Please help ASAP and please explain how you got the answer.

Answer:[tex]\huge \boxed{x=180-26-90=64}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

You have the angels 180, 26, 90(right angle) and x. So when you add them all up you should get 360 because there aren’t two straight lines. Only line makes a 180 angle. So...

180 + 26 + 90 + x = 360

296 + x = 360

x = 360 - 296

x = 64

Answer:

b-8=9

b=9+8

b=17

Step-by-step explanation:

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Answer:

b=17

Step-by-step explanation:

b-8=9

first isolate the variable by adding 8 to both sides

this gives us

b=17

Answer:

Step-by-step explanation:

Use the property of 30°-60°-90° right triangle.

The ratio of sides:

Compare with the given:

Apply the property of 30-90-60 angle

So

Answer:

c) 21

Step-by-step explanation:

[tex] \sqrt{169} + \sqrt{64} [/tex]

13+8

answer is 21

Answer:

wyatt

Step-by-step explanation:

4:30 mins is 270 seconds

Answer:

x^2 +2x -6

Step-by-step explanation:

f(x)=2x+1

g(x)=x^2-7,

(f+g)(x) = 2x+1 + x^2 -7

Combine like terms

           = x^2 +2x -6

f (x) = 2x + 1

g (x) = x² - 7

(f+g) (x) = 2x+1 + x² - 7

Adding like terms

⇛ x² + 2x - 6

Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]

So we could have this piecewise function

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]

Or we could easily swap the "or equal to" portion to move to the first part instead like this

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]

Either way, we're involving the equations mentioned in choice A

Answer:

9x^2 + 2x - 5

Step-by-step explanation:

7x^2 - 5x + 3

2x^2 + 7x - 8

__________

9x^2 + 2x - 5

Option B is the correct answer.

Answer:

22 m/s

Step-by-step explanation:

Take the distance and divide by the time

1210 m/55s

22 m/s

Answer:

Step-by-step explanation:

[tex]speed = \frac{distantce}{time} \\ = \frac{1210m}{55s} \\ = 22m {s}^{ - 1} [/tex]

G(x)=2x+1 , vertical stretch by 2 units and shifted 1 unit up

Given :

Original function f(x)=x

To find :

Function G whose graph is a vertical stretch by 2  and move one unit up

We use the given function to for vertical stretch and shifting up

for Vertical stretch multiply the factor by f(x)

f(x) becomes  2f(x)

so the function becomes 2x

[tex]f(x)=2f(x)=2x\\[/tex]

For moving up , we need to add the units at the end of the function

f(x)+1

2x+1

Hence, G(x)=2x+1

Learn more :  /brainly.com/question/4521517

Answer:

D

Step-by-step explanation:

I took the quiz

Answer:

The cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Step-by-step explanation:

Given that Sayad bought a watch and sold to Dakshes at 10% profit, and Dakshes again sold it to Sahayata for $ 6,050 at 10% profit, to find the cost price of Dakshes and the cost price of Sayad the following calculations must be performed:

6,050 / 1.1 = X

5,500 = X

5,500 / 1.1 = X

5,000 = X

Therefore, the cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Answer:

Does the answer help you?

Answer:

B

Step-by-step explanation:

here we use trigonometric ratio involving soh,cah,toa

Answer:

(a+b)³=a³+3a²b+3ab²+b³

Answer:

Step-by-step explanation:

Hello!

(a+b)(a+b)(a+b)

(a+b)(a+b) = a²+2ab + b²

(a²+2ab + b²) (a+b)=

a³ + a²b +  2a²b + 2ab² + ab² + b³ =

a³ + b³ +  2a²b + 2ab² + ab²  + a²b

Answer:

Find the domain by finding where the equation is defined.

Interval Notation:

(−∞,−4)∪(−4,7)∪(7,∞)

Set-Builder Notation:

{x|x≠−4,7}

Step-by-step explanation:

Answer:

all real numbers except x=-4 or x = 7

Step-by-step explanation:

The domain is the numbers that x can take

We have restrictions for this problem

the denominator cannot be zero

x^2 -3x-28 cannot be zero

(x-7)(x+4) ≠ 0

x-7≠0  x+4≠0

x≠7 x≠-4

Otherwise all real numbers are valid

Answer:

26

Step-by-step explanation:

Answer:

26

Step-by-step explanation:

(g•h)(x) = 2(x²+4)

(g•h)(3)=2(3²+4)

=2(9+4)

