
Foci [tex]=(h\pm c,k)=(0\pm \sqrt{5},0)=(\sqrt{5},0),(-\sqrt{5},0)[/tex]
Therefore, the correct option is A.
What number comes next in this series 7,10,10,13,16,16,
Answers
you’re just adding 3
you’re welcome :)
A scatter plot is shown below.. PLEASE HELPPP!!
Answers
Answer:
(0,9.8) and (10, 1.2)
Step-by-step explanation:
These are the only points that are the best fit for the garph correlation.
Answer:
(0, 9.8) and (10, 1.2)
Step-by-step explanation:
:) hope this helped
* The American Diabetes Association estimates that 8.3% of people in the
United States have diabetes. Suppose that a medical lab has developed
a simple diagnostic test for diabetes that is 98% accurate for people who
have the disease and 95% accurate for people who do not have it. The
medical lab gives the test to a randomly selected person. What is the
probability that the diagnosis is correct? Explain each step.
Answers
Answer:
The probability that the diagnosis is correct is 0.95249.
Step-by-step explanation:
We are given that the American Diabetes Association estimates that 8.3% of people in the United States have diabetes.
Suppose that a medical lab has developed a simple diagnostic test for diabetes that is 98% accurate for people who have the disease and 95% accurate for people who do not have it.
Let the probability that people in the United States have diabetes = P(D) = 0.083.
So, the probability that people in the United States do not have diabetes = P(D') = 1 - P(D) = 1 - 0.083 = 0.917
Also, let A = event that the diagnostic test is accurate
So, the probability that a simple diagnostic test for diabetes is accurate for people who have the disease = P(A/D) = 0.98
And the probability that a simple diagnostic test for diabetes is accurate for people who do not have the disease = P(A/D') = 0.95
Now, the probability that the diagnosis is correct is given by;
Probability = P(D) [tex]\times[/tex] P(A/D) + P(D') [tex]\times[/tex] P(A/D')
= (0.083 [tex]\times[/tex] 0.98) + (0.917 [tex]\times[/tex]0.95)
= 0.08134 + 0.87115
= 0.95249
Hence, the probability that the diagnosis is correct is 0.95249.
The graph shows the weight of a jar when filled with different numbers of marbles.
What does the y-intercept represent?
A) The weight of the marbles without the jar.
B) The weight of the jar without the marbles.
C) The weight of one marble and the jar.
D) The unit rate for each marble added.
Answers
Answer:
B
Step-by-step explanation:
The weight of the jar depends on the number of marbles in it, therefore the weight is the dependent variable (y) and the number of marbles is the independent variable (x). The y-intercept is when x = 0 and since the number of marbles is x, the answer is that the y-intercept represents the weight of the jar without the marbles.
. In statistics, a data set has the following characteristics: (Choose all that apply) A:A data set is a collection of similar data. B:A data set can contain only quantitative data. C:A data set is any piece of descriptive or quantitative information on any object of study. D:A data set contains data all of which have some common characteristic.
Answers
Answer:
A. A data set is a collection of similar data.
D. A data set contains data all of which have some common characteristic.
Please! David has several chains of length 5 and of length 7. By joining chains one after the other, David can create different lengths. Which of these lengths is impossible to make? A)10 B)12 C)13 D)14 E)15
Answers
Answer:
13
Step-by-step explanation:
A)5+5=10
B)5+7=12
C) impossible
D)7+7=14
E)5+5+5=15
M&M plain candies come in various colors. According to the M&M/Mars Department of Consumer Affairs, the distribution of colors for plain M&M candies is as follows. Color Purple Yellow Red Orange Green Blue Brown Percentage 22% 20% 23% 10% 6% 6% 13% Suppose you have a large bag of plain M&M candies and you choose one candy at random. (a) Find P(green candy or blue candy). Are these outcomes mutually exclusive? Why? Yes. Choosing a green and blue M&M is possible. Yes. Choosing a green and blue M&M is not possible. No. Choosing a green and blue M&M is not possible. No. Choosing a green and blue M&M is possible. (b) Find P(yellow candy or red candy). Are these outcomes mutually exclusive? Why? Yes. Choosing a yellow and red M&M is possible. No. Choosing a yellow and red M&M is not possible. Yes. Choosing a yellow and red M&M is not possible. No. Choosing a yellow and red M&M is possible. (c) Find P(not purple candy).
