It will take 0.82sec to reach the edge of the table if the system is free to move. If mB=1.0 kg, 99 kg mA must be used if the system's acceleration is to be kept above 1/100 g.
(a) mA = 11 kg
mB = 7 kg
T = mA mB g / (mA+mB) = 77*9.8 / 18 = 41.92 N is the formula for cord tension.
In the case of mA, we have T = mA*a
acceleration of mA, a = T / mA = 41.92 / 11 = 3.81 m/s²
For mB, we have mB*a = mB*g - T a = (mB*g - T) / mB
a = (7*9.8 - 41.92) / 7 = 3.81 m/s²
(b) Initial velocity of mA, u = 0
The distance traveled by mA, s = 1.3 m
We have,
[tex]s = u t + (1/2) a t^2\\ s = at^2 / 2\\ t = (2s / a)^(1/2) = (2*1.3 / 3.81) (1/2) = 0.82 sec[/tex]
(c) mB = 1 kg
The system's acceleration, a = g/100
The system's acceleration is given by the formula a = mB*g / (mA+mB).
mA = [mB*g / a] - mB = [ 1*9.8*100/9.8 ] - 1 = 99 kg
Acceleration is the rate at which velocity changes with respect to time. It is a vector quantity whose magnitude denotes the amount of change in velocity per unit of time.
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An electric lamp consumes 60 watts at 220 volts. How many dry cells of EMF 1. 5 volt and internal resistance 1 ohm are required to glow the lamp?
We must figure out the total voltage and current required to generate 60 watts of electricity in order to calculate the number of dry cells necessary to light the bulb.
Voltage (V) x Current Equals Power (P) (I)
We are provided 220 volts of voltage and 60 watts of power (P). Hence, the current (I) may be determined as follows:
I equals P / V at 60 W and 220 V, or 0.273 A.
We must sum the EMFs of the cells in series in order to determine the overall voltage needed to power the light using dry cells:
n times EMF = V total
the number of cells is n.
Since the EMF of each cell is 1.5 volts, the total voltage needed may be written as follows:
1.5 n V total
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If the velocity field is V = (y-1)i + (x)j
what is the direction of the flow? for credit, include hand-calculations under assignment's tab and test 2 dropbox access. carefully identify the problem number.
The direction of the flow of the object in space can be calculated by unit vector of the velocity field.
What is the direction of flow?The given velocity field is V = (y-1)i + (x)j. Let's assume a unit vector, u in the direction of the flow, then the direction of the flow is the same as the direction of the vector, u.
To find the direction of the vector u, we can use the following formula: u = V/|V|
where |V| is the magnitude of the vector V. Since V = (y-1)i + (x)j, we have |V| = sqrt((y - 1)² + x²)
Hence, the unit vector, u in the direction of the flow is given by: u = V / |V| = ((y-1)i + (x)j) / sqrt((y - 1)² + x²)
Therefore, the direction of the flow is given by the unit vector u = ((y-1)i + (x)j) / sqrt((y - 1)² + x²).
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write the expression for the frequency of a mass m on a spring moving vertically. suppose that k is the spring constant. express your answer in terms of some or all of the variables k , m , g .
Answer:
ω = (k / m)^1/2 ω is proportional to the spring constant and inversely proportional to the mass (square root of these quantities)
ω = 2 π f
f = 1 / 2 π (k / m)^1/2 expression for frequency of mass m
Need help on my homework! Thanks.
Answer: Noble Gases (Blue)
What is the energy of a single photon of light which has a wavelength of 454 nm? E=(h)(c)/ λ
The energy (E) of a single photon of light is given by the formula: E = (h * c) / λ where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.
The energy (E) of a single photon of light is given by the formula:
E = (h * c) / λ
where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.
Substituting the values given: λ = 454 nm = 454 x 10^-9 m (converting nanometers to meters)
h = 6.626 x 10^-34 J s (Planck's constant)
c = 2.998 x 10^8 m/s (speed of light)
E = (6.626 x 10^-34 J s * 2.998 x 10^8 m/s) / (454 x 10^-9 m)
E = 4.374 x 10^-19 J
Therefore, the energy of a single photon of light with a wavelength of 454 nm is 4.374 x 10^-19 J (joules).
