How do I solve this
Answer:
-36
Step-by-step explanation:
[tex]-\frac{t}{2} -8 = 10\\-\frac{t}{2} = 18\\\frac{t}{2} = -18\\t = -36[/tex]
you
work.
Factor each expression. If the expression cannot be factored, write
cannot be factored. Use algebra tiles if needed. (Examples 4,5,6
4. 3x + 6
5. 2x - 15
6.12x+30y
Answer:
4) 3(x+2)
5) Cannot be factored
6)3(4x+10y)
Step-by-step explanation:
4)3x+6
3(x+2)
Proof:
3(x+2)
3x+6
5)2x-15
Cannot be factored.
6)12x+30y
3(4x+10y)
Proof:
3(4x+10y)
12x+30y
Hope this helps ;) ❤❤❤
What's the recursive formula of the geometric sequence below?
2, 6, 18, 54, 162, 486,...
O ay = 3; an = an-1 · (2)n-1 for n 2 2
a1 = 2; an = an-1 . (3) for n 2 2
O a1 = 2; an = an-1 • (3)n-1 for n 2 1
ay = 2; an = an-1. (2) for n 2 1
Answer:
Hey there!
We have an=a1(r^n-1), which is the formula for a geometric sequence.
The common ratio is 3, and 2 is the 1st term.
Thus, we have a1=2(3)^(n-1)
Hope this helps :)
Answer:
Hey there!
We have an=a1(r^n-1), which is the formula
for a geometric sequence.
The common ratio is 3, and 2 is the 1st
term.
Thus, we have a1=2(3)^(n-1)
(k) 1 + tan 4A . tan 2A = sec 4A.
Please help me.... question from multiple angle of trigonometry!!!!!
it was a long proof...
follow the caption and steps and you'll understand it
proved...
Step-by-step explanation:
this is too easy method to solve this problem
abbi invested $1,000 in a certificate of deposit with a simple interest rate of 6% find the interest earned in 4 years. then find the total of principal plus interest.
Answer:
Step-by-step explanation:
Find the average rate of change of g(x)= – x2 over the interval [ – 8, – 2]. Write your answer as an integer, fraction, or decimal rounded to the nearest tenth. Simplify any fractions.
Answer:
[tex]Average\ Rate = 10[/tex]
Step-by-step explanation:
Given
[tex]g(x) = -x^2[/tex]
[tex](-8,-2)[/tex]
Required
Determine the average rate of change;
Average rate of change is calculated as thus;
[tex]Average\ Rate = \frac{g(b) - g(a)}{b - a}[/tex]
Where
[tex](a,b) = (-8,-2)[/tex]
i.e. a = -8 and b = -2
[tex]Average\ Rate = \frac{g(b) - g(a)}{b - a}[/tex] becomes
[tex]Average\ Rate = \frac{g(-2) - g(-8)}{-2 - (-8)}[/tex]
[tex]Average\ Rate = \frac{g(-2) - g(-8)}{-2 + 8}[/tex]
[tex]Average\ Rate = \frac{g(-2) - g(-8)}{6}[/tex]
Calculating g(-2)
Substitute -2 for x in [tex]g(x) = -x^2[/tex]
[tex]g(-2) = -(-2)^2[/tex]
[tex]g(-2) = -4[/tex]
Calculating g(-8)
Substitute -8 for x in [tex]g(x) = -x^2[/tex]
[tex]g(-8) = -(-8)^2[/tex]
[tex]g(-8) = -64[/tex]
Substitute values for g(-2) and g(-8)
[tex]Average\ Rate = \frac{g(-2) - g(-8)}{6}[/tex]
[tex]Average\ Rate = \frac{-4 - (-64)}{6}[/tex]
[tex]Average\ Rate = \frac{-4 + 64}{6}[/tex]
[tex]Average\ Rate = \frac{60}{6}[/tex]
[tex]Average\ Rate = 10[/tex]
Hence, the average rate of change is 10
find the perimeter and area of the shaded region.
Answer:
Area=576 cm²
Perimeter=123.4 cm
Step-by-step explanation:
We have to assume that ABCD would form a square and not a rectangle. If so, the area is simple: 24x24=576 (Just picture the half circle sliding into the empty space - it’s the same area.)
