Please answer correctly i will give brainliest

Answer: continuous random variable.

Step-by-step explanation:

A discrete random variable is defined as a random variable which consists of countable number. Examples include numbers of shoes, number of sales etc.

A continuous random variable is a random variable whereby the data can take several values. It is a random variable that takes time into consideration.

Therefore, the amount of time six randomly selected volleyball players play during a game will be a continuous random variable since time so involved.

Answer:

x>3

Step-by-step explanation:

3x+2>x+8

   -2      -2

3x>x+6

-x    -x

2x>6

/2   /2

x>3

The solution of the inequality 3x+2>x+8 will be x>3. The correct option is A.

When two expressions are connected by a sign like "not equal to," "greater than," or "less than," it is said to be inequitable. The inequality shows the greater than and less than relationship between variables and the numbers.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that inequality is  3x+2>x+8. The inequality will be solved as below,

3x+2>x+8

3x>x+6

2x>6

x>3

Hence, the solution is x>3.

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Answer:

The answer is 0.

Step-by-step explanation:

solve 9+5=14

14/7=2

2-2=0

solve the pther side

25-20=5

4*5=20

0*20=0

Answer:

[tex]\mathbf{4 \lim \limits _{n \to \infty} \sum \limits ^n_{i=1} \Big ( \dfrac{n(n+4i)}{2n^3 +(n+4i)^3} \Big )}[/tex]

Step-by-step explanation:

Given integral:

[tex]\int ^5_1 \dfrac{x}{2+x^3} \ dx[/tex]

[tex]\mathbf{Using \ Riemann \ sums; \ we \ have: }[/tex]

[tex]\int ^b_a \ f(x) \ dx = \lim_{n \to \infty} \sum \limits ^n_{i =1} \ f( a + i \Delta x) \Delta x[/tex]

[tex]here; \ \Delta x = \dfrac{b-a}{n}[/tex]

∴

[tex]\int ^5_1 \dfrac{x}{2+x^3} \ dx = f(x) = \dfrac{x}{2+x^3}[/tex]

[tex]\implies \Delta x = \dfrac{5-1}{n} =\dfrac{4}{n}[/tex]

[tex]f(a + i \Delta x ) = f ( 1 + \dfrac{4i}{n})[/tex]

[tex]f( 1 + \dfrac{4i}{n}) = \dfrac{n^2 ( n+4i)}{2n^3 + (n + 4i)^3}[/tex]

[tex]\lim_{n \to \infty} \sum \limits ^n_{i=1} \ f(a + i \Delta x) \Delta x = \lim_{n \to \infty} \sum \limits ^n_{i=1} \Big ( \dfrac{n^2(n+4i)}{2n^3 +(n+4i)^3} \Big )\dfrac{4}{n}[/tex]

[tex]\mathbf{= 4 \lim \limits _{n \to \infty} \sum \limits ^n_{i=1} \Big ( \dfrac{n(n+4i)}{2n^3 +(n+4i)^3} \Big )}[/tex]

Answer:

1. 90

2. 61

3. 29

4. 61

Step-by-step explanation:

1 is a 90 degree angle. Triangles = 180 degrees

Answer:

[tex]g^{-1}(x)=\sqrt[3]{\frac{x-a}{41}}[/tex]

Step-by-step explanation:

The inverse of a function has [tex]x[/tex] and [tex]y[/tex] values switched from the original function. Therefore, simply switch [tex]x[/tex] and [tex]y[/tex] and isolate [tex]y[/tex] to get your inverse function:

Original function: [tex]g(x)=41x^3+a[/tex]

Switching [tex]x[/tex] and [tex]y[/tex], then isolating [tex]y[/tex]:

[tex]x=41y^3+a,\\x-a=41y^3,\\\frac{x-a}{41}=y^3,\\y=\sqrt[3]{\frac{x-a}{41}}[/tex].

Therefore, the inverse of the [tex]g(x)=41x^3+a[/tex] is:

[tex]\fbox{$g^{-1}(x)=\sqrt[3]{\frac{x-a}{41}}$}[/tex].

Answer:

1 is false

2 is blueprints

Step-by-step explanation:

Answer:

The house is 18.75 feet tall

Step-by-step explanation:

The triangles are similar by the AA postulate.  

We are given the length of the bottom sides of the triangles, 4 and 15 respectively.  

Thus, the ratio is 4:15

We are also given the height of Annie's eyes, which is 5 feet. The height of the side that corresponds to the house is 5, so we can set up a proportion.

[tex]\frac{4}{15} = \frac{5}{x} \\4x = (5*15) = 75\\x = \frac{74}{4} \\x = 18.75[/tex]

Thus, the house is 18.75 feet tall.

Answer:

I hope this helps.

Step-by-step explanation:

h(t) = -16t2 + 108t + 28

(a)

Maximum height occurs at the vertex of the height-vs.-time parabola, which is at

t = -108/[2(-16)] sec = ? sec

Evaluate h(t) at this value of t to get hmax.

(b)

Set h(t) = 0 and solve the quadratic equation for t.  You will get a positive and a negative solution.  Discard the negative solution, since time starts at t = 0.

The quadratic function, h = -16t + 136t + 72, gives us:

a) The maximum height of the ball is 360 feet.

b) The time taken by the ball to hit the ground is 9 seconds.

A quadratic function is a function over a quadratic expression, that is, over an expression having degree 2.

In the question, we are informed that a person standing close to the edge of a 72-foot building throws a ball vertically upward. The quadratic function h = -16t² + 136t + 72 models the ball's height above the ground, h in feet, t seconds after it was thrown.

We solve the following:-

a) What is the maximum height of the ball?

The maximum height of the ball can be obtained by differentiating the given quadratic function, h = -16t² + 136t + 72.

