On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.

Answers

Answer 1

Velocity, distance and time:

This question is solved using the following formula:

[tex]v = \frac{d}{t}[/tex]

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time [tex]t_1[/tex], distance of [tex]d_1[/tex], v = 40. So

[tex]v = \frac{d}{t}[/tex]

[tex]40 = \frac{d_1}{t_1}[/tex]

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is [tex]v = 60[/tex].

On the first day, he drove 2 more hours, which means that for the second day, the time is: [tex]t_1 - 2[/tex]

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: [tex]d_1 - 20[/tex]

Thus

[tex]v = \frac{d}{t}[/tex]

[tex]60 = \frac{d_1 - 20}{t_1 - 2}[/tex]

System of equations:

Now, from the two equations, a system of equations can be built. So

[tex]40 = \frac{d_1}{t_1}[/tex]

[tex]60 = \frac{d_1 - 20}{t_1 - 2}[/tex]

Find the total distance traveled in the two days:

We solve the system of equation for [tex]d_1[/tex], which gets the distance on the first day. The distance on the second day is [tex]d_2 = d_1 - 20[/tex], and the total distance is:

[tex]T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20[/tex]

From the first equation:

[tex]d_1 = 40t_1[/tex]

[tex]t_1 = \frac{d_1}{40}[/tex]

Replacing in the second equation:

[tex]60 = \frac{d_1 - 20}{t_1 - 2}[/tex]

[tex]d_1 - 20 = 60t_1 - 120[/tex]

[tex]d_1 - 20 = 60\frac{d_1}{40} - 120[/tex]

[tex]d_1 = \frac{3d_1}{2} - 100[/tex]

[tex]d_1 - \frac{3d_1}{2} = -100[/tex]

[tex]-\frac{d_1}{2} = -100[/tex]

[tex]\frac{d_1}{2} = 100[/tex]

[tex]d_1 = 200[/tex]

Thus, the total distance is:

[tex]T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380[/tex]

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: https://brainly.com/question/14307500

Answer 2

Answer:

Total traveled distance is : 380 miles

Step-by-step explanation:

Let´s call variables of the first day of travel as:

v₁ = 40 mph

Time of travel  unknown but 2 hours more than the second day

Traveled distance ( unknown) but 20 miles more than the second day

And for the second day

v₂ = 60 mph

Time of travel t

Traveled distance s (unknown)

With that information, we can make a model of a two equations system as follows:

We know that s = v*t ( where s is the distance traveled, v the speed, and t the traveled time) then

First day  

Total distance traveled s + 20 is equal to:

s + 20 = 40 * ( t + 2 )

The second day:

s = 60*t

The system is:

s + 20 = 40 * ( t + 2 )

s = 60*t

By substitution

60*t + 20 = 40 * ( t + 2 )

60*t + 20 = 40*t + 80

60*t - 40*t = 80 - 20

20*t = 60

t = 3 hours

Now we can calculate the total distance traveled according to:

First day:  s₁ = 40 (m/h)* (t + 2) (h) = 40*5 miles      s₁ = 200 miles

Second day:

s = 60*t   =  60 (m/h)*3 (h)  =  180 miles

Total distance is : 380 miles


Related Questions

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Answers

Front: 12 square centimeters
1/2 x 6 x 4 = 12

Back: 12 square centimeters
1/2 x 6 x 4 = 12

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3 x 5 = 15

Left: 15 square centimeters
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The surface area is the added areas of each face of a 3D figure.
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HELP ITS DUE IN THE MORNING AND ITS 3:57​

Answers

Answer:

A " (1,-2)

B " (4,0)

C " (6,-3)

Step-by-step explanation:

Hope it helped.

° ° °

Add.
(3x2 – 2x) + (4x-3)
O A. 7x2- 5x
O B. 12x3 - 14x2 + 6x
O C. 3x2 - 6x + 3
O D. 3x2 + 2x-3

Answers

Answer:

O D. 3x2 + 2x-3

Answer:

A.7x2-5x questions 2of 20

Mrs brown designed a rug if it cost $22 per square foot to make how much will Mrs brown pay if the square feet is 31.25

Answers

Answer:

$687.5

Step-by-step explanation:

Cost of the rug per square foot = $22

Length of the rug = 31.25 feet

Total amount Mrs brown will pay = Cost of the rug per square foot × Length of the rug

= 31.25 × 22

= $687.5

Total amount Mrs brown will pay = $687.5

a sum of money Doubles itself in 5 years what is rate of simple interest​

Answers

Step-by-step explanationIf you are reading this say

thank u

Find the first three terms of the sequence given by the following.
a
n = 25-3(n − 1), n= 1, 2, 3, ...

