Please help I’ll give brainliest

Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the required histograms are not provided; however, the general explanation is as follows.

(a) If any of the histograms has more bars at the left hand side, then it means that the distribution is skewed left.

(b) If any of the histograms has more bars at the right hand side, then it means that the distribution is skewed right.

(c) If any of the histograms has appears to have increasing number of bars at the middle, then it means the such histogram is symmetrical.

Use the above illustration to answer your question.

Answer:

C: Both distributions are skewed right.

Step-by-step explanation:

x = 16°

Step-by-step explanation:

The sum of angles in a straight line = 180°

Therefore

5x + 100° = 180°

5x = 180° - 100°

5x = 80°

x = 80/5

x = 16°

Answer:

The first number (x) = 8

Step-by-step explanation:

Let x = the first number

Let y = the second number

x = 3*y - 4

2x + 3 - 2y = 11        Subtract 3 from both sides

2x - 2y = 11 - 3

2x - 2y = 8              Divide by 2

x - y = 4                   Add y to both sides

x = y + 4                  Now go back to the very first equation. Substitute for x

y + 4 = 3y - 4          Subtract y from both sides

4 = 3y - y - 4

4 = 2y - 4                Add 4 to both sides

4 + 4 = 2y

8 = 2y                     Divide by 2

8/2 = y

y = 4

x = 3y - 4

x = 3*4 - 4

x = 12 - 4

x = 8

Answer: 2 to the 8th power

Step-by-step explanation:

Answer:

two

Step-by-step explanation:

The number of solutions is the number of times the graphs intersect.

The line and the parabola intersect two times, so there are two solutions

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "

According to Pythagoras theorem,

[tex] \boxed{ \large \boxed{h {}^{2} = {b}^{2} + p{}^{2} }}[/tex]

note :

let's solve for " y² " first ( square of other missing side )

[tex]➢ \: \: {y}^{2} = {8}^{2} + 3 {}^{2} [/tex]

[tex]➢ \: \: {y}^{2} = 64 + 9[/tex]

[tex]➢ \: \: {y}^{2} = 73[/tex]

now let's solve for " x " , by using pythagorous theorem

[tex]➢ \: \: {x}^{2} = {y}^{2} + {6}^{2} [/tex]

[tex]➢ \: \: {x}^{2} = 73 + 36[/tex]

[tex]➢ \: \:x {}^{2} = 109[/tex]

[tex]➢ \: \: x = \sqrt{109} [/tex]

Approximate :

[tex]➢ \: \: 10.44 \: \: units[/tex]

[tex] \mathrm{✌TeeNForeveR✌}[/tex]

Answer:

22h−9.25

Step-by-step explanation:

Step-by-step explanation:

Given

Inequalities are [tex]y\leq -\dfrac{1}{3}x+2[/tex] and [tex]y>2x-3[/tex]

Take the inequality as two equations to get the intersection point

[tex]y=-\dfrac{1}{3}x+2\ and\ y=2x-3[/tex]

Equate the value of y

[tex]\Rightarrow -\dfrac{1}{3}x+2=2x-3\\\Rightarrow 5=\dfrac{7x}{3}\\\\\Rightarrow x=\dfrac{15}{7}[/tex]

[tex]\therefore y=1.286[/tex]

The common region gives the required regions for inequalities.

Step-by-step explanation:

câu trả lời là trong hình ảnh trên

Answer:

x=20, g=100, f=80

Step-by-step explanation:

when ever somthing is suplementary it means the the answer will euqal to 180 degrees. That means your equation is going to be

3x+40+5x-20=180

8x+20=180

8x=160

x=20

Finding g

3(20)+40

60+40

g=100

FInding f

5(20)-20

100-20

f=80

90% off means is is selling for 10% of the original price.

Multiply original price by 10%

107 x 0.01 = $10.70

It is selling for $10.70

Answer:

- 5, 3, 11, 19, 27, 35

Step-by-step explanation:

Using the recursive rule and a₁ = - 5

a₂ = a₁ + 8 = - 5 + 8 = 3

a₃ = a₂ + 8 = 3 + 8 = 11

a₄ = a₃ + 8 = 11 + 8 = 19

a₅ = a₄ + 8 = 19 + 8 = 27

a₆ = a₅ + 8 = 27 + 8 = 35

The first six terms are - 5, 3, 11, 19, 27, 35

Answer:

The answer is 74

Step-by-step explanation:

First you need to find the number of student in total so just multiply 26 by 3 which is 78.

