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Hope this helps *smiles*
Related Questions
plz help me plz and correctly!!!! only 3 questions plz!!! 100 points
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Answer:
Step-by-step explanation:
6)b) Sin A - x Cos A = 0
Sin A = x Cos A
[tex]\dfrac{Sin \ A}{Cos \ A} = x[/tex]
[tex]\dfrac{1}{x}=\dfrac{1}{\dfrac{Sin \ A }{Cos \ A}}=1*\dfrac{Cos \ A}{Sin \ A}=\dfrac{Cos \ A}{Sin \ A}[/tex]
[tex]RHS = x +\dfrac{1}{x}\\\\\\[/tex]
[tex]= \dfrac{Sin \ A}{Cos \ A}+\dfrac{Cos \ A}{Sin \ A}\\\\\\=\dfrac{Sin \ A*Sin \ A}{Cos \ A*Sin \ A}+\dfrac{Cos \ A * Cos \ A}{Sin \ A* Cos \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Cos \ A*Sin \ A}+\dfrac{Cos^{2} \ A}{Cos \ A* Sin \ A}\\\\= \dfrac{Sin^{2} \ A+Cos^{2} \ A}{Cos \ A*Sin \ A}\\\\=\dfrac{1}{Cos \A*Sin \ A}\\\\= \dfrac{1}{Cos \ A}*\dfrac{1}{Sin \ A}\\\\=Sec \ A * Cosec \ A[/tex]
= LHS
7a) 1 - Sin A = 1/2
[tex]1 = \dfrac{1}{2}+ Sin \ A\\\\1-\dfrac{1}{2}=Sin \ A\\\\\dfrac{1}{2}=Sin \ A\\[/tex]
⇒ A = 30°
Sec² A = Sec² 30° = [tex](\frac{2}{\sqrt{3}})^{2}=\frac{2^{2}}{(\sqrt{3)^{2}}}=\frac{4}{3}[/tex]
[tex]tan^{2} \ A = tan^{2} 30 = (\dfrac{1}{\sqrt{3}})^{2} = \dfrac{1}{3}[/tex]
LHS = 6 Sec² A + 9 tan² A
[tex]= 6*\dfrac{4}{3}+9*\dfrac{1}{3}\\\\\\=2*4 + 3*1\\\\\\= 8 + 3\\\\= 11 = RHS[/tex]
x=-4 +6+ (11 +4(-3))
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Answer:
x=1
Step-by-step explanation:
x = -4 + 6 + (11 + 4(-3)).
First get the numbers in the parentheses
x = -4 + 6 + (11 - 12)
Since 11 - 12 = -1. We can replace (11-12) with -1
x = -4 + 6 -1
Now add and subtract
x = 1
If 3x = y -5 and x = 4, then y =
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Answer:
y = 17
Step-by-step explanation:
3x = y - 5, for x = 4
=> 3(4) = y - 5
=> 12 = y - 5
=> 12 + 5 = y
=> 17 = y
pls answer with steps <3
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Answer:
Step-by-step explanation:
If a=b+7 and b+7=9, then a=9
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Answer:
a = 9
b = 2
Step-by-step explanation:
Given : a = 9
a = b + 7
9 = b + 7
b = 9 - 7 = 2
please helpppppp!!!!!!!!!
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Answer:
64w^2
Step-by-step explanation:
Because 8w is in parentheses, you must apply the exponent to both the 8 and w.
So, it becomes (8*8)(x*x) which equals (64)(x^2).
Which then gives you your final answer, 64x^2.
b+6/4 when b=1.5???????????????????????
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Answer:
3
Step-by-step explanation:
Judging by appearance, name an acute angle, an obtuse angle, and a right angle.
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Answer:
Step-by-step explanation:
How do you find the GCF of each?
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For the coefficients, take the smaller number (so 30 in the exercise #12) and find all the numbers that divide into 30:
1, 2, 3, 5, 6, 10, 15, 30
Then start with the largest of those and see which is the first to divide into 66.
30 does not divide evenly into 66.
15 does not divide evenly into 66.
10 does not divide evenly into 66.
6 does. You’ll use 6.
For the x’s, consider how many x’s each expression has.
66yx has 1 x
30x^2y has 2 x’s.
The greatest number they all have is 1 x.
For the y’s, do the same thing:
66xy has 1 y.
