N
Using the graph below, how many adults do NOT carpool to work?
Transportation to Work
Account
80
ashboard
70
60
50
Dunes
Number of Adults
40
30
Hondar
20
10
DOK
0
Bus
Walk
Car
Carpool
Method of Transportation
cory
2
160
O 15
50
130

[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

Answer:

fluorine is the right answer of this question

Answer: It states that for every action, there is an equal and opposite reaction.

I hope this helps, and Happy Holidays! :)

Answer: so it can reach the frame

Explanation:

Answer:

To increase force on the door

Answer:

C. 2042

Explanation:

trust me I know the answer

In 2042 the Social Security fund will dry up at its current level. The correct option is C.

The answer is not entirely clear, as projections can vary depending on various economic and demographic factors. However, based on the 2021 Social Security Trustees Report, the projected depletion date for the Social Security Trust Fund is 2034. This means that at the current rate of payouts and contributions, the Trust Fund will only be able to pay out about 78% of scheduled benefits after 2034.

Therefore, the closest option to the projected depletion date of the Social Security Trust Fund is C. 2042. However, it is important to note that this projection may change as economic and demographic factors change over time.

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Answer:

The value is  [tex]N = 2.69 *10^{26} \ photons[/tex]

Explanation:

From the question we are told that

    The power is  [tex]P = 510 \ W[/tex]  

    The wavelength is  [tex]\lambda = 10.5 \ cm = 0.105 \ m[/tex]

Gnerally the number of photon produced is mathematically represented as

             [tex]N = \frac{P * \lambda }{ h * c }[/tex]

Here  [tex]h[/tex] is the Planck's constant with a value   [tex]h = 6.62607015 * 10^{-34} J \cdot s[/tex]

          c is the speed of light with value  [tex]c = 3.0*10^{8 } \ m/s[/tex]

So  

             [tex]N = \frac{ 510 * 0.105 }{ 6.62607015 * 10^{-34} * 3.0 *10^{8} }[/tex]

=>          [tex]N = 2.69 *10^{26} \ photons[/tex]

Answer:

answer is a very large amount of energy is produced from a very small mass

Explanation:

nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)

Answer:

The value is  [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]

Explanation:

From the question we are told that  

    The maximized electric field strength is  [tex]E = 3.0 \ MV/m = 3.0 *10^{6} \ V/m[/tex]

     The diameter is  [tex]d = 1.5\ cm = 0.015 \ m[/tex]

Generally the cross -sectional area is mathematically represented as

 =>      [tex]A = \frac{\pi * d^2 }{4}[/tex]

 =>      [tex]A = \frac{3.142 * 0.015^2 }{4}[/tex]

 =>      [tex]A = 0.0001767 \ m^2[/tex]

Generally the maximum power is mathematically represented as

       [tex]P_{max} = \frac{E_{max}^2}{ 2 * \mu_o * c } * A[/tex]

Here c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

        [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4 \pi *10^{-7} \ H/m[/tex]

      [tex]P_{max} = \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} } * 0.0001767[/tex]

=>   [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]

The maximum power that can be delivered by a laser beam propagating through air is equal to [tex]2.11 \times 10^6\;Watts[/tex]

Given the following data:

Radius = [tex]\frac{Diameter}{2} = \frac{0.015}{2} = 0.0075\;meter[/tex]

Scientific data:

To determine the maximum power that can be delivered by a laser beam propagating through air:

First of all, we would solve for the area of the laser beam as follows:

[tex]Area = \pi r^2\\\\Area = 3.142 \times 0.0075^2\\\\Area = 3.142 \times 0.00005625\\\\Area = 1.77 \times 10^{-4}\;m^2[/tex]

Now, we can determine the maximum power that can be delivered by a laser beam:

Mathematically, maximum power is given by the formula:

[tex]P_{max} = \frac{AE_{max}^2}{2 \mu_o c}[/tex]

Substituting the given parameters into the formula, we have;

[tex]P_{max} = \frac{1.77 \times 10^{-4} \;\times \;(3 \times 10^6)^2}{2 \;\times \;1.25663706 \times 10^{-6} \; \times \;3 \times 10^8}\\\\P_{max} = \frac{1.77 \times 10^{-4} \;\times \;9 \times 10^{12}}{753.982236}\\\\P_{max} = \frac{1593000000}{753.982236}\\\\P_{max} = 2.11 \times 10^6\;Watts[/tex]

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Answer:

Explanation:

Potential energy of vessel with liquid upto height .954 m

= mgh where m is mass , h is height of CG of the liquid and g is acceleration due to gravity

mass = volume x density

= cross sectional area x height x density

potential energy = cross sectional area x height x density x g x height / 2

because CG lies at depth of half  the height .

= 4.85 x 10⁻⁴ x .954 x 980 x .954/2 x 9.8

= 2.12  J .

