Please answer this, I don't have much time left!

Answer:

Following are solutions to the given question:

Step-by-step explanation:

First-test probability: [tex]\frac{3}{4}[/tex]

A person's chances of passing a second test are reduced if he fails the first test: [tex]\frac{1}{3}[/tex]

However, the chance of failing the first test is 1 in 4. As just a result, the probability of these events is low.

[tex]\to \frac{1}{4}\times \frac{1}{3}=\frac{1}{12}\\\\\to \frac{3}{4} + \frac{1}{12} = \frac{9+1}{12} = \frac{10}{12} = \frac{5}{6}[/tex]

One of the other.

Answer:

Independence and Exclusiveness are two topics which are important to probability and often confused. Discuss the difference between two events being independent and two events being mutually exclusive. Use examples to demonstrate the difference. Remember to explain as if you are talking to someone who knows nothing about the topic.

[my response: talk to them in formal language about the topic.]

Step-by-step explanation:

Answer:

-x^2-10x-26

Step-by-step explanation:

f(x) = -x^2 – 1, and

g(x) = x + 5

f(g(x)) = Plug g(x) in for x in f(x)

        = -(x+5)^2 -1

        = -(x^2 +10x+25) -1

         = -x^2 -10x-25 -1

         =-x^2-10x-26

Answer:

See explanation

Question has been corrected

Step-by-step explanation:

Given:

3x² + 11x + 30

To factorise, multiply the coefficient of x² by 30

= 3 * 30

= 90

Find two numbers that have a product of 90 and a sum of 11

** There are no such two numbers, therefore the question can't be solved using factorization

Correcting the error in the question:

x² + 11x + 30

To factorise, multiply the coefficient of x² by 30

= 1 * 30

= 30

Find two numbers that have a product of 30 and a sum of 11

6 and 5

6 + 5 = 11

6 * 5 = 30

x² + 11x + 30

= x² + 6x + 5x + 30

= x(x + 6) + 5(x + 6)

= (x + 6) (x + 5)

Answer:

379

Step-by-step explanation:

4(-9)²+73-18

4(81)+55

324+55

379

Step-by-step explanation:

An=-6+(20-1)×2

=-6+19(2)

=-6+38

=32

Answer:

The area of the sector in circle G formed by segments [tex]\overline{AG}[/tex], and [tex]\overline {GB}[/tex] is approximately 125.66 square units

Step-by-step explanation:

The given parameters are;

The radius of the circle with center G, r = 15

The measure of the given angle, m∠AGB = 64°

The area of a sector is given as follows;

Area of a sector of a circle = (θ/360°) × π × r²

Therefore;

The area of the sector in circle G formed by segments [tex]\overline{AG}[/tex], and [tex]\overline {GB}[/tex] is given as follows;

The area of the sector in circle G  = (64°/360°) × π × 15² ≈ 125.66 square units

Answer:

A number s plus 21

Step-by-step explanation:

s+21

A number s plus 21

Answer:

a) yes

b) y = -x

c) yes it goes thru the origin (0,0)

Step-by-step explanation:

a) x**2 + y**2 = 17

(-4)**2 + (-1)**2 = 17

16 + 1 = 17 YES

b) the slope of DE is

(y1 - y2)/(x1 - x2)

(-1 -4)/(-4 -1) = -5/-5 = 1,  so a perpendicular segment will have a

slope of - 1/current slope or -1.

The midpoint of DE is

x = (x1 + x2)/2 = (-4 +1)/2 = -3/2

y = (y1 + y2)/2 = (-1 +4)/2 = 3/2 so

y = mx + b

y = -x + b plug in the point (-3/2,3/2)

3/2 = -(-3/2) + b

b = 0 SO y = -x

c) The circle equation dictates that it has no offset so centers around the origin (0,0) and the equation of the bisector y = -x indeed fits (0,0).

