Many different parts of the brain work together to encode, store, and retrieve information as needed. The diagram below indicates three parts of the human brain that are involved in information storage.


Image courtesy of FDA

Which of these terms best describes the process by which the brain stores information that can be retrieved at a later time?
A.
memory
B.
stimulation
C.
nerve specialization
D.
sensory reception

Please help me

Answer:

The interior of the Earth, like that of the other terrestrial planets, is chemically divided into layers. The Earth has an outer silicate solid crust, a highly viscous mantle, a liquid outer core that is much less viscous than the mantle, and a solid inner core.

Answer:

[tex]pH=8.43[/tex]

Explanation:

Hello there!

In this case, since the reaction between benzoic acid and sodium hydroxide is carried out in a 1:1 mole ratio, it is possible to calculate the moles of sodium benzoate salt that are produced due to the neutralization as show below:

[tex]n_{salt}=0.2mol/L*1L=0.2mol[/tex]

We can assume that the volume of benzoic acid is 1 L and therefore the used volume of NaOH is:

[tex]V_{NaOH}=\frac{0.200M*1L}{0.060M}=3.33L[/tex]

Which means that the total final volume is 4.33 L and the concentration of the resulting basic salt is:

[tex][salt]=\frac{0.2mol}{4.33L}=0.046M[/tex]

Next, since the salt is C6H5COONa, we can see it is ionized in Na+ cations and C6H5COO- anions, but just the latter is able to react with the water in the solution in order to undergo the following reaction:

[tex]C_6H_5COO^-+H_2O\rightleftharpoons C_6H_5COOH+OH^-[/tex]

Whose equilibrium expression, it terms of Kb, due to the release of OH- ions, is:

[tex]Kb=\frac{[C6H5COOH][OH^-]}{[C6H5COO^-]}[/tex]

And can be written in terms of x, Kw and Ka:

[tex]\frac{Kw}{Ka} =\frac{x*x}{0.046M-x} \\\\\frac{1x10^{-14}}{6.3x10^{-5}}=1.59x10^{-10}= \frac{x^2}{0.046M-x}[/tex]

And because Kb<<<<<1 we can neglect the x on the bottom to get:

[tex]1.59x10^{-10}= \frac{x^2}{0.046M}[/tex]

Whereas x is computed as follows:

[tex]x=\sqrt{1.59x10^{-10}*{0.046M} =2.7x10^{-6}M[/tex]

Which is actually equal to the concentration of OH- ions so that we can calculate the pOH prior to the pH:

[tex]pOH=-log(2.7x10^{-6})=5.57[/tex]

And therefore the pH as shown below:

[tex]pH=14-5.57\\\\pH=8.43[/tex]

Which makes sense since this sodium benzoate is a basic salt.

Regards!

Answer:

The answer is "As [tex]Q=336[/tex], at high-temperature [tex]\Delta G_{rxn}>0[/tex] and When[tex]K>1,[/tex][tex]\Delta G^{\circ}_{rxn}>0[/tex]."

Explanation:

The equation for the reaction is:

[tex]A(g) \leftrightharpoons B(g)[/tex]  

[tex]K=5.8\\\\Q=336[/tex]

At equilibrium,

[tex]\Delta G^{\circ}_{rxn}>0[/tex][tex]=-RT \ln \ K[/tex]

When k=5.8(>1), the value of [tex]\ln k[/tex] would be positive

So, [tex]\Delta G^{\circ}_{rxn}[/tex] is negative (< 0)

So if K > l, [tex]\Delta G^{\circ}_{rxn}<0[/tex]

If the reaction is not in equilibrium so the equation is :

[tex]\Delta G_{rxn}>0[/tex]=[tex]\Delta G^{\circ}_{rxn}[/tex][tex]+RT \ln Q[/tex]

Substituting the expression:

[tex]\Delta G_{rxn}>0[/tex][tex]= (-RT \ln K) + RT \ln Q[/tex]

                 [tex]= RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)[/tex]

It is the positive value for all temperatures.

So, As Q = 336, at the high temperature [tex]\Delta G_{rxn}>0[/tex].

Answer:

C2H4(g) +H2O(g)=C2H5OH(g)

When water is boiled, the heat energy is transferred to the molecules of water, which begin to move more quickly. Eventually, the molecules have too much energy to stay connected as a liquid. When this occurs, they form gaseous molecules of water vapor, which float to the surface as bubbles and travel into the air.

Answer:

its the lunar and solar eclipse

Explanation:

the solar eclipse happens when the moon is in between the sun and earth

Answer: An amount of [tex]40980.48 J/g^{o}C[/tex] heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

Explanation:

Given: mass of lead = 4.64 kg

Convert kg into grams as follows.

[tex]1 kg = 1000 g\\4.64 kg = 4.64 kg \times \frac{1000 g}{1 kg}\\= 4640 g[/tex]

[tex]T_{1} = 150^{o}C[/tex]

[tex]T_{2} = 219^{o}C[/tex]

The standard value of specific heat of lead is [tex]0.128 J/g^{o}C[/tex].

Formula used to calculate heat is as follows.

[tex]q = m \times C \times \Delta T[/tex]

where,

q = heat energy

m = mass of substance

C = specific heat of substance

[tex]\Delta T[/tex] = change in temperature

Substitute the value into above formula as follows.