For the perimeter, we find it for the half circle first. 1/2(2)[tex]\pi[/tex](12)=37.7
Then add the top and bottom (24 and 24) to the left and right (37.7 And 37.7)
24+24+37.7+37.7=123.4
Kara has twenty-four thousand, five hundred sixty stickers in her album.
Raul has 20,000 + 4,000 + 500 + 60 stickers in his collection.
Answer:
they are both the same thing the first one with kara is in numbers and with raul it is in words
Step-by-step explanation:
hope i helped and have a great day :)
Vince and 11 of his friends went out for pizza on Saturday night to celebrate Vince’s birthday. The cost of the pizza and soft drinks before sales tax and tip was $47.96. What is the amount of sales tax for the bill if the rate is 7%? Show your work.
Step-by-step explanation:
Since the original price is $47.96 and bill rate is 7%, $47.96 × 1.07 ≈ $51.32
Answer:
$51.32
The amount of sales tax for the bill if the rate is 7% will be $3.36.
What is the percentage?The quantity of anything is stated as though it were a fraction of a hundred.
Vince and 11 of his friends went out for pizza on Saturday night to celebrate Vince’s birthday.
The cost of the pizza and soft drinks before sales tax and tip was $47.96.
Then the amount of sales tax for the bill if the rate is 7% will be
⇒ $47.96 x 0.07
⇒ $3.36
More about the percentage link is given below.
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A grocery store recently sold a bag of peanuts for $0.76 and a bag of Pikachu's for $3.68 at the end of the day 50 bags of peanuts and Pikachu's were sold for a total of 128 point 52 how many bags of each were sold
Answer:
31 Pikachu bags were sold.
19 peanut bags were sold.
Step-by-step explanation:
Let's set up an equation of the total revenue of the day, where x is the number of Pikachu's sold.
We know that the number of Peanuts sold is 50-x (as the total needs to be 50)
We know that the total revenue is:
Number of Pikachus * Cost per Pikachus + Number of Peanuts * Cost per Peanuts
Using our definitions above:
Total Revenue = x * $3.68 + (50-x) * $0.76
We know that the revenue needs to be $128.52.
$128.52 = x * $3.68 + (50-x) * $0.76
Let's remove the $ signs.
128.52 = x * 3.68 + (50-x) * 0.76
Multiplying both 50 and -x with 0.76, "expanding" the parenthesis.
128.52 = x*3.68 + 50*0.76 - x*0.76
128.52 = x*3.68 + 38 - 0.76*x
Subtracting 38 from both sides
90.52 = 3.68*x - 0.76*x
We can simplify the right side.
90.52 = 2.92*x
We can divide both sides by 2.92:
31 = x
And flip it:
x = 31
So 31 Pikachus were sold (remember we claled that x), and as we know, the number of peanut bags sold is
50-x = 50-31 = 19
31 Pikachu bags were sold.
19 peanut bags were sold.
[tex] \LARGE{ \boxed{ \rm{ \pink{Solution:}}}}[/tex]
Let the number of peanut bags be x
Then, Number of pikachu bags = 50 - x
Given,
Cost of each peanut bag = $0.76Cost of each pikachu bag = $3.68Then,
⇛ Total cost he gets from peanut bag = $0.76 × x
⇛ Total cost he gets from pikachu bag = $3.68(50 - x)
According to question,
⇛ $0.76x+ $3.68(50 - x) = $128.52
Solving this equation,
⇛ 0.76x + 184 - 3.68x = 128.52 (Removed $ symbol)
⇛ 184 - 2.92x = 128.52
⇛ 184 - 128.52 = 2.92x
⇛ 55.48 = 2.92x
Flipping the equation,
⇛ 2.92x = 55.48
⇛ x = 55.48 / 2.92
⇛ x = 19
Then,
⇛ 50 - x = 50 - 19 = 31
[tex] \large{ \therefore{ \boxed{ \rm{ \purple{No. \: of \: peanut \: bags = 19}}}}}[/tex]
[tex] \large{ \therefore{ \boxed{ \rm{ \purple{No. \: of \: pikachu \: bags = 31}}}}}[/tex]
━━━━━━━━━━━━━━━━━━━━
PLEASE HELP PLEASE WILL MARK BRAINLY
Answer:
16,20,8,36
Step-by-step explanation:
he plans to have 2 tables for every 8 guest, which means 1 table for each 4 guest!
