The information given is incomplete :
Answer:
x = 1/2(2083 - 3y)
y = 1/3(2083 - 2x)
Step-by-step explanation:
Let
Laptop cost = x
Earpiece cost = y
Number of laptops= 2
Number of earpiece = 3
2x + 3y = $2083
The cost per laptop :
2x = 2083 - 3y
Divide both sides by 2
x = (2083 - 3y) / 2
x = 1/2(2083 - 3y)
Or
3y = 2083 - 2x
y = (2083 - 2x) / 3
y = 1/3(2083 - 2x)
how do i find perimeter and area of this triangle?
Answer:
u should use a ruler and multiplied
Step-by-step explanation:
I dont know the step by step sorry
In the class interval 5-10, find the
(i) lower limit
(ii) upper limit
(iii) class mark
(iv) class size
Answer:
lower limit = 5
upper limit = 10
class mark = lower limit + upper limit ÷ 2 = 7.5
class size = upper limit - lower limit
= 10-5 = 5
Step-by-step explanation:
I hope this help you have an great day and safe health
The value of w???????
Answer:
Step-by-step explanation:
The angle bisector of a triangle divides the opposite side in 2 segments that are proportional to the other 2 sides of the triangle. Namely:
[tex]\frac{15}{18}=\frac{w}{30}[/tex] and cross multiply.
18w = 450 so
w = 25
If x−2/4=2, then x=10
Answer:
True.
Step-by-step explanation:
[tex]\frac{(10)-2}{4}=2\\\\\frac{8}{4}=2\\\\2=2[/tex]
Allowing 20 % discount on the marked price of an article and levying 15 % VAT. a buyer has to pay Rs 9.200 for the article. Find the marked price of the article.
Answer:
here I'm confused that whether the selling price is Rs.9,200 or Rs.9.200
any ways you can take the help of below procedure
Step-by-step explanation:
here,
let marked price be X
discount(d)=20%
VAT=15%
SP with VAT= 9200
now,
SP without VAT= SP - VAT of SP
= 9200-15/100 ×9200
= 9200- 1380
=Rs. 1380
again,
SP= MP - D of MP
or,7820= x- 20/100 × x
or, 7820× 100 = 100x- 20x
or,782000=80x
or, 782000/80=X
or, X= 9775.
hence MP is Rs 9775
Tính giá trị của I = [tex]\lim_{x \to \infty}[/tex] ([tex]\frac{4^{n} - 5.3^{n} + 1}{2.4^{n} + 2}[/tex])
I assume you're supposed to find the limit as n approaches infinity, not x.
You have
[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5.3^n+1}{2.4^n+2} = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-\left(\dfrac{5.3}{5.3}\right)^n+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}} \\\\ = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-1+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}}[/tex]
For |x| < 1, we have lim |x|ⁿ = 0 as n goes to infinity. Then each exponential term converges to 0, which leaves us with -1/0. This means the limit is negative infinity.
On the other hand, perhaps you meant to write
[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5\times3^n+1}{2\times4^n+2}[/tex]
The same algebraic manipulation gives us
[tex]\displaystyle\lim_{n\to\infty}\frac{\left(\dfrac44\right)^n-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2\left(\dfrac44\right)^n+\dfrac2{4^n}} = \lim_{n\to\infty}\frac{1-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2+\dfrac2{4^n}}[/tex]
Again the exponential terms converge to 0, but this time we're left with the limit 1/2.
A tank is capable of holding 36,18 and 72 litres of milk . Determine which is the greatest vessel which can be uses to fill each one of them on exact number of times
Answer:
Greatest vessel to fill each in exact number of times is 6 litres
Step-by-step explanation:
To solve this, we will find the greatest common factor of 36,18 and 72
Thus;
Their prime factors are;
18: 2, 3
36: 2, 2, 3, 3,
72: 2, 2, 2, 3, 3
The factors common to all of them are 2 & 3.
Thus;
GCF = 2 × 3 = 6
Can somebody help me PLEASE IM BEGGING YOU !!