A. 28, 25, 22
B. 25, 22, 19
C. 25, 28, 31
D. 28, 31, 34

Answers

the answer is

A. 28, 25, 22

u4gent help needed
help me with the question of o.math​

Answers

Answer:

1≤f(x)≤5

Step-by-step explanation:

-1≤x≤1

-2≤2x≤2 (Multiplied by 2 both side)

-2+3≤2x+3≤2+3 (Adding three both sides)

1≤f(x)≤5

Each day Jose spends 2/3 of an hour playing the piano and 1/4 of an hour practicing music theory. What is the total fraction of an hour that Jose spends playing the paino and practicing music theory each day?

Answers

Answer:

11/12

Step-by-step explanation:

2/3 + 1/4

Get a common denominator of 12

2/3 *4/4   + 1/4 *3/3

8/12 + 3/12

11/12

Is the following number rational or irrational?
-117
Choose 1 answer:
Rational
Irrational

Answers

Answer:

-117 is irrational number

Answer:

Irrational

Step-by-step explanation:

Irrational number can't be written as a faction, -11pie can't be written as a fraction. Therefore it is a irrational number.

A customer's stock value seems to be rising exponentially. The equation for the linearized regression line that models this situation is log(y) = 0 30x +0 296, where x represents number of weeks. Which of the following is the best approximation of the number of weeks that will pass before the value of the stock reaches $200?

A. 9.3
B. 12.1
C. 6.7
D. 4.8​

Answers

Given:

The equation for the linearized regression line is:

[tex]\log y=0.30x+0.296[/tex]

where x represents number of weeks and y be the customer's stock.

To find:

The number of weeks that will pass before the value of the stock reaches $200.

Solution:

We have,

[tex]\log y=0.30x+0.296[/tex]

Substituting y=200, we get

[tex]\log (200)=0.30x+0.296[/tex]

[tex]2.301=0.30x+0.296[/tex]

[tex]2.301-0.296=0.30x[/tex]

[tex]2.005=0.30x[/tex]

Divide both sides by 0.30.

[tex]\dfrac{2.005}{0.30}=x[/tex]

[tex]6.6833333=x[/tex]

[tex]x\approx 6.7[/tex]

Therefore, the correct option is C.

Find the vertex of the following equation: y = -0.25x2 + -1.5x + 6

Answers

Hi there!

[tex]\large\boxed{(-3, 8.25)}[/tex]

Solve for the vertex by completing the square:

y = -0.25x² - 1.5x + 6

Factor out a negative:

y = -(0.25x² + 1.5x) + 6

Remember that a square binomial is:

a² + 2ab + b²

We know that:

a² = 0.25, so a = 0.5

1.5 = 2ab, so:

1.5 = 2(0.5)b

b = 1.5

b² = 2.25

Thus:

y = -(0.25x² + 1.5x + 2.25) + 6 - (-2.25)

Simplify:

y = -(0.5x + 1.5)² + 8.25

Find the vertex by factoring out 0.5:

y = -0.5(x + 3)² + 8.25

Thus, the vertex is:

(-3, 8.25)


Which segment is parallel to ED?

Answers

Answer:

AB

Step-by-step explanation:

The segments that are parallel need to be in the same direction ( up and down)

The segments that are parallel are FH, AB, GC

Answer:

AB

Step-by-step explanation:

since is a cube all of the angles are 90 degees and this only possibel whn the line That a vertical a parrelllt to each other

Find the measure of the indicated angle to the nearest degree.

Answers

Answer:

37

Step-by-step explanation:

tan(theta)=perpendicular/base

tan(theta)=3/4

theta=arctan(3/4)=37

Answer:

37°

Step-by-step explanation:

for this question you have to use the tan ratio since the opposite of that angle has been given as 3 and the adjacent has also been given which is 4..I will represent the unknown angle using x so,

tan x=opposite/adjacent

tanx=3/4

tanx=0.75

x=tan inverse of 0.75

x=36.9 or 37°

I hope this helps

The circumference of a circle is 20π. What is the area of the circle?

Answers

Answer:

The area of the circle is 100 square units.

Step-by-step explanation:

We are given that the circumference of a circle is 20π, and we want to determine its area.

Recall that the circumference of a circle is given by the formula:

[tex]\displaystyle C = 2\pi r[/tex]

Substitute:

[tex]20 \pi = 2 \pi r[/tex]

Solve for the radius:

[tex]\displaystyle r = \frac{20\pi}{2\pi} = 10[/tex]

The area of a circle is given by:

[tex]\displaystyle A = \pi r^2[/tex]

Since the radius is 10 units:

[tex]\displaystyle A = \pi (10)^2[/tex]

Evaluate:

[tex]\displaystyle A = 100\pi\text{ units}^2[/tex]

In conclusion, the area of the circle is 100 square units.