now:
2(tables)×4(number of people at each table)=8(number of guests
4×4=16
5×4=20
32(number of guests)÷4(number of people at each table)=8(number of tables)
9×4= 36
Answer:
Since there are 8 guests every 2 table we need to find how many guests are in one table:
8 ÷ 2 = 4 guests
4 tables = 4 x 4 = 16 guests
5 tables = 5 x 4 = 20 guests
32 guests = 32 ÷ 4 = 8 tables
9 tables = 9 x 4 = 36 guests
Hope this helps :D
Which equation represents an ellipse with foci at (3, 2) and (-9, 2)
that passes through the point (-3, 10)?
Answer:
D, since it horizontal ellipse, a is greater than b
An ellipse has two foci. The correct option is D.
What is the equation of ellipse if its major and minor axis and centre are given?Suppose that the major axis is of the length 2a units and that the minor axis is of 2b units, and let the ellipse is centred on (h,k) with a major ellipse parallel to the x-axis, then the equation of that ellipse would be:
[tex]\dfrac{(x-h)^2}{a^2} + \dfrac{(y-k)^2}{b^2} =1[/tex]
Coordinates of its foci would be: (h±c, k) where c² = a² - b²
If its major axis is parallel to the y-axis, then,
coordinates of its foci would be: (h, k±c) where c² = a² - b² and its equation would be:
[tex]\dfrac{(x-h)^2}{b^2} + \dfrac{(y-k)^2}{a^2} =1[/tex]
Given the foci at (3, 2) and (-9, 2) that pass through the point (-3, 10), therefore, the equation of the ellipse will be,
[tex]\dfrac{\left(x+3\right)^{2}}{100}+\dfrac{\left(y-2\right)^{2}}{64}=1[/tex]
Hence, the correct option is D.
Learn more about Ellipse:
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Solve the equation using the square root method. Select all solutions that apply. x^2 = 36 A.-8 B.6 C.-6 D.8
Answer:
x = ± 6
Step-by-step explanation:
x^2 = 36
Take the square root of each side
sqrt(x^2) = sqrt(36)
x = ± 6
Answer:
[tex]\large \boxed{\boxed{x=\pm 6}}[/tex]
Step-by-step explanation:
[tex]x^2 =36[/tex]
Take the square root on both sides.
[tex]\sqrt{x^2} =\pm \sqrt{36}[/tex]
Simplify.
[tex]x=\pm 6[/tex]
Factor the following expression completely:
32
z
4
+
8
z
3
−
4
z
2
Answer:
40z + 5
Step-by-step explanation:
I'm assuming you need to factor 32z + 4 + 8z + 3 - 4 + 2
32z + 8z ( since they both have the same variable ) = 40z4 + 3 - 4 + 2 ( since they have to variables ) = 5Hope this helped
Answer:
The factored expression for the given equation is 4(8z⁴ + 2z³ - z²)
Step-by-step explanation:
In the problem, we a re given an equation.
32z⁴ + 8z³ - 4z²
We can factor out this equation by finding the common factor between all of the coefficients which are 32, 8, and 4.
A common factor between them is 4 because each number can be easily divided by 4. Each number is also a multiple of 4. So, when we are factoring, we will divide each number by 4 because 4 will be on the outside of the parentheses in the final answer.
4(8z⁴ + 2z³ - z²)
So, this is your factored expression from the given equation.
You are making the kite shown at the right from
five pairs of congruent panels. In parts (a)-(d)
below, use the given information to find the side
lengths of the kite's panels.
Answer:
a. Side lengths of ΔBEX are;
BE = 15 ft.
EX = 12 ft.
BX = 9 ft.
b. Side lengths of XEFY are;
XY = 6 ft.
EX = 12 ft.
FY = 7.5 ft.
EF = 7.5 ft.
c. Side lengths of YFGZ are;
GZ = 6 ft.
FY = 7.5 ft.
YZ = 2 ft.
FG = 2.5 ft.
d. Side length of triangle ZGC
GZ = 6 ft.
