Here is a circle. Points A, B, C, and D are drawn, as
well as Segments AD and BC.
D.
What is the area of the circle, in square units?
model the unknown number problem by writing an algebraic expression. Then complete the statements
juan doubled his workout time
Please help me! How much would you expect gas to cost in 2030. Show your work.
Answer:World Bank expects the natural gas price at Henry Hub to increase to $4 per MMBtuStep-by-step explanation:
Myopia in children. Myopia, also called short-sightedness, is a common visual impairment that is reaching alarming proportions worldwide. The condition typically develops in school-age children and adolescents. It has long been thought that the condition was associated with too much reading, but recent evidence suggests instead that a lack of exposure to natural outdoor light may play a role. To investigate this new theory, researchers compared rates of myopia among randomly selected young children (6 and 7 years old) of Chinese ethnicity living in either Sydney (Australia) or Singapore. The researchers found that 4 of the 124 children in the Australian sample had myopia, compared with 183 among the 628 children from Singapore.
a. Display the findings in a two-way table. What percent of the children in the study had myopia? What is that percent among the children living in Australia and among those living in Singapore?
b. The researchers obtained information for most of the children in the study about their weekly amount of time in hours) spent reading or writing and the weekly amount of time in hours) spent on outdoor activities. Here are the summary statistics:
Time reading/writing Number of children Mean Standard deviation
Australia 109 20.8 13.9
Singapore 611 17.8 8.8
Time outdoors Number of children Mean Standard deviation
Australia 102 13.75 1.02
Singapore 586 3.05 0.12
How do the children from both countries in this study differ in how they spend their time?
c. Does the study suggest that more time spent reading or writing is associated with a greater risk of myopia among the enrolled children? Does it suggest that more time spent outdoors is associated with a greater risk of myopia? Can we draw a conclusion of causality based on this study?
d. The children enrolled in this study were all of Chinese ethnicity. What is the advantage in this study of collecting data from children with the same ethnicity compared with selecting random samples of children from each location regardless of ethnicity?
Answer:
a. A two way table is presented as follows;
[tex]\begin{array}{cccc}&Had \ Myopia&Do \ not \ have \ Myopia& Totals\\Sydney \ (Australia)&4&120&128\\Singapore&183&445&628\end{array}[/tex]
ii) The percentage of students in the study that have myopia are approximately 24.867%
iii) The percentage of children living in Australia with myopia are approximately 3.2258%
The percentage of children living in Singapore with myopia are approximately 29.14%
b. Children in Australia spend more time reading, writing and also outdoors than children in Singapore
c. The study does not suggest that more time spent reading or writing is associated with a greater risk of myopia among the enrolled children
The study does not suggests that more time spent outdoors is associated with a greater risk of myopia
d. The advantage is to reduce associated variables the generate more accurate findings or result
Step-by-step explanation:
a. A two way table is presented as follows;
[tex]\begin{array}{cccc}&Had \ Myopia&Do \ not \ have \ Myopia& Totals\\Sydney \ (Australia)&4&120&128\\Singapore&183&445&628\end{array}[/tex]
ii) The percentage of students in the study that have myopia are;
(4 + 183)/(124 + 628) × 100 ≈ 24.867%
iii) The percentage of children living in Australia with myopia is given as follows;
4/124 × 100 ≈ 3.2258%
The percentage of children living in Singapore with myopia is given as follows;
183/628 × 100 ≈ 29.14%
b. The data for the time spent reading and writing is presented as follows;
Number of children [tex]{}[/tex] Mean Standard deviation
Australia 109 [tex]{}[/tex] 20.8 13.9
Singapore [tex]{}[/tex] 611 17.8 8.8
The data for the time spent outdoors is presented as follows;
Number of children [tex]{}[/tex] Mean Standard deviation
Australia 102 [tex]{}[/tex] 13.75 1.02
Singapore [tex]{}[/tex] 586 3.05 0.12
From the data, more children in Australia spend more time reading and writing and also outdoors than children in Singapore
c. From the data, more children spend their time reading and writing in Australia and are also less likely to develop myopia than children in Singapore
Therefore, the study does not suggest that more time spent reading or writing is associated with a greater risk of myopia among the enrolled children
Similarly, the study does not suggests that more time spent outdoors is associated with a greater risk of myopia
d. The advantage of collecting data from children with the same ethnicity compared with selecting random samples of children from each location regardless of ethnicity is to reduce the variables or influential factors that may alter the impact on the test and the results
A private beach is 6/7 mile in length and 1/4 mile in width. What is the area of the private beach? (Don't forget to simplify)Immersive Reader
(20 Points)
Need help ASAP!!!!!!!!!!
Answer:
the last two
Step-by-step explanation:
Jordyn is weighing the ingredients on a kitchen scale to make bread. The bowl weighs 1 1/2 pounds. He adds several scoops of flour. the total weight of the bowl and the flour is 2 3/4pounds. If each cup weighs 5/16 pound, how many cups of flour does he add?
