Answer:
380
Step-by-step explanation:
This is a bit nasty. It depends on how you read the 20 miles more and what you do with it. The best and most careful way to do it is do it a long way setting up the two equations carefully.
Second day
Let the time travelled = t
Let the speed travelled = 60 mph
d2 = 60*t
First Day
40*(t + 2) = d1
but d1 = d2 + 20 because he travelled 20 miles further on d1
40 * (t + 2) = d2 + 20
d2 however = 60*t
40*(t+2 ) = 60*t + 20 Remove the brackets
40t + 80 = 60t + 20 Subtract 20 from both sides
40t + 60 = 60t Subtract 40t from both sides
60 = 20*t Divide by 20
t = 60/20
t = 3 hours.
Day 2 = 60 + t = 180
Day 1 = 40*5 = 200
Total distance = 380
Where did that 20 miles go? It was just an observation about the difference in distance travelled between the 2 days.
The total distance the driver traveled in the two days is 260 miles
From the question, on the first day, the driver was going as a speed of 40 mph.
Let s be speed
∴ [tex]s_{1}= 40mph[/tex]
On the second day, he increased the speed to 60 mph
∴ [tex]s_{2}= 60mph[/tex]
From the statement- If he drove 2 more hours on the first day
Let time be t
Then
[tex]t_{1}= t_{2} + 2[/tex] hrs
and traveled 20 more miles
Let d be distance
Then,
[tex]d_{1}= d_{2} + 20[/tex] miles
From the formula
Distance = Speed × Time
Then,
[tex]d = s \times t[/tex]
∴ [tex]d_{1} = s_{1} \times t_{1}[/tex]
From above,
[tex]d_{1}= d_{2}+20[/tex] miles
[tex]s_{1}= 40mph[/tex]
[tex]t_{1}= t_{2} + 2[/tex] hrs
Putting these into
[tex]d_{1} = s_{1} \times t_{1}[/tex]
[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex] ...... (1)
But,
[tex]Time = \frac{Distance}{Speed}[/tex]
∴ [tex]t_{2}= \frac{d_{2} }{s_{2} }[/tex]
From above, [tex]s_{2}= 60mph[/tex]
∴ [tex]t_{2}= \frac{d_{2} }{60}[/tex]
Put this into equation (1)
[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex]
[tex]d_{2} + 20 = 40\times (\frac{d_{2}}{60} +2)[/tex]
[tex]d_{2} + 20 = \frac{2}{3}d_{2} +80\\d_{2} = \frac{2}{3}d_{2} +80-20\\d_{2} = \frac{2}{3}d_{2} +60[/tex]
Multiply through by 3
[tex]3\times d_{2} = 3\times \frac{2}{3}d_{2} +3 \times 60\\3d_{2} = 2d_{2} + 120\\3d_{2} -2d_{2} = 120[/tex]
∴ [tex]d_{2} = 120[/tex] miles
∴The distance traveled on the second day is 120 miles
For the distance traveled on the first day,
Substitute [tex]d_{2}[/tex] into the equation
[tex]d_{1}= d_{2}+20[/tex] miles
∴ [tex]d_{1}= 120+20[/tex]
[tex]d_{1}= 140[/tex] miles
∴ The distance traveled on the first day is 140 miles
The total distance traveled in the two days = [tex]d_{1} + d_{2}[/tex]
The total distance traveled in the two days = 120 miles + 140 miles
The total distance traveled in the two days = 260 miles
Hence, the total distance the driver traveled in the two days is 260 miles
Learn more here: https://brainly.com/question/23531710
-2z² + 4z + 2z² = ?
Anyone know this?
Answer:
4
Step-by-step explanation:
Let's simplify step-by-step.
−2z2+4z+2z2
Combine Like Terms:
=−2z2+4z+2z2
=(−2z2+2z2)+(4z)
=4z
Answer:
4z
Hope this helps <3 Need thanks?
Comment /hearthelp
[tex]\\ \sf\longmapsto -2z^2+4z+2z^2[/tex]
Combine like. variables[tex]\\ \sf\longmapsto -2z^2+2z^2+4z[/tex]
[tex]\\ \sf\longmapsto (-2+2)z^2+4z[/tex]
[tex]\\ \sf\longmapsto 0z^2+4z[/tex]
[tex]\\ \sf\longmapsto 4z[/tex]
You and six friends play on a basketball team. A sponsor paid $100 for the league fee, x dollars for each player’s T-shirt, and $68.25 for trophies. Write an expression for the total amount paid by the sponsor
Answer:
Total amount paid by the sponsor = 175 + 6d
Step-by-step explanation:
You and 5 friends = 6 people
Cost of renting a bus = $75
Team entry fee = $100
Cost of each student t shirts = $d
Cost of 6 student t shirts = $d × 6= $6d
Write an expression for the total amount the sponsor paid.