[tex]q = m \times C \times \Delta T\\= 4640 g \times 0.128 J/g^{o}C \times (219 - 150)^{o}C\\= 40980.48 J/g^{o}C[/tex]

Thus, we can conclude that [tex]40980.48 J/g^{o}C[/tex] heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

Answer:

Liquid water is held together by hydrogen bonds. (Liquid water has fewer hydrogen bonds than ice.) Oils and fats not have any polar part and so for them to dissolve in water they would have to break some of water's hydrogen bonds. Water will not do this so the oil is forced to stay separate from the water.

Answer:

98 g/mol

Explanation:

La masa molar de un compuesto es la cantidad de materia (medida como masa) que hay en 1 mol de dicho compuesto. Por lo tanto, puede calcularse como sigue:

masa molar = masa/número moles

Tenemos los siguientes datos del compuesto Y:

masa Y = 196 g

número de moles de Y = 2 mol

Entonces, podemos calcular la masa molar de Y de la siguiente manera:

masa molar Y = (masa Y)/(número de moles de Y) = 196 g/2 mol = 98 g/mol

Answer:

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

[tex]P_1V_1 = P_2V_2[/tex]

Since we're finding the new pressure

[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]

We have

[tex]P_2 = \frac{6.4 \times 0.87}{20.5} = \frac{5.568}{20.5} \\ = 0.2716.... \\ \\ = 0.27 \: \: \: atm[/tex]

But

1 atm = 14.7 psi

Then 0.27 atm =

[tex] \frac{14.7 \times 0.27}{1} = 3.969 \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

3.97 psi

Explanation:

Answer:

La cantidad de energía disponible de una fuente de energía determinada se denomina recurso energético. La escasez de recursos energéticos (petróleo, carbón y madera) en algunas de las fuentes de energía más utilizadas plantear necesidad de usar otras fuentes investigar el modo más rentable de emplearlas

Explanation:

Answer:

false

Explanation:

its the amount of high-quality energy available from a given quantity of an energy resource minus the high-quality energy needed to make the energy available.

Answer:

option d) is the correct answer

Answer:

The answer is in the photo

Explanation:

I hope that is useful for you :)

Answer:

166.04g

Explanation:

Mass=Moles xRMM

1 mole = 6.023 x10^23molecules

5.0 x10^25molecules

=83.02moles

RMM=2

mass=83.02 x2

and=166.04g

Answer:

Hydrogen

Explanation:

BECAUSE IT HAS NO NEURTONS!!

Answer:

Explanation:

The mass of the sun is about 1.98 x 10^30 kilograms. The mass of the earth is 5.97x 10^24 kilograms.

1.98 x 10^30 / 5.97x 10^24 = 331658 times greater

Answer:

Explanation:

The mass of the sun / the mass of the earth

= 1.98 x 10^30 / 5.97x 10^24

= 3.32 x 10^5 times greater

Answer:

A, D, E

Explanation:

Answer:  The bonds that are made and broken in a reaction release energy when forming products that contain less total energy than the reactants.

Explanation:  Elements form bonds with each other when the total energy of the resulting products is less than the starting energy.  The term "energy" refers to the energy of the electrons that are being held in an atom by the nucleus.  Keeping the positively charged nucleus happy means that the electrons are trying to get closer, but they repel each other as they get closer to the nucleus.  This results in orbits, preferred areas around the nucleus where the electrons spend their day in a delicate balance with the nucleus and other electrons.  These orbits offer housing for the electrons that involve discreet energies for the electrons.  When elements react, the resulting bonding pattern often results in an overall reduction in total energy.  The energy reduction results in heat, light, and/or sound.  The release is termed "exothermic."

Answer:

Explanation:

The answer is 202

Answer: There is 0.8 liters (L) of water required to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Explanation:

Given: [tex]M_{1}[/tex] = 0.5 M        

[tex]V_{1}[/tex] = 4800 mL

Convert mL into L as follows.

[tex]1 mL = 0.001 L\\4800 mL = 4800 mL \times \frac{0.001 L}{1 mL}\\= 4.8 L[/tex]

[tex]M_{2}[/tex] = 3 M

Formula used to calculate the volume of water required as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 4.8 L = 3 M \times V_{2}\\V_{2} = \frac{0.5 M \times 4.8 L}{3 M}\\= 0.8 L[/tex]

Thus, we can conclude that 0.8 liters (L) of water need to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Answer:

2260 J

Explanation:

For water at its boiling point of 100 ºC, the heat of vaporization is 2260 J g-1. This means that to convert 1 g of water at 100 ºC to 1 g of steam at 100 ºC, 2260 J of heat must be absorbed by the water.

Answer:

But there is nothing above

Answer:

See the explanation below

Explanation:

Both the cup of coffee and drop of coffee have the Same temperature of 95°C.

Although the difference is the cup of coffee has more heat contained in it than the drop of coffee. An explanation is when we heat a cup of coffee it will take more time to Attain in 95°C while the drop of coffee will take less time

Answer:

The heat contained is 1236 Joules

Explanation:

As we know

[tex]Q = mc\Delta[/tex]T

Where

[tex]\Delta[/tex]T is the change in temperature

m is the mass in grams

c is the specific heat of water (ice) = 2.06 joules/gram

Substituting the given values, we get -

[tex]Q = 20 * (-15+45)*2.06\\Q = 20*2.06*30\\Q = 1236[/tex]Joules

Answer:

V=d/t

,,,,,,,,,,,,,,,,,

Answer:

Decreased change in temperature

Explanation:

Delta T signifies the temperature is changing, but by adding a negative, it specifies that it changes by decreasing.