My town has two cell phone providers. The provider Don’tTalkMuch charge is $80 per month plus 1 dollar per hour the provider TalkLots charges $20 per month plus 4 dollars per hour how much do you have to use your phone in a month in order for Don’tTalkMuch’s much is a deal to be better for you?

Answer:

[tex]Probability = 0.35[/tex]

Step-by-step explanation:

Given

Probability of success free throw = 90%

Number of throw = 10

Required

Determine the probability of 10 consecutive free throws

Let p represents the given probability

[tex]p = 90\%[/tex]

Convert to decimal

[tex]p = 0.9[/tex]

Let n represents the number of throw

[tex]n = 10[/tex]

Provided that each throw is independent;

The probability of n consecutive free throw is

[tex]p^n[/tex]

Substitute 0.9 for p and 10 for n

[tex]Probability = 0.9^{10}[/tex]

[tex]Probability = 0.3486784401[/tex]

[tex]Probability = 0.35[/tex] (Approximated)

Answer

arrange the element in increasing order

-1.9, -1.3, -0.8, 2.3, 5.8, 7.4, 8.5, 9.9

interquatile = Q3 - Q1

[tex] = \frac{7.4 + 8.5}{2} - \frac{ - 1.3 - 0.8}{2} [/tex]

[tex] = 7.95 + 1.05[/tex]

[tex] = 9[/tex]

Answer:

9.0

Step-by-step explanation:

i took the quiz

Answer:

P(C|Y) = 0.5.

Step-by-step explanation:

We are given the following table below;

               X             Y               Z             Total

A             32           10             28              70

B              6             5              25              36

C             18            15              7                40

Total       56           30            60              146

Now, we have to find the probability of P(C/Y).

As we know that the conditional probability formula of P(A/B) is given by;

                    P(A/B) =  [tex]\frac{P(A \bigcap B)}{P(B)}[/tex]

So, according to our question;

P(C/Y) =  [tex]\frac{P(C \bigcap Y)}{P(Y)}[/tex]

Here, P(Y) = [tex]\frac{30}{146}[/tex] and P(C [tex]\bigcap[/tex] Y) =  [tex]\frac{15}{146}[/tex]  {by seeing third row and second column}

Hence, P(C/Y) =  [tex]\frac{\frac{15}{146} }{\frac{30}{146} }[/tex]

                       =  [tex]\frac{15}{30}[/tex]  = 0.5.

Answer: 0.5

Step-by-step explanation:

edge

Answer:

The null hypothesis is rejected and  research hypotheses is supported

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 30[/tex]

     The standard deviation is [tex]\sigma = 5[/tex]

      The sample size is  n =  1

      The  cutoff Z score for significance is  [tex]Z_{\alpha } = 1.96[/tex]

       The mean score is  [tex]\= x = 45[/tex]

Generally the test hypothesis is mathematically represented as

            [tex]t = \frac{\= x - \mu }{ \frac{ \sigma }{\sqrt{n} } }[/tex]

=>         [tex]t = \frac{45 - 30 }{ \frac{ 5}{\sqrt{1} } }[/tex]

=>         [tex]t = 3[/tex]

From the obtained value  we can see that [tex]t > Z_{\alpha }[/tex]

Hence the null hypothesis is rejected and  research hypotheses is supported

The width of the gym will be W=60 feet for the area of 6,960 square feet.

Area is defines as the space covered by a surface in the two dimensional plane.

It is given that

Area of the gym =6960 square feet

Width of the gym = ?

Length of the gym=116 feet

The width of the gym will be calculated as

[tex]A=\L\times W\\\\\\6960=116\times W\\\\\\w=\dfrac{6960}{116}=60\ \ Feet[/tex]

hence the width of the gym will be W=60 feet for the area of 6,960 square feet.

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Answer:

0.1587

Step-by-step explanation:

Given the following :

Mean (m) of distribution = 64 inches

Standard deviation (sd) of distribution = 2 inches

Probability that a randomly selected woman is taller than 66 inches

For a normal distribution :

Z - score = (x - mean) / standard deviation

Where x = 66

P(X > 66) = P( Z > (66 - 64) / 2)

P(X > 66) = P(Z > (2 /2)

P(X > 66) = P(Z > 1)

P(Z > 1) = 1 - P(Z ≤ 1)

P(Z ≤ 1) = 0.8413 ( from z distribution table)

1 - P(Z ≤ 1) = 1 - 0.8413

= 0.1587

Rewrite f in terms of the unit step function:

[tex]f(t)=\begin{cases}5&\text{for }0\le t<7\\-3&\text{for }t\ge7\end{cases}[/tex]