Then after since there are 4 students absent subtract 4 from 78 which is 74.

Answer:

D. 8

Step-by-step explanation:

the upper quartile = 8

Answer:

[tex]5[/tex]

Step-by-step explanation:

Segments are named by their endpoints. Therefore, segment PQ will have endpoints P and Q. The length of the segment is equal to the distance between these points.

To find the distance between P and Q given their coordinates, use the distance formula:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Let:

[tex]P(-2, 7)\implies (x_1, y_1),\\Q(1, 3)\implies (x_2, y_2)[/tex]

The distance between these points is equal to:

[tex]d=\sqrt{(1-(-2))^2+(3-7)^2},\\d=\sqrt{3^2+(-4)^2},\\d=\sqrt{9+16},\\d=\sqrt{25},\\d=\boxed{5}[/tex]

Answer:

[tex]5[/tex]

Step-by-step explanation:

This problem gives one the following points on a line: ([tex]P(-2,7)[/tex]), and ([tex]Q(1,3)[/tex]). The problem asks one to find the distance between the two points. The formula to find the distance between two points on a coordinate point is the following,

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substitute the given values in and solve for the distance;

[tex]D=\sqrt{(-2)-(1))^2+((7)-(3))^2}[/tex]

Simplify,

[tex]D=\sqrt{(-2)-(1))^2+((7)-(3))^2}\\\\D=\sqrt{(-3)^2+(4)^2}\\\\D=\sqrt{9+16}\\\\D=\sqrt{25}\\\\D = 5[/tex]

Answer:

ss

Step-by-step explanation:

s

Step-by-step explanation:

add all the freqency up which is 100

you have to use a customize spinner and put in all the colors that are all on the side...

Spin 150 times ( 250-100= 150) and put tally marks on the sheet of tallys.

Then count all you red and see.

Hope all that makes sense..

Answer:

[tex](m−15)(m+2)[/tex]

Step-by-step explanation:

[tex] m² - 13m - 30?[/tex]

Formula :

[tex] {x}^{2} +bx+c[/tex]

[tex](m−15)(m+2)[/tex]

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {C. \:20.25}}}}}}[/tex]

[tex]0.25, 0.75, 2.25, 6.75,20.25,..[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]0.25, 0.75, 2.25, 6.75,20.25 \\ \\ ➺ \: 0.25 \times 3 = 0.75 \\ \\ ➺ \: 0.75 \times 3 = 2.25 \\ \\ ➺ \: 2.25 \times 3 = 6.75 \\ \\ ➺ \: 6.75 \times 3 = 20.25[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

[tex] \large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}[/tex]

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

[tex] \large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }[/tex]

Since tan is negative in the second quadrant. Hence,

[tex] \large{ \cancel{ tan \theta = \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta = - \frac{ \sqrt{5} }{2} }}[/tex]

Answer

Answer:

1 : 2

Step-by-step explanation:

the ratio is 1 : 2

_____

Answer:

nah its a.

Step-by-step explanation:

bakit?(#boyinthebrainly)

Answer:

The average rate of change of h(x) in the given interval is 7.

Step-by-step explanation:

When we want to find the average rate of change of a function f(x), in an interval a < x < b, we just need to calculate:

[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]

Here we have:

h(x) = 2*x^2 - 7*x

And we want to find the average rate of change between x = 2 and x = 5

This will be:

[tex]r = \frac{h(5) - h(2)}{5 - 2} = \frac{(2*5^2 - 7*5) - ( 2*2^2 - 7*2)}{3} = \frac{15 - (-6)}{3} = \frac{21}{3} = 7[/tex]

The average rate of change of h(x) in the given interval is 7.

Answer:

300 Bags

Step-by-step explanation:

According to the Question,

The radius of the pool = 3.5 m; the overall radius including the border = 3.5 + 2 = 5.5m

overall area - pool area = border area(A)

A = π×5.5² - π×3.5²

A = 56.55 sq m  

the volume of the concrete, change 50 mm to .05 m

56.55 * 05 = 2.8275 cu/meters

1 cubic metre requires 106 x 20 kg bags.

106 * 2.8275 = 299.715 ≈ 300bags

Answer:

Its either exponential growth or increasing linear. I am positive it is not exponential decay or decreasing linear, but if I had to choose it would be exponential growth.

Answer:

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