Answer:
48 molecules
Explanation:
From the given reaction:
[tex]\mathtt{P_4 + 6Cl_2\to 4PCl_3}[/tex]
i.e. 1 mole of Phosphorus react 6 moles of chlorine to yield 4 moles of PCl₃
This implies that for each P₄ molecule, we will require 6 molecules of Cl₂
We are provided with 15 molecules of P₄ and 42 molecules of Cl₂
Suppose we utilized the whole 15 molecules of P₄, we will require:
= 15 × 6 = 90 moles of Cl₂ which is not readily available except 42 are available.
If we utilized 42 molecules of Cl₂, we will require 42/6 = 7 molecules of P₄ which is readily available.
From this analysis, we can opine that Cl₂ serves as the limiting agent
∴
P₄ : Cl₂ : PCl₃ = 1 : 6 : 4 = 7 : 42 : 48
It implies that only 48 molecules of phosphorus trichloride will be formed.
A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this bubble?
Answer:
1.5x10²² particulates
Explanation:
Assuming ideal behaviour, we can solve this problem by using the PV=nRT formula, where:
P = 2.4 atmV = 250 mL ⇒ 250 / 1000 = 0.250 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 15 °C ⇒ 15 + 273 = 288 KWe input the given data:
2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 KAnd solve for n:
n = 0.025 molFinally we calculate how many particulates are there in 0.025 moles, using Avogadro's number:
0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulatesWhat is the role of a decomposer in a food chain?
A. to move food from producers to consumers
B. to move food from consumers to other consumers
C. to make food for the ecosystem
D. to return matter to the environment
Answer:D
Explanation:
Decomposers decompose food and return it to the environment through the soil
Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This causes sodium azide (NaN3) to decompose explosively according to the following reaction. 2 NaN3(s) --> 2 Na(s) 3 N2(g) What mass in grams of NaN3(s) must be reacted in order to inflate an air bag to 79.5 L at STP
Answer:
154 g
Explanation:
Step 1: Write the balanced decomposition equation
2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)
Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP
At STP, 1 mole of N₂ occupies 22.4 L.
79.5 L × 1 mol/22.4 L = 3.55 mol
Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂
The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.
Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃
The molar mass of NaN₃ is 65.01 g/mol.
2.37 mol × 65.01 g/mol = 154 g
what is the pH value of water
Answer:
The pH of pure water (H20) is 7 at 25oC, but when exposed to the carbon dioxide in the atmosphere this equilibrium results in a pH of approximately 5.2. Because of the association of pH with atmospheric gasses and temperature, it is strongly recommended that the water be tested as soon as possible.
Determine the number of moles of C in each sample
2.0 mol CH4, 0.175 mol C2H6,
4.21 mol C4H10, 24.5 mol C8 H18
Explanation:
In [tex]CH_4[/tex]:Given moles = 2.0 moles
1 mole of methane contains 1 mole of carbon and 4 moles of hydrogen
Moles of carbon in [tex]CH_4=(2.0\times 1)=2.0 moles[/tex]
In [tex]C_2H_6[/tex]:Given moles = 0.175 moles
1 mole of ethane contains 2 moles of carbon and 6 moles of hydrogen
Moles of carbon in [tex]C_2H_6=(0.175\times 2)=0.35 moles[/tex]
In [tex]C_4H_{10}[/tex]:Given moles = 4.21 moles
1 mole of butane contains 4 moles of carbon and 10 moles of hydrogen
Moles of carbon in [tex]C_4H_{10}=(4.21\times 4)=16.84 moles[/tex]
In [tex]C_8H_{18}[/tex]:Given moles = 24.5 moles
1 mole of octane contains 8 moles of carbon and 18 moles of hydrogen
Moles of carbon in [tex]C_8H_{18}=(24.5\times 8)=196 moles[/tex]
Calculate the number of representative particles of 0.0391 mol Neon gas.
i need help ASAP !
Answer:
2.35 × 10²² particles
Explanation:
To get the number of particles in a substance, we multiply the number of moles (n) of that substance by Avogadro's number (nA).
That is, we say;
number of atoms = n × 6.02 × 10²³
In this question, Neon gas is said to have 0.0391 moles. The number of atoms in that field.
number of particles = 0.0391 × 6.02 × 10²³
number of particles = 0.235 × 10²³
number of particles = 2.35 × 10²² particles
Calculate the molality of a 35.4 % (by mass) aqueous solution of phosphoric acid (H3PO4) (35.4 % means 35.4 g of H3PO4in 100 g of solution)
Answer:
3.6124 m/kg
Explanation:
Molality is calculated as moles of solute (mol) divided by kilogram of solvent (kg). Here, we can find these numbers by using the 35.4%, which gives us 35.4 g of H3PO4 and 100 g of solution to work with.
