Please answer it now

Answer:

U B = 100.5

Step-by-step explanation:

the upper bound of the size of the television screen= 95.5 since it is corrected to the nearest 5 then the U B =100.5 cm

The upper bound of the size of the television screen is 100.5 cm

The conversion of the size of the television screen to the nearest 5cm from the initial size of 95 cm is = 100 cm.

Now, the upper bound of the size of the television screen which is 100 is can be determined by the addition of a half value to 100 cm:

i.e.

= (1/2) + 100 cm

= 0.5 + 100 cm

= 100.5 cm

Therefore, we can conclude that the upper bound of the size of the television screen is 100.5 cm

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Answer:

5.08 cm

Step-by-step explanation: You dont have the choices for answers.

2inches is also 1/6 of a foot, etc

Answer:

2m - 3

Step-by-step explanation:

We know that Jim ran m miles. Twice that amount is simply 2 times that, or 2 * m which simplifies to 2m. 3 miles fewer means that we have to subtract 3 from that quantity, so the answer is 2m - 3.

Answer:

2m - 3

Step-by-step explanation:

Distance ran by Jim = m

Twice as far as Jim : 2 * m = 2m

3 miles fewer than '2m' = 2m - 3

Distance ran by Kelly = 2m - 3

Answer:

2x²-32 ⇒ x²=16⇒ (-4,4)

4x²-100 ⇒x²=25 ⇒(-5,5)

x²-55=9 ⇒x²=64 ⇒(-8,8)

x²-140=-19 ⇒x²=121 ⇒(-11,11)

2x²-18=0 ⇒x²=9 ⇒(-3,3)

Answer:

Step-by-step explanation: Further explanation

[tex]2x^2-32=0\\\\\mathrm{Add\:}32\mathrm{\:to\:both\:sides}\\\\2x^2-32+32=0+32\\\\2x^2=32\\\\\frac{2x^2}{2}=\frac{32}{2}\\\\\mathrm{For\:}x^2=f\left(a\right)\\\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{16},\:x=-\sqrt{16}\\\\x=\sqrt{16},\:x=-\sqrt{16}\\x=4,\:x=-4[/tex]

[tex]4x^2-100=0\\\mathrm{Add\:}100\mathrm{\:to\:both\:sides}\\4x^2-100+100=0+100\\4x^2=100\\\frac{4x^2}{4}=\frac{100}{4}\\x^2=25\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{25},\:x=-\sqrt{25}\\\\x=5,\:x=-5[/tex]

[tex]x^2-140=-19\\x^2-140+140=-19+140\\x^2=121\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{121},\:x=-\sqrt{121}\\x=11,\:x=-11[/tex]

[tex]x^2-55=9\\x^2-55+55=9+55\\x^2=64\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{64},\:x=-\sqrt{64}\\x=8,\:x=-8\\[/tex]

[tex]2x^2-18=0\\2x^2-18+18=0+18\\2x^2=18\\\frac{2x^2}{2}=\frac{18}{2}\\x^2=9\\\mathrm{For\:}x^2=f\left(a\right)\\\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\x=\sqrt{9},\:x=-\sqrt{9}\\x=3,\:x=-3[/tex]

Answer:

See Explanation

Step-by-step explanation:

Given

Students = 24

Musical Instrument and Sport = 6

Neither = 3

Sport = 14

Required

Complete the two-way frequency table

-------------------------------------------------------- Plays sport || Does not play sport

Plays a musical instrument ---------------------6--------------------------------------

Does not play a musical instrument -------------------------------------3-----------

Total ---------------------------------------------------- 14 ---------------------------------------

To solve this, we'll make use of the following naming rules

A represent students that plays musical instrument; A = 6

B represent students that do not play musical instrument

C represent students that plays sport

D represent students that do not play sport; D = 3

Considering the first column [Plays a sport] and taking note of the naming rules;

[tex]A + B = 14[/tex]

Substitute 6 for A

[tex]6 + B = 14[/tex]