Answer:
37
Step-by-step explanation:
360 -(110+110+66) = 74
74/2 = 37
Can someone help me ASAP this is almost due
Answer:
5
Step-by-step explanation:
8-1-(18-2)÷8
PEMDAS says parentheses first
8-1-16÷8
Then divide
8-1-2
Then subtract from left to right
7-2
5
If the length of the shorter arc AB is 22cm and C is the center of the circle then the circumference of the circle
is:
Answer:
22= 2(pi)(r)(45/360)
28.01
C=176
Step-by-step explanation:
Evaluate 5⁰-5¹ in positive index form
Step-by-step explanation:
5⁰ - 5¹ = -4¹
(1/3)^‐1 + 2^-1 = 3 + 1/2 = (7/2)¹
Answer: -5
Step-by-step explanation: 5^0 is 0 and 5^1=5
0-5=-5
Find the slope of
(-3,6)(5,-4)
Answer:
Slope: -5/4
Step-by-step explanation:
Slope formula: [tex]\frac{y^2-y^1}{x^2-x^1}[/tex]
Plug in:
[tex]\frac{-4-6}{5-(-3)}[/tex]
Solve:
[tex]\frac{-4-6}{5-(-3)}[/tex]
-4 - 6 = -10
5-(-3) = 8
-10 5
----- = - -----
8 4
The answer is -5/4
Hope this helped.
if a+1/a=3
What is the answer? a⁵+1/a⁵
Answer:
123
Step-by-step explanation:
We can square and cube the equation, then multiply the results together.
(a + [tex]\frac{1}{a}[/tex]) = 3 ← square both sides
a² + 2 + [tex]\frac{1}{a^2}[/tex] = 9 ( subtract 2 from both sides )
a² + [tex]\frac{1}{a^2}[/tex] = 7 → (1)
-----------------------
Now cube both sides
a³ + [tex]\frac{1}{a^3}[/tex] + 3(a + [tex]\frac{1}{a}[/tex]) = 27
a³ + [tex]\frac{1}{a^3}[/tex] + 3(3) = 27
a³ + [tex]\frac{1}{a^3}[/tex] + 9 = 27 ( subtract 9 from both sides )
a³ + [tex]\frac{1}{a^3}[/tex] = 18 → (2)
------------------------------
Multiply (1) and (2)
(a² + [tex]\frac{1}{a^2}[/tex] )(a³ + [tex]\frac{1}{a^3}[/tex] ) = 7(18)
[tex]a^{5}[/tex] + ( [tex]\frac{1}{a}[/tex] + a) + [tex]\frac{1}{a^5}[/tex] = 126
[tex]a^{5}[/tex] + 3 + [tex]\frac{1}{a^5}[/tex] = 126 ( subtract 3 from both sides )
[tex]a^{5}[/tex] + [tex]\frac{1}{a^5}[/tex] = 123
If (x + 1) is a factor of 2x - kx²-8x + 5, find the value of k.
[ Using Factor Theorem ]
Answer:
k = 11
Step-by-step explanation:
What the factor theorem is telling us is that if x + 1 is a factor of 2x - kx²-8x + 5 then when x = - 1 is put into the equation, the result will be 0. That's because x +1 = 0 when x = - 1
f(-1) = 2(-1) - k(-1)^2 - 8(-1) + 5
f(-1) = -2 - k(1) + 8 + 5 = 0
-k*(1) + 11 = 0
-k = -11
k = 11
YujiC this is incorrect
5x and -4x
Paul wants M₁ and M₂ to have a total that is +x, and a product that is -20x². The values of M₁ and M₂ that will do that are ...
5x and -4x
Answer: 5x and -4x
Step-by-step explanation:
= 5x + (-4x)
= 5x -4x
= +x
= 5x × (-4x)
= -20x²
please click thanks and mark brainliest if you like :)
if 1cm on a map represents 37 1/2 km what does a length of 2/5cm on the map represent
Answer:
15
Step-by-step explanation:
[tex]37 \frac{1}{2} \times \frac{2}{5} = \frac{75}{2} \times \frac{2}{5} = 15[/tex]
Find derivative of 3x^2+4 using limits
The derivative of a function f(x) is defined as
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]
For f(x) = 3x ² + 4, we have
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x+h)^2+4) - (3x^2+4)}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x^2+2xh+h^2) - 3x^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{6xh+3h^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}(6x+3h) = \boxed{6x}[/tex]
Find the value of x.
B
10-X
3
D
х
2.
A
С
x = [?]