Potential energy of vessel with liquid upto height 1.58 m

= 4.85 x 10⁻⁴ x 1.58 x 980 x 1.58/2 x 9.8

= 5.8 J  

Total energy = 2.12 + 5.8 = 7.92 J

when the level becomes equal , common height becomes

(1.58 + .954 )/ 2 = 1.267 m

potential energy of liquid in two cylinders = 2 x 4.85 x 10⁻⁴ x 1.267 x 980 x 1.267/2 x 9.8

= 7.477 J

Work done by gravitational force

= 7.92 - 7.477 = .443 J  

Answer:

A. 19.8 cm.

Explanation:

The apparent depth of the combination is

As it mentioned that the two clear but non-mixing liquid having depth of 15 cm that placed in a glass container together

Also the refractive indices would be 1.75 and 1.33

Based on the above information

As we know that

Refractive indices = real depth ÷ apparent depth

1.33 ÷ 1.75 = 15  ÷ apparent depth

So, it would be 19.736842 cm

Now the combination of apparent depth would be

= ( 19.736842 + 15) ÷ (1.75)

= 19.8 cm

hence, the correct option is A.

Answer: 54.88 meters/s

Explanation:

The final velocity will be calculated by using the formula:

v = u + at

where,

v = final velocity

u = initial velocity = 0

a = 9.8

t = 5.6

Therefore, we slot the value back into the formula. This will be:

v = u + at

v = 0 + (9.8 × 5.6)

v = 0 + 54.88

v = 54.88 meters per second

Therefore, the final velocity is 54.88m/s

Given :

Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal.

To Find :

How long is it in the air.

Solution :

We know, the formula of time of flight is :

[tex]T = \dfrac{2usin\ \theta}{g}\\\\T = \dfrac{2\times 30\times sin\ 30^o}{9.8}\\\\T = 3.06\ seconds[/tex]

Therefore, the ball is in air for 3.06 seconds.

Answer:

repel

Explanation:

Answer:

1.) 7.3 m/s 2.) 6.1 m/s

Explanation:

To calculate the initial horizontal velocity with just degrees and velocity alone is pretty simple. The formula is     Velocity*cos(degrees)

eg 9.5*cos(40)

2.  To calculate the initial vertical velocity with just degrees and velocity alone is pretty simple. The formula Velocity*sin(degrees)

eg 9.5*sin(40)

Answer:

Explanation:

This is a common question on Khan Academy's "Calculating change in kinetic energy from a force" practice exercises. (AP Physics 1)

Here's the real question without all the formatting:

A truck pushes a pile of dirt in the horizontal direction with a force of 20 N to a distance of 15 m then the kinetic energy of the dirt is 300 J.

In physics, the term "work" refers to the measurement of energy transfer that takes place when an item is moved over a distance by an externally applied, at least a portion of which is applied inside the direction of the displacement.

The duration of the path is multiplied by the component of a force acting along the path to calculate work if the forces are constant. The work W is theoretically equivalent to the pressure f times the range d, or W = fd, to represent this idea. Work is done when a force is applied at an angle of to a displacement, or W = fd cos.

The work done, [tex]W = Force * Displacement[/tex]

W = 15× 20

W = 300 J

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Answer:

B, electrons.

Explanation:

An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.

Answer:

40N in either direction is the answer

Answer:

  B)  100 J

Explanation:

Assuming the distance given is measured along the incline, the vertical change in height is (5 m)(sin 30°) = 2.5 m. Then the change in potential energy is ...

  ∆PE = mg(∆h) = (4 kg)(10 m/s^2)(2.5 m) = 100 J

The force is defined as the product of the mass and the acceleration. The energy stored in an object which is converted into kinetic energy is called potential energy.

The formula for the potential energy is mgh.

The correct answer is B that is 100J.

As the surface is inclined the vertical change in height is[tex](5 m)(sin 30^o) = 2.5[/tex]m.

Therefore the potential energy after solving it is as follows:-

[tex]PE = mg(h) \\= (4 kg)(10 m/s^2)(2.5 m)\\\\= 100 J[/tex]

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Answer:

Explanation:

I'm going to assume that all the givens are in m/s. If I am correct, The orange line is speeding up. It is going from 4 m/s to 7 m/s. Its slant is from lower left to upper right. It is increasing in speed.

The green line is slowing down. It is going from 4 to 0 m/s. It's slant is from upper left to lower right.

The blue line is horizontal. It is neither slowing down or speeding up.

Answer:

sorry for being very very very late, but here is your answer)

car speed A

car slow down C

car constant speed B

hope this helped!!!!