Solve for B

[tex]B = 14 - 6[/tex]

[tex]B = 8[/tex]

Also, given that there are 24 students in the class and 14 of them play sport; this implies that 10 do not play sport

Considering the second column [Does not play a sport]

[tex]C + D = 10[/tex]

Substitute 3 for D

[tex]C + 3 = 10[/tex]

Solve for C

[tex]C = 10 - 3[/tex]

[tex]C = 7[/tex]

Hence, the complete table is:

-------------------------------------------------------- Plays sport || Does not play sport

Plays a musical instrument ---------------------6--------------------------7----------

Does not play a musical instrument ---------8--------------------------3---------

Total ---------------------------------------------------- 14 -----------------------10---------

Answer:

5.2/0.052 is 100, and 100 is 10^2, so the missing divisor is 10^2

Answer:

100

Step-by-step explanation:

5.2/x = 0.052

Since the decimal place moves 2 places to the left from 5.2 to 0.052, the divisor is 100.

5.2/100 = 0.052

Answer:

It would be y = -x + 9

Step-by-step explanation:

Answer:

Y=-x+9

Step-by-step explanation:

Answer:

-8x + 12

Step-by-step explanation:

Distribute -4 to the parentheses:

-4(2x - 3)

-4(2x) = -8x

-4(-3) = 12

-8x + 12

Answer:

-8x +12

Step-by-step explanation:

-4(2x-3)

Distribute

-4* 2x -4 *-3

-8x +12

Answer:

32 adulta

Step-by-step explanation:

96÷6 = 16 number of families

now we need to see how many adults there are in 16 families.

and the number is 32 adults.

Answer:

32 adults.

Step-by-step explanation:

At the very least, there are 4 children for every 2 adults. That means that, at the very least, there are 6 people in one group to get into the fun fair.

96 / 6 = 16

So, there are 16 groups trying to get into the fun fair, with 2 adults in each group. 2 * 16 = 32 adults are in the queue.

Hope this helps!

Answer:

7³

Step-by-step explanation:

Using PEMDAS, we see that E (which stands for exponents) comes before M (which stands for multiplication) and A (which stands for addition) so the first operation you should do is 7³.

Answer:

x = 2

Step-by-step explanation:

3x - 5 = 1

Adding 5 to both sides gives us:

3x - 5 + 5 = 1 + 5

3x = 6

Dividing the equation by 3 gives us:

3x / 3 = 6 / 3

x = 2

Answer:

x = 2 Hfizfifsits96eotst9s

Answer: Choice B)

The relation is a function because there are no vertical lines that can be drawn on the graph that pass through more than one point.

This graph passes the vertical line test. Any input (x) leads to one and only one output (y). An example of a graph failing the vertical line test would be a graph that is a sideways parabola.

Answer:

to find the mean add all numbers the divide by the ammount of numbers given

Step-by-step explanation:

ex: 1 , 2 , 3    

add:

1+2+3=6

divide:

6 / 3 = 2  

your mean is 2

all good?

Answer: to find the mean add up all numbers and divide them by the amount of numbers there and to find the median that is the middle number write it on a piece of paper and cross out the beginning and end till you get the to the middle that is your median

Step-by-step explanation:

Answer:

The x-intercept is (-2,0)

The y-intercept is (0,3)

Step-by-step explanation:

An x-intercept is the point when the graph crosses the x-axis. In other words, the y-coordinate of the x-intercept is 0 (since it lays on the x-axis). In other words, to solve for the x-intercept(s), plug in 0 for y and solve for x:

[tex]-3x+2y=6\\-3x+2(0)=6\\-3x=6\\x=-2[/tex]

So, the x-intercept is (-2,0).

Likewise, the y-intercept is the point when the graph crosses the y-axis. Because it's on the y-axis, the x-coordinate value would be 0. Thus, to find the y-intercept, plug in 0 for x and solve for y:

[tex]-3x+2y=6\\-3(0)+2y=6\\2y=6\\y=3[/tex]

Thus, the y-intercept is (0,3).

