Answer:
B. -infinity < x < infinity
Step-by-step explanation:
Since it's linear and kind of horizontal, it stretches to infinity on both sides (indicated by arrows on both sides of the line.
the cost of 1 kg tomato is RS . 75.Find the cost of 14 kg
Answer:
Cost of 1kg tomato=rs.75
Cost of 14kg tomato=(75×14)
rs.1050
If x + 1 =3, then x=
Answer:
x = 2
Step-by-step explanation:
x + 1 = 3
transpose
x = 3-1
x= 2
The temperature in Buffalo, New York, was -2 °F one day. This was 42 degrees warmer than the temperature in Nome, Alaska, on the same day. Find the temperature in Nome. Justify your answer by writing and solving an equation. pls I'll make the first to answer with equation get brainlyest
The temperature in Buffalo, New York, was -2 °F one day. This was 42 degrees warmer than the temperature in Nome, Alaska, on the same day. Find the temperature in Nome. Justify your answer by writing and solving an equation
Answer:
40
Step-by-step explanation:
urgent !!!! HELP NEEDED
Answer:
[tex]352\ yd^2[/tex]
Step-by-step explanation:
1. Approach
The surface area of a three-dimensional figure is the two-dimensional space around the figure. Simply put, if one was going to wrap the figure up in paper, the surface area is the amount of paper one would need to wrap the entirety of the figure. One can find the surface area of a figure by finding the area of each individual facet of the figure and then adding up the areas.
2. Finding the area of the triangular faces
The formula to find the area of a triangle is the following:
[tex]A_t=\frac{b*h}{2}[/tex]
Where (b) is the base of the figure, and (h) is the figure's height. Since there is only one type of triangular face, one only has to find the area of one triangular face and then multiply its measurement by four.
Triangle 1
[tex]A_t=\frac{b*h}{2}[/tex]
[tex]A_t=\frac{11*10.5}{2}[/tex]
[tex]A_1=\frac{115.5}{2}[/tex]
[tex]A_t=57.75[/tex]
3. Finding the area of the quadrilateral
The following formula can be used to find the area of a quadrilateral:
[tex]A_q=b*h[/tex]
Substitute the dimensions of the quadrilateral in and solve for its area:
[tex]A_q=b*h[/tex]
[tex]A_q=11*11[/tex]
[tex]A_q=121[/tex]
4. Find the total surface area of the figure
To find the total surface area of the figure, add up all of the area values of its faces. Remember the area of the triangular face is multiplied by four because there are four triangular faces.
[tex]4(A_t)+(A_q)=A[/tex]
[tex]4(57.75)+121=A[/tex]
[tex]231+121=A[/tex]
[tex]352=A[/tex]
A trader sold 90 oranges at 3 for GHC 0.75.
How much did she get from selling all the
oranges?
Answer:
GHC22.5
Step-by-step explanation:
90/3=30
30=0.75
30×0.75
=22.5
6x — Зу = 5
y - 2x = 8
How many solutions does the system have?
9514 1404 393
Answer:
none
Step-by-step explanation:
Multiplying the second equation by -3 gives ...
6x -3y = -24
Values of x and y that satisfy this equation cannot also satisfy the first equation ...
6x -3y = 5
There are no solutions to this system of equations.
__
The equations describe parallel lines. There is no point of intersection.
