Many universities and colleges have instituted supplemental instruction (SI) programs, in which a student facilitator meets regularly with a small group of students enrolled in the course to promote discussion of course material and enhance subject mastery. Suppose that students in a large statistics course (what else?) are randomly divided into a control group that will not participate in SI and a treatment group that will participate. At the end of the term, each student’s total score in the course is determined.
a. Are the scores from the SI group a sample from an existing population? If so, what is it? If not, what is the relevant conceptual population?
b. What do you think is the advantage of randomly dividing the students into the two groups rather than letting each student choose which group to join?
c. Why didn’t the investigators put all students in the treatment group? Note: The article "Supplemental Instruction: An Effective Component of Student Affairs Programming" (J. of College Student Devel., 1997: 577–586) discusses the analysis of data from several SI programs.

Answer:

a³b

Step-by-step explanation:

(ab²)³/b⁵

= a³b⁶/b⁵

= a³b

Answer:

90 i think

Step-by-step explanation:

Answer:

7≤r≤12

Step-by-step explanation:

The domain is the values that the input takes

The input goes from 7 to 12

7≤r≤12

Answer: Choice B) [tex]7 \le r \le 12[/tex]

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Explanation:

The domain is the set of allowed x inputs of a function.

How far to the left can we go on this red line? That would be x = 7.

How far to the right? That would be x = 12.

We can have x equal anything between 7 and 12, including both endpoints. We include the endpoints because they are filled in circles (as opposed to open holes).

So the domain is [tex]7 \le x \le 12[/tex]. If we replace x with r, then we update that inequality into [tex]7 \le r \le 12[/tex]. This replacement happens because r is along the horizontal x axis.

Answer:

Step-by-step explanation:

x = 0, 1/5

Answer:

y2-y1/x2-x1

y2: 1050

y1:600

x2:75

x1:30

1050-600=450

75-30=45

450/45=10

slope is 10

Answer:

let:

A(30, 600)=(x1,y1)

B((75, 1050)=(x2,y2)

now,

[tex]slope(m) = \frac{y2 - y1}{x2 - x1} [/tex]

[tex] = \frac{1050 - 600}{75 - 30} [/tex]

[tex] = \frac{450}{ 45} [/tex]

[tex] = \frac{10}{1} [/tex]

Answer:

18c^3d^9

Step-by-step explanation:

2c^3 d^2 * 9d^7

We know that  we add the exponents when the base is the same

2*9  c^3 d^(2+7)

18c^3d^9

Step-by-step explanation:

the average change rate is the change of the functional values from the beginning to the end of the interval, and then that divided by the length of the interval.

like with every average or mean value calculation.

g(-4) = 2×(-4)³ - 5 = -128 - 5 = -133

g(2) = 2×2³ - 5 = 16 - 5 = 11

so, on an interval of x values of 2- -4 = 6 units the function changes its values by 11 - -133 = 144 units.

the average charge rate for this x interval is therefore

144 / 6 = 24 = 24/1

for 1 unit change of x, g(x) changes in the average by 24 units.

Answer:

2x^2+x-15

Step-by-step explanation:

foil

Answer:

2x^2 + x - 15

Step-by-step explanation:

using FOIL

(2x - 5)(x + 3)

[(2x ⋅ x) + (2x ⋅ 3) + (-5 ⋅ x) + (-5 ⋅ 3)]

[2x^2 + 6x - 5x - 15]

2x^2 + x - 15

The value of x in the figure is 125°

 And the right option is (D) 125°

To solve the problem, we use the formular for the sum of the interior angle of a polygon.

(n-2)180°

         [tex](5-2)180 = 540[/tex]

     ∠P+∠T+∠R+∠Q+∠S = 540°

       [tex]35+200+x+90+90 = 540[/tex]

        [tex]415+x = 540[/tex]

         [tex]x = 540-415[/tex]

         [tex]x = 125[/tex]

Hence the value of x in the figure is 125°

And the right option is (D) 125°

Learn more about polygons here: https://brainly.com/question/17042929

Answer:

.

Step-by-step explanation:

Answer:

[tex](a)\ V = \{(N,30),(R,37),(S,17)\}[/tex]

[tex](b)[/tex]

[tex]Domain = \{N,R,S\}[/tex]

[tex]Range = \{37,30,17\}[/tex]

Step-by-step explanation:

Given

[tex]V(R) = 37,\ V(N) = 30,\ V(S) = 17[/tex]

Solving (a): Set of ordered pair

A function y = f(x) is represented as (x,y)

So, the ordered pair of V is:

[tex]V = \{(R,37),(N,30),(S,17)\}[/tex]

Order the alphabets in increasing order

[tex]V = \{(N,30),(R,37),(S,17)\}[/tex]

Solving (b): The domain and the range

In a function [tex]\{(x_1,y_1),...,(x_n,y_n)\}[/tex]

The domain and the range are represented as:

[tex]Domain = \{x_1,x_2....x_n\}[/tex]

[tex]Range = \{y_1,y_2....y_n\}[/tex]

So, we have:

[tex]Domain = \{N,R,S\}[/tex]

[tex]Range = \{37,30,17\}[/tex]

Answer:

Two numbers differ by 9 and the sum of their square is 653. What are the numbers?

Well,that's a mathematical question from algebra and it's quite difficult to answer such questions by writing through the circumstances offered by apps like quora.

However,I have tried to answer your question in an understandable way.Hope you may not find it difficult to analyze.

Let the numbers be x and (9+x)

Therefore,according to given,

x^2 + (9+x)^2 =653

=>x^2 + (9)^2 + x^2 + 2×(9)×(x)=653 (Applying the formula of (a+b)^2)

=>x^2 + 81 + x^2 + 18x =653

=>2x^2 + 18x + (81-653)=0

=>2x^2 + 18x - 572=0

=>2x^2 + (44x - 26x) - 572=0

=>2x^2 + 44x - 26x - 572=0

=>2x(x + 22) - 26(x + 22)=0

=>(x + 22)(2x - 26)=0

But since the number can't be negative

Therefore, x=13

Hence,the required numbers are 13 and 22.

Step-by-step explanation:

in first hope you like it

Answer: r = 50 miles/h

Step-by-step explanation:

Let r be the rate of average speed.

Then

r = D/t

r = 150/3

r = 50 miles/h

please click thanks and mark brainliest if you like :)

Answer:

The missing segment length is 20.

Step-by-step explanation:

2 is multiplied by 4 to get to 8, so 5 must be multiplied by 4 to get to 20.

Answer:

the answer would be (7,5)

Answer:

-1

Step-by-step explanation:

Pick two points on the line

(0,2) and (2,0)

Using the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 0-2)/(2-0)

    = -2/2

  = -1

Answer:

-1

Step-by-step explanation:

Use two points on the line to find the slope, using rise over run.

We can use the points (0, 2) and (2, 0).

From the first point to the other, the y value decreases by 2 and the x value increases by 2.

Use rise (change in y value) over run (change in x value):

-2 / 2

= -1

So, the slope is -1.

Sampling technique is a way of selecting a sample from a given population. The best way to get a sample of students that represents all 8:00 AM classes is by using a stratified sampling technique.

From the complete question, we can summarize the given data as follows:

[tex]Buildings = 3[/tex] ----3 buildings in the college

[tex]Lecture\ Halls =2[/tex]  ---- 2 lecture halls in each building

[tex]Capacity = 100[/tex] --- 100 students in each lecture hall

Because the students' lecture halls are not in the same building, the best way to get a sample is as follows:

The number of students in each building is:

[tex]Students = Capacity \times Lecture\ Halls[/tex]

[tex]Students = 100 \times 2[/tex]

[tex]Students = 200[/tex]

There are 200 students in each building

The above method is referred to as a stratified sampling technique because the population of the students are divided into groups, before being randomly selected.

Read more about sampling techniques at:

https://brainly.com/question/9612230

Answer:

A) area decreases

Step-by-step explanation:

Example: we have a 2 by 3 rectangle with area of 2*3 = 6. If we cut the first dimension in half, then we have a 1 by 3 rectangle that has area 1*3 = 3. The area has decreased. To keep the area the same, we would have to increase the other dimension some specific amount.

HOPE THIS HELPS

HAVE A GOOD DAY :)

ITS RASPUTIN002

Answer:

93.6

Step-by-step explanation:

The easiest way for me to complete this was to break it up into parts. I Separated the small triangle and the big triangle. I turned them both into squares and multiplied the dimensions. I then divided those by two and added them together.

Answer:

6

Step-by-step explanation:

đạo hàm cấp 2 của f(x) rồi thế 0 vào

Answer:

To Find F(3) you just have to replace x=3 so:

F(3)= -3^3 + 4×3^2 -2×3 = -27 +4×9 - 6 = -33 + 36 = 3

You're looking for a solution of the form

[tex]\displaystyle y = \sum_{n=0}^\infty a_n x^n[/tex]

Differentiating twice yields

[tex]\displaystyle y' = \sum_{n=0}^\infty n a_n x^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n[/tex]

[tex]\displaystyle y'' = \sum_{n=0}^\infty n(n-1) a_n x^{n-2} = \sum_{n=0}^\infty (n+1)(n+2) a_{n+2} x^n[/tex]

Substitute these series into the DE:

[tex]\displaystyle (x-1) \sum_{n=0}^\infty (n+1)(n+2) a_{n+2} x^n - x \sum_{n=0}^\infty (n+1) a_{n+1} x^n + \sum_{n=0}^\infty a_n x^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty (n+1)(n+2) a_{n+2} x^{n+1} - \sum_{n=0}^\infty (n+1)(n+2) a_{n+2} x^n \\\\ \ldots \ldots \ldots - \sum_{n=0}^\infty (n+1) a_{n+1} x^{n+1} + \sum_{n=0}^\infty a_n x^n = 0[/tex]

[tex]\displaystyle \sum_{n=1}^\infty n(n+1) a_{n+1} x^n - \sum_{n=0}^\infty (n+1)(n+2) a_{n+2} x^n \\\\ \ldots \ldots \ldots - \sum_{n=1}^\infty n a_n x^n + \sum_{n=0}^\infty a_n x^n = 0[/tex]

Two of these series start with a linear term, while the other two start with a constant. Remove the constant terms of the latter two series, then condense the remaining series into one:

[tex]\displaystyle a_0-2a_2 + \sum_{n=1}^\infty \bigg(n(n+1)a_{n+1}-(n+1)(n+2)a_{n+2}-na_n+a_n\bigg) x^n = 0[/tex]

which indicates that the coefficients in the series solution are governed by the recurrence,

[tex]\begin{cases}y(0)=a_0 = -7\\y'(0)=a_1 = 3\\(n+1)(n+2)a_{n+2}-n(n+1)a_{n+1}+(n-1)a_n=0&\text{for }n\ge0\end{cases}[/tex]

Use the recurrence to get the first few coefficients:

[tex]\{a_n\}_{n\ge0} = \left\{-7,3,-\dfrac72,-\dfrac76,-\dfrac7{24},-\dfrac7{120},\ldots\right\}[/tex]

You might recognize that each coefficient in the n-th position of the list (starting at n = 0) involving a factor of -7 has a denominator resembling a factorial. Indeed,

-7 = -7/0!

-7/2 = -7/2!

-7/6 = -7/3!

and so on, with only the coefficient in the n = 1 position being the odd one out. So we have

[tex]\displaystyle y = \sum_{n=0}^\infty a_n x^n \\\\ y = -\frac7{0!} + 3x - \frac7{2!}x^2 - \frac7{3!}x^3 - \frac7{4!}x^4 + \cdots[/tex]

which looks a lot like the power series expansion for -7eˣ.

Fortunately, we can rewrite the linear term as

3x = 10x - 7x = 10x - 7/1! x

and in doing so, we can condense this solution to

[tex]\displaystyle y = 10x -\frac7{0!} - \frac7{1!}x - \frac7{2!}x^2 - \frac7{3!}x^3 - \frac7{4!}x^4 + \cdots \\\\ \boxed{y = 10x - 7e^x}[/tex]

Just to confirm this solution is valid: we have

y = 10x - 7eˣ   ==>   y (0) = 0 - 7 = -7

y' = 10 - 7eˣ   ==>   y' (0) = 10 - 7 = 3

y'' = -7eˣ

and substituting into the DE gives

-7eˣ (x - 1) - x (10 - 7eˣ ) + (10x - 7eˣ ) = 0

as required.

Answer:

18

Step-by-step explanation:

The diameter is equal to twice the length of the radius

So if the radius is 9 then the diameter is 9 * 2 = 18

Answer and Step-by-step explanation:

First, we need to set this equation equal to y, which means we need to get y by itself, and all other terms equal to y.

x = [tex]2y^2 + 1[/tex]

Subtract 1, then divide by 2 on both sides.

[tex]x - 1 = 2y^2\\\\\frac{x-1}{2} = y^2[/tex]

Now, take the square root of both sides.

[tex]y=\sqrt{\frac{x-1}{2}}[/tex]

We see that the value with the x (1) is positive, and that we have a square root function, which means the parabola would open to the right.

(If the x value was negative, the square root function's parabola would open to the left)

So, C (Right) is the correct answer.

#teamtrees #PAW (Plant And Water)

I hope this helps!