pi = c/d solve for d?

Answers

Answer 1

Answer:

[tex]d=\displaystyle\frac{C}{\pi}[/tex]

Step-by-step explanation:

Hi there!

[tex]\pi =\displaystyle\frac{C}{d}[/tex]

Multiply each side by d:

[tex]d\pi =\displaystyle\frac{C}{d}*d\\\\d\pi=C[/tex]

Divide both sides by π:

[tex]d=\displaystyle\frac{C}{\pi}[/tex]

I hope this helps!


Related Questions

Who know how to do this??

Answers

find what the whole line is equal to then take 6.5 and subtract it from the whole thing

Answer:

Step-by-step explanation:

With some research I found that the medians (QK, RJ, and SI) are broken into 2:1 ratios.

So what this means is that QD is twice as long as DK.

QD = 2DK

QD = 2 * 6.5

QD = 13

Now that you know the vertex, find the y-values that pair with a few x-values that are less than 2 and a few that are greater than 2.

Plsssss help!!!!!!!

Answers

y when x=0: 3
y when x=1: 2
y when x=3: 2
y when x=4: 3

Abel bought a mini hi-fi set for S600.
He sold it to Bob at a loss of 20%.
Bob sold it to Charles and made a profit of 5%. How much did Charles pay for it?

Answers

Answer:

$504

$600* .8 = $480

$480 * 1.05 = $504

Step-by-step explanation:

Answer:

Step-by-step explanation:

Abel:

Cost price = $ 600

Loss = 20%

Selling price = [tex]\frac{100-loss}{100}*Cost \ price[/tex]

                     [tex]= \frac{(100-20)}{100}*600\\\\=\frac{80}{100}*600[/tex]

                     = 80 * 6 = $ 480

Cost price for Bob = Selling price of Abel = $ 480

Bob's cost Price = $480

Selling price = [tex]\frac{100+Profit}{100}*CP\\\\[/tex]

                     [tex]= \frac{100+5}{100}*480\\=\frac{105}{100}*480[/tex]

                      = $ 504

Amount paid by Charles =$ 504

A 90 ° angle is divided into 2 angles.
Find the size of the angles.
5x+10 and 6x-41

Answers

Answer:

So required ans is 5*11+10=65 6x-41=25

Step-by-step explanation:

You can do as,

5x+10+6x-41=90

11x-31=90

11x=31+90

11x=121

x=121/11

x=11

write 2^60 as an exponent with a base of 16

Answers

Recall that 2⁴ = 16. So you have

2⁶⁰ = 2⁴ˣ¹⁵ = (2⁴)¹⁵ = 16¹⁵

reciprocal of. 0×7/11​

Answers

Answer:

it doesn't exist

Step-by-step explanation:

the expression 0×7/11​ is equivalent to 0. 1/0 isn't possible, so its reciprocal doesn't exist.

HELPPPP MEEEE OUTTTT!!!

Answers

Answer:

Solution given:

Relationship between base and hypotenuse is given by Cos angle

Cos Angle(?)=base/hypotenuse

Angle{?}=Cos-¹(40/58)

Angle{?}=46°

The indicated angle is 46°

Over what interval is the function in this graph constant?​

Answers

Answer:

hjjjnnnhjjjjj

Step-by-step explanation:

answer is d

please help



yuffytdgtutidrysryrdf

Answers

Answer:

19 + 1 + 9 + 1

put any of those in the slots

Answer:

19 + 1 + 9 + 1

peace

Which of the following statements does not prove that ABCD is a parallelogram.
Given: A(-4, 7), B(3,0), C(2,-5) and D(-5, 2).

Answers

Answer:

answer A

Step-by-step explanation:

A=(-4,7)

C=(2,-5)

midpoint = U=((-4+2)/2, (7+(-5))/2)=(-1,1))

B=(3,0)

D=(-5,2)

midpoint = V=((3+(-5))/2,(0+2)/2)=( -1,1)

Diagonals have the same middle, the quadrilater is a parallogram.

Anyone knows the answer?

Answers

Answer:

a) yes

b) y = -x

c) yes it goes thru the origin (0,0)

Step-by-step explanation:

a) x**2 + y**2 = 17

(-4)**2 + (-1)**2 = 17

16 + 1 = 17 YES

b) the slope of DE is

(y1 - y2)/(x1 - x2)

(-1 -4)/(-4 -1) = -5/-5 = 1,  so a perpendicular segment will have a

slope of - 1/current slope or -1.

The midpoint of DE is

x = (x1 + x2)/2 = (-4 +1)/2 = -3/2

y = (y1 + y2)/2 = (-1 +4)/2 = 3/2 so

y = mx + b

y = -x + b plug in the point (-3/2,3/2)

3/2 = -(-3/2) + b

b = 0 SO y = -x

c) The circle equation dictates that it has no offset so centers around the origin (0,0) and the equation of the bisector y = -x indeed fits (0,0).