[tex]\implies f(t)=5(u(t)-u(t-7))-3u(t-7)=5u(t)-8u(t-7)[/tex]

where

[tex]u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t<0\end{cases}[/tex]

Recall the time-shifting property of the Laplace transform:

[tex]L[u(t-c)f(t-c)]=e^{-cs}L[f(t)][/tex]

and the Laplace transform of a constant function,

[tex]L[k]=\dfrac ks[/tex]

So we have

[tex]L[f(t)]=L[5u(t)-8u(t-7)]=5L[1]-8e^{-7s}L[1]=\boxed{\dfrac{5-8e^{-7s}}s}[/tex]

In this exercise you have to find the laplace transform:

[tex]L[f(t)]=\frac{5-8e^{-7s}}{s}[/tex]

Rewrite f in terms of the unit step function:

[tex]f(t)=\left \{ {{5, for 0\leq t\leq 7} \atop {-3, for t\geq 7}} \right. \\f(t)= 5(u(t)-u(t-7)-3u(t-7)=5u(t)-8u(t-7)[/tex]

Where:

[tex]u(t)= \left \{ {{1, t\geq 0} \atop {0, t<0}} \right.[/tex]

Recall the time-shifting property of the Laplace transform:

[tex]L[u(t-c)f(t-c)]= e^{-cs}L[f(t)][/tex]

and the Laplace transform of a constant function,

[tex]L[k]=\frac{k}{s}[/tex]

So we have:

[tex]L[f(t)]= L[5u(t)-8u(t-7)]= 5L[1]-8e^{-7s}L[1]= \frac{5-8e^{-7s}}{s}[/tex]

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Answer:

Step-by-step explanation:

1. The sum of one-third of a number and 27

= [tex]\frac{1}{3}\times x +27\\= 1/3x +27[/tex]

2. The product of a number squared and 4

[tex]Let\:the\:unknown\: number\: be \:x\\\\x^2\times4\\\\= 4x^2[/tex]

3.Write a verbal expression for 5n^3 +9.

The sum of the product and of 5 and a cubed number and 9

Answer:

[tex]\Large \boxed{\sf \bf \ \ 2(x-4)^3(x+2)^2 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

Construct a polynomial function with the following properties...

... fifth degree

It means that the polynomial can be written as below.

[tex]a_5x^5+a_4x^4+a_3x^3+a_2x^2+a_1x+a_0 \ \text{ with }a_5\text{ different from 0}\\\\\text{ or } k(x-x_1)(x-x_2)(x-x_3)(x-x_4)(x-x_5) \\\\ \text{ with k different from 0 and } (x_i)_{1\leqi\leq 5 } \text { are the roots.}[/tex]

... 4 is a zero of multiplicity 3

We can write the polynomial as below.

[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)=k(x-4)^3(x-x_4)(x-x_5)[/tex]

... −2 is the only other zero

Because this is the only other zero, we can deduce that -2 is a zero of multiplicity 2.

[tex]k(x-4)(x-4)(x-4)(x-x_4)(x-x_5)\\\\=k(x-4)^3(x-(-2))(x-(-2))\\\\=k(x-4)^3(x+2)^2[/tex]

... leading coefficient is 2.

Finally, it means that k = 2 and then the polynomial function is:

[tex]\large \boxed{2(x-4)^3(x+2)^2}[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

3/500

Step-by-step explanation:

3/5 x 1%

=> 3/5 x 1/100

=> 3/500

Hope it helps you

Answer:

If x is replaced with -x the graph will stay the same because the absolute value makes 2 values so a negative number and a positive one.

Step-by-step explanation:

Go search it up on desmos.

Answer:

[tex]\huge\boxed{a=9 ; b = -8}[/tex]

Step-by-step explanation:

[tex]f(x) = \frac{ax+b}{x}[/tex]

Putting x = 1

=> [tex]f(1) = \frac{a(1)+b}{1}[/tex]

Given that f(1) = 1

=> [tex]1 = a + b[/tex]

=> [tex]a+b = 1[/tex]  -------------------(1)

Now,

Putting x = 2

=> [tex]f(2) = \frac{a(2)+b}{2}[/tex]

Given that f(2) = 5

=> [tex]5 = \frac{2a+b}{2}[/tex]

=> [tex]2a+b = 5*2[/tex]

=> [tex]2a+b = 10[/tex]  ----------------(2)

Subtracting (2) from (1)

[tex]a+b-(2a+b) = 1-10\\a+b-2a-b = -9\\a-2a = -9\\-a = -9\\a = 9[/tex]

For b , Put a = 9 in equation (1)