Answer:
3/(10-x) = 5/(10-x+x)
3/(10-x) = 1/2
6 = 10-x
x = 4
Hope this helps!
can i get some help please
Hi there!
[tex]\large\boxed{102^o}[/tex]
Using the triangle exterior angle theorem, we know that:
∠4 = the other two angles of the triangle combined (both are given)
Thus:
∠4 = 51 + 51 = 102°
Angle 4 is an outside angle.
An outside angle of a triangle is equal to the sum of the two opposite inside angles.
The two opposite inside angles to angle 4 are shown as 51 and 51
Angle 4 = 51 + 51
Angle 4 = 102 degrees.
Help pleaseeeee like ASAP
Answer:
m is slope and y is the intercept
What is the total surface area of a cuboid with length 16cm, width 8cm and height 6cm?
Answer:
Step-by-step explanation:
The dimensions as a pair, appear twice for each combination.
SA = 2* 16 * 8 + 2 * 16 * 6 + 2*8* 6
That's because when you look at the figure, there are 2 places each face is positioned.
SA = 256 + 192 + 96
SA = 544
Please help explanation if possible
Answer: x = 2 and y = -4
x + 2y = -6
x = -6-2y
Putting this in value of x in
6x + 2y = 4
6(-6-2y) + 2y = 4
-36-12y+2y = 4
-10y = 4+36
y = 40/(-10)
y = -4
Now putting this value of y in
x + 2y = -6
x + 2(-4) = -6
x -8 = -6
x = -6+8
x = 2
Therefore x = 2 and y = -4
If we put these values we can check this
x + 2y = -6
2 + 2(-4) = -6
2 -8 = -6
-6 = -6
please click thanks and mark brainliest if you like :)
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER
Answer:
V=l×w×h
so the answer is 66km
11×2×3=66
What is the equation of the line that passes through (-1, 5) and (3, -7)?
Answer:
[tex] 3x + y = 2 [/tex]
Step-by-step explanation:
[tex] y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1) [/tex]
[tex] y - 5 = \dfrac{-7 - 5}{3 - (-1)}(x - (-1)) [/tex]
[tex] y - 5 = \dfrac{-12}{4}(x + 1) [/tex]
[tex] y - 5 = -3(x + 1) [/tex]
[tex] y - 5 = -3x - 3 [/tex]
[tex] 3x + y = 2 [/tex]
Hope made 3 different yo-yo's. She used 1 3/4 meters of string for the first yo-yo, 1 meter of string
Answer:
See explanation
Step-by-step explanation:
Your question is different from the attachment
Statement 1
1 adult + 5 Children
$4 for adult and total of $16 for both adult and children
Let
Cost of children skating = x
The equation is
4 + 5x = 16
Statement 2:
Cost of making a bike bag= $4
Selling price of the bike bag = $5
Profit = $16
Let x = number of bike bag
Profit = selling price - cost price
16 = 5x - 4x
16 = x(5 - 4)
Also written as
(5 - 4)x = 16
Statement 3:
Initial temperature = 16°C
Change in temperature per hour = 4°C
Final temperature = 5°C
Let
x = number of hours it changes
16 - 4x = 5
Hope made 3 different yo-yos. She used 1 3/4 meters of string for the first yo-yo, 1 meter of string for the second yo-yo, and a total of meters of string 4 1/3
length of first yo-yo = 1 3/4
length of second yo-yo = 1
Length of third yo-yo = x
Total = 4 1/3
Total length = length of first yo-yo + length of second yo-yo + length of third yo-yo
4 1/3 = 1 3/4 + 1 + x
4 1/3 = 2 3/4 + x
4 1/3 - 2 3/4 = x
13/3 - 11/4 = x
(52-33) / 12 = x
19/12 = x
x = 1 7/12
Chase took a taxi from his house to the airport. The taxi company charged a pick-up fee of $1.20 plus $4.75 per mile. The total fare was $48.70, not including the tip. Write and solve an equation which can be used to determine x, the number of miles in the taxi ride. write the equation
Determine what type of model best fits the given situation: A retirement account that is expected to
grow by $1,000 per year.
Answer:
Step-by-step explanation:
If the account grows steadily, this is a linear representation, where the constant, steady growth translates to the slope of a line.