30x^2y has 1 y.
They both have 1 y in common.
So the greatest things they all have in common are 6xy. That’s your GCF.
E
Initial Knowledge Check
Question
Find the surface area of a cylinder with a height of 5 m and a base radius of 3 m.
Use the value 3.14 for it, and do not do any rounding.
Be sure to include the correct unit.
5 m
Í
3 m
1
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IF U HELP ME I WILL MARK U BRAINLIEST
Answers
Answer- -4
SOMEONE HELP??????!!!!!!!
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Answer: a = 300, b = b = 50.24
Step-by-step explanation:
Plss tell me guy's plssssssssssssssssssssssssssssssssssssssssssssss
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Answer:
According to my equation it's 20°
-3x=-60
X=20
So the angle is 40
Two complex numbers are given, where m, n, p, and q are real numbers.
m+ni
p+qi
For what relationship among m, n, p, and q, will be the product of these two complex numbers have only an imaginary part?
This is Algebra 2.
Answer choices:
np mq
mp-np=0
mp+nq=-1
Answers
Answer:
[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]
Or:
[tex]pm = qn \text{ and } pn + qm \neq 0[/tex]
Step-by-step explanation:
We are given two complex numbers:
[tex]\displaystyle m + ni \text{ and } p + qi[/tex]
Where m, n, p, and q are real numbers.
And we want to determine the relationship among m, n, p, and q such that the product of the two complex numbers will only have an imaginary part.
Find the product:
[tex]\displaystyle \begin{aligned} (m+ni)(p+qi) &= p(m+ni) + qi(m+ni) \\ &= (pm + pni) + (qmi + qni^2) \\ &= (pm + pni) + (qmi - qn) \\ &= (pm - qn) + i(pn + qm) \end{aligned}[/tex]
Therefore, for the product to have only an imaginary part, the real part must be zero and the imaginary part must not be zero. That is:
[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]
In conclusion, the relationship between m, n, p, and q is:
[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]
Or:
[tex]pm = qn \text{ and } pn + qm \neq 0[/tex]
(Note: I couldn't understand the provided answer choices, but the above answer is indeed correct (and the second equation can be ignored).)
WILL MARK BRAINIEST
Zach and Ginny are building model cars. Ginny's car is 2 more than 3 times the length of Zach's car. The sum of the lengths of both cars is 30 inches. Write an equation to determine the lengths of Zach's and Ginny's cars.
3x + 2 = 30
x + 2 + 3x = 30
2x + 3 = 30
x + 2x + 3 = 30
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Answer:
x + 2 + 3x = 30
Step-by-step explanation:
Both lengths are unknown, but Ginny's car length is described in terms of Zach's car length, so we choose a variable for Zach's car length.
Let x = Zach's car length.
Zach's car length is x.
"Ginny's car is 2 more than 3 times the length of Zach's car."
Ginny's car length is 2 + 3x.
Add the lengths:
x + 2 + 3x
"The sum of the lengths of both cars is 30 inches."
x + 2 + 3x = 30
Answer: x + 2 + 3x = 30
Subtraction with Real Numbers (I need the equation on how to solve the answer)
-3-(-8)=
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Answer:
5Step-by-step explanation:
Given:
- 3 - (- 8)Remember two subsequent negatives turn to positive:
- 3 + 8 = 8 - 3 = 5Answer:
5
Step-by-step explanation:
[tex] - 3 - ( - 8)[/tex]
Remove the parentheses:
[tex] - 3 + 8[/tex]
= 5
4q verbal expression
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Answer:
sum of two terms. So, the verbal expression 15 plus r can be used to describe the algebraic expression 15 + r
Step-by-step explanation:
Answer this problem…..
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Answer:
[tex]-13\frac{5}{7} x[/tex] or [tex]-\frac{96x}{7}[/tex]
Step-by-step explanation:
What is 6(x-6)+12=6(x+1)-3x show your work.
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determine the area of the triangular ABC with AC =5cm and height DB=30mm
Answers
Answer:
Step-by-step explanation:
AC² = AD² + DB ²
25 = AD² + 9
AD²= 25 - 9
AD² = 16
AD = 4
Area = 4*3 /2
= 6cm
You withdraw $40 each month from your savings account. what integer represents the change in your balance after 4 months?
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Answer:
The balance would be $160 from whatever it was before the 4 months.
