PLEASE HELP QUICK!!! How many molecules are there in 4.00 L of
glucose, C6H1206? Please show your work!!
Answers
So mass= 4000g
Molar mass of Glucose= 180 g/mol
As Number of molecules= mass/molar mass x Avogadro’s no.
Number of molecules= 4000/180 x 6.022 x 10^23
Number of molecules = 1.3 x 10^25 molecules
Molar mass of NO2= 46
Number of molecules = 14/46 x 6.022 x 10^23
Number of molecules= 1.8 x 10^23 molecules
Related Questions
1.Which of the following forms only Ionic Bond?
1)Ca 2)C 3)Si 4)P
2.How many atoms of Na are present in 92 a.m.u of it?
a)4 b)5 c)6 d)7
Answers
The Answer is A)4 atoms of NA are present in 92 a.m.u
What is the pressure in atm exerted by 1.8 g of H2 gas exert in a 4.3 L balloon at 27ºC? R = 0.821(L*atm) / (mol*K)
Answers
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The pressure in atm exerted by 1.8 g of H₂ gas exert in a 4.3 L balloon at 27ºC is 5.12 atm
What is Ideal gas law ?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Let's convert grams to moles (via molar mass).
Molar Mass (H₂) : 2 (1.008 g/mol)
Molar Mass (H₂) : 2.016 g/mol
1.8 grams H₂ 1 mole
---------------------- x ---------------------- = 0.893 moles H₂
2.016 grams
The Ideal Gas Law equation looks like this:
PV = nRT
In this equation,
P = pressure (atm) V = volume (L) n = moles R = Ideal Gas Constant (0.0821 L*atm/mol*K)T = temperature (K)After converting Celsius to Kelvin, you can put the given values into the equation and simplify to find the pressure.
P = ? atm R = 0.0821 L*atm/mol*K
V = 4.3 L T = 27 °C + 273.15 = 300.15 K
n = 0.893 moles
PV = nRT
P (4.3 L) = (0.893 moles) (0.0821 L*atm/mol*K)( 300.15 K)
P (4.3 L) = 22.0021
P = 5.12 atm
Therefore, The pressure in atm exerted by 1.8 g of H₂ gas exert in a 4.3 L balloon at 27ºC is 5.12 atm
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How is a slump different from creep?
Answers
Answer:
Is this chemistry or ELA!
. De las siguientes soluciones:
1. 20 ml de alcohol etílico mezcladas con 80 ml de agua.
2. 500 ml de agua con 20 g de sal disueltas (V Sln: 500ml).
3. 80 g de sal en 2 litros de agua.
a) Identifica el soluto y solvente de cada solución y explica ¿por qué?
b) Encuentra la concentración por peso de la solución número 3 c) Entre la disolución 2 y 3 ¿Cuál presenta mayor concentración?
por favor lo necesito para hoy ¡gracias!
Answers
Answer:
can u translate this to English? I might be able to help
a) Solution 1: Solute is ethyl alcohol, solvent is water. Solution 2 and 3: Solute is salt, solvent is water.
b) Concentration by weight of solution 3: Approximately 3.85%.
c) Solution 3 has a higher concentration than solution 2.
a) Solutions and their solutes and solvents:
Solution 1: The solute is ethyl alcohol, and the solvent is water. This is because ethyl alcohol is the substance that dissolves in water to form the solution.
Solution 2: The solute is salt, and the solvent is water. Salt is the substance that dissolves in water to form the solution.
Solution 3: The solute is salt, and the solvent is water. Similar to solution 2, salt is the substance that dissolves in water to form the solution.
b) Weight concentration of solution number 3:
The weight concentration is calculated by dividing the mass of the solute (80 g of salt) by the total mass of the solution (80 g of salt + 2000 g of water):
Weight concentration = (80 g / 2080 g) * 100% ≈ 3.85%
c) Comparison of concentrations between solution 2 and 3:
Solution number 3 has a higher concentration than solution 2, as the weight concentration of solution 3 is approximately 3.85%, while the exact amount of water is not provided for solution 2 to calculate its