GC = 10 ft.
ZC = 8 ft.
Step-by-step explanation:
The given parameters are;
XY : YZ : ZC is 3 : 1 : 4
The length of BC = 25 in.
The length of EB = 15 in.
Therefore, EC = √(BC² - EB²) = √(25² - 15²) = √400 = 20 in.
Given that EX║ YF║GZ, we have;
EF : FG : GC is 3 : 1 : 4 (Parallel lines cut segments in equal proportions)
Therefore;
EF = 20 × 3/(3 + 1 + 4) = 7.5 ft.
FG = 20×1/8 = 2.5 ft.
GC = 20×4/8 = 10 ft.
EC/EX = BC/EB
20/EX = 25/15
EX = 15×20/25 = 12 ft.
XC = √(EC² - EX²) = √(20² - 12²) = 16
XY : YZ : ZC is 3 : 1 : 4
Therefore;
XY = 16 × 3/8 = 6 ft.
YZ = 16 × 1/8 = 2 ft.
ZC = 16 × 4/8 = 8 ft.
GZ = √(GC² - ZC²) = √(10² - 8²) = 6
Area of triangle ΔZGC = 1/2×6×8 = 24 ft²
XB = BC - XC = 25 - 16 = 9 ft.
Area of ΔBEX = 1/2×9×12 = 54 ft²
a. Side lengths of ΔBEX are;
BE = 15 ft.
EX = 12 ft.
BX = 9 ft.
FY = √(FC² - YC²) = √((10 + 2.5)² - (8 + 2)²) = 7.5 ft.
Area of YFGZ = (GZ + FY)/2 × YZ = (6 + 7.5)/2 × 2 = 13.5 ft²
Area of YFGZ = 13.5 ft²
Area of XEFY = XY × (EX + FY)/2 = 6 × (12 + 7.5)/2 = 58.5 ft.²
b. Side lengths of XEFY are;
XY = 6 ft.
EX = 12 ft.
FY = 7.5 ft.
EF = 7.5 ft.
c. Side lengths of YFGZ are;
GZ = 6 ft.
FY = 7.5 ft.
YZ = 2 ft.
FG = 2.5 ft.
d. Side length of triangle ZGC
GZ = 6 ft.
GC = 10 ft.
ZC = 8 ft.
Drag each value to the correct location on the equation. Each value can be used more than once.
Answer:
[tex]x=\frac{-b\pm \sqrt{b^{2}-4ac } }{2a}[/tex]
Step-by-step explanation:
If a quadratic equation is in the form of ax²+ bx + c = 0
Then the roots of this quadratic equation can be obtained by,
1). Factoring the expression.
2). By quadratic formula.
If we use the method to get the value of x or roots of the equation,
x = [tex]\frac{-b\pm \sqrt{b^{2}-4ac } }{2a}[/tex]
where a, b and c are the coefficients used in the quadratic equation.
write the fraction for each of the following do number 3 and 4 thanks
Answer:
7
Step-by-step explanation:
Help plz, thx urgent
Answers:
5. Quadrilateral
6. Rhombus
7. Rectangle
8. Parallelogram
=============================
Explanations:
5. We don't know much about this other than it has 4 sides, so we simply say it is a quadrilateral. Quad = 4, lateral = side
-----------
6. The four sides are the same length as shown by the similar tickmarks. Therefore we have a rhombus. A rhombus is any quadrilateral with four equal sides. A square is a special type of rhombus, though in this case it appears to be a non-square type of rhombus, as the angles are not 90 degrees.
-----------
7. A rectangle has 4 angles that are all 90 degrees. Visually the tiny little square angle marker tells the reader we have a 90 degree angle.
-----------
8. We have a parallelogram here because the opposite sides are the same length. In addition, the opposite angles are the same measure. Through using the SSS congruence rule, we can do a bit of work to show that the alternate interior angles are congruent, leading to the opposite sides being parallel. So in short, the given info here is enough to prove we have opposite sides being parallel which is what makes a parallelogram possible.
Order matters in a combination.
True
False
Answer:
False
Step-by-step explanation:
So, in Mathematics we use more precise language: When the order doesn't matter, it is a Combination. When the order does matter it is a Permutation.