a recent survey shows that 66% of college students have a cat and 37% have a HBO subscription. Assuming these two events are independent, what is the probability that a randomly selected student has neither a cat nor HBO
Answer:
[tex]P(C'\ and\ H') =0. 2178[/tex]
Step-by-step explanation:
Let
[tex]C \to[/tex] Student with cat
[tex]H \to[/tex] Student has HBO sub
[tex]P(C) = 66\% \\ P(H) = 37\%[/tex]
Required
[tex]P(C'\ and\ H')[/tex]
This is calculated as:
[tex]P(C'\ and\ H') = P(C') * P(H')[/tex]
Using complement rules, we have:
[tex]P(C'\ and\ H') = [1 - P(C)] * [1 - P(H)][/tex]
So, we have:
[tex]P(C'\ and\ H') = [1 - 66\%] * [1 - 37\%][/tex]
[tex]P(C'\ and\ H') = [33\%] * [66\%][/tex]
[tex]P(C'\ and\ H') =0. 2178[/tex]
round to the nearest Ten-thousand: 849,708
Answer:
850,000
Step-by-step explanation:
Answer: 850,000
Concept:
Here, we need to know the order and name of each place value.
Please refer to the attachment below for the specified names.
Solve:
8 = Hundred thousands
4 = Ten thousands
9 = One thousands
7 = Hundreds
0 = Tens
9 = Ones
Since the values before the ten thousands place, which would be the one thousands place, is greater than 5, then we should round up.
Therefore, the rounded value would be [tex]\boxed{850,000}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
How to divide using area model
Answer:
In mathematics, an area model is a rectangular diagram or model used for multiplication and division problems, in which the or the and define the length and width of the rectangle.
We can break one large of the rectangle into several smaller boxes, using number bonds, to make the calculation easier. Then we add to get the area of the whole, which is the or quotient.
To multiply two 2-digit numbers, using the area model, follow the given steps:
Write the multiplicands in expanded form as tens and ones.
For example, 27 as 20 and 7, and 35 as 30 and 5.
Draw a 2 × 2 grid, that is, a box with 2 rows and 2 columns.
Write the terms of one of the multiplicands on the top of the grid (box). One on the top of each cell.
On the left of the grid, write the terms of the other multiplicand. One on the side of each cell.
Write the product of the number on the tens in the first cell. Then write the product of the tens and ones in the second and third cell. Write the product of the ones in the fourth cell.
write the product in the cell
Finally, add all the partial products to get the final product.
Here, for example, the area model has been used to multiply 27 and 35.
area model multiplication
Let us see how to find the product of 3-digit number by a 2-digit number using the area model.
Find the Product using Area Model
Let us now use the area model for the division. Here, we divide 825 by 5.
Area Model Division 1
Area Model Division 2
Fun Facts
The area model is also known as the box model.
The area model of solving multiplication and division problems is derived from the concept of finding the area of a rectangle. Area of a rectangle = Length × Width.
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The number 42 has the prime factorization 2.3.7. Thus 42 can be written in four ways as a product of two positive integer factors (without regard to the order of the factors):
1.42, 2 · 21,3 · 14, and 6. 7.
Required:
List the distinct ways the number 770 can be written as a product of two positive integer factors.
Answer:
Step-by-step explanation:
770 = 2*5*7*11
So they are:
2*385
10*77
5*154
7*110
14*55
11*70
22*35
Apply Simpson's rule to approximate the value of integration 1 to 4 e^x In x dx with n = 3.
[tex]Here, h=41,0.25,y=1+x21
[/tex]
[tex]x y101.020.25 0.9413 0.250.94140.750.64510.5
[/tex]
[tex]By Simpson's Rule:
[/tex]
[tex]∫011+x2dx=4×31
[/tex]
[tex][(1+0.5)+4(0.941+0.941+0.64)+2(0.8)]
[/tex]
[tex]=121[9.424]=0.785
[/tex]
y=0.0111x+2.7617 what is the x axis
Step-by-step explanation:
here's the answer to your question
Estimate the product of 0.235 and 13.467 to the nearest hundredth. Round each value to the nearest hundredth before multiplying. Your final answer should also be rounded to the nearest hundredth.
Answer:
0.235 = 0.24
13.467 = 13.47
0.24+13.47=13.71
Help on 3,5,7,9,11,13.15,17, please thank you
Answer:
3. 6a+60
5. 25+5w
7. 90-10t
11. 4.5-12c
13. f-2
15. 12z+1.5
Step-by-step explanation:
3.
