Answer:
a
Explanation:
If the same change in velocity occurs in less time, does the magnitude of the corresponding average acceleration increase, decrease, or stay the
same? Explain
Answer:
increase
Explanation:
As acceleration is the time rate of change of velocity
a = Δv/t
with t in the denominator, smaller time values result in greater acceleration values with constant velocity change.
A driver entering the outskirts of a city takes her foot off the accelerator so that the car slows down from 90 km/h to 50 km/h in 10.0s. Find the car’s average acceleration
Answer:
Explanation:
a = (vf - vi) / t
a = (50 - 90) / 10.0
a = -4 km/h/s(1000 m/km / 3600 s/h)
a = - 1.11 m/s²
70 POINT!!!!!! PLS HELP IT'S VERY IMPORTANT FOR ME
WILL MARK AS BRAINLIEST
IF YOU DON'T KNOW THE ANSWER PLS DON'T PUT COMMENT BELOW
LiF:
Element: Lithium fluoride
Ionic
------------------------
Co2:
Element: Carbon dioxide
Covalent
------------------------
NaF:
Element: sodium fluoride
Ionic
-------------------
Li20:
Element: Lithium oxide
Ionic
-----------------------
HCI:
Element: hydrogen chloride
Covalent
---------------------------
NH3:
Element:
Ammonia
Covalent
-----------
CS2O:
Element: Cesium Oxide
Ionic
-----------------------
H2O2:
Element: Hydrogen peroxide
Covalent
need some help plsss!
Answer:
1and4attract and1and 2repel
50 Points Help Asap !!
Briefly describe V-T graph For every point please if its increasing if its flat or if its positive or negative help fast
#A
It's flat as no change can be seen on the graph of A part#B
Its increasing as the line goes up in B part.#C.
It's flat as no change can be seen on the graph of C part#D
It's decreasing as the graph goes down in D part.#E
It's decreasing as the graph goes down in E part#F
It's decreasing as the graph goes down in F part.#G
It's increasing as the graph goes up in G part.An object moves 45m due East and then 15m due West, the total distance is
Answer:30m east
Explanation: 45m-15m=30m, which cancels out the one to the west. All that is left is 30m east.
Is this a test/quiz btw?
Question 2 of 5 Which two statements are true for both compounds and mixtures? A. They can be separated into two or more elements. B. Their particles all have the same chemical formula. C. Their particles are held together by chemical bonds. D. They are made up of more than one type of atom.
Answer:
D and A
I'm not sure about A lol
Which of Newton’s Laws of motion help explain the following scenario?
A paddle wheel boat pushes on the water and the water pushes back causing the boat to move
Answer:
Newton #3
Explanation:
For every action there is an equal and opposite reaction.
A 15 g bullet is fired at 630 m/s into a 4.9 kg block that sits at the edge of a 75-cm-high table. The bullet embeds itself in the block and carries it off the table.
How far from the point directly below the table's edge does the block land?
The horizontal distance traveled below the table's edge is 29.4 cm.
The given parameters;
mass of the bullet, = 15 g = 0.015 kgspeed of the bullet, = 630 m/smass of the block, = 4.9 kgThe final velocity of the bullet-block system is calculated as follows;
[tex]m_1 u_1 + m_2u_1 = v(m_1 + m_2)\\\\0.015(630) + 4.9(0) = v(0.015 + 4.9)\\\\9.45 = 4.915 v\\\\v = \frac{9.45}{4.915} \\\\v = 1.923 \ m/s[/tex]
The time for the bullet-block system to reach the ground from the table is calculated as follows;
[tex]h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\2h = gt^2\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.75}{9.8} }\\\\t = 0.153 \ s[/tex]
The horizontal distance traveled below the table's edge is calculated as follows;
[tex]X = vt\\\\X = 1.923 \times 0.153\\\\X = 0.294 \ m\\\\X = 29.4 \ cm[/tex]
Thus, the horizontal distance traveled below the table's edge is 29.4 cm.
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Compare and contrast isometric and isotonic exercises. Provide two examples of each.