Total amount paid by the sponsor = Cost of renting a bus + Team entry fee + Cost of 6 student t shirts
= $75 + $100 + $6d
= $175 + $6d
Total amount paid by the sponsor = 175 + 6d
Where,
d = cost of each student t shirts
Debt is a result of spending more than you make.
True
False
Write equations for the vertical and horizontal lines passing through the point (5,-9).
Answer:
the vertical line is:
x = 5
The horizontal line is:
y = -9
Step-by-step explanation:
A vertical line has a fixed x-value, while a horizontal line has a fixed y-value.
Then we can write a vertical line as:
x = a
and a horizontal line as
y = b
Then, if we want a vertical line that passes through the point (5, -9), remember that the x-vale will be fixed, then we fix the x-value at the same x-value of the point, which we know that is 5, then the vertical line that passes through the point (5, -9) is:
x = 5
While the horizontal line that passes through the point (5, -9) will be a line with the y-value fixed at the y-value of the point, which we know is -9
Then the horizontal line is:
y = -9
8 ÷ -2 · 42 + 9 i need help please
Rewrite using exponents
AxAxAxAxAxAxA
need answer quick!!! please
Answer:
A^7
Step-by-step explanation:
Best answer gets brainliest and 5 stars
Answer:
A
Step-by-step explanation:
pgt states if the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle.
Answer:
Does the answer help you?
30 Points cuz I need help ASAP
Answer:
the answer is option 1
Step-by-step explanation:
the negative angle => a quarter round angle (clockwise) = ¼ x ( -360°) = -90°
and
the positive angle => a full round angle + 270° = (360°)+270°
= 630°
Answer:
correct answer is -90 and 630
Step-by-step explanation:
will mark brainliest!!
Answer:
In March she sent 752 texts
In April she sent 617
Step-by-step explanation:
The phone bill is 35 + additional texts, so in both bills the value relative to the texts are:
72.6 - 35 = 37.6 for March
65.85 - 35 = 30.85 for April
Each texts costs 0.05, so if we divide the value relative to the texts by 0.05 we will have the number of texts she sent:
37.6/0.05 = 752 texts
30.85/0.05 = 617 texts
What is the greatest common factor of 24s3, 12s4, and 18s?
Answer:
24s3
Step-by-step explanation:
24s3 is the greatest common factor of 24 S3 12 s4 and 18s.
Graph the solution to the following system of inequalities.
y-2x-9
y<2x+7
Answer:
Tb bight by icing I jb Yves j by by by navy by iffy i by by by
what is 2x 3 -7x^{3}−7x 3
Answer:
It is given that
4x/3−7x/3=1
Step-by-step explanation:
By further calculation
−3x/3=1
So we get
−x=1
x=−1.
You start with a given set of rules and conditions and determine something to
be true. What type of reasoning did you use?
O A. deductive
O B. inductive
C. logical
D. conditional
Answer:
i use logical reasoning
Alex can cut a cord into 7 pieces in 36 seconds. How long will it take him to cut the cord into 12 pieces? (the answer is NOT 61 or 62.)
Answer:
x=61.71428 or 61 5/7
Step-by-step explanation:
We can use a ratio to solve
7 pieces 12 pieces
----------------- = ---------------
36 seconds x seconds
Using cross products
7x = 36*12
7x = 432
Divide by 7
7x/7 = 432/7
61 5/7
x=61.71428
Answer:
66
Step-by-step explanation:
What is the length of BD?
Answer:
BD = 10 √3
Step-by-step explanation:
ABC ∆ ,
BD ÷ 20 = sin 60
BD = 20 sin 60
BD = (20 √3) / 2
= 10 √3
If you have to invest in an account that pays 5.3 compound annually, after 10 years how much interest is earned
[tex]\\ \sf\longmapsto Interest=Rate\times Time[/tex]
[tex]\\ \sf\longmapsto Interest=5.3(10)[/tex]
[tex]\\ \sf\longmapsto Interest =53[/tex]
It means that if your principal is $100 after 10years you will receive $53 as interest
Step-by-step explanation:
[tex]thank \: you[/tex]
Atlantic Hurricanes
Number
1925
1930
1935
1940
1945
1950
1955
1960
1965
1970
1975
Year
Between which years was
the biggest change in the
number of hurricanes?