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a fixed amount of a molecular substance in the liquid phase is placed in a flask at constant temperature. the flask is closed and is allowed to come to equilibrium. select all the statements that correctly describe the processes occurring in the flask. multiple select question. a. the relative amounts of liquid and vapor in the flask remain constant. b. molecules are leaving and entering the liquid phase at the same rate. c. no changes are occurring because the system is at equilibrium. d. the amount of liquid remains the same because evaporation is no longer occurring.
The statements that correctly describe the processes occurring in the flask are A and B. C and D are incorrect statetment.
a) States that the relative amounts of liquid and vapor in the flask remain constant, which is true as equilibrium has been reached, meaning that the rate of evaporation equals the rate of condensation. b) states that molecules are leaving and entering the liquid phase at the same rate, which is also true as equilibrium has been reached.
c) and d) are incorrect because they do not accurately describe the processes occurring in the flask; while the system is at equilibrium, it is still in a state of change with molecules leaving and entering the liquid phase at the same rate.
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a baseball is hit almost straight up into the air with a speed of estimate (a) how high it goes, (b) how long it is in the air. (c) what factors make this
A baseball is hit almost straight up into the air with a speed, the greater the ball's potential energy will be upon launch, resulting in a greater maximum height.
(a) The time it takes to reach the maximum height. (b) The duration of the flight can be calculated using the following formula:(c) The launch angle, initial speed, and launch height are all variables that influence how high and far the ball flies. The higher the launch angle, the higher the ball's height; the higher the initial velocity, the higher and farther the ball will travel; and the greater the launch height, the greater the ball's potential energy will be upon launch, resulting in a greater maximum height.
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In the context of the motor control process related to the speed-accuracy trade-off, the _____ phase of movement includes the beginning of limb movement in the direction of a target.
In the context of the motor control process related to the speed-accuracy trade-off, the initiation phase of movement includes the beginning of limb movement in the direction of a target.
What is motor control?Motor control is the ability to regulate and coordinate motor skills to achieve a desired outcome. The central nervous system (CNS) is in charge of regulating these skills. The CNS is divided into two parts: the peripheral nervous system (PNS) and the central nervous system (CNS). Motor skills are regulated by both parts of the nervous system. The CNS, on the other hand, is more involved in higher-level motor control.
A motor control system can be divided into three stages: planning, initiation, and execution. When the central nervous system processes the desired movement, it activates the motor program in the initiation stage, which produces the motor command sent to the muscles. Movement is initiated by the initiation stage. Following that, the movement is executed to meet the task's requirements. The motor program adjusts movement by making corrections based on previous trials and feedback. Therefore, the initiation phase is critical in the context of the motor control process related to the speed-accuracy trade-off.
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in simple meters, the beat is divided into two, and in compound meters the beat is divided into how many?
In simple meters, the beat is divided into two parts, while in compound meters, the beat is divided into three parts.
A meter, or time signature, in music notation is a fraction-like symbol placed at the beginning of a piece of music that indicates the number and duration of beats in each measure. In simple meters, such as 2/4 or 3/4, the beat is subdivided into two parts, which are typically equal in duration. In compound meters, such as 6/8 or 9/8, the beat is subdivided into three parts, each of which is typically shorter than the beat duration and adds up to the beat duration. Compound meters are often used in music genres such as jazz, Latin, and folk music.
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In music theory, a beat is divided into two equal parts in simple meters, while in compound meters, the beat is generally divided into three equal parts. One example of a compound meter is 6/8, where the 6 beats would be split into two groups of 3 beats.
Explanation:In music theory, specifically relating to rhythm and meter, a beat can be divided into different ways depending on whether the music is in simple meter or compound meter. In simple meters, the beat is divided into two equal parts. However, in compound meters, the beat is typically divided into three equal parts.
For example, if you have a compound meter such as 6/8, there are 6 beats in a measure, and these 6 beats would split into two groups of 3 beats, giving it a 'triplet feel'. This contrasts with a simple meter like 2/4, where the beats would divided into two halves.
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consider a single crystal of some hypothetical metal that has the fcc crystal structure and is oriented such that a tensile stress is applied along a direction. if slip occurs on a (111) plane and in a direction, compute the stress at which the crystal yields if its critical resolved shear stress is 3.42 mpa.
Consider a single crystal of some hypothetical metal that has the FCC crystal structure and is oriented such that a tensile stress is applied along a direction. If slip occurs on a (111) plane and in a direction, compute the stress at which the crystal yields if its critical resolved shear stress is 3.42 MPa.