Answer:
Isometric exercises are static and great for people who suffer from joint pain. Isometric exercises, like planks, don't require you to move or bend any joints. Isotonic exercises, like squats, involve straining the muscles while moving the joints and applying a constant amount of weight.
Explanation:
Answer:
Isometric exercises are static and great for people who suffer from joint pain. Isometric exercises, like planks, don't require you to move or bend any joints. Isotonic exercises, like squats, involve straining the muscles while moving the joints and applying a constant amount of weight.
Explanation:
Option B.
Consider a setup in which two springs are attached to a mass in parallel.
Convince yourself that in this setup, the compression of each spring must be the same. Using
this fact, derive the effective spring constant for springs in parallel
This is asking, "ll1 replace the two springs by a single imaginary spring, what would its spring
constant be such that the force stays the same?" Your answer should only depend on k, and k
Answer:
it would be...
Explanation:
List 3 examples of chemical properties:
Why does air pressure decrease with increasing altitude? (Select all that apply.)
Colder air is less dense.
The weight of the air below is smaller.
Less air above pushes down.
Hot air rises.
The weight of the air above is smaller.
There is more air below to push up more strongly
The air pressure decrease with increasing altitude as less air above pushes down and the weight of the air above is smaller.
When the temperature cools, molecules often slow down and they do not move and bump into each other.When altitude increases, the amount of gas molecules in the air also decrease.
The air becomes less dense than air nearer to sea level.
When the atmospheric pressure is high at lower altitudes, the density being higher.
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Vesta is a minor planet (asteroid) that takes 3.63 years to orbit the Sun.
Calculate the average sun -Vesta distance
Using Kepler's third law, the average sun -Vesta distance is 2.36 AU.
According to Kepler's laws, the square of the period of revolution of planets are proportional to the cube of their average distances from the sun. Hence, we can write; [tex]T^{2} =r^{3}[/tex]
Where;
T = period of the planet
r = average distance of the planet
When;
T = 3.63 years
r = [tex]\sqrt[3]{T^2}[/tex]
r = [tex]\sqrt[3]{(3.63)^2}[/tex]
r = 2.36 AU
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12. A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3.00 m tall on the top of the head. It bounces
back up 1.50 m before falling to the ground. If the mass of the coconut is 2.00 kg, calculate the potential energy of the
coconut relative to the ground at each of the following sites:
(a) while it is still in the tree,
(b) when it hits the bystandlar on the head,
(c) when it bounces up to its maximum height,
(d) when it lands on the ground,
(e) when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole,
Explanation:
hhhhgyyytttfghjhnjhhhhhhbbbbbbbbh
For a horizontally projectile object if the initial velocity doubled, the Vertical displacement (angle y) will be :
Answer:
Unchanged
Explanation:
horizontal projection always has initial vertical velocity equal to zero.
gravity works pretty much the same at any point on earth and will accelerate any falling object at the same rate traveling the same vertical distance in the same time. Neglecting air resistance of course.
By the way, Δy is read "delta y" not "angle y" which would be "∠ y"
delta represents a change in something, in this case the y coordinate.
Before the collision, the toy train is travelling at 0.5 m/s. The train and the stationary
truck both have a mass of 75 g.
Calculate the momentum of the toy train before the collision?
Answer:
Explanation:
p = mv = 0.075(0.5) = 0.0375 kg•m/s
A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.
What is the acceleration of the SRB and main engine during the first 2.0 minutes of flight?