Answer:

-15abc - 12ac + 15bc

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

(-5abc - 6ac + 7cb) - (10abc + 6ac - 8bc)

Step 2: Simplify

Answer:

Solution given:

Relationship between base and hypotenuse is given by Cos angle

Cos Angle(?)=base/hypotenuse

Angle{?}=Cos-¹(40/58)

Angle{?}=46°

The indicated angle is 46°

Recall that 2⁴ = 16. So you have

2⁶⁰ = 2⁴ˣ¹⁵ = (2⁴)¹⁵ = 16¹⁵

Answer:

19 + 1 + 9 + 1

put any of those in the slots

Answer:

19 + 1 + 9 + 1

peace

Answer:

y=-2x+2

Step-by-step explanation:

substitute either the x or y value into the equations, if you substitute x=3 and get back y=-4, the equation is correct

Answer:

Step-by-step explanation:

With some research I found that the medians (QK, RJ, and SI) are broken into 2:1 ratios.

So what this means is that QD is twice as long as DK.

QD = 2DK

QD = 2 * 6.5

QD = 13

Answer:

Following are the responses to the given question:

Step-by-step explanation:

[tex]\to y=(\frac{1}{2})(x-4)(x+4)\\\\\to y=(\frac{1}{2}) (x^2-16)\\\\\to y=(\frac{1}{2})(x-0)^2-8\\\\vertex \to (0,-8)[/tex]

The general x-intercept parabola equation [tex]y=k(x-4)(x+4)[/tex]

Parabola crosses the dot (2,-12)

[tex]\to k(2-4)(2+4)=-12\\\\\to k(-2)(6)=-12\\\\\to -12k=-12\\\\\to k=\frac{-12}{-12}\\\\\to k=1[/tex]

The parabolic equation which crosses the position [tex](2,-12)[/tex] is[tex]y=(x-4)(x+4)[/tex]

[tex]\to y=(x-4)(x+4)\\\\\to y=x^2-16\\\\\to y=(x-0)^2-16\\\\vertex \to (0,-16)[/tex]

The distance among the vertices of the two parabolas:

[tex]= \sqrt{(0 - 0)^2+(-8-(-16))^2}\\\\ = \sqrt{0+(-8+16))^2}\\\\ =\sqrt{0+(8)^2}\\\\=\sqrt{(8)^2}\\\\= 8\\\\[/tex]

Answer:

hjjjnnnhjjjjj

Step-by-step explanation:

answer is d

Answer:

96 in²

36 in²

60 in²

6.51 in

Step-by-step explanation:

Given that :

Dimension of paper = 12 in by 8 in

Dimension of right triangles :

2 in by 9 in ; 3 in by 6 in

Area of sheet of paper = 12 in * 8 in = 96 in²

Area of triangle = 1/2 base * height

Therefore, area of remnant right triangle :

2 * 1/2 * 2 * 9 = 18 in²

2 * 1/2 * 3 * 6 = 18 in²

Combined area of triangle left = 18in + 18in = 36 in²

Area of parallelogram = Area of sheet - Area of triangles left

Area of parallelogram = 96in² - 36in² = 60 in²

Base, b of parallelogram = 9.22 in

Area of parallelogram = base * altitude,h

60in² = 9.22h

h = 60 / 9.22 = 6.51 in

Answer:

So required ans is 5*11+10=65 6x-41=25

Step-by-step explanation:

You can do as,

5x+10+6x-41=90

11x-31=90

11x=31+90

11x=121

x=121/11

x=11

Answer:

[tex]a+b+c=10[/tex]

Step-by-step explanation:

We are given that the graph of the equation:

[tex]y=ax^2+bx+c[/tex]

Passes through the three points (0, 5), (1, 10), and (2, 19).

And we want to find the value of (a + b + c).