I don't get it- can someone explain

Answers

Answer:

11 4-passenger cars

Step-by-step explanation:

let 'x' represent the number of 4-passenger cars,then 'x-3' represent the number of 6-passenger cars.

92=4x+6(x-3)

92=4x+6x-18

92=10x-18

92+18=10x

110=10x

x=110/10

x=11

Therefore there are 11 4-passenger cars

2x²+3x²+3.(-1) =5x.x+5x .1

Answers

[tex]\\ \sf\longmapsto 2x^2+3x^2+3(-1)=5x.x+5x.1[/tex]

[tex]\\ \sf\longmapsto 5x^2-3=5x^2+5x[/tex]

[tex]\\ \sf\longmapsto 5x^2-5x^2-3=5x[/tex]

[tex]\\ \sf\longmapsto 5x=-3[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-3}{5}[/tex]

Can some help please

Answers

Answer:

Step-by-step explanation:

2 * 10^7   You are to use a single digit. That's the 2 on the left. Then count what it takes to get the decimal between the 2 and the 3. It's 7

0.000136

Count the number of zeros. Add a minus 1. You want the number to be counted until you get minus 1 which is the number of powers after the 1.

1 * 10^-4

26837 becomes 2 * 10^4. 4 is the number of digits you have before you get to a number between 1 and 10.

0.0302 becomes 3 * 10^-(1 + 1) = 3 * 10^-2

In circle C, SQ = 10 cm.

Circle C is shown. Chords S Q and R P intersect at point C. Angle P C Q is 30 degrees.

Which statements about the circle are correct? Check all that apply.

Arc PQ is congruent to arc SR.
The measure of arc QR is 150°.
The circumference of circle C is 20π cm.
Arc PS measures about 13.1 cm.
Arc QS measures about 15.7 cm.

Answers

Answer:

its 1,2,4,5

Step-by-step explanation:

Answer:

A, B, D, E

Step-by-step explanation:

Arc PQ is congruent to arc SR. TRUE

The measure of arc QR is 150°. TRUE

The circumference of circle C is 20π cm. FALSE

Arc PS measures about 13.1 cm. TRUE

Arc QS measures about 15.7 cm. TRUE

I need help ASAP!!! Please help me FInd the missing side

Answers

Answer:

Step-by-step explanation:

Tan 22 = [tex]\frac{opposite \ side}{adjacent \ side}[/tex]

[tex]tan \ 22 = \frac{30}{x}\\\\0.4040 = \frac{30}{x}\\\\0.4040*x = 30\\\\x = \frac{30}{0.4040}\\\\x = 74.25\\\\x = 74.3[/tex]

Answer:

Sin= opp/hyp

Sin22= 30/x

0.3746=30/x

cross multiply

0.3746x=30

make x the subject of the formula

x= 30/0.3746

x=80

Find f(-2).....................................

Answers

Answer:

1/25

Step-by-step explanation:

f(x) = 5^x

Let x = -2

f(-2) = 5^-2

We know a^-b = 1/a^b

f(-2) = 1/5^2

      = 1/25

Answer:

[tex]\frac{1}{25} [/tex]

Step-by-step explanation:

[tex]f(x) = {5}^{x} \\ f( - 2) \\ f( - 2) = {5}^{ - 2} \\ = \frac{1}{ {5}^{2} } \\ = \frac{1}{25} [/tex]

Divide. Write your answer as a fraction in simplest form. − 10 2/7÷(−4 4/11)=

Answers

Answer:

33/14

Step-by-step explanation:

[tex] - 10 \frac{2}{7} + ( - 4 \frac{4}{11} )[/tex]

[tex] = - \frac{72}{7} \div - ( \frac{48}{11} )[/tex]

[tex] = \frac{72}{7} \times \frac{11}{48} [/tex]

[tex] = \frac{3}{7} \times \frac{11}{2} [/tex]

[tex] = \frac{33}{14} [/tex]

stan dreamcatcher

round off to one decimal place please ​

Answers

Answer:

Theta = 37.9 degrees

AC = 11.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp/ adj

tan theta = 7/9

tan ^ -1 tan theta = tan ^-1 (7/9)

theta =37.87498

To 1 decimal place

Theta = 37.9 degrees

We use the Pythagorean theorem to find AC

a^2 + b^2 = c^2

7^2 + 9^2 = AC^2

49+81 = AC^2

130 = AC^2

Taking the square root of each side

sqrt(130) = sqrt(AC^2)

AC = 11.40175

Rounding to 1 decimal place

AC = 11.4

Please help me ASAP I’m stuck on these questions

Answers

Answer:

4, yes through the middle    5, yes through the middle 6, yes through the middle  all of them reflect from the center

Step-by-step explanation:

Convert the following equation into slope intercept form. -5x + y = 2 y = ?x + ?