Which point below is not on the graph of h(x) ^3√x+64 = ? (65, 5) (-37, 3) (-72, -2) (-64, 0)
Answer:
(-37, 3)
Step-by-step explanation:
asap please x÷7=11÷15help
Answer:
x = 77/15 or 5 2/15
Step-by-step explanation:
x/7 = 11/15
Multiply each side by 7
x/7 *7 = 11/15 *7
x = 77/15
We can leave as an improper fraction or change to a mixed number
15 goes into 77 5 times with 2 left over
5 2/15
━━━━━━━☆☆━━━━━━━
▹ Answer
x = 77/15, 5 2/15, or 5.13
▹ Step-by-Step Explanation
x ÷ 7 = 11 ÷ 15
15x = 77
Divide both sides by 15:
x = 77/15, 5 2/15, or 5.13
Hope this helps!
CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
Plzzz help I’ll give brainlest
Answer:
cos y = r/q
Step-by-step explanation:
If we know sin y = 7/q, then we know that the base is 7 and the hypotenuse is q due to sine = opposite/hypotenuse.
If we know tan y = 7/r, then we know that the base is 7 and the right side is r due to tan = opposite/adjacent.
Cos = adjacent / hypotenuse
So cos y = r/q, because the right side is r and the hypotenuse is q.
Answer:
ignore sorry
Step-by-step explanation:
Which constants could each equation be multiplied by to eliminate the x-variable using addition in this system of equations? 2x+3y=25 -3x+=22 first equation can be multiplied by –3 and the second equation by 2. The first equation can be multiplied by –4 and the second equation by 2. The first equation can be multiplied by 3 and the second equation by 2. The first equation can be multiplied by 4 and the second equation by –3.
Answer:
The first equation can be multiplied by 3 and the second equation by 2.
Step-by-step explanation:
Given
[tex]2x+3y=25[/tex]
[tex]-3x + y=22[/tex]
Required
How to eliminate x
To eliminate x using addition, we have to do the following;
1. Take the coefficient of x in equation 1; Coefficient = 2
2. Take the coefficient of x in equation 2; Coefficient = -3
3. Multiply equation 1 by 3
[tex]3(2x + 3y = 25)[/tex]
[tex]6x +9y = 75[/tex]
4. Multiply equation 2 by 2
[tex]2(-3x + y = 22)[/tex]
[tex]-6x + 2y = 44[/tex]
5. Add both resulting equations
[tex]6x +9y = 75[/tex] + [tex]-6x + 2y = 44[/tex]
[tex]6x - 6x + 9y + 2y = 75 + 44[/tex]
[tex]11y = 75 + 44[/tex]
Notice that x has been eliminated;
The frequency table above is presented as a pie chart
The sectorial angle of score"3" is ....
Answer:
[tex]Angle = 96[/tex]
Step-by-step explanation:
Given
The frequency table
Required:
Determine the sectorial angle of "3"
First we need to determine the total frequency;
[tex]Total = 3 + 4 + 6 +8 + 5 + 4[/tex]
[tex]Total = 30[/tex]
The sectorial angle is calculated as thus;
[tex]Angle = \frac{Frequency}{Total\ Frequency} * 360[/tex]
Where Frequency of "3" = 8
So;
[tex]Angle = \frac{8}{30} * 360[/tex]
[tex]Angle = \frac{8* 360}{30}[/tex]
[tex]Angle = \frac{2880}{30}[/tex]
[tex]Angle = 96[/tex]
Hence; the sectorial angle of "3" is 96
Help pls! Will give brainliest to first person who answers correct
Answer:
a) x greater than or equal to 10
b) x = 9
Step-by-step explanation:
a)
[tex]x + 5 \geqslant 15 \\ x \geqslant 15 - 5 \\ x \geqslant 10[/tex]
b)
[tex]2x < 18 \\ x = \frac{18}{2} \\ x = 9[/tex]
A package of 8-count AA batteries costs $6.32. A package of 20-count AA batteries costs $16.00. Which statement about the unit prices is true?
Answer:
A
Step-by-step explanation:
The first option is correct.
The 8 count pack of AA batteries has a lower unit price of $0.79 per battery.
What is unitary method?The method in which first we find the value of one unit and then the value of the required number of units is known as the Unitary Method.