6(a+10)
Multiply 6 by both factors in the parentheses, in this case, a and 10.
6*a = 6a
6*10 = 60
6(a+10) = 6a + 60
I only put the step- by- step explanation for #3, but you should be able to figure the rest out with that.
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Consider the equation below.
[tex]3x^{3x-2}=81[/tex]
To solve the given exponential equation, solve the linear equation [tex]3x-2=[/tex]
Answer:
[tex]ıf \: {3x}^{3x - 2} = 81[/tex]
Step-by-step explanation:
use logarithmic function
[tex] log_{3x}(81) = 3x - 2[/tex]
Answer:
4 and x=2
Step-by-step explanation:
:}
There are 5 members on a board of directors. If they must elect a chairperson, a secretary, and a treasurer, how many different slates of candidates are possible?
Answer:
60
Step-by-step explanation:
To begin, we can look at combinations and permutations. A permutation or combination is when we need to find how many possibilities there are to choose a certain amount of objects (in this case, candidates) given an array of options (members on the board)
Combinations are when the order doesn't matter, and permutations are when the order does matter. Here, we know that we care whether someone is chairperson or secretary. If we were to just choose three for an "elite" board, and there were no specific positions in the board, then order would not matter. However, because it does matter which person gets which role, order does matter.
Assuming that someone cannot have more than one role, we know that this is a permutation without repetition. The formula for this is
(n!) / (n-r)!, where we have to choose from n number of people and choose r number of people. We have 5 members to choose from, and 3 people to choose, making our equation
(5!) / (5-3)! = 120 / 2! = 120/2 = 60
Find the area of the figure to the nearest tenth?
Am I right?
Describe and correct the error in determining the formula for the sequence below
Answer:An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.
Step-by-step explanation:
A particle is moving such that its height h at time t is given by h(t) = 2 + 8t - 3t^2 + 1/5t^3. The average velocity of the particle on the period [0,3] is
[tex]\\ \Large\sf\longmapsto h(t)[/tex]
[tex]\\ \Large\sf\longmapsto 2+8t-3t^2+\dfrac{1}{5}t^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+8(3)-3(3)^2+\dfrac{1}{5}(3)^3[/tex]
[tex]\\ \Large\sf\longmapsto 2+24-3(9)+\dfrac{27}{5}[/tex]
[tex]\\ \Large\sf\longmapsto 26-27+5.4[/tex]
[tex]\\ \Large\sf\longmapsto -2+5.4[/tex]
[tex]\\ \Large\sf\longmapsto h(t)=3.4m[/tex]
Which choices are equivalent to the quotient below? Check All That Apply.
Answer:
Option C. √5/3
Step-by-step explanation:
We'll begin by simplifying √15 / 3√3. This can be obtained as follow:
√15 / 3√3
Rationalise
√15 / 3√3 × (√3 /√3)
(√15 × √3) / (3√3 × √3)
√45 / (3 × 3)
√45 / 9
Recall:
√45 = √(9 × 5) = √9 × √5 = 3√5
Thus,
√45 / 9 = 3√5 / 9
√45 / 9 = √5 / 3
Therefore,
√15 / 3√3 = √5 / 3
Thus, option C gives the right answer to the question.
find the missing length indicated
Answer:
192
Step-by-step explanation:
geometric mean theorem :
with p and q being the segments of the Hypotenuse, then
h = x = sqrt(p×q)
p = 144
q = 400-144 = 256
h = x = sqrt(144×256) = 12×16 = 192
in alska the colderst temprauter ever recorded is -80 that is much colder than in hawil where the coldest temperature is 15
Answer: What are we supposed to do ???