A fruit stand has to decide what to charge for their produce. They decide to charge \$5.30$5.30dollar sign, 5, point, 30 for 111 apple and 111 orange. They also plan to charge \$14$14dollar sign, 14 for 222 apples and 222 oranges. We put this information into a system of linear equations. Can we find a unique price for an apple and an orange?
Answer:
a + b = 5.30
a + b = 7
No
Step-by-step explanation:
Expressing the information as system of linear equation :
Let apples = a, oranges = b
If $5.30 is charged for one apple and one orange, then we have ;
a + b = 5.30 - - - (1)
If $14 is charged for 2 apples and 2 oranges, then we have ;
2a + 2b = 14 - - - - (2)
a + b = 7
Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.
From (1)
a = 5.30 - b
Put a = 5.30 - b in (2)
2(5.30 - b) + 2b = 14
10.6 - 2b + 2b = 14
10.6 = 14 - - - - - (variables cancels out).
Answer:No the System has no solution
Step-by-step explanation:
A, B and C, in that order, are three-consecutive whole numbers. Each is greater that 2000. A is a multiple of 4. B is a multiple 5. C is a multiple of 6. What is the smallest possible value of A?
Answer:
[tex]A=2044[/tex]
Step-by-step explanation:
Note that [tex]x\in\mathbb{W}[/tex] denotes that [tex]x[/tex] is a whole number.
By definition, consecutive numbers follow each other when we count up (e.g. 1, 2, 3).
Let's consider our conditions:
A, B, and C are consecutive whole numbers greater than 2,000A is a multiple of 4B is a multiple of 5C is a multiple of 6Since B is a multiple of 5, the ones digit of B must be either 0 or 5. However, notice that the number before it, A, needs to be a multiple of 4. The ones digit of a number preceding a ones digit of 0 is 9. There are no multiples of 4 that have a ones digit of 9 and therefore the ones digit of B must be 5.
Because of this, we've identified that the ones digit of A, B, and C must be 4, 5, and 6 respectively.
We can continue making progress by trying to identify the smallest possible whole number greater than 2,000 with a units digit of 6 that is divisible by 6. Notice that:
[tex]2000=2\mod6[/tex]
Therefore, [tex]2000-2=1998[/tex] must be divisible by 6. To achieve a units digit of 6, we need to add a number with a units digit of 8 to 1,998 (since 8+8 has a units digit of 6).
The smallest multiple of 6 that has a units digit of 8 is 18. Check to see if this works:
[tex]C=1998+18=2016[/tex]
Following the conditions given in the problem, the following must be true:
[tex]A\in \mathbb{W},\\B\in \mathbb{W},\\C\in \mathbb{W},\\A+1=B=C-1,\\A=0\mod 4,\\B=0\mod 5,\\C=0\mod 6,[/tex]
For [tex]C=2016[/tex], we have [tex]B=2015[/tex] and [tex]A=2014[/tex]:
[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2014\neq 0\mod 6, \times\\B=2015=0\mod 5,\checkmark\\C=2016=0\mod 6\checkmark\\[/tex]
Not all conditions are met, hence this does not work. The next multiple of 6 that has a units digit of 8 is 48. Adding 48 to 1,998, we get [tex]C=1998+48=2046[/tex].
For [tex]C=2046[/tex], we have [tex]B=2045[/tex] and [tex]A=2044[/tex]. Checking to see if this works:
[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2044=0\mod 4,\checkmark\\B=2045=0\mod 5,\checkmark\\C=2046=0\mod 6\checkmark[/tex]
All conditions are met and therefore our answer is [tex]\boxed{2,044}[/tex]
3. A straight line passes through two points with
coordinates (6,8) and (0,5).
Work out the equation of the line.
Answer:
Step-by-step explanation:
Find the slope of the line
(x₁ , y₁) = (6 , 8) & (x₂ , y₂) = (0 , 5)
[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{5-8}{0-6}\\\\=\frac{-3}{-6}\\\\=\frac{1}{2}[/tex]
m = 1/2 ;(x₁ , y₁) = (6 , 8)
y - y₁ = m(x - x₁)
[tex]y - 8 = \frac{1}{2}(x - 6)\\\\y - 8 =\frac{1}{2}x -\frac{1}{2}*6\\\\y - 8 =\frac{1}{2}x- 3\\\\y = \frac{1}{2}x - 3 + 8\\\\y = \frac{1}{2}x + 5[/tex]