The resolved shear stress (τR) can be calculated using the following formula:τR = σs cos φ cos λWhere,σs = tensile stress applied along a directionφ = angle between tensile stress direction and (111) planeλ = angle between the slip direction and [110] directionThe resolved shear stress (τR) should be compared to the critical resolved shear stress (τc) to determine if slip will occur. If τR > τc, slip will occur. If τR < τc, the crystal will remain undeformed.In this case, the slip direction is also along [110] and therefore φ = λ.
The critical resolved shear stress (τc) = 3.42 MPa. Hence, for slip to occur,τR > τc ⇒ σs cos φ cos λ > τc cos φ cos λ = 3.42 MPaSince φ = λ, we can simplify the above equation toσs > τc / cos φ⇒ σs > 3.42 MPa / cos φIf we assume φ = 45°, we can substitute in this value to get the value of σs at which slip occurs:σs > 4.83 MPa. Therefore, the stress at which the crystal yields is 3.42 MPa.
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one electron collides elastically with a second electron initially at rest. after the collision, the radii of their trajectories are 0.00 cm and 3.00 cm. the trajectories are perpendicular to a uniform magnetic field of magnitude 0.0350 t. determine the energy (in kev) of the incident electron.
The energy of the incident electron is 26.3 keV. The energy is calculated from the conservation of energy which states that the initial energy is equal to the final energy of the electrons. Total energy is sum of kinetic energy and potential energy of the electrons.
The initial energy of the incident electron can be determined using the following equation:
[tex]E_{initial}= \Delta K + E_{final} + U[/tex]
where ΔK is the change in kinetic energy, [tex]E_{final}[/tex] is the final energy, and U is the potential energy.
Here, the second electron is initially at rest, and after the collision, the trajectories of the two electrons are at 90° to a uniform magnetic field. The magnetic force is perpendicular to the direction of motion, and hence, there is no work done. The potential energy U is, therefore, zero.
Initially, only the incident electron has energy, and hence, its initial energy is equal to its kinetic energy.
[tex]E_{initial} = \Delta K + E_{final}[/tex]
But, [tex]E_{final} = \frac{1}{2}mv_f^2[/tex]
Therefore,
[tex]E_{initial} = \Delta K + \frac{1}{2}mv_f^2[/tex]
The change in kinetic energy ΔK can be calculated using the following equation:
[tex]\Delta K = K_f - K_i[/tex]
But, [tex]K_i = \frac{1}{2}mv_i^2[/tex] where, [tex]v_i[/tex] is the initial velocity of the incident electron.
Therefore,
[tex]\Delta K = K_f - K_i= \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2[/tex]
Substituting the given values,
[tex]\Delta K = \frac{1}{2}(9.11 \times 10^{-31} kg)(4.24\times 10^5 m/s)^2 - \frac{1}{2}(9.11\times10^{-31} kg)(3\times10^8 m/s)^2\\= -4.22\times10^{-15} Joules[/tex]
The energy of the incident electron can be converted to keV by dividing it by the charge of an electron and then multiplying by 1000.eV .
Therefore,
[tex]E_{initial} = 4.22 \times 10^{-15} J / (1.602 \times 10^{-19} C/eV)\\ = 26.3 keV[/tex]
Thus, the energy of the incident electron is 26.3 keV.
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The major types of stress are ___ A. Ductile and Brittle B. Compression, Ductile, and Brittle C. Compression, Strain, and Deformation D.Shear, Tension and Compression E. Shear, Ductile, Tension, Brittle, and Compression
The major types of stress are shear, Tension, and Compression. Therefore option D is correct.
Stress refers to the internal forces acting on a material, causing it to deform or change shape. Different types of stress can act on a material, and they are characterized by the way in which the forces are applied.
1. Shear stress: Shear stress occurs when two forces act parallel to each other but in opposite directions, causing the material to deform by sliding or shearing.
2. Tension stress: Tension stress occurs when forces are applied to pull a material apart. It leads to elongation or stretching of the material.
3. Compression stress: Compression stress occurs when forces are applied to squeeze or compress a material.
Therefore, the correct answer is D. Shear, Tension, and Compression, as these three options represent distinct types of stress commonly encountered in materials and structures.
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The major types of stress are Shear, Tension and Compression. The correct option is D.
Thus, Shear stress, tension stress, and compression stress are the three main forms of stress.
Shear stress is a condition when forces acting in opposite directions and parallel to a surface cause the material to deform by sliding or shearing. It is connected to the propensity for one layer of material to slide or move in relation to another layer.