You are enrolling swimmers in a study on lung capacity. You want 25% of your sample to be those who compete at 100m or less distances and 50% to be swimmers who compete at 100m-500m distances and 25% to be swimmers who compete at >500m distances. You begin enrolling for your study at 5am at the pool. By 9 AM you have all of your 100-500m swimmers enrolled, and all of your >500m swimmers enrolled. This is an example of what type of sampling method
Answer:
Stratified sampling
Step-by-step explanation:
Samples may be classified as:
Convenient: Sample drawn from a conveniently available pool.
Random: Basically, put all the options into a hat and drawn some of them.
Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.
Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.
Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.
In this question:
People divided by groups, for each group(<100, >100<500, >500), a number(not all) is selected, so stratified sampling.
Complete the statement below. A Type II Error is made... Choose the correct answer below. A. A Type II Error is made when there's not enough evidence to reject the null hypothesis and the null hypothesis is true. B. A Type II Error is made when there's evidence to reject the null hypothesis, but the null hypothesis is true. C. A Type II Error is made when there's not enough evidence to reject the null hypothesis, but the null hypothesis is not true. D. A Type II Error is made anytime we do not reject the null hypothesis.
The principle
P=6000 A=6810 T=3 years
Answer:
incomplete question
Step-by-step explanation:
that is what is wrong with your question
Answer:
r = 4.3%
Step-by-step explanation:
6810= 6000(x)^3
6810/6000= (x)^3
x = 1.043114431
r = 043114431
Find the missing side. Round your answer to the nearest tenth please help me
9514 1404 393
Answer:
16.9
Step-by-step explanation:
The marked sides are the hypotenuse and the one opposite the angle. The relevant trig function is ...
Sin = Opposite/Hypotenuse
Multiplying by the hypotenuse gives an equation for the opposite side.
x = 22·sin(50°)
x ≈ 16.9
(d) (8x2 + 7y2 – z2 + 2yz + 3xz – 5xy) * (2x – 3y) vertical method
Answer:
(8x²+7y²–z²+2yz+3xz–5xy) × ( 2x–3y)
= (16x³+14xy²–2z²x+4yzx+6x²z–10x²y –24yx²–21y³+3z²y–6y²z–9xzy+15xy²)
=( 16x³+29xy²–2z²x–5xyz+6x²z–34x²y–21y³+3z²y–6y²z)
[tex] = 16 {x}^{3} - 21 {y}^{3} - 2 {z}^{2}x + 3 {z}^{2} y - 5xyz - 6 {y}^{2} z + 6 {x}^{2} z - 34 {x}^{2} y+ 29x {y}^{2} [/tex]
I hope I helped you^_^
Write a quadratic equation with integer coefficients having the given numbers as solutions.
9514 1404 393
Answer:
x² -22 = 0
Step-by-step explanation:
The roots are opposites, so the equation is pretty simple.
x = ±√22
x² = 22 . . . . . square both sides
x² -22 = 0 . . . . your quadratic equation in standard form
Convert 2546 in base 10 to base 5
Answer:
40141
Step-by-step explanation:
A construction crane lifts a bucket of sand originally weighing 145 lbs at a constant rate. Sand is lost from the bucket at a constant rate of .5lbs/ft. How much work is done in lifting the sand 80ft?
Answer: [tex]10,000\ lb.ft[/tex]
Step-by-step explanation:
Given
Initial weight of the bucket is [tex]145\ lb[/tex]
It is lifted at constant rate and rate of sand escaping is [tex]0.5\ lb/ft[/tex]
At any height weight of the sand is [tex]w(h)=145-0.5h[/tex]
Work done is given by the product of applied force and displacement or the area under weight-displacement graph
from the figure area is given by
[tex]\Rightarrow W=\int_{0}^{80}\left ( 145-0.5h \right )dh\\\\\Rightarrow W=\left | 145h-\dfrac{0.5h^2}{2} \right |_0^{80}\\\\\Rightarrow W=\left [ 145\times 80-\dfrac{0.5(80))^2}{2} \right ]-0\\\\\Rightarrow W=11,600-1600\\\\\Rightarrow W=10,000\ lb.ft[/tex]