Differentiating both sides. we get:

[tex]\frac{\delta h}{\delta t} = -32t + 136[/tex] .

To get point of inflection, we equate this to 0, to get:

[tex]\frac{\delta h}{\delta t} = -32t + 136 = 0[/tex],

or, -32t + 136 = 0,

or, t = 136/32 = 4.5.

To check whether the value of h is maximum/minimum at t = 4.5, we differentiate [tex]\frac{\delta h}{\delta t} = -32t + 136[/tex] again, to get:

[tex]\frac{\delta^{2} h}{\delta t^{2} } = -32[/tex] , which is < 0, which that implies, h is maximum at t = 4.5.

Now, we calculate the maximum height, by putting in t = 4.5, in the equation, to get:

h = -16(4.5)² + 136(4.5) + 72,

or, h = -16(20.25) + 612 + 72,

or, h = -324 + 684 = 360.

Therefore, The maximum height of the ball is 360 feet.

b) How many seconds does it take until the ball hits the ground?

The time taken can be calculated by putting the value of h = 0, and solving the quadratic function h = -16t² + 136t + 72, as the height of the ball at the ground is 0.

Therefore, it can be written as:

0 = -16t² + 136t + 72.

or, 16t² - 136t - 72 = 0.

Solving this using the quadratic equation, we get:

[tex]t = \frac{-(-136)\pm \sqrt{(-136)^{2} - 4(16)(-72)}}{2(16)}[/tex] ,

or, [tex]t = \frac{136\pm \sqrt{18496 + 4608}}{32}[/tex] ,

or, [tex]t = \frac{136\pm \sqrt{23104}}{32}[/tex] ,

or, [tex]t = \frac{136\pm 52}{32}[/tex]

Therefore, either t = (136+152)/32 = 9,

or, t  (136 - 152)/32 = -0.5.

Since t represents time, we won't take the negative value, and hence t = 9.

Therefore, The time taken by the ball to hit the ground is 9 seconds.

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Answer:

1. 29.67°

2. 68.96°

3. 89.85°

Step-by-step explanation:

1. Reference angle = x

Opposite = 45 cm

Adjacent = 79 cm

Therefore:

[tex] tan(x) = \frac{45}{79} [/tex]

[tex] tan(x) = 0.569620253 [/tex]

[tex] x = tan^{-1}(0.569620253) [/tex]

[tex] x = 29.67 [/tex] (nearest hundredth)

2. Reference angle = B

Opposite = 14

Hypotenuse = 15

Therefore:

[tex] sin(B) = \frac{14}{15} [/tex]

[tex] sin(B) = 0.93333 [/tex]

[tex] B = sin^{-1}(0.93333) [/tex]

[tex] B = 68.96 [/tex] (nearest hundredth)

3. Reference angle = x

Adjacent = 238,900 mi

Hypotenuse = 92,955,807 mi

Therefore:

[tex] cos(x) = \frac{238,900}{92,955,807} [/tex]

[tex] x = cos^{-1}(\frac{238,900}{92,955,807}) [/tex]

[tex] x = 89.85 [/tex] (nearest hundredth)

The answer is 65

Step-by-step explanation:

all you had to do was divide

Answer:

m < 1 = 52

m < 3 = 52

Step-by-step explanation:

m < 8 = 128 therefore m < 4 = 128

1.) we know that m < 4 + m < 1 must equal 180

128 + m < 1 = 180

180 - 128 = m < 1

52 = m < 1

due to the position of m < 1 and m < 3, they are the exact same

Answer:

x>4 or x≤-6

Step-by-step explanation:

x+6>10 or 3x+11≤-7

x>4 or 3x≤-18

x>4 or x≤-6

Answer:

Slope Intercept Form

Step-by-step explanation:

its the basics

Answer: D

Step-by-step explanation:

$4x-5$ is less than 25$

Answer:

110.835389 ft3

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

5x5 = 25

hope this helps (again) :D

Answer:

Gradient of Line A: 0.75

Gradient of Line B: 0.8

Therefore the lines ARE NOT parallel.

Step-by-step explanation:

Find the gradient (slope) of line A and B respectively.

Line A Gradient:

Equation of line A is 3x - 4y = 5

Rewrite this in slope-intercept form as y = mx + b, where m is the gradient (slope).

Thus,

3x - 4y - 3x = -3x + 5

-4y = -3x + 5

Divide both sides by -4

y = ¾x + ⁵/4

The gradient = ¾ = 0.75

Line B Gradient:

Gradient of line passing through (4, 7) and (-1, 3)

[tex] m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 7}{-1 - 4} = \frac{-4}{-5} = \frac{4}{5} [/tex]

Gradient (m) = ⅘ = 0.8

Since both lines do not have the same gradient, therefore the lines are not parallel.

Answer:

A 4040 bag sample 25.0425.0 grams. A level of significance of 0.020.02

the decision rule. Assume the standard deviation is known to be 11.011.0.

Step-by-step explanation:

Answer:

Rewriting [tex]6^{-2}[/tex] without an exponent we get [tex]\mathbf{\frac{1}{36}}[/tex]

Step-by-step explanation:

We need to rewrite the following without an exponent. [tex]6^{-2}[/tex]

We need to solve the exponent to find the result.

We know the exponent rule: [tex]a^{-b}=\frac{1}{a^b}[/tex]

Now using this rule to solve the equation:

[tex]6^{-2}\\=\frac{1}{6^2}\\We \:know \:that\:6^2 = 6\times 6=36\\=\frac{1}{36}[/tex]

So, Rewriting [tex]6^{-2}[/tex] without an exponent we get [tex]\mathbf{\frac{1}{36}}[/tex]