Find x in the right triangle (not drawn to scale):

Answers

can I please know where angle x is located? there isn’t an x labeled on the triangle

The graph of a function f(x) is shown below:


What is the domain of f(x)? (1 point)
integers from - 1< x <2
integers from -3 < y < 3
integers from -3 < y <3
integers from -1 < x < 2

Answers

Answer:

It's all integers x such that -1<=x<=2.

Step-by-step explanation:

The domain is the x values for which the relation exists.

Lets read from left to right.

First point I see from left exists at x=-1, next one at x=0, then x=1, and finally at x=2.

So it's all integers x such that -1<=x<=2.

*<= means less than or equal to

6. Which of the following equations has a slope of -2 and passes
through the point (3,-4).
O) y=-2x - 4
O) y=-2x + 2
O) y = -2x+3
O) y = -2x - 1

Answers

Answer:

y=-2x+2

Step-by-step explanation:

substitute either the x or y value into the equations, if you substitute x=3 and get back y=-4, the equation is correct

Which rate is equivalent to $800 per 40 hours?

Answers

$800 per 40 hours can be expressed as a fraction as 800/40. We can find the unit rate by dividing the numerator and denominator by 40. 800/40 is 20, and 40/40 is 1. This means that the unit rate is $20 per hour.

Write the words that represent s + 21.

Answers

Answer:

A number s plus 21

Step-by-step explanation:

s+21

A number s plus 21

Can someone help me with this math homework please!

Answers

Answer:

10

Step-by-step explanation:

f ( 1 ) = 18

First term ( a ) = 18

f ( n + 1 ) = f ( n ) - 2

When, n = 1

f ( 1 + 1 ) = f ( 1 ) - 2

f ( 2 ) = 18 - 2

f ( 2 ) = 16

f ( 2 ) - f ( 1 )

= 16 - 18

= - 2

Common difference ( d ) = - 2

f ( 5 )

= a + 4d

= 18 + 4 ( - 2 )

= 18 - 8

= 10

What is the slope-intercept form is?

Answers

Slope intercept form is y = -3/4x - 3

Consider two parabolas: One has equation 1 ( 4)( 4) 2 y x x =−+ . The other has the same xintercepts, but goes through the point (2,−12) How far apart are the vertices of the two parabolas

Answers

Answer:

Following are the responses to the given question:

Step-by-step explanation:

[tex]\to y=(\frac{1}{2})(x-4)(x+4)\\\\\to y=(\frac{1}{2}) (x^2-16)\\\\\to y=(\frac{1}{2})(x-0)^2-8\\\\vertex \to (0,-8)[/tex]

The general x-intercept parabola equation [tex]y=k(x-4)(x+4)[/tex]

Parabola crosses the dot (2,-12)

[tex]\to k(2-4)(2+4)=-12\\\\\to k(-2)(6)=-12\\\\\to -12k=-12\\\\\to k=\frac{-12}{-12}\\\\\to k=1[/tex]

The parabolic equation which crosses the position [tex](2,-12)[/tex] is[tex]y=(x-4)(x+4)[/tex]

[tex]\to y=(x-4)(x+4)\\\\\to y=x^2-16\\\\\to y=(x-0)^2-16\\\\vertex \to (0,-16)[/tex]

The distance among the vertices of the two parabolas:

[tex]= \sqrt{(0 - 0)^2+(-8-(-16))^2}\\\\ = \sqrt{0+(-8+16))^2}\\\\ =\sqrt{0+(8)^2}\\\\=\sqrt{(8)^2}\\\\= 8\\\\[/tex]

There are nine different marbles in a bag. Supposed you reach in and draw one at a time. And do this three times. How many ways can you draw the three marbles if you do not replace the marble each time

Answers

Answer: 504 ways

Step-by-step explanation:

Given

There are nine different marbles in a bag

For the first time, there are 9 possible ways to draw a marble

After removal of first marble, there are 8 possible ways to draw a marble

for the third time, there are 7 possible ways

so, total ways to draw three marble are

[tex]\Rightarrow 9\times 8\times 7=504\ \text{ways}[/tex]

simplify
(−5abc − 6ac + 7cb) − (10abc + 6ac − 8bc)

Answers

Answer:

-15abc - 12ac + 15bc

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

(-5abc - 6ac + 7cb) - (10abc + 6ac - 8bc)

Step 2: Simplify

[Distributive Property] Distribute negative:                                                        -5abc - 6ac + 7cb - 10abc - 6ac + 8bcCombine like terms:                                                                                         -15abc - 12ac + 15bc

A parallelogram is cut out of a 12 inch by 8 inch sheet of paper there are four right triangles remnats two have the dimensions 2 inches by 9 inches and the other two have the dimensions 3 inches by 6 inches

Answers

Answer:

96 in²

36 in²

60 in²

6.51 in

Step-by-step explanation:

Given that :

Dimension of paper = 12 in by 8 in

Dimension of right triangles :

2 in by 9 in ; 3 in by 6 in

Area of sheet of paper = 12 in * 8 in = 96 in²

Area of triangle = 1/2 base * height

Therefore, area of remnant right triangle :