First, since the graph passes through (0, 5), its y-intercept or c is 5. Hence:

[tex]y=ax^2+bx+5[/tex]

Next, since the graph passes through (1, 10), when x = 1, y = 10. Substitute:

[tex](10)=a(1)^2+b(1)+5[/tex]

Simplify:

[tex]5=a+b[/tex]

The point (2, 19) tells us that when x = 2, y = 19. Substitute:

[tex](19)=a(2)^2+b(2)+5[/tex]

Simplify:

[tex]14=4a+2b[/tex]

This yields a system of equations:

[tex]\begin{cases} 5 = a + b \\ 14 = 4a + 2b\end{cases}[/tex]

Solve the system. We can do so using elimination (or any other method you prefer). Multiply the first equation by negative two:

[tex]-10=-2a-2b[/tex]

Add the two equations together:

[tex](-10)+(14)=(-2a+4a)+(-2b+2b)[/tex]

Combine like terms:

[tex]4 = 2a[/tex]

Hence:

[tex]a=2[/tex]

Using the first equation:

[tex]5=(2)+b\Rightarrow b=3[/tex]

Therefore, our equation is:

[tex]y=2x^2+3x+5[/tex]

Thus, the value of (a + b + c) will be:

[tex]a+b+c = (2) + (3) + (5) = 10[/tex]

Answer:

10

Step-by-step explanation:

f ( 1 ) = 18

First term ( a ) = 18

f ( n + 1 ) = f ( n ) - 2

When, n = 1

f ( 1 + 1 ) = f ( 1 ) - 2

f ( 2 ) = 18 - 2

f ( 2 ) = 16

f ( 2 ) - f ( 1 )

= 16 - 18

= - 2

Common difference ( d ) = - 2

f ( 5 )

= a + 4d

= 18 + 4 ( - 2 )

= 18 - 8

= 10

Answer:

The volume is approximately 50 m^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

The radius is 1/2 of the diameter r = 8/2 = 4

V = pi ( 4)^2 (1)

V = 16 pi

Letting pi be approximated by 3.14

V = 3.14 * 16

V = 50.24

The volume is approximately 50 m^3

Answer:

answer A

Step-by-step explanation:

A=(-4,7)

C=(2,-5)

midpoint = U=((-4+2)/2, (7+(-5))/2)=(-1,1))

B=(3,0)

D=(-5,2)

midpoint = V=((3+(-5))/2,(0+2)/2)=( -1,1)

Diagonals have the same middle, the quadrilater is a parallogram.

Answer:

A

Step-by-step explanation:

First, the list of congruence theorems are:

SSS

SAS

ASA

AAS

HL

SSA is not on the list, so we can cross that out

Next, ASA implies that two angles are congruent, but we only know that one pair of angles (the right angles) are congruent, so we can cross that out

After that, the angle is not connecting the congruent sides, so D is not an option

Finally, we know that the longest sides (AD / AC) are congruent to each other, one other pair of legs/sides are congruent, and the triangles are both right triangles. Therefore, we can apply HL here

Answer:

it doesn't exist

Step-by-step explanation:

the expression 0×7/11​ is equivalent to 0. 1/0 isn't possible, so its reciprocal doesn't exist.

Given:

Consider the equation is:

[tex]\log_81000=\log_210[/tex]

To prove:

[tex]\log_81000=\log_210[/tex] by using the properties of logarithms.

Solution:

We have,

[tex]\log_81000=\log_210[/tex]

Taking left hand side (LHS), we get

[tex]LHS=\log_81000[/tex]

[tex]LHS=\dfrac{\log 1000}{\log 8}[/tex]                  [tex]\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right][/tex]

[tex]LHS=\dfrac{\log (10)^3}{\log 2^3}[/tex]

[tex]LHS=\dfrac{3\log 10}{3\log 2}[/tex]                   [tex][\because \log x^n=n\log x][/tex]

[tex]LHS=\dfrac{\log 10}{\log 2}[/tex]

[tex]LHS=\log_210[/tex]                    [tex]\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right][/tex]

[tex]LHS=RHS[/tex]

Hence proved.