Step-by-step explanation:
Since the bank balance is being added by 40 for each month for 4 months, 4 * 40 is just 4*4 with an extra zero on the end. so that would be $160.
So if the balance before was $40, then the new balance after 4 months would be $200.
If there's no money previously, then there is now $160 after 4 months.
If there's a value before the $40 for 4 months, let me know and I will explain and tell you what it is.
Julie is arranging pictures in a photo album one time she arranges them into six on each page she rearrange them with eight on each page what is the least number of photos Julie could have put in her album
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Answer:
Step-by-step explanation:
Point B is the midpoint of AC. AB=3x and AC=5x+21 . What is the value of AB?
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First, let's write down what we know.
AB = 3x
AC = 5x+21
Since B is the midpoint, AB is half the length of AC. The sum of AB + AB is equal to the length of AC.
AB + AB = AC
Let's plug in our values.
3x + 3x = 5x + 21
Simplify the left side.
6x = 5x + 21
Subtract 5x from both sides.
x = 21
Now, let's plug in 21 for x in AB
AB = 3x = 3(21) = 63
Equation : 12v + 10v + 14 = 80
What is v equaled to?
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Answer:
this can be simplified
12v + 10v + 14 = 80
22v + 14 = 80
22v = 66
v = 3
Answer:
v = 3
Step-by-step explanation:
12v + 10v = 22v
22v + 14 = 80
Subtract 14 from both sides.
80 - 14 = 66
22v = 66
now divide both sides by 22
66/22 = 3
v = 3
If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you know that
it is a type of active transport.
it is a type of passive transport.
it could be active or passive transport.
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- option A
If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you know that
it is a type of active transport.
What do pinocytosis and phagocytosis have in common?
They are both forms of endocytosis.
Help me on this math questionnn
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On Tuesday, Jessica paid $14.12 each on two tickets to a movie theater. Popcorn was
$3.98, but Jessica didn't buy any. She also borrowed a movie for $5.93. Jessica paid
with two $20 bills. How much change did Jessica get?
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Answer:
14.12 × 2 + 5.93 = 34.17
40$ - 34.17 = 5.83$
Answer:
$14.12+$14.12=$28.24+$5.93=$34.17
Change is $6.83
A, B and E are non-collinear O True O False
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Answer:
it would be false
Step-by-step explanation:
Part E
Now check your work by using the GeoGebra geometry tool to repeat parts A through D. Open GeoGebra, and complete each step below. If you need help, follow these instructions for using GeoGebra. You will take a screenshot of your work when you are through, so be sure to clearly label your construction as you work.
Plot points A, B, and C, and draw a polygon, ΔABC, through the points.
Draw a line perpendicular to AC¯ through point B.
Label the intersection of the line perpendicular to AC¯ through B and AC↔ point D.
Measure and display the slopes of AC↔ and BD↔.
Display the equations of AC↔ and BD↔ in the Algebra margin.
Measure and display the lengths of AC¯ and BD¯.
Calculate and display the area of ΔABC.
Take a screenshot showing the geometric construction and the Algebra margin, save it, and insert the image in the space below.
Part F
Compare the calculations displayed in GeoGebra with the calculations you completed in parts A through D. Look in the Algebra margin too. Do the results in GeoGebra match the results you obtained earlier? If not, where do the discrepancies occur? You might have to rearrange equations algebraically to determine whether two equations match.
Part G
You’ve seen two methods for finding the area of ΔABC—using coordinate algebra (by hand) and using geometry software. How are the two methods similar? How are they different? Why might coordinate algebra be important in making and using geometry software?
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Answer:Hopefully this is how you do it sorry if i am wrong
Step-by-step explanation:
P, Q, V, and K are collinear with V between K and P, and Q between V and K. If VP = 14x + 4, PK = x + 630, VQ = 17x + 6, and KQ = 11x + 5, solve for VP.
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If the points P, Q, V and K are collinear, they will follow the segment addition postulate.
Measure of segment VP will be 214 units.
It's given in the question,
P, Q, V and K are collinear.VP = 14x + 4PK = x + 630VQ = 17x + 6KQ = 11x + 5By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x = [tex]\frac{615}{41}[/tex]
x = 15
Therefore, measure of VP = (14x + 4)
= 14(15) + 4
= 214 units
Measure of segment VP will be 214 units.
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