Answer:

The value is [tex]T_2 =416.9 \ K[/tex]

Explanation:

From the question we are told that

     The mass of the aluminum baking sheet is  [tex]m = 225 \ g = 0.225 \ kg[/tex]

      The energy absorbed is [tex]E = 2.4 *10^{4} \ J[/tex]

       The initial  temperature is  [tex]T_1 = 25 ^oC = 25 + 273 = 298 \ K[/tex]

Generally the heat absorbed is mathematically represented as

         [tex]Q = m * c_a * [T_2 - T_1][/tex]

Here  [tex]c_a[/tex] is the specific heat capacity of  aluminum with value  [tex]c_a = 897 \ J / kg \cdot K[/tex]

So

           [tex]2.4 *10^{4 } =0.225 * 897 * [ T_ 2- 298][/tex]

=>         [tex]T_2 - 298 = 118.915[/tex]

=>          [tex]T_2 =416.9 \ K[/tex]

Answer:

A, 13 electrons.

Explanation:

The number of protons is equal to the number of electrons.

Answer:

a = 0.1 m/s²

Explanation:

       [tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]

       [tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]

        [tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]

Answer:

110.25 watt/s

Explanation:

The rate of heat transfer is given by the formula

R = k*A(T1 - T2) / d, where

k = thermal conductivity, 0.105 (W/(m*K)

d = thickness, 4 mm = 0.004 m

T1 = inside temperature, 25° C

T2 = outside temperatures, -10° C

A = area 0.3 * 0.4 = 0.12 m²

Now, applying the given data to the formula, we have

Rate = 0.105 * 0.12 (25 - -10) / 0.004

Rate = 0.105 * 0.12(35) / 0.004

Rate = 0.105 * 4.2 / 0.004

Rate = 0.441 / 0.004

Rate = 110.25 Watt/s

Therefore, the steady state rate of heat flow is 110.25 watt/s

In an open circuit like the picture the light bulb will be off. So, option (C) is correct.

Electric circuit is a way for current to flow through electricity. An electric circuit consists of a source of energy for the charged particles that make up the current, like a battery or generator; sources of current-using equipment, like lamps, electric motors, or computers; and the connecting wires or transmission lines.

Ohm's law and Kirchhoff's rules are two of the fundamental mathematical laws that define how electric circuits function.

In the given diagram, the circuit is open. So, no current passes through it and the light bulb will be off. Hence, option (C) is correct.

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Answer:

2.94 m/s²

3.43 N

Explanation:

To start with, the combination of rotational and translational kinetic energy can be converted to gravity potential energy. So, we will apply this in solving our question.

PE = KE

mgh = ½mv² + ½Iω²

Moment of inertia of a hollow sphere

I = ⅔mr²

We also know that,

ω = v/r, so if we substitute for ω and I, we have

mgh = ½mv² + ½(⅔mr²)(v/r)², simplifying

gh = ½v² + ½(⅔r²)(v/r)², simplifying further

gh = ½v² + ⅓v², adding up

gh = (5/6)v², making h subject of formula

h = 5v²/6g

Now, we substitute for v and g to have

h = 5(2.63)² / 6(9.81)

h = 34.585 / 58.86

h = 0.588 m

To get the distance that the ball rolls on the ramp before stopping, we say

d = 0.588 / sin30.0

d = 0.588 / 0.5

d = 1.176 m

so acceleration is

a = (2.63² - 0²) / 2(1.176)

a = 6.917 - 0 / 2.352

a = 2.94 m/s

B

Neglecting friction, the sphere acts like a point mass and tends to rise.

mgh = ½mv², simplifying

h = v²/2g

h = 2.63² / 2(9.81)

h = 6.917 / 19.62

h = 0.353 m

The work done by the friction force is the same as the rotational kinetic energy of the sphere, so we say

U = KEr

Fd = ½Iω²

Fd = ½(⅔mr²)(v/r)²

Fd = ⅓mv²

F = mv²/3d

where d is the actual distance up the slope the sphere did roll.

The average friction force is thus

F = 1.75(2.63)² / 3(1.176)

F = 1.75 * 6.917 / 3.528

F = 12.1 / 3.528

F = 3.43 N

Answer:

18.392 N

Explanation:

Given that,

Smaller force acting on the car, F₁ = 3.8 N

Radius of smaller radius, r₁ = 10 cm = 0.1 m

The radius of the larger piston, r₂ = 0.22 m

We need to find the force exerted on the larger piston. Let it is F₂.

Using the relation,

[tex]\dfrac{F_1}{F_2}=\dfrac{A_1}{A_2}\\\\\dfrac{F_1}{F_2}=\dfrac{\pi r_1^2}{\pi r_2^2}\\\\\dfrac{F_1}{F_2}=\dfrac{r_1^2}{r_2^2}\\\\F_2=\dfrac{F_1r_2^2}{r_1^2}\\\\F_2=\dfrac{3.8\times (0.22)^2}{(0.1)^2}\\\\F_2=18.392\ N[/tex]

Hence, the force exerted on the larger piston is 18.392 N.