According to the given question.
Cost of a package with 8 AA batteries = $6.32
⇒ Cost of 1 AA battery of this package = [tex]\frac{6.32}{8}[/tex] = $0.79
And, cost of another package with 20 AA batteries = $16.00
⇒ Cost of 1 AA battery of another package = [tex]\frac{16}{20}[/tex] = $0.8
Hence, the 8 count pack of AA batteries has a lower unit price of $0.79 per battery.
Find out more information about unitary method here:
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PLEASE HELP ASAP
No explanation needed
The Kellen school district gives awards to its schools based on overall student attendance. The data for attendance are shown in the table, where Low represents the fewest days attended and High represents the most days attended for a single student. School Low High Range Mean Median IQR σ High School W 108 180 72 169 150 47.5 29.5 High School X 112 180 68 160 124 49.5 32.4 High School Z 130 180 50 162 151 39.5 27.5 Part A: If the school district wants to award the school that has the most consistent attendance among its students, which high school should it choose and why? Justify your answer mathematically. Part B: If the school district wants to award the school with the highest average attendance, which school should it choose and why? Justify your answer mathematically.
Answer:
(A) It should choose High school Z for the most consistent attendance among its students.
(B) It should choose High school W with the highest average attendance.
Step-by-step explanation:
We are given the data for attendance in the table below, where Low represents the fewest days attended and High represents the most days attended for a single student.
School Hight School W High School X High School Z
Low 108 112 130
High 180 180 180
Range 72 68 50
Mean 169 160 162
Median 150 124 151
IQR 47.5 49.5 39.5
S.D. (σ) 29.5 32.4 27.5
(A) It is stated that the school district wants to award the school that has the most consistent attendance among its students.
Now, to check which high school should it choose; we will look for the standard deviation (σ) of each of the three schools because consistency is measured through standard deviation and the school with the lowest standard deviation means that it has the most consistent attendance among its students.
So, after looking at the standard deviation of all the three schools; the High School Z has the lowest standard deviation of 27.5.
This means that it should choose High school Z.
(B) It is stated that the school district wants to award the school with the highest average attendance.
Now, to check which high school should it choose; we will look for the Mean of each of the three schools because average is measured through mean of the data, and the school with the highest mean means that it has the highest average attendance.
So, after looking at the Mean of all the three schools; the High School W has the highest average of 169.
This means that it should choose High school W with the highest average attendance.
At the same time, Sam and Fred who are 168 miles apart begin moving toward each other. Find the number of hours before they meet if Sam runs 12 mph and Fred runs 9 mph.
Hi I'mjust tryna get points for my sister this is actually the first time i use this app but yea, sorry if you got disappointed.
Ms. Canton went to the store to buy grapes. She bought four bunches of purple grapes. Each bunch had the same amount of grapes (x) She also bought two bunches of green grapes.Each bunch of green grapes had the same amount of grapes in them (y). Write an expression that will show how many bunches of grapes Ms. Canton purchased. *
the solution to (d+4)^2=9 is D=
Answer:
[tex] \boxed{\sf d = -1 \ \ \ or \ \ \ d = -7} [/tex]
Step-by-step explanation:
[tex] \sf Solve \: for \: d \: over \: the \: real \: numbers: \\ \sf \implies {(d + 4)}^{2} = 9 \\ \\ \sf Take \: the \: square \: root \: of \: both \: sides: \\ \sf \implies \sqrt{ {(d + 4)}^{2} } = \sqrt{9} \\ \\ \sf 9 = {3}^{2} : \\ \sf \implies \sqrt{ {(d + 4)}^{2} } = \sqrt{ {(3)}^{2} } \\ \\ \sf \implies d + 4 = \pm 3 \\ \\ \sf \implies d + 4 = 3 \: \: \: \: \: or \: \: \: \: \: d + 4 = - 3 \\ \\ \sf Subtract \: 4 \: from \: both \: sides: \\ \sf \implies d + (4 - 4)= 3 - 4 \: \: \: \: \: or \: \: \: \: \: d + (4 - 4) = - 3 - 4 \\ \\ \sf \implies d = - 1 \: \: \: \: \: or \: \: \: \: \: d = - 7[/tex]