Tension stress, sometimes referred to as tensile stress, is the strain that develops when a material is subjected to pulling or stretching forces that are applied in opposition to one another, causing the material to elongate. The material tends to be pulled apart by tension stress.
Thus, The major types of stress are Shear, Tension and Compression. The correct option is D.
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_______because the terminals of the battery are connected to__________ of the lightbulb filament
Electric current flows because the terminals of the battery are connected to opposite ends or terminals of the lightbulb filament.
What is current flow?Current flow refers to the movement of electric charge through a conductor, such as a wire. Electric current is the rate at which electric charge flows past a given point in the conductor, and it is measured in amperes (A).
In a circuit, electric current flows because of the presence of a voltage difference, or potential difference, between two points in the circuit. The voltage difference causes the electrons to flow from the negative terminal of the battery or power source, through the conductor, and back to the positive terminal of the battery or power source. This flow of electrons constitutes an electric current.
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Give specific examples that illustrate the following processes. a. Work is done on a system, thereby increasing kinetic energy with no change in potential energy. b. Potential energy is changed to kinetic energy with no work done on the system. c. Work is done on a system, increasing potential energy with no change in kinetic energy. d. Kinetic energy is reduced, but potential energy is unchanged. Work is done by the system.
a. Examples of work being done on a system to increase kinetic energy with no change in potential energy include a person pushing a box across the floor, a ball rolling down a hill, and a rocket blasting off a launchpad.
b. Examples of potential energy changing to kinetic energy with no work done on the system include a skydiver jumping out of a plane and a rollercoaster car descending down a hill.
c. Examples of work being done on a system to increase potential energy with no change in kinetic energy include lifting a box up onto a shelf and pulling a rubber band back and stretching it.
d. Examples of kinetic energy being reduced but potential energy remaining unchanged with work done by the system include a ball rolling up a hill and a rocket thrusting up into the sky.
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a bullet of mass, m is fired horizontally into a block of mass, m as shown. the block with the embedded bullet rises to height, h. acceleration due to gravity is g acting downward. part a: what is the speed, v of the block (with the bullet embedded in it) immediately after the collision, in terms of the variables provided in the problem?
The speed of the block (with the bullet embedded in it) immediately after the collision, in terms of the variables provided in the problem, is given by [tex]v = (m/(m + M)) * (2gh)^{0.5}[/tex], where m is the mass of the bullet, M is the mass of the block, and h is the height to which the block rises.
First, we assume that the collision is perfectly inelastic, meaning that the bullet becomes embedded in the block and they move together as a single mass. In this case, the conservation of momentum equation can be written as:
[tex]m_{bullet} * v_{bullet} = (m_{block} + m_{bullet}) * v_{final}[/tex]
where v_bullet is the initial velocity of the bullet, v_final is the final velocity of the block with the embedded bullet, and we have used the fact that the block and bullet move together as a single mass after the collision.
Next, we can apply conservation of energy to find the velocity of the block with the embedded bullet at the height h. Since the collision is inelastic, some of the initial kinetic energy is lost as heat and deformation. We can express the conservation of energy equation as:
[tex](1/2) * m_{bullet} * v_{bulle}t^2 = (m_{block} + m_{bullet}) * g * h[/tex]
where g is the acceleration due to gravity and we have used the fact that the potential energy gained by the block-bullet system is equal to the initial kinetic energy of the bullet.
Solving for v_final in the momentum equation and substituting it into the energy equation, we get:
[tex](1/2) * m_{bullet} * v_{bullet}^{2} = (m_{block} + m_{bullet}) * g * h[/tex]
[tex]v_{final} = v_{bullet} * (m_{bullet} / (m_{block} + m_{bullet}))^{0.5}[/tex]
So the speed of the block with the bullet embedded in it immediately after the collision can be calculated using this equation, where we plug in the values of [tex]m_{bullet}, m_{block}, v_{bullet}[/tex], and h.
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What does the average kinetic energy of gas depend on?
Answer: temperature
Explanation: The last postulate of the kinetic molecular theory states that the average kinetic energy of a gas particle depends only on the temperature of the gas. Thus, the average kinetic energy of the gas particles increases as the gas becomes warmer.
A car’s cooling system contains 25 kg of water. What is the increased change in temperature of the water if 872. 0 kJ of thermal energy is added?
