Answer:
[tex]n_{KClO_3}=0.0353molKClO_3[/tex]
Explanation:
Hello!
In this case, according to the experiment, we first realize that the pressure of oxygen is:
[tex]p_{O_2}=1.00atm-26.0/760 atm=0.966atm[/tex]
Next, we compute the moles based off the ideal gas law:
[tex]PV=nRT\\\\n=\frac{PV}{RT}=\frac{0.966atm*1.35L}{0.08206\frac{atm*L}{mol*K}*300K}=0.0530molO_2[/tex]
Thus, since there is 3:2 mole ratio between oxygen and potassium chlorate, we can compute the consumed moles of the latter as shown below:
[tex]n_{KClO_3}=0.0530molO_2*\frac{2molKClO_3}{3molO_2} \\\\n_{KClO_3}=0.0353molKClO_3[/tex]
Best regards!
How does a limiting reagent affect how much product is formed?
O A. The amount of product will be limited by the molar mass of the
limiting reagent
B. The amount of product will be limited by the sum of the reactant
coefficients.
C. The amount of product will be limited by the number of moles of
the limiting reagent.
D. The amount of product will be limited by leftover amounts of other
reactants.
Answer:
C. The amount of product will be limited by the number of moles of
the limiting reagent.
Explanation:
a p e x :)) i just took the quiz
The amount of product will be limited by the number of moles of
the limiting reagent. Hence, option C is correct.
What is a Limiting reagent?The reactant that gets consumed early in the reaction restricts the quantity of product which will be produced in the chemical reaction. Thus, the reactant that gets consumed early in a chemical reaction is a limiting reagent.
Hence, the amount of product will be limited by the number of moles of the limiting reagent.
Learn more about limiting reagents:
brainly.com/question/14225536
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What is the molarity when 1.25 mol is dissolved in 3.50 L of solution?
Answer:
0.36 mol/L
Explanation:
The formula for molarity M=m/L
m stands for moles
L stands for liters
Plug it into the equation...
M=1.25 mol/3.5 L
M=0.35714285714
Las capas del lecho marino del Mar Mediterráneo cuentan la historia de los cambios ambientales en el hoy desértico norte de Africa desde hace 160.000 años, haciendo uso de la regla de tres simple y notación científica indicar a cuántas décadas corresponde este periodo de tiempo con procedimiento
Answer:
160.000 años corresponde a 16.000 décadas.
Explanation:
Para resolver correctamente el ejercicio debemos plantear la regla de tres simple de la siguiente manera:
1 década equivale a 10 años; A cuantas decadas equivalen 160.000 años?
1 década→10 años
x ←160.000 años
Debemos multiplicar 160.000 por 1 y luego dividir entre 10 ;
x=([tex]\frac{160.000x1}{10}[/tex])=16.000 décadas; en notación científica sería 16x10^3.
Respuesta: 160.000 años corresponde a 16.000 décadas.