[tex]9+b = 1\\Subtracting \ both \ sides \ by \ 9\\b = 1-9\\b = -8[/tex]

Answer:

so first convert to fraction so

9 3/4 = 39/4

so it was spread among 3

so this is division so you do 39/4 divided by 3

so you keep switch flip

which is  39/4 *1/3

answer is 13/4

Answer:

Step-by-step explanation:

[tex]9\frac{3}{4}= \frac{(4 \times 9)+3}{4}= \frac{39}{4} \\\\\frac{39}{4} = 3 \:vegetable \: beds\\x \:\:\:= 1 \: vegetable \:bed\\\\3x = \frac{39}{4} \\\\\frac{3x}{3} = \frac{\frac{39}{4} }{3} \\\\x = \frac{13}{4} \\\\x = 3\frac{1}{4}[/tex]

Step-by-step explanation:

a2=a1+1/2=-1

a3=a2+1/2=-1/2, then we have common difference 0.5

a9=a1+(n-1)d

a9=-3/2+(8)0.5=5/2

Answer:

[tex]\huge\boxed{f^{-1}(x) = (x-3)^2+2}[/tex]

Step-by-step explanation:

[tex]f(x) = \sqrt{x-2} + 3[/tex]

Replace y = f(x)

[tex]y = \sqrt{x-2} + 3[/tex]

Exchange x and y

[tex]x = \sqrt{y-2}+3[/tex]

Solve for y

[tex]x = \sqrt{y-2}+3[/tex]

Subtracting both sides by 3

[tex]x - 3 = \sqrt{y-2}[/tex]

Taking square on both sides

[tex](x-3)^2 = y -2[/tex]

Adding 2 to both sides

[tex]y = (x-3)^2+2[/tex]

Substitute y = [tex]f^{-1}(x)[/tex]

[tex]f^{-1}(x) = (x-3)^2+2[/tex]

Answer:

Option D is the correct option

Step-by-step explanation:

[tex] \mathsf{f(x) = \sqrt{x - 2} + 3}[/tex]

Replace f(x) with y

[tex] \mathsf{y = \sqrt{x - 2} + 3}[/tex]

Interchange variables

[tex] \mathsf{x = \sqrt{y - 2} + 3}[/tex]

[tex] \mathsf{{(x - 3)}^{2} = {( \sqrt{y - 2)} }^{2} }[/tex]

[tex] \mathsf{ {(x - 3)}^{2} = y - 2}[/tex]

[tex] \mathsf{ y = {(x - 3)}^{2} + 2}[/tex]

Replace y with f ⁻¹( x )

[tex] \mathsf{ {f}^{ - 1} (x) = {(x - 3)}^{2} + 2}[/tex]

Hope I helped!

Best regards!

Answer:

Attachment 1 : Option C

Attachment 2 : Option A

Step-by-step explanation:

( 1 ) Expressing the product of z1 and z2 would be as follows,

[tex]14\left[\cos \left(\frac{\pi \:}{5}\right)+i\sin \left(\frac{\pi \:\:}{5}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{3\pi \:}{2}\right)+i\sin \left(\frac{3\pi \:\:}{2}\right)\right][/tex]

Now to solve such problems, you will need to know what cos(π / 5) is, sin(π / 5) etc. If you don't know their exact value, I would recommend you use a calculator,

cos(π / 5) = [tex]\frac{\sqrt{5}+1}{4}[/tex],

sin(π / 5) = [tex]\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}[/tex]

cos(3π / 2) = 0,

sin(3π / 2) = - 1

Let's substitute those values in our expression,

[tex]14\left[\frac{\sqrt{5}+1}{4}+i\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}\right]\cdot \:2\sqrt{2}\left[0-i\right][/tex]

And now simplify the expression,

[tex]14\sqrt{5-\sqrt{5}}+i\left(-7\sqrt{10}-7\sqrt{2}\right)[/tex]

The exact value of [tex]14\sqrt{5-\sqrt{5}}[/tex] = [tex]23.27510\dots[/tex] and [tex](-7\sqrt{10}-7\sqrt{2}\right))[/tex] = [tex]-32.03543\dots[/tex] Therefore we have the expression [tex]23.27510 - 32.03543i[/tex], which is close to option c. As you can see they approximated the solution.