Answers
Answer:
A) 0.12. Yes. Choosing a green and blue M&M is possible
B) 0.43. Yes. Choosing a yellow and red M&M is possible
C) 0.78
Step-by-step explanation:
First of all, the summation of the distribution of all colours is;
Σ(all colors ) = 22% + 20% + 23% + 10% + 6% + 6% + 13% = 100%, or 1.
Thus;
a) P(green candy or blue candy) is;
P(GREEN ∪ BLUE) = P(G) + P(BL)
P(GREEN ∪ BLUE) = 6%+6%
P(GREEN ∪ BLUE) = 12% or 0.12
Now, due to the fact that we have to choose ONE candy and only ONE candy at random, then they are mutually exclusive: Yes. Choosing a green and blue M&M is possible
b)P(yellow candy or red candy is;
P(YELLOW ∪ RED) = P(Y) + P(R)
P(YELLOW ∪ RED) = 20% + 23% = 43% or 0.43
Yes. Choosing a yellow and red M&M is possible
c) P(NOT PURPLE)
the probability of having a purple is;
P(PURPLE) = 22% or 0.22
So, the Probability of NOT having a PURPLE is 1 - 0.22 = 0.78
What is the approximate area of a circle enclosed by a piece of rope 50.24 inches long? (Use the fact that π ≈ 3.14 to make your calculations.)
Answers
Answer:
the approximate area of this circle is 200.96 inches long.
Step-by-step explanation:
To answer this problem we need to remember that the area of a circle is given by the formula:
Area = π[tex]r^2[/tex] where r is the radius.
and the perimeter is:
Perimeter = 2πr
Now, the problem tells us that the circle is enclosed by a piece of rope that's 50.24 inches long. So the perimeter of the circle is 50.24 inches.
Since we have the value of the perimeter and the value of pi, we are going to substitute these values in the perimeter formula to find r.
Perimeter = 2πr
50.24=2(3.14)r
50.24= 6.28r
50.24/6.28= r
8= r
Thus, the radius of the circle is 8 inches long.
Now, we can use this value to find the area of the circle:
Area = π[tex]r^2[/tex]
Area = π[tex]8^2[/tex]
Area = 3.14 (64)
Area = 200.96
Therefore, the approximate area of this circle is 200.96 inches long.
The approximate area of a circle enclosed by a piece of rope is 200.96 square inch.
The length of rope by which a circle is made, is known as circumference of circle.
Circumference of circle = [tex]2\pi r[/tex] , where r is radius of circle.
Since, length of rope is 50.24 inches.
[tex]2\pi r=50.24\\\\r=\frac{50.24}{2*3.14}=8 inch[/tex]
Area of circle = [tex]\pi r^{2}[/tex]
= [tex]3.14 *(8)^{2}=200.96[/tex] square inch
Thus, the approximate area of a circle enclosed by a piece of rope is 200.96 square inch.
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Please help me on question a
I would really appreciate it
Answers
Answer:
[tex]x = 3.6[/tex]
Step-by-step explanation:
To find the area of a rectangle, you multiply its length by its width. The formula is [tex]lw = a[/tex].
We already know the length, 5, and the area, 18, so we can plug it into the equation.
[tex]5\cdot w=18[/tex]
We can simplify this equation by dividing both sides by 5.
[tex]5\cdot w \div5 = 18\div5\\\\w = 3.6[/tex]
Hope this helped!
Answer: x= 13
Step-by-step explanation:
x+3y-Z=0
2x+y+Z=1
3X-y+Z=3
Answers
Explanation:
I added a picture
Nan lives 13 miles from the airport. Felipe lives 6 miles from the airport.
How many more miles does Nan live from the airport than Felipe?
Answers
Answer:
7
Step-by-step explanation:
it's simply 13 - 6
7 it the answer, that was easy