=2(13)

=26

Answer:

55 cm

Step-by-step explanation:

height = 4895/89 = 55 cm

Answer:

a₁₀₀ = 697

Step-by-step explanation:

The nth term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 4 and d = a₂ - a₁ = 11 - 4 = 7 , then

a₁₀₀ = 4 + (99 × 7) = 4 + 693 = 697

Answer:

-71/25

Step-by-step explanation:

We can use the slope formula when given two points

m = (y2-y1)/(x2-x1)

m = (86-15)/(1 -26)

   = 71/-25

  = -71/25

Answer:

[tex]\displaystyle m = \frac{-71}{25}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

Point (26, 15)

Point (1, 86)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Answer:

A

Step-by-step explanation:

since there are 3 corresponding sides shown, the SSS similarity theorem can be utilized.

Answer:

t=2

Step-by-step explanation:

We are given the equation

h = -16t²+36t+1

Next, we are asked to find how long the ball was in the air (the time, in seconds) if Casey caught the ball 9 feet above the ground (9 feet is the height).

Therefore, as 9 is the height, we can plug that into our equation to get

9 = -16t²+36t+1

To make this a quadratic equation that is easy to factor, we can subtract 9 from both sides to get

-16t²+36t-8=0

To factor this, we need to find two values that add up to 36 and multiply to (-16)*(-8) = 128. With a little guess and check, I found the numbers 32 and 4 to work well. We can then make the equation

-16t²+32t+4t-8=0

-16t(t-2) + 4(t-2) = 0

(-16t+4)(t-2) = 0

Therefore, to solve for the equation being 0, or 9 = -16t²+36t+1, either (t-2) or (-16t+4) must equal 0

t-2 = 0

t=2

-16t+4 = 0

-16t = -4

t = 1/4

Therefore, t=1/4 and/or t=2. To figure out which one it is (or both!), we can take into account that the question states "on its way down". This means that the ball goes up and then down, and we want to find t when it is going down. Using the knowledge that a ball that is hit goes up and then down, as well as that -16t²+36t-8=0 is a quadratic equation with 2 solutions, we can say that the higher value of t (t=2) represents when the ball is going down

Step-by-step explanation:

(f*g) (x)=f(x) * g(x)

=(x+3)(2x^2-4)

=2x^3-4x+6x^2-12

Answer:

True

Step-by-step explanation:

Any two points are always collinear because you can always connect them with a straight line. Three or more points can be collinear, but they don't have to be. ... Coplanar points: A group of points that lie in the same plane are coplanar. Any two or three points are always coplanar.

Answer:

m

Step-by-step explanation:

Answer:

10.99

Step-by-step explanation:

c=[tex]\pi[/tex]d

c=3.14 x 3.5cm

c=10.99

Answer:

y = -x + 1

Step-by-step explanation:

eqn of line: y=mx+c

perpendicular, m1 x m2 = -1

m × 1 = -1

m = -1

y=-x+c

sub x=-5, y=6

6 = -(-5) +c

6 = 5 + c

c = 1

y = -x + 1

Answer:

-0.01

Step-by-step explanation:

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Answer:

-0.01

Step-by-step explanation:

9514 1404 393

Answer:

  D.) a+2b

Step-by-step explanation:

The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...

  A) 3(0) = 0 . . . even

  B) 1 +3 = 4 . . . even

  C) 2(1+0) = 2 . . . even

  D) 1 +2(0) = 1 . . . odd

_____

Additional comment

These rules apply to even/odd:

Then A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.

Answer:

try 14n

Step-by-step explanation:

Answer:

[tex]r \: = 2sin2 \theta \\ = > r = 2.2sin\theta.cos\theta \\ = > r = 4sin\theta.cos\theta \: \\ \\ \sf \: we \: know \: that \: \\ x = r \: cos\theta \: \therefore \: cos\theta = \frac{x}{r} \\ \\ y = r \: sin\theta \: \therefore \: sin\theta = \frac{y}{r} \\ \\ \sf \: now \\ \\ r = 4 \times \frac{y}{r} \times \frac{x}{r} \\ = > {r}^{3 } = 4xy \\ \\ \sf \: again \: \: r = \sqrt{ {x}^{2} + {y}^{2} } \\ \\ = > {( \sqrt{ {x}^{2} + {y}^{2} } })^{3} = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{ \frac{3}{2} } = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{3} = 16 {x}^{2} {y}^{2} [/tex]

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