2 * 1/2 * 2 * 9 = 18 in²

2 * 1/2 * 3 * 6 = 18 in²

Combined area of triangle left = 18in + 18in = 36 in²

Area of parallelogram = Area of sheet - Area of triangles left

Area of parallelogram = 96in² - 36in² = 60 in²

Base, b of parallelogram = 9.22 in

Area of parallelogram = base * altitude,h

60in² = 9.22h

h = 60 / 9.22 = 6.51 in

TRIANGLES please help!! :)

Answers

Answer:

A

Step-by-step explanation:

First, the list of congruence theorems are:

SSS

SAS

ASA

AAS

HL

SSA is not on the list, so we can cross that out

Next, ASA implies that two angles are congruent, but we only know that one pair of angles (the right angles) are congruent, so we can cross that out

After that, the angle is not connecting the congruent sides, so D is not an option

Finally, we know that the longest sides (AD / AC) are congruent to each other, one other pair of legs/sides are congruent, and the triangles are both right triangles. Therefore, we can apply HL here

Dividing with powers of 10

Answers

You could Divide powers of 10 multiple times depending on the question

does anyone know this?

Answers

Answer:

The volume is approximately 50 m^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

The radius is 1/2 of the diameter r = 8/2 = 4

V = pi ( 4)^2 (1)

V = 16 pi

Letting pi be approximated by 3.14

V = 3.14 * 16

V = 50.24

The volume is approximately 50 m^3

Find the 20th term of the following sequence.
-6, -4,-2, O,...

Answers

Step-by-step explanation:

An=-6+(20-1)×2

=-6+19(2)

=-6+38

=32

please help with this too

Answers

Answer:

The area of the sector in circle G formed by segments [tex]\overline{AG}[/tex], and [tex]\overline {GB}[/tex] is approximately 125.66 square units

Step-by-step explanation:

The given parameters are;

The radius of the circle with center G, r = 15

The measure of the given angle, m∠AGB = 64°

The area of a sector is given as follows;

Area of a sector of a circle = (θ/360°) × π × r²

Therefore;

The area of the sector in circle G formed by segments [tex]\overline{AG}[/tex], and [tex]\overline {GB}[/tex] is given as follows;

The area of the sector in circle G  = (64°/360°) × π × 15² ≈ 125.66 square units

The graph of $y=ax^2+bx+c$ passes through points $(0,5)$, $(1,10)$, and $(2,19)$. Find $a+b+c$.

Answers

Answer:

[tex]a+b+c=10[/tex]

Step-by-step explanation:

We are given that the graph of the equation:

[tex]y=ax^2+bx+c[/tex]

Passes through the three points (0, 5), (1, 10), and (2, 19).

And we want to find the value of (a + b + c).

First, since the graph passes through (0, 5), its y-intercept or c is 5. Hence:

[tex]y=ax^2+bx+5[/tex]

Next, since the graph passes through (1, 10), when x = 1, y = 10. Substitute:

[tex](10)=a(1)^2+b(1)+5[/tex]

Simplify:

[tex]5=a+b[/tex]

The point (2, 19) tells us that when x = 2, y = 19. Substitute:

[tex](19)=a(2)^2+b(2)+5[/tex]

Simplify:

[tex]14=4a+2b[/tex]

This yields a system of equations:

[tex]\begin{cases} 5 = a + b \\ 14 = 4a + 2b\end{cases}[/tex]

Solve the system. We can do so using elimination (or any other method you prefer). Multiply the first equation by negative two:

[tex]-10=-2a-2b[/tex]

Add the two equations together:

[tex](-10)+(14)=(-2a+4a)+(-2b+2b)[/tex]

Combine like terms:

[tex]4 = 2a[/tex]

Hence:

[tex]a=2[/tex]

Using the first equation:

[tex]5=(2)+b\Rightarrow b=3[/tex]

Therefore, our equation is:

[tex]y=2x^2+3x+5[/tex]

Thus, the value of (a + b + c) will be:

[tex]a+b+c = (2) + (3) + (5) = 10[/tex]

Use the properties of logarithms to prove log, 1000 = log2 10.

Answers

Given:

Consider the equation is:

[tex]\log_81000=\log_210[/tex]

To prove:

[tex]\log_81000=\log_210[/tex] by using the properties of logarithms.

Solution:

We have,

[tex]\log_81000=\log_210[/tex]

Taking left hand side (LHS), we get

[tex]LHS=\log_81000[/tex]

[tex]LHS=\dfrac{\log 1000}{\log 8}[/tex]                  [tex]\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right][/tex]

[tex]LHS=\dfrac{\log (10)^3}{\log 2^3}[/tex]

[tex]LHS=\dfrac{3\log 10}{3\log 2}[/tex]                   [tex][\because \log x^n=n\log x][/tex]

[tex]LHS=\dfrac{\log 10}{\log 2}[/tex]

[tex]LHS=\log_210[/tex]                    [tex]\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right][/tex]

[tex]LHS=RHS[/tex]

Hence proved.

plz help me to do this​

Answers

Answer: b

Explain: because that’s where they both meet
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