When 872.0 kJ of thermal energy are injected, the temperature of the 25 kg of water in the car's cooling system changes by 35.0 degrees Celsius.
Water's specific heat capacity (J/(gK), or 4,180 J/ (kgK). Thus, we can use the following formula to get the temperature change:
Q = mcΔT
where Q is the extra thermal energy (872 000 J), m the water mass (25 kg), c the water's specific heat capacity (4,180 J/(kg*K)), and T the temperature change.
When we solve for T, we get:
The equation T = Q/(mc) Equals 872,000 J/(25 kg * 4,180 J/(kgK)) = 35.0 °C.
When 872.0 kJ of thermal energy are injected, the temperature of the 25 kg of water in the car's cooling system changes by 35.0 degrees Celsius.
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true or false an action potential introduced at the neuromuscular junction is propagated along the sarcoplasmic reticulum.
The given statement an action potential introduced at the neuromuscular junction is propagated along the sarcoplasmic reticulum is false because the action potential is only propagated along the muscle cell membrane and not along the sarcoplasmic reticulum.
An action potential introduced at the neuromuscular junction (NMJ) triggers the release of calcium ions (Ca2+) from the sarcoplasmic reticulum (SR), but the action potential itself is not propagated along the SR. The SR is a specialized organelle found in muscle cells that stores and releases calcium ions, which are necessary for muscle contraction. When an action potential reaches the NMJ, it triggers the release of the neurotransmitter acetylcholine, which binds to receptors on the muscle cell membrane and causes an influx of sodium ions (Na+) and an efflux of potassium ions (K+), generating an action potential that spreads across the muscle cell membrane and into the SR. The release of Ca2+ from the SR then initiates the process of muscle contraction.
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A block of weight w = 25.0 N sits on a frictionless inclined plane, which makes an angle 8 = 29.0° with respect to the horizontal, as shown in the figure. (Figure 1) A force of magnitude F = 12.1 N, applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed.
Part B: What is We, the work done on the block by the force of gravity was the block moves a distance L = 3.40 m up the incline?
Part C. What is Wf the work done on the block by the applied force F as the block moves a distance L = 3.40 mm up the incline? Express your answer in Joules
a) The net Work done is zero. b) The work done on the block by the applied force F as the block moves a distance L is -41.2 J. c) The work done on the block by the applied force F as the block moves a distance L is 41.2 J.
Given:
Weight of the block (w) = 25.0 N
Distance moved by the block (d) = 3.40 m
The angle of the inclined plane (θ) = 29.0°
a) we know that from the work-energy theorem,
W = change in kinetic energy
But since speed is constant which means no change in KE, hence the net Work done is zero.
b) W = -mgy
W = -25 × (3.10 × sin29°)
W = -41.2 J
Therefore, the work done on the block by the force of gravity is -41.2 J.
c) The work done on the block by the applied force F as the block moves a distance L = 3.10m up the incline is,
W = Fd
W = 12.1 × 3.1
W = 41.2 J
Therefore, the work done on the block by the applied force F as the block moves a distance L is 41.2 J.
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consider a 10 m length of 2 cm-i.d tube. what is the average convective heat transfer coefficient and pressure gradient inside the tube when the tube wall is at 330 k and water enters at 300 k, 1 atm pressure, and flows at a velocity of 3 m/s?
The average convective heat transfer coefficient and pressure gradient inside a 10 m long tube with a 2 cm inner diameter when the tube wall is at 330 K and water enters at 300 K and 1 atm pressure, flowing at a velocity of 3 m/s, is: 1420 W/m²K and 2.6 x 10⁴ Pa
This can be calculated using the equations of fluid mechanics. The average convective heat transfer coefficient, or h, is determined using the following equation:
[tex]h = (k/d) x (v/P).[/tex]
k is the thermal conductivity of the fluid (water), d is the tube inner diameter, v is the velocity of the fluid, and P is the pressure gradient across the tube wall.
The pressure gradient is found using the equation: [tex]P = (v²/2g) + P₀[/tex],
where v is the fluid velocity, g is the acceleration due to gravity, and P₀ is the pressure at the inlet of the tube (1 atm in this case). Plugging the given values into the equations yields a heat transfer coefficient of 1420 W/m²K and a pressure gradient of 2.6 x 10⁴ Pa.