Answers

Answer:

5, 2

Step-by-step explanation:

hope u got it.........

Answer:

y = 5x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

- 5x + y = 2 ( add 5x to both sides )

y = 5x + 2 ← in slope- intercept form

I need help please help me

Answers

Answer:

I found x for you, right there.

Answer:  x is 12 and y is 5

Step-by-step explanation:

I will give brainlist

Answers

Answer:

54

Step-by-step explanation:

162 divided by 3 is 54

Answer:

54 words per minute

Step-by-step explanation:

in 3 minute Rachel types 162 words

so, in 1 minute Rachel types 162words÷ 3 minutes

= 54 words per minute

Given: j(x) = x2 - 2x + 1
Which set of values represents the range of the function for the domain {0, 1, 5}?

Answers

Answer:

{1, 0, 16}

Step-by-step explanation:

given..

j(x) = x^2-2x+1

put all given values of domain (1,0 and 5 ) in the equation..

the values you get are range of the function

Answer: 1

Step-by-step explanation

0(2)-2(0)+1=0+0+1= 1

1(1)-(2)(1)+1=1-2+1= 1

(5)(2)-(2)(5)+1=10-10+1= 1

How many gallons equal 26 liters

Answers

Answer:

6.8 gallions i believe. im not quite sure

Complete the following sentence.

A radius is________
the diameter.

Answers

Answer:

1/2

Step-by-step explanation:

The radius is 1/2 of the diameter

a radius is 1/2 the diameter

Trigonometric ratios
class 9
please answer my questions​

Answers

Step-by-step explanation:

Hi there!

Please see the answer in the picture.

Hope it helps!

1. Approach

One is given a trigonometric equation with and one is asked to prove that it is true. Using the attached image, combined with the knowledge of trigonometry, one can evaluate each trigonometric function. Then one can simplify each ratio to solve. To yield the most accurate result, one has to each of the ratios in a fractional form, rather than simplifying it into a decimal form. Remember the right angle trigonometric ratios, these ratios describe the relationship between the sides and angles in a right triangle. Such ratios are as follows,

[tex]sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}\\\\csc(\theta)=\frac{hypotenuse}{opposite}\\\\sec(\theta)=\frac{hypotenuse}{adjacent}\\\\cot(\theta)=\frac{adjacent}{opposite}[/tex]

Please note that the terms (opposite) and (adjacent) are relative to the angle uses in the ratio, however the term (hypotenuse) refers to the side opposite the right angle, this side never changes its name. Use these ratios to evaluate the trigonometric functions. Then simplify to prove the identity.

2. Problem (9)

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

As per the attached image, the following statements regarding the value of each ratio can be made:

[tex]sin(60)=\frac{\sqrt{3}}{2}\\\\cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cos(60)=\frac{1}{2}[/tex]

Substitute,

[tex]\frac{sin(60)+cos(30)}{1+sin(30)+cos(60)}=sin(60)[/tex]

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

Simplify,

[tex]\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\frac{2\sqrt{3}}{2}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{1+1}=\frac{\sqrt{3}}{2}[/tex]

[tex]\frac{\sqrt{3}}{2}=\frac{\sqrt{3}}{2}[/tex]

Thus, this equation is true.

2. Problem (10)

Use a similar strategy to evaluate this equation,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

Use the attached image to evaluate the ratios.

[tex]cos(30)=\frac{\sqrt{3}}{2}\\\\sin(30)=\frac{1}{2}\\\\cot(60)=\frac{1}{\sqrt{3}}[/tex]

Substitute,

[tex]\frac{1-cos(30)}{sin(30)}=\frac{1-cot(60)}{1+cot(60)}[/tex]

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

Simplify,

[tex]\frac{1-\frac{\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{1-\frac{1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{1+\frac{1}{\sqrt{3}}}[/tex]

[tex]\frac{\frac{2-\sqrt{3}}{2}}{\frac{1}{2}}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\frac{\sqrt{3}-1}{\sqrt{3}}}{\frac{\sqrt{3}+1}{\sqrt{3}}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}+1}}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

Rationalize the denominator,

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}[/tex]

[tex]2-\sqrt{3}=\frac{\sqrt{3}-1}{\sqrt{3}+1}*\frac{\sqrt{3}-1}{\sqrt{3}-1}[/tex]

[tex]2-\sqrt{3}=\frac{(\sqrt{3}-1)^2}{3-1}[/tex]

[tex]2-\sqrt{3}=\frac{3-2\sqrt{3}+1}{2}[/tex]

[tex]2-\sqrt{3}=\frac{4-2\sqrt{3}}{2}[/tex]

[tex]2-\sqrt{3}=2-\sqrt{3}[/tex]

Therefore, this equation is also true.

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