A. 52 m/s2
B. 13 m/s2
C. 9.8 m/s2
D. 11 m/s2
A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
A rocket ship has several engines and thrusters. We can divide its initial movement into 2 parts:
From t = 0 min to t = 2.0 min, the SRB and the main engines act together and the speed goes from 0 m/s (rest) to 1341 m/s.From t = 2.0 min to t = 8.5 min, the main engines alone accelerate the ship form 1341 m/s to 7600 m/s.We want to know the acceleration in the first part (first 2.0 minutes). We need to consider that:
The speed increases from 0 m/s to 1341 m/s.The time elpased is 2.0 min.1 min = 60 s.The acceleration of the ship during the first 2.0 minutes is:
[tex]a = \frac{\Delta v }{t} ) \frac{(1341m/s-0m/s)}{2.0min} \times \frac{1min}{60s} = 11 m/s^{2}[/tex]
A rocket ship is accelerated by the SRB and the main engines for 2.0 minutes and the main engines for 8.5 minutes after the launch. The acceleration of the ship during the first 2.0 minutes is 11 m/s² (D).
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When an object is thrown horizontally into the air, which of the following information can be assumed of its motion? *
Vix is zero.
Viy is zero.
ax is -9.8m/s^2
Vfx is zero.
Vfy is zero.
ay is -9.8m/s^2
Answer:
The answer is ay is -,9.8m/s^2
what is the approximate distance from the surface of the earth center 2900km 700km 50000km 6400km
Answer:
6400km is the closest
Explanation:
ou are pulling a 35 kg object with 18.4 N force which is oriented at 10 degree with ground. What is acceleration?
Answer:
Acceleration= 0.52 m/s²
Write a question you would like to see on a quiz to calculate NET FORCE.
Answer:
How do you find the net force?
Explanation:
i think this is want you asked for?
Why are electromagnetic waves used to transmit signals?
Because everybody who is trying to receive signals is using an electromagnetic wave receiver. If you used anything else to transmit your signals, the person looking for your signals would never know when they show up.
1
2) Mighty Mouse can lift seven mammoths with a total mass of 525 kg. Using the acceleration of
gravity, find the total WEIGHT that Mighty Mouse is lifting. (answer: 5250 N)
Answer:
5250N
Explanation:
Weight= Mass × acceleration due to gravity
= 525kg × 10m/s^2
= 5250N
How can you use the Pythagorean theorem to add two vectors that are not perpendicular?
When heat is added to a solid how do its particles move
When a substance is heated, it releases energy, which causes the particles to become more active, vibrating, rotating, and even moving faster. If a substance has enough energy, it can overcome the bonding forces that hold the particles together and change state as a result.
an electric field is 16 n/c northwest. that makes it a
a) magnitude
b)direction
c)vector
d)scalar
16 n/c to the northwest lies an electric field. hence it qualifies as a direction. Thus, the correct response is (b). It is assumed that the field's direction corresponds to the direction in which a positive test charge should experience force.
With a positive point charge, the electric field radiates outward, whereas with a point charge that's negative, it radiates in.
How big and which way is the electric field pointing?
A positive point charge is pointed directly away by the electric field, while a negative point charge is pointed directly inside the opposite direction. When you go away again from point charge, the power of the electrical field diminishes as 1 / r 2 1/r21, slash, r, square.
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Answer:
c)vector
Explanation:
I got it right :)
ILS) Retake question
If you saw these 2 structures in a cell, you would definitely be looking at an animal
cell.
Answer:
lysosome,flagellum are the 2 structures in a cell
Pushing a chair is a law of______?
A. Law of friction
B. Law of interaction
C. Law of acceleration
D. Law of universal gravitation
please help..
Answer:
A.Law of friction
Explanation:
because friction is the move chair floor
A water balloon is thrown toward a target at 18 m/s. If the water balloon has a mass of 0.4 kg, what is its
momentum?
A) 18.4 kg · m/s
B) 7.2 kg • m
C) 7.2 kg • m/s
D) 45 kg - m/s
The momentum of the water balloon is equal to: C) 7.2 kgm/s
Given the following data:
Velocity of water balloon = 18 m/sMass of water balloon = 0.4 kgTo determine the momentum of the water balloon:
In Physics, momentum refers to the multiplication of the mass of an object and its velocity. Thus, momentum is a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
[tex]Momentum = mass \times velocity[/tex]
Substituting the given parameters into the formula, we have;
[tex]Momentum = 0.4 \times 18[/tex]
Momentum = 7.2 kgm/s
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