To go from grams to moles for the phosphoric acid, you need to find the molar mass of the compound or element and divide the grams of the compound or element by that molar mass.
Here, the molar mass for phosphoric acid is 97.9952 g/mol. The equation would look like this:
35.4 g x 1 mol / 97.9952 g = 0.3612422 mol
Next, the 100 g of solvent can easily be converted to 0.1 kg of solvent.
To find the molality, divide the moles of solute and kilograms of solution.
0.3612422 mol / 0.1 kg = 3.6124 m/kg
When optically active (R)-2-methylcyclohexanone is treated with either aqueous base or acid, racemization occurs. Explain.
Answer:
See explanation
Explanation:
Racemization is said to occur when a 1:1 ratio of (+) and (-) enantiomers of a compound are produced in a reaction.
The reaction of optically active (R)-2-methylcyclohexanone with either aqueous base or acid leads to the formation of a planar enol species for reaction with acid and a planar enolate species for reaction with base.
Both reactions involves the formation of achiral species which reverts back to the chiral product with equal chances of the formation of both enantiomers of the product during the process. This leads to racemization of the product in both cases.
Racemization of the optically active (R)-2-methylcyclohexanone results from the production and subsequent interconversion of intermediates during the reaction with an aqueous base or acid. This is due to the inversion of stereochemistry at the chiral centre.
Racemization can happen when an optically active molecule is exposed to an aqueous base or acid because the compound's enantiomers are interconverted. The carbon-carbon bond next to the carbonyl group in (R)-2-methylcyclohexanone breaks as a result of the chemical reaction with the aqueous base or acid. The creation of the negatively charged intermediate known as the enolate ion occurs when a base, such as hydroxide ions, is present and attacking the carbonyl carbon. The carbonyl group can then be reformated by this enolate ion after it has undergone a nucleophilic attack on a proton.
To know more about racemization, here:
https://brainly.com/question/31665891
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1. Determine the volume of SO2 (at STP) formed from the reaction of 96.7 mol FeS2 and 55.0 L of O2 at 358 K and 1.20 atm.
4 FeS2(s) + 11O2(g) 2Fe2O3(s) + 8SO2(g)
Answer:
40.0L of SO2 are produced
Explanation:
To solve this question we need to find the moles of O2 using PV = nRT in order to find the moles. Thus, we can find the limiting reactant and the moles (And volume) of SO2 produced as follows:
Moles O2:
n = PV/RT
n = 1.20atm*55.0L / 0.082atmL/molK*358K
n = 2.25 moles of O2.
Clearly, limiting reactant is O2.
The moles of SO2 produced are:
2.25 moles of O2 * (8mol SO2 / 11mol O2) = 1.6351 moles SO2
Volume SO2:
V = nRT/P
V = 1.6351 moles SO2*0.082atmL/molK*358K / 1.20atm
V = 40.0L of SO2 are produced
A 1 liter solution contains 0.402 M hypochlorous acid and 0.302 M potassium hypochlorite. Addition of 0.332 moles of hydrochloric acid will:
Answer:
Lower the pH by several units.
Exceed the buffer capacity.
Explanation:
The options are:
*Raise the pH slightly
*Lower the pH slightly
*Raise the pH by several units
*Lower the pH by several units
*Not change the pH
*Exceed the buffer capacity
The hydrochloric acid reacts with potassium hypochlorite to produce hypochlorous acid. The amount of HCl added is the HClO produced and the KClO consumed. As the moles of HCl > moles KClO, all the KClO is consumed exceeding the buffer capacity and lowering the pH by several units.
A community has a nearby forest that has some insect-damaged trees that are dying. They decide to cut the dying trees and sell the wood for
firewood.
How does science knowledge support this solution?
A. Cutting down the trees allows more animals to live in the forest.
B. Using the trees for firewood eliminates pollution caused by heating homes.
C. Selling the diseased trees as firewood allows the community to make money.
D. Removing the diseased trees allows the remaining trees to get more water and sunlight.
identify the organ system pictured below and state two functions of this system in the body
Answer:
skeletal system
Explanation:
to create and fliter blood and provide frame-work to the human body and support
An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.
How many milliliters of this suspension should be given to an infant weighing 13 lb.
Answer:
0.8853 mL
Explanation:
First we convert 13 lb to kg, keeping in mind that 1 lb = 0.454 kg:
13 lb * [tex]\frac{0.454kg}{1lb}[/tex] = 5.902 kgThen we calculate how many mg of acetaminophen should be given, using the recommended dose and infant mass:
15 mg/kg * 5.902 kg = 88.53 mgFinally we calculate the required mL of suspension, using its concentration:
88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mLYou are an intermediate product of an industrial process which intends to separate iron from its ore. A well known iron ore is hematite. Which of these ores does not contain iron?