( 2 ) Here we will apply the following trivial identities,

cos(π / 3) = [tex]\frac{1}{2}[/tex],

sin(π / 3) = [tex]\frac{\sqrt{3}}{2}[/tex],

cos(- π / 6) = [tex]\frac{\sqrt{3}}{2}[/tex],

sin(- π / 6) = [tex]-\frac{1}{2}[/tex]

Substitute into the following expression, representing the quotient of the given values of z1 and z2,

[tex]15\left[cos\left(\frac{\pi \:}{3}\right)+isin\left(\frac{\pi \:\:}{3}\right)\right] \div \:3\sqrt{2}\left[cos\left(\frac{-\pi \:}{6}\right)+isin\left(\frac{-\pi \:\:}{6}\right)\right][/tex] ⇒

[tex]15\left[\frac{1}{2}+\frac{\sqrt{3}}{2}\right]\div \:3\sqrt{2}\left[\frac{\sqrt{3}}{2}+-\frac{1}{2}\right][/tex]

The simplified expression will be the following,

[tex]i\frac{5\sqrt{2}}{2}[/tex] or in other words [tex]\frac{5\sqrt{2}}{2}i[/tex] or [tex]\frac{5i\sqrt{2}}{2}[/tex]

The solution will be option a, as you can see.

Answer:

y = 8x + 70

Step-by-step explanation:

Start with the third line.

x = 3, y = 94

Subtract 1 from x and 8 from y:

x = 2, y = 86; this is the second line

Subtract 1 from x and 8 from y:

x = 1, y = 78; this is the first line

Subtract 1 from x and 8 from y:

x = 0; y = 70

For selling 0 games, she earns $70.

y = mx + b

y = mx + 70

For each game she sells, her commission is $8.

y = 8x + 70

Answer:

The mean age is 48

The standard deviation is 4

Step-by-step explanation:

The answer is, (a) mean age is 48.

                          (b)  standard deviation is 4.

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Answer:

The  95% confidence interval is  [tex]295.9 < \mu< 324.1[/tex]

A   95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

Step-by-step explanation:

From the question we are told that

    The sample size is  [tex]n = 25[/tex]

    The mean is  [tex]\= x = 310 \ mg[/tex]

     The standard deviation is  [tex]\sigma = 36 \ mg[/tex]

Given that the confidence level is  95% then the level of significance is mathematically represented as

           [tex]\alpha = 100 - 95[/tex]

=>        [tex]\alpha = 5\%[/tex]

=>        [tex]\alpha = 0.05[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table , the value is  

           [tex]Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} } = 1.96[/tex]

Generally the margin of error is mathematically represented as

        [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

        [tex]E = 1.96 * \frac{36 }{\sqrt{25} }[/tex]

        [tex]E = 14.1[/tex]

The 95% level of confidence interval  is mathematically represented as

      [tex]\= x - E < \mu<\ \= x - E[/tex]

substituting values

     [tex]310- 14.1 < \mu< 310+ 14.1[/tex]

     [tex]295.9 < \mu< 324.1[/tex]

The  95% level of confidence mean that there is 95%  chance  that the true population mean will be in this interval

You would type in

32^(6/5)

Or you could type in

32^(1.2)

since 6/5 = 1.2

Either way, the final result is 64

Answer:

-16

Step-by-step explanation:

8q

Let q = -2

8*-2

-16

Answer:

14 + 25l + 6l^2

Step-by-step explanation:

(7 + 2i) (2 + 3i)

=> 14 + 4l + 21l + 6l^2

=> 14 + 25l + 6l^2

This is the correct answer

Answer:

Decision Rule:  To reject the null hypothesis if t > 1.328

t = 3.913

Step-by-step explanation:

The summary of the given statistics include:

sample size n = 21

the correlation between the number of passengers and total fuel cost r = 0.668

(1) We are tasked to state the decision rule for 0.10 significance level

The degree of freedom df = n - 1

degree of freedom df = 21 - 1

degree of freedom df = 19

The  null and the alternative hypothesis can be computed as:

[tex]H_o : \rho < 0\\ \\ Ha : \rho > 0[/tex]

The critical value for [tex]t_{\alpha, df}[/tex]  is  [tex]t_{010, 19}[/tex] = 1.328

Decision Rule:  To reject the null hypothesis if t > 1.328

The test statistics can be computed as follows by using the formula for t-test for Pearson Correlation:

[tex]t = r*\sqrt{ \dfrac{(n-2)}{(1-r^2)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(21-2)}{(1-0.668^2)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(19)}{(1-0.446224)}[/tex]

[tex]t = 0.668*\sqrt{ \dfrac{(19)}{(0.553776)}[/tex]

[tex]t = 0.668*5.858[/tex]

t = 3.913144

t = 3.913    to 3 decimal places

Answer:

It's 8.3

Step-by-step explanation:

Answer:

8.3

Step-by-step explanation:

Answer:

Final population after 10 years

= 288911718

Step-by-step explanation:

Present population p = 258,316,051

Rate of growth R%= 1.12%

Number of years t= 10 years

Number of times calculated n = 10

Final population A

= P(1+r/n)^(nt)

A= 258,316,051(1+0.0112/10)^(10*10)

A= 258,316,051(1+0.00112)^(100)

A= 258,316,051(1.00112)^100

A= 258,316,051(1.118442762)

A= 288911717.6

Approximately A= 288911718

Final population after 10 years

= 288911718

Hi there! :)

Answer:

x = 1/2 or -7.