Answer: 4 pounds of flour
Step-by-step explanation:
helppppppppppppppppppppppp
Answer:
E = N × C
for
E: earnings
N: number sold
C: cost
she will make:
50 × 1.25 = $62.5
it is acceptable to divide by zero true or false
Answer:
flase.,......,........
Answer:
true
Step-by-step explanation:
so like for example you say 0÷50
your answer will remain 0
Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.56 and a standard deviation of 0.43. Using the empirical rule, what percentage of the students have grade point averages that are between 2.13 and 2.99
Answer:
Approximately 68% of the students have grade point averages that are between 2.13 and 2.99.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this question, we have that:
Mean = 2.56
Standard deviation = 0.43
What percentage of the students have grade point averages that are between 2.13 and 2.99?
2.56 - 0.43 = 2.13
2.56 + 0.43 = 2.99
Within one standard deviation of the mean, so, by the Empirical Rule:
Approximately 68% of the students have grade point averages that are between 2.13 and 2.99.
HELP PLS QUICK!MIGHT GIVE BRAINLIST IF TWO PEOPLE ANSWER!
Answer: A=bh to find the area of parallelograms.
Step-by-step explanation:
Help please someone please
Answer:
lateral area of cylinder =2×pi ×radius×height
lateral area of cylinder =2×3.14×1×2
lateral area of cylinder=12.56 unit²
Which of the following values are in the range of the function graphed below?
Check all that apply.
10
-10
10
- 10 -
I A. -1
B. 0
C. 4
D. -4
E. 1
F. 2
Answer:
1
Step-by-step explanation:
in the problem 12+58=70,12 and 58 are called factors true or false
Answer:
false
Step-by-step explanation:
Answer:
false they are called addend s
A triangle has sides 12cm, 9cm and 15cm. Is the triangle right-angled? Justify your answer
Answer:
yes
Step-by-step explanation:
Yes this triangle is right angled and can be justified using the Pythagorean theorem. The theorem states that: [tex]a^{2} +b^{2} = c^{2}[/tex]. Substitute using the given values:
(9^2)+(12^2)=15^2
81 + 144 = 255
255 = 255.
It satisfies the theorem therefore it is a right angle triangle.
Please help
For 20 points
Answer:
Step-by-step explanation:
Vertex: ( -2, -25)
Axis of symmetry: -2
the sum of m and the difference of r and 2
Answer:
Step-by-step explanation:
Read simply, it is m + (r - 2). It is a very clear statement, so you can depend on the answer.
Janet bought 12 guavas and 16 apples. What is the ratio of guavas to apples?
12 : 16
divide by 4
3 : 4
that's it
Pleas help I will give brainliest also please show how you did it please
Answer:
for n ≤ 3
we are going to put a circle on the 3 and make it filled in then you are going to start an arrow starting from the 3 going to the left all the way to the -10.
Answer:
n ≥ -1 or n ≤ 3
Combined:
-1 ≤ n ≤ 3
Since the inequalities are ≤, it'll be a closed circle
The closed circle will start AT -1 and another closed circle will end at 3
PLEASE HELP!!!!!!
Find the next 3 terms in this pattern: 18, -6, 2, ___, ___, ___.
Answer: -0.67, 0.22, -0.074
Step-by-step explanation:
This is a geometric sequence because it has a common ratio. The common ratio is divide by -3.
18 / -6 = -3
-6 / 2 = -3
Therefore, we'd continue that ratio.
2 / -3 = -0.67
-0.67 / -3 = 0.22
0.22 / -3 = -0.074
It may ask you to write that in fraction form^^
In that case, 2/-3, then 2/-3 / -3, etc etc. :)
Divide by -3
______________
Hope this helps :)
-Lexi
really need help! anything would be appreciated
How do I do this please help
Answer:
1. y= 1/3x+2
2.y=-3/4x-5
Step-by-step explanation:
Melissa and Madeline love pepperoni pizza, but sometimes they are disappointed with the small number of pepperonis on their pizza. To investigate, they went to their favorite pizza restaurant at 10 random times during the week and ordered a large pepperoni pizza. Here are the numbers of pepperoni on each pizza.
47 36 25 37 46 36 49 32 32 34
Use the 4 step method to construct and interpret a 95% confidence interval for the true mean number of pepperonis on a large pizza at this restaurant.
Answer:
(31.919,42.881)
Step-by-step explanation:
Using the t-distribution, it is found that the 95% confidence interval for the true mean number of pepperonis on a large pizza at this restaurant is (31.92, 42.88). It means that we are 95% that the true mean number of pepperonis for all large pizzas at the restaurant is within this interval.
In this problem, we will find the standard deviation for the sample, hence the t-distribution will be used.