Goethite
Malachite
Siderite
Limonite
Answer:
Malachite
Explanation:
Malachite is a copper carbonate hydroxide mineral, with the equation Cu2CO3(OH)2. This dark, green-joined mineral solidifies in the monoclinic precious stone framework, and frequently shapes botryoidal, sinewy, or stalagmitic masses, in cracks and profound, underground spaces, where the water table and aqueous liquids give the way to synthetic precipitation. So, the answer is malachite. Best of Luck!
Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct number of significant figures.
a. [9.8(±0.3)−2.31(±0.01)]8.5(±0.6)= __________
b. absolute uncertainty: __________
c. absolute uncertainty: _________
d. percent relative uncertainty: ___________
Answer:
Explanation:
Given the equation:
[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}[/tex]
The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.
The first step is to determine the algebraic value on the numerator.
Algebraic value = 9.8 - 231
= 7.49
The absolute uncertainty = [tex]\sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}[/tex]
absolute uncertainty = [tex]\sqrt{(0.3)^3 + (0.01)^2}[/tex]
= [tex]\sqrt{0.09 + 0.0001}[/tex]
= 0.300167
∴
[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)
The division process now is:
[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}[/tex]
Relative uncertainty = [tex]\dfrac{(\pm 0.300167)}{7.49}\times 100 \ , \ \dfrac{(\pm 0.6) }{8.5} \times 100[/tex]
Relative uncertainty = ±4.007565% , ±7.058824%
[tex]\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}[/tex]
[tex]\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}[/tex]
[tex]\text{Relative uncertainty} = \sqrt{65.88757349}[/tex]
[tex]\text{Relative uncertainty} = 8.117116[/tex]
≅ 8%
The algebraic value = [tex]\dfrac{7.49}{8.5}[/tex]
= 0.881176
≅ 0.88
The percentage of the relative uncertainty =[tex]\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100[/tex]
By cross multiplying:
[tex]\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}[/tex]
[tex]\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}[/tex]
[tex]\text{Absolute uncertainty} (\%) = 0.0715260[/tex]
[tex]\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}[/tex]
Finally:
[tex]\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}[/tex]
Look at this picture.
Which process in the water cycle is shown in the picture?
evaporation
transpiration
condensation
precipitation
Answer:
condensation
Explanation:
the water has condensed from the gaseous form into rain drops
Answer:
precipitation
Explanation:
What is erosion?
A) Weathered materials staying in one place
B) The movement of weathered materials by wind, water or ice
C) New materials on a land form
Answer:
B. The movement of weathered materials by wind, water or ice.
Identify the alkene obtained on dehydration of each of the following alcohols:
a. 3-Ethyl-3-pentanol
b. 1-Propanol
c. 2-Propanol
d. 2,3,3-Trimethyl-2-butanol
Answer:
Explanation:
The information below explains how dehydration of alcohol occurs to produce alkene.
Under the influence of a catalyst, alcohol dehydrates to produce an alkene and water. To produce alkene and water, the reaction eliminates the OH group from alcohol containing the carbon atom and the hydrogen atom from a neighboring carbon atom via the same molecule.
The –OH group in alcohol contribute two(2) electrons to H+ out from the acid reagent, resulting in the formation of an alkyloxonium ion. This ion serves as an excellent leaving group, allowing a carbocation to form. The nucleophile which acts as the deprotonated acid subsequently attacks and creates a double bond with the hydrogen next to the carbocation.
Emily spills concentrated sodium hydroxide solution on her lab bench. What she should do first?
Answer:
Explanation: hell noo
Gizmo Warm-up Just like students sharing markers, atoms sometimes share or swap electrons. By doing this, atoms form bonds. The Ionic Bonds Gizmo allows you to explore how ionic bonds form. To begin, check that Sodium (Na) and Chlorine (Cl) are selected from the menus at right. Click Play ( ) to see electrons orbiting the nucleus of each atom. (Note: These atom models are simplified and not meant to be realistic.) 1. Each atom consists of a central nucleus and several shells that contain electrons. The outermost electrons are called valence electrons. How many valence electrons does each atom have
Answer: Sodium element has 1 valence electron and chlorine element has 7 valence electrons.
Explanation:
Valence electrons are defined as the electrons that are present in the outermost shell.
An ionic compound is formed when the complete transfer of electrons takes place from one element (usually metals) to another element (usually non-metals).
To know this, we need to write the electronic configuration of each element.
Sodium is the 11th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^1[/tex]
It has 1 valence electron
Chlorine is the 17th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^23p^5[/tex]
It has 7 valence electrons
Hence, sodium element has 1 valence electron and chlorine element has 7 valence electrons.