Answer:

True

Step-by-step explanation:

Given that:

M = 27, sample of n = 36 scores, µ = 30 and σ = 18.

The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the z score is positive, the raw score is greater than the mean and if the z score is negative the raw score is less than the mean. The z score is given as:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

Given that M = 27, this means that x = 27. Therefore:

[tex]z=\frac{x-\mu}{\sigma}\\\\for \ a\ sample\ size(n):z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\z=\frac{27-30}{18/\sqrt{36} } =\frac{-3}{3}=-1[/tex]

This sample mean corresponds to a z-score of z = –1.00.

Answer:

x = 16

Step-by-step explanation:

The figure shown shows an inscribed angle F and central angle E. Both angles intercept the same arc.

Therefore, angle E is twice the measure of angle F, according to the central angle theorem of a circle.

Thus,

m<E = 2 * m<F

(x + 94)° = 2(55)

We can find the value of x with this equation.

x + 94 = 110

Subtract 94 from both sides

x = 110 - 94

x = 16

Answer:

2n+7

Step-by-step explanation:

First lets find the common difference which is 2, now we can use this formula to find the nth term.

an = a1 + (n - 1 ) d

an= 9+(n-1)2

=9+2n-2

=2n+7

To check let's insert n=5, 2(5)=10+7=17.

15+2=17!

Answer: 14 units^2

Step-by-step explanation: 2 times 3 is 6, 2 times 4 is 8, 6+8=14.

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable X can be defined as the pregnancy length in days.

Then, from the provided information [tex]X\sim N(\mu=268, \sigma^{2}=12^{2})[/tex].

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ z = 1.23

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283[/tex]

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ z = -1.645

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248[/tex]

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

Answer: 0.26

Step-by-step explanation:

As per given , we have

P(green tail) = 0.36

P(red fins) = 0.59

P(both a green tail and red fins ) = 0.21

Now, P(Neither red fin nor green tail )= 1 - P(either red fin or green tail )

[P(neither A nor B)= 1- P(either A or B)]

= 1-(P(green tail) +P(red fins)+P(both a green tail and red fins ))

[P(A or B)= P(A)+P(B)-P(A and B)]

= 1- (0.36+0.59-0.21)

= 1-(0.74)

= 0.26

Hence, the probability that the selected fish will not have a red fin or a green tail = 0.26

Answer:

(-4,7)

Step-by-step explanation:

solved by graphing

Answer:

-.26

Step-by-step explanation:

If you take the absolute value (indicates how far a number-negative/positive- is from 0) of each number u listed you will find that .26 is the smallest number,thus smallest number.

Answer:

-.26 is closest to 0 on the number line.

Step-by-step explanation:

To find distance we use absolute value to find the smallest absolute value.

The absolute value of each number is as follows

-0.26 (0.26)

0.3 (0.3)

0.275 (0.275)

-0.51 (0.51)

In order from least to greatest we have

.26, .275, .3, .51

Therefore -.26 is closest to 0 on the number line.

Good luck!!

Answer:

slope = 2 : 8 or 1:4

Step-by-step explanation:

a(-3, 4)

b(5, 6)

slope = rise / run

slope (6-4, 3+5))

slope = 2 : 8 or 1:4

Answer:

Slope =¼

Step-by-step explanation:

[tex](-3, 4) \: (5, 6) \\ x _{1} = - 3 , y_1 = 4 \\ x_2 = 5 \\ y_2 = 6[/tex]

[tex]m = \frac{y_2 - y_1}{x_2 - x_1} \\ m = \frac{6 - 4}{5 - ( - 3)} \\ m = \frac{2}{8} = \frac{1}{4} [/tex]

Answer:

5.2 inches

Step-by-step explanation:

Let a be the side of the square poster.

The area of it is:

● A = a^2

● 27 = a^2

● a = √27

● a = √(9×3)

● a = 3√3

● a = 5.19

Round it to the nearest tenth

● a = 5.2 inches

The length of one side of the poster is approximately 5 inches rounded to nearest tenth.