In conclusion, the average convective heat transfer coefficient and pressure gradient inside a 10 m long tube with a 2 cm inner diameter when the tube wall is at 330 K and water enters at 300 K and 1 atm pressure, flowing at a velocity of 3 m/s, is 1420 W/m²K and 2.6 x 10⁴ Pa, respectively.
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Five docks are being tested in a laboratory. Exactly at noon, as determined by the WWV
Exactly at noon, as determined by the WWV time signal, on successive days of a week the clocks according to their relative value as good timekeepers, best to worst.
Time signals are also used in many everyday applications, such as GPS navigation, where precise timing is essential for calculating positions accurately. A time signal refers to any signal that provides information about the passage of time. Time signals are often used in experiments to measure the duration of events or to synchronize the timing of multiple processes.
One common type of time signal is a periodic signal, which repeats itself at regular intervals. This can be used to measure the period or frequency of a phenomenon, such as the oscillation of a pendulum or the vibration of a guitar string. Another type of time signal is a pulse signal, which provides a brief burst of energy at a specific time. This can be used to trigger the start or stop of a process or to measure the time delay between different events.
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question 6: circuit balance given 6 , what is the current of the ideal current source, , for which there is no current flowing through the 5 resistor?
The current of the ideal current source in the given circuit is zero.
This is because the current source is not providing any current and the 5 ohm resistor is not providing any resistance. Thus, no current can flow through the circuit.
In this circuit, there is a current source with 6 volts and a 5 ohm resistor. The current source does not provide any current since it is ideal, meaning it does not create any voltage drops. Therefore, no current can flow through the circuit.
This is because there is no voltage difference between the two nodes (points) between which the current is supposed to flow.
The 5 ohm resistor also does not provide any resistance, meaning the same current would flow through the resistor as well. Thus, the current of the ideal current source in the given circuit is zero.
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One object is placed on each shelf in the image above (W, X, Y, Z). The four objects have the same mass, 2.0 kg. Match each object to its potential energy.
Object W 7.84 J 15.7 J 13.4 J 0 J 23.5 J 5.62
Object X
Object Y
Object Z
Potential Energy of Object W, X, Y and Z are 0 J, 7.84 J, 15.7J and 23.5J, for better understand we have to know the meaning of potential energy.
What is Potential Energy?Potential energy in physics is the energy that an item retains as a result of its location in relation to other objects, internal tensions, electric charge, or other elements. Potential energy develops in systems having components whose configurations, or relative positions, determine the amount of the forces they apply to one another.
Potential Energy of an Object = m * g * h
Where, m = mass,
g = gravity, and
h = height
Potential Energy of Object W = 2 * 9.8 * 0
= 0 J
Potential Energy of Object X = 2 * 9.8 * 0.4
= 7.84 J
Potential Energy of Object Y = 2 * 9.8 * 0.8
= 15.68 J
≈ 15.7 J
Potential Energy of Object Z = 2 * 9.8 * 1.2
= 23.5 J
Therefore, Potential Energy of Object W, X, Y and Z are 0 J, 7.84 J, 15.7 J and 23.5 J.
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if a force is exerted on an object, is it possible for that object to be moving with constant velocity? explain
Yes, it is possible for an object to be moving with a constant velocity even when force is exerted on the object. When an object is in a state of rest, a force is required to move it from that position.
What is Newton's second law of motion?Newton’s second law states that the acceleration of an object is directly proportional to the force exerted on it and inversely proportional to its mass. Thus, a larger force results in a greater acceleration of the object. If there is no force applied to the object, the object will remain stationary or move at a constant velocity.
However, if there is a force applied to the object, it will accelerate. If the force applied is balanced by an equal and opposite force, the object will continue to move with a constant velocity. An object in motion is said to be in equilibrium when the net force acting on the object is zero. When the net force acting on an object is zero, it moves at a constant velocity. Therefore, if a force is exerted on an object, it is possible for the object to be moving with a constant velocity if the forces are balanced.
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You stand 3.5 m in front of a large mirror, and your little sister stands 2.0 m directly in front of you. At what distance should you focus your camera if you want to take a picture of your sister in the mirror?
Answer:
D = 3.5 m to mirror
d = 1.50 m from mirror to sister
Total distance from camera to sister = d + D = 5.0 m
A 71. 0 kg
football player is gliding across very smooth ice at 2. 05 m/s. He throws a 0. 440 kg
football straight forward
Using conservation of momentum the player's speed afterward if the ball is thrown at 17.5 ms relative to the player is 3.02 m/s.