The molecule β-carotene has λ 450 nm, and ɛ = 15,000 m2 mol-1. Calculate the absorption (A) expected for a solution in which 0.1 mg has been dissolved in 10 ml of water (given: the molecular weight of β-carotene, C40H56, as 536) with a path length of 1 cm. Group of answer choices
Answer: The absorbance for a solution is 0.0028
Explanation:
To calculate the absorption of a solution, the equation by Beer-Lambert law is used:
[tex]A=\varepsilon \times b\times C[/tex]
OR
[tex]A=\varepsilon \times b\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex]
where,
A = absorbance = ?
[tex]\varepsilon[/tex] = molar absorptivity = [/tex]15000m^2mol^{-1}L[/tex]
b = path length = 1 cm = 0.01 m (Conversion factor: 1 m = 100 cm)
Given mass of [tex]\beta-[/tex] carotene = 0.1 mg = 0.0001 g (Conversion factor: 1 g = 1000 mg)
Molar mass of [tex]\beta-[/tex] carotene = 536 g/mol
Volume of solution = 10 mL
Putting values in equation 1:
[tex]A=15000\times 0.01\times \frac{0.0001\times 1000}{536\times 10}\\\\A=0.0028[/tex]
Hence, the absorbance for a solution is 0.0028
Wat are representative elements
Answer:
the representative elements are elements where the the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3-11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.
Explanation:
=)
Gaseous methane CH4 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.963 g of methane is mixed with 1.2 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits.
Answer:
[tex]m_{H_2O}=0.676gH_2O[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:
[tex]0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O[/tex]
Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:
[tex]m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O[/tex]
Regards!
Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2and 0.229 gof H2O and 0.407g of SO2are obtained.
Calculate its empirical formula.
Answer:
The empirical formula is, C4H4S
Explanation:
Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles
Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g
Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles
Mass of hydrogen = 0.025 moles × 1 = 0.025 g
Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles
Mass of sulphur= 0.0064 moles ×32 = 0.2 g
Now we obtain the mole ratios by dividing through by the lowest ratio.
C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles
C4H4S
Diameter of the Balloon
Before Heat
After Heat
6 centimeters 10 centimeters
Which conclusion is supported by the evidence?
A. Air expands when heated.
B. Air is warmer when heated.
C. The balloon will pop when heated.
D. The balloon contracts when heated.
Answer:
A. air expands when heated.
Explanation:
hope this helps!
Write the structural formula for a primary, a secondary, and a tertiary constitutionally isomeric alcohol of the molecular formula C5H12O.
Answer:
The structures of all isomeric alcohols of molecular formula C5H12O along with their IUPAC names are as shown.
Their classification of primary, secondary, and tertiary alcohols are -
1-pentanol -
2-pentanol -
3-pentanol
2-methylbutan-1-ol
2-methylbutan-2-ol
3-methylbutan-2-ol
3-methylbutan-1-ol
2,2-dimethylpropanol
What is the price coke difference between a strong and weak acid?
Explanation:
Strong acids are those that are completely ionized in body fluids, and weak acids are those that are incompletely ionized in body fluids. Hydrochloric acid (HCl) is considered a strong acid because it is present only in a completely ionized form in the body, whereas carbonic acid (H2 CO3) is a weak acid because it is ionized incompletely, and, at equilibrium, all three reactants are present in body fluids. See the reactions below.
H2 CO3 (acid)↔H+ + HCO3- (base)
MAY IT HELPS U MATE ☃️☃️
For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase in GPS of the system, decrease S, or leave S unchanged. If you don’t have enough information to decide, check the “not enough information“ button in the last column. Note for advanced students: you may assume ideal gas and ideal solution behavior.
Answer:
For each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don?t have enough information to decide, check the not enough information button in the last column
What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid a 0° C?
la. A man was traveling by sie is allowed a maximum of 20kg luggage. The man
weighing 3.5kg, 15kg.2kg and 15kg
Find the excess weight of his luggage.
Express the excess weight as a percentage of the maximum weight allowed
Answer: The excess weight of the luggage is 15.5 kg and its percentage is 77.5%
Explanation:
Given values:
Maximum amount of luggage allowed = 20 kg
Amount of luggage man is carrying = [3.5 + 15 + 2 + 15] kg = 35.5 kg
Excessive weight of the luggage carried = Amount of luggage carrying - Maximum amount of luggage allowed
Excessive weight of the luggage carried = [35.5 - 20] = 15.5 kg
To calculate the percentage of excess weight, we use the equation:
[tex]\% \text{excess weight}=\frac{\text{Excess weight carried}}{\text{Maximum allowed}}\times 100[/tex]
Putting values in above equation, we get:
[tex]\% \text{excess weight}=\frac{15.5kg}{20kg}\times 100\\\\\% \text{excess weight}=77.5%[/tex]
Hence, the excess weight of the luggage is 15.5 kg and its percentage is 77.5%