Answer:
1950
Step-by-step explanation:
because 1950 column has the most highest number which is 11
Answer:
Between 1945 and 1950 ( from 5 to 11 ),
Step-by-step explanation:
2^12÷2^(k/2 )= 32 find k
Answer:
k = 14
Step-by-step explanation:
Prime factorize 32
32 = 2 * 2 * 2 * 2 * 2 = 2⁵
[tex]\frac{2^{12}}{2^{\frac{k}{2}}}= 32\\\\\frac{2^{12}}{2^{\frac{k}{2}}}=2^{5}\\\\2^{12-\frac{k}{2}}=2^{5}[/tex]
Both sides base are same.So, compare exponents
[tex]12-\frac{k}{2}=5\\[/tex]
Subtract 12 from both side
[tex]-\frac{k}{2}=5-12\\\\-\frac{k}{2}=-7\\[/tex]
Multiply both sides by (-2),
[tex](-2)*(-\frac{k}{2})=-7*(-2)\\\\k = 14[/tex]
Si Juana tiene dos perros y lo simbolizamos y 2p y le regalan un hato y lo simbolizamos por g como se representa en el leguaje algebraico.
A) 3P
B) 3G
C) 2PTG
D) 2P-G
2x²+3x²+3.(-1) =5x.x+5x .1
[tex]\\ \sf\longmapsto 2x^2+3x^2+3(-1)=5x.x+5x.1[/tex]
[tex]\\ \sf\longmapsto 5x^2-3=5x^2+5x[/tex]
[tex]\\ \sf\longmapsto 5x^2-5x^2-3=5x[/tex]
[tex]\\ \sf\longmapsto 5x=-3[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-3}{5}[/tex]
Divide. Write your answer as a fraction in simplest form. − 10 2/7÷(−4 4/11)=
Answer:
33/14
Step-by-step explanation:
[tex] - 10 \frac{2}{7} + ( - 4 \frac{4}{11} )[/tex]
[tex] = - \frac{72}{7} \div - ( \frac{48}{11} )[/tex]
[tex] = \frac{72}{7} \times \frac{11}{48} [/tex]
[tex] = \frac{3}{7} \times \frac{11}{2} [/tex]
[tex] = \frac{33}{14} [/tex]
stan dreamcatcher
Is the following number rational or irrational?
-117
Choose 1 answer:
Rational
Irrational
Answer:
-117 is irrational number
Answer:
Irrational
Step-by-step explanation:
Irrational number can't be written as a faction, -11pie can't be written as a fraction. Therefore it is a irrational number.
Find the surface area of the triangular prism
Add.
(3x2 – 2x) + (4x-3)
O A. 7x2- 5x
O B. 12x3 - 14x2 + 6x
O C. 3x2 - 6x + 3
O D. 3x2 + 2x-3
Answer:
O D. 3x2 + 2x-3
Answer:
A.7x2-5x questions 2of 20
Trigonometric ratios
class 9
please answer my questions
Step-by-step explanation:
Hi there!
Please see the answer in the picture.
Hope it helps!
1. Approach
One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,
[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]
Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.
2. Problem (9)
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
As per the attached image, the following statements regarding the value of each ratio can be made:
[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]
Substitute,
[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
Simplify,
[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]
Thus, this equation is true.
2. Problem (10)
Use a similar strategy to evaluate this equation,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
Use the attached image to evaluate the ratios.
[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]
Substitute,
[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
Simplify,
[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]
[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
Rationalize the denominator,
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]
[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]
[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]
[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]
[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]
[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]
Therefore, this equation is also true.
u4gent help needed
help me with the question of o.math
Answer:
1≤f(x)≤5
Step-by-step explanation:
-1≤x≤1
-2≤2x≤2 (Multiplied by 2 both side)
-2+3≤2x+3≤2+3 (Adding three both sides)
1≤f(x)≤5
Find the first three terms of the sequence given by the following.
a
n = 25-3(n − 1), n= 1, 2, 3, ...
A. 28, 25, 22
B. 25, 22, 19
C. 25, 28, 31
D. 28, 31, 34
the answer is
A. 28, 25, 22
HELP ITS DUE IN THE MORNING AND ITS 3:57
Answer:
A " (1,-2)
B " (4,0)
C " (6,-3)
Step-by-step explanation:
Hope it helped.
° ° °
a sum of money Doubles itself in 5 years what is rate of simple interest
Step-by-step explanationIf you are reading this say
thank u
The circumference of a circle is 20π. What is the area of the circle?
Answer:
The area of the circle is 100 square units.
Step-by-step explanation:
We are given that the circumference of a circle is 20π, and we want to determine its area.
Recall that the circumference of a circle is given by the formula:
[tex]\displaystyle C = 2\pi r[/tex]
Substitute:
[tex]20 \pi = 2 \pi r[/tex]
Solve for the radius:
[tex]\displaystyle r = \frac{20\pi}{2\pi} = 10[/tex]
The area of a circle is given by:
[tex]\displaystyle A = \pi r^2[/tex]
Since the radius is 10 units:
[tex]\displaystyle A = \pi (10)^2[/tex]
Evaluate:
[tex]\displaystyle A = 100\pi\text{ units}^2[/tex]
In conclusion, the area of the circle is 100 square units.