We can use the principle of conservation of momentum to solve this problem, which states that the total momentum of a closed system remains constant if no external forces act on it.
Initially, the momentum of the system is the sum of the momentum of the football player and the football, given by:
p_initial = m_player × v_player + m_football × v_football
where:
m_player = 71 kg is the mass of the football player
v_player = 2 m/s is the initial velocity of the football player
m_football = 0.430 kg is the mass of the football
v_football = 17.5 m/s is the velocity of the football relative to the football player
Plugging in the values, we get:
p_initial = (71 kg)(2 m/s) + (0.430 kg)(17.5 m/s) = 15.325 kg m/s
After the football is thrown, the football player will move in the opposite direction with a new velocity v_player'. The momentum of the system after the throw is:
p_final = m_player × v_player' + m_football × v_football'
where v_football' = 0 m/s since the football has left the system.
Since the total momentum of the system is conserved, we have:
p_initial = p_final
which gives us:
m_player × v_player + m_football × v_football = m_player × v_player'
Solving for v_player', we get:
v_player' = (m_player × v_player + m_football × v_football) / m_player
Plugging in the values, we get:
v_player' = (71 kg × 2 m/s + 0.430 kg × 17.5 m/s) / 71 kg = 3.02 m/s
Therefore, the football player's speed after throwing the football is 3.02 m/s.
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The question is -
A 71 kg football player is gliding across very smooth ice at 2 ms. He throws a 0.430 kg football straight forward. What is the player's speed afterward if the ball is thrown at 17.5 ms relative to the player?
A car moves with this distance vs time function: 5 = 2t^2 + 2. what is the acceleration rate of the car? (clue: use derivatives) answer with number only, e.g. if it's 6t m/s^2, just write 6t
Answer:
just write 6t and the same
Based on the equation given in the lab manual, what is the equation to find the equivalent resistance of two resistors in parallel? Note: I do not want inverse resistance, I'm asking for R = ..) R1 + R2 Req + R2 Req R2 R1 Rea R1 R2 R1+R2
This equation can be used to determine the equivalent resistance of two parallel resistors: 1/Req = 1/R1 + 1/R2 Upon solving for Req, we obtain: Requirement = (R1-R2) / (R1+R2)
What is the parallel pairing of two resistors' equivalent resistance?The equivalent resistance of two identical resistors connected in parallel is equal to one-half the value of each resistor. Both share an equal amount of the current.
How are resistance and resistance calculated?Resistors are connected in series when they are connected one after the other. This is seen below. You add up the individual resistances to determine the total overall resistance of several resistors connected in this manner. The following equation is used to accomplish this: Rtotal = R1 + R2 + R3 and so forth.
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suppose the roller coaster had had an initial speed of 5 m/s uphill instead, and it coasted uphill, stopped, and then rolled back down to a final point 20 m below the start. we would find in that case that its final speed is the same as its initial. explain in terms of conservation of energy.
In this case, the roller coaster starts with kinetic energy because it has an initial speed of 5 m/s.
Since the roller coaster's total energy is conserved throughout the ride, its final speed when it reaches the bottom will be the same as its initial speed of 5 m/s.
As it goes uphill, the kinetic energy is gradually converted into potential energy, so its speed decreases until it reaches the top, where it has only potential energy. When it stops, all the kinetic energy has been converted to potential energy. As the roller coaster rolls back down, the potential energy is converted back to kinetic energy, and its speed increases until it reaches the bottom, where all the potential energy has been converted back to kinetic energy.
This is because the roller coaster's potential energy at the top is equal to the sum of its initial kinetic energy and the work done by gravity as it went uphill. The roller coaster then converts all of its potential energy back into kinetic energy as it rolls back down the hill.
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to be credible an rca must be internally consistent
Be regularly applied, have strong backing from the organization's leadership, involve people who are close to you, and take into account relevant literature and EBM.
What is RCA?An RCA must: Involve participation from the organization's leadership and those who are most directly involved in the systems and processes if it is to be considered credible. Maintain intrinsic coherence. Take into account any pertinent literature.RCA is a structured, assisted team procedure used to find the underlying reasons why an event led to an undesirable outcome and create appropriate corrective measures. You can determine process and system flaws that contributed to the occurrence and how to avoid it in the future by using the RCA procedure.For more information on root cause analysis kindly visit to
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Complete question: to be credible an rca must be _______.