Step-by-step explanation:

(I'm assuming the expression is 2x² + 13x - 7 = 0)

Factor the equation to solve for the possible values of "x":

2x² + 13x - 7 = 0

When factored, we get:

(2x - 1) ( x + 7) = 0

Use the Zero-Product property to solve for the roots:

2x - 1 = 0

2x = 1

x = 1/2.

-----------

x + 7 = 0

x = -7.

Therefore, possible values of x are x = -1/2, 7.

Answer:

x = 1/2     x=-7

Step-by-step explanation:

2 x^2  + 13 x − 7 = 0

Factor

(2x-1)(x+7)=0

Using the zero product property

2x-1 =0   x+7=0

2x=1       x =-7

x = 1/2     x=-7

Answer:

Tran family's sprinkler was used for 20 hours

Green's  family's sprinkler was used for 30 hours

Step-by-step explanation:

Let the hours for which Tran family's sprinkler used is x hours

water output rate for the Tran family's sprinkler = 35L per hour

water output from  Tran family's sprinkler in x hours = 35*x L = 35x

Let the hours for which Green family's sprinkler used is y hours

water output rate for the Green family's sprinkler = 40L per hour

water output from  Green family's sprinkler in x hours = 40*y L = 40y

Given

The families used their sprinklers for a combined total of 50 hours

thus

x + y = 50 -------------------equation 1

y = 50-x

total water output of 1900L

35x+40y = 1900  -------------------equation 1

using  y = 50-x in equation 2, we have

35x + 40(50-x) = 1900

35x + 2000 - 40x = 1900

=> -5x = 1900 - 2000 = -100

=> x = -100/-5 = 20

y = 50-20 = 30

Thus,

Tran family's sprinkler was used for 20 hours

Green's  family's sprinkler was used for 30 hours

Answer:

Step-by-step explanation:

Adjacent angles are supplementary, so ...

  (y +x) +(y -x) = 180

  2y = 180 . . . . . . . . . simplify

  y = 90 . . . . . . . . . . . divide by 2

__

  2x +(y +x) = 180

  3x +90 = 180 . . . . substitute for y

  x + 30 = 60 . . . . . . divide by 3

  x = 30 . . . . . . . . . . subtract 30

__

With these values of x and y, the angle measures are ...

  2x° = 2(30)° = 60°

  (y+x)° = (90+30)° = 120°

  (y-x)° = (90-30)° = 60°

Answer:

Step-by-step explanation:

G = { 3 , 7 , 8 , 9 }

H = { 2 , 5 , 7 , 8 }

The intersection of any two or more sets are the members that occur in both sets.

To find the intersection of G and H look for the members that occur in both sets

From the question , the members that occur in both G and H are 7 and 8

So the intersection of the sets is

Hope this helps you

=================================================

Explanation:

The piecewise function shows that we have two cases. Either x = 1 or [tex]x \ne 1[/tex].

If x = 1, then g(x) = 3 as shown in the bottom row. This is why g(1) = 3.

If [tex]x \ne 1[/tex], then g(x) = (1/4)x^2-4

Plug x = -5 into this second definition

g(x) = (1/4)x^2-4

g(-5) = (1/4)(-5)^2-4

g(-5) = (1/4)(25)-4

g(-5) = 25/4 - 4

g(-5) = 25/4 - 16/4

g(-5) = 9/4

Repeat for x = 4

g(x) = (1/4)x^2-4

g(4) = (1/4)(4)^2-4

g(4) = (1/4)(16)-4

g(4) = 4-4

g(4) = 0

The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

The functions are given below.

g(x) = (1/4)x² - 4, x ≠ 1

g(x) = 3, x = 1

The value of the function at x = -5 will be given as,

g(-5) = (1/4)(-5)² - 4

g(-5) = 25 / 4 - 4

g(-5) = 6.25 - 4

g(-5) = 2.25

The value of the function at x = 4 will be given as,

g(4) = (1/4)(4)² - 4

g(4) = 16 / 4 - 4

g(4) = 4 - 4

g(4) = 0

The value of the function at x = 1 will be given as,

g(1) = 3

The value of the function at x = -5, x = 1, and x = 4 will be 2.25, 3, and 0, respectively.

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