We round numbers because they are easy to deal with and they also retain their value to that place they have been rounded.

According to the given question the area of a square poster is 27inch².

We have to determine the length of one side of the poster.

We know area of a square is (side)².

∴ (side)² = 27.

side = [tex]\sqrt{27}[/tex].

We know [tex]\sqrt{25}[/tex] is 5 and [tex]\sqrt{36}[/tex] is 6 so [tex]\sqrt{27}[/tex] will lie between 5 and 8 and much closer to 5.

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Answer:

Step-by-step explanation:

Given the  ratio of  the profit, cost of  materials and labour  in the production of

an article to be 5:7:13 respectively, total ratio = 5+7+13 = 25

If the cost of labour is x, the cost of material will be 840+x (since the  cost of materials is Le  840 more than that of  labour)  .

Let the total cost of producing the article be y.

Cost of labour = 13/25 * y = x

Cost of labour  = 13y/25 = x.................... 1

Cost of material = 7/25*y = 840+x

Cost of material = 7y/25 = 840+x ..................... 2

From 1, 13y = 25x

x = 13y/25 ................... 3

Substituting equation 3 into 2:

7y/25 = 840+x

7y/25 = 840+13y/25

collect the like terms:

7y/25 - 13y/25 = 840

-6y/25 = 840

-6y = 25*840

y = 25*840/6

y = 3,500

Hence the total cost of producing the article is 3500

Answer:

$6291.70

Step-by-step explanation:

You have the equation and a value to solve for. So, plug this in to get m = 2500 + 0.05(75,834) = 2500 + 3791.70 = $6291.70.

Answer:

17

Step-by-step explanation:

Answer:

145.8

Step-by-step explanation:

l.s.f for the two is 3:5

volume scale factor will be 3³:5³ which us 27:125

so 27×675 / 125

= 145.8

Answer:

a) [tex]a+b+c=\begin{pmatrix}-2\\-3\end{pmatrix}[/tex]

b) (i) [tex]a+2c=\begin{pmatrix}-4\\2\end{pmatrix}[/tex]

   (ii) [tex]k=2[/tex]

Step-by-step explanation:

It is given that,

[tex]a=\begin{pmatrix}4\\-10\end{pmatrix},b=\begin{pmatrix}-2\\1\end{pmatrix},c=\begin{pmatrix}-4\\6\end{pmatrix}[/tex]

a)

We need to find the value of a+b+c.

[tex]a+b+c=\begin{pmatrix}4\\-10\end{pmatrix}+\begin{pmatrix}-2\\1\end{pmatrix}+\begin{pmatrix}-4\\6\end{pmatrix}[/tex]

[tex]a+b+c=\begin{pmatrix}4+(-2)+(-4)\\-10+1+6\end{pmatrix}[/tex]

[tex]a+b+c=\begin{pmatrix}-2\\-3\end{pmatrix}[/tex]

b)

(i) We need to find the value of a+2c.

[tex]a+2c=\begin{pmatrix}4\\-10\end{pmatrix}+2\begin{pmatrix}-4\\6\end{pmatrix}[/tex]

[tex]a+2c=\begin{pmatrix}4\\-10\end{pmatrix}+\begin{pmatrix}-8\\12\end{pmatrix}[/tex]

[tex]a+2c=\begin{pmatrix}4+(-8)\\-10+12\end{pmatrix}[/tex]

[tex]a+2c=\begin{pmatrix}-4\\2\end{pmatrix}[/tex]

(ii) It is given that a+2c=kb, where k is an integer. We need to find the value of k.

[tex]a+2c=k\begin{pmatrix}-2\\1\end{pmatrix}[/tex]

[tex]\begin{pmatrix}-4\\2\end{pmatrix}=\begin{pmatrix}-2k\\k\end{pmatrix}[/tex]

On comparing both sides, we get

[tex]k=2[/tex]

the graph will shift 3 units to the right