What is a t-distribution confidence interval?The confidence interval is given by:
[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]
In which:
[tex]\overline{x}[/tex] is the sample mean.t is the critical value.n is the sample size.s is the standard deviation for the sample.For this problem:
The sample size is n = 10.Using a calculator, we have that [tex]\overline{x} = 37.4, s = 7.66[/tex].The critical value, considering a 95% confidence interval with 10 - 1 = 9 df, is of t = 2.2622.The lower bound of the interval is:
[tex]\overline{x} - t\frac{s}{\sqrt{n}} = 37.4 - 2.2622\frac{7.66}{\sqrt{10}} = 31.92[/tex]
The upper bound of the interval is:
[tex]\overline{x} + t\frac{s}{\sqrt{n}} = 37.4 + 2.2622\frac{7.66}{\sqrt{10}} = 42.88[/tex]
The 95% confidence interval for the true mean number of pepperonis on a large pizza at this restaurant is (31.92, 42.88). It means that we are 95% that the true mean number of pepperonis for all large pizzas at the restaurant is within this interval.
More can be learned about the t-distribution at https://brainly.com/question/16162795
Will give brainliest if the answer is correct
Answer:
The answer to 5 is 3 and the answer to 6 is -2
Step-by-step explanation:
-8=2x-14
add 14 to each side
6=2x
divide by 2
3=x
----------------------------
11x+13=-9
subtract 13 from both sides
11x=-22
divide each side by 11
x=-2
Answer:
5.x=3
6.x=-2
Step-by-step explanation:
you're welcome
Noise levels at 5 airports were measured in decibels yielding the following data:
117,118,140,116,119
1. Construct the 90% confidence interval for the mean noise level at such locations. Assume the population is approximately normal.
2. Calculate the sample mean for the given sample data.
3. Find the critical value that should be used in constructing the confidence interval.
Answer:
1. 112.364<μ,131.636
2. mean = 122
3. critical value = +-2.1318
Step-by-step explanation:
117+118+140+116+119/5
= 610/5
= 122
the sample mean = 122
the sample standard deviation
s² = (117-122)²+(118-122)²+(140-122)²+(116-122²)+(119-122)²/5-1
= 25+16+324+36+9/4
= 410/4
= 102.5
s² = 102.5
s = √102.5
s= 10.12
SE = s/√n
= 10.12/√5
= 4.52
degree of freedom = 5-1 = 4
critical value of t = +-2.1318 using soft ware
confidence interval =
mean +- t(SE)
122-(2.1318)(4.52), 122+(2.1318)(4.52)
= [112.364, 131.636]
112.364<μ,131.636
therefore these are the answers in the ordre it was given in the question
1. 112.364<μ,131.636
2. mean = 122
3. critical value = +-2.1318
here's my face I just dyed my hair-
Answer:
that looks nice
Step-by-step explanation:
the hair looks cool
The manager of a fast-food restaurant wants to be sure that, on average, customers are served within 4 minutes from the time the order is placed. He is particularly concerned about the staff working during the early morning shift. From a random sample of 41 orders, the mean time was 3.75 minutes with a standard deviation of 1.2 minutes.
(a) Is there convincing evidence at the a = 0.05 significance level that the true mean service time during the early morning shift is less than 4 minutes?
Answer:
There is not convincing evidence at the a = 0.05 significance level that the true mean service time during the early morning shift is less than 4 minutes
Step-by-step explanation:
The null hypothesis is:
[tex]H_{0} = 4[/tex]
The alternate hypothesis is:
[tex]H_{1} < 4[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
From a random sample of 41 orders, the mean time was 3.75 minutes with a standard deviation of 1.2 minutes.
This means that [tex]n = 41, \mu = 3.75, \sigma = 1.2[/tex]
The test-statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{3.75 - 4}{\frac{1.2}{\sqrt{41}}}[/tex]
[tex]z = -1.33[/tex]
[tex]z = -1.33[/tex] has a pvalue of 0.0918, looking at the z-table.
0.0918 > 0.05, which means that the null hypothesis is accepted, and that there is not convincing evidence at the a = 0.05 significance level that the true mean service time during the early morning shift is less than 4 minutes
PLZZZZZ HELPPPP MEEE!!!!
Answer:
Step-by-step explanation:
area = (3x³y)(2xy + x⁵)
= 3x³y·2xy + 3x³y·x⁵
= 6x⁴y² + 3x⁸y
After sales tax, a $96 watch costs
$101.28. What is the sales tax
percentage?
A:6.2%
B:5.5%
C:5.2%
D:8.5%
Somebody help me asap please giving brainliest
Answer:
70!
Step-by-step explanation:
If you divide the shape in rectangles, you'll just add it up in the end.
5 x 3 = 15
5 x 3 = 15
10 x 4 = 40
40 + 15 + 15 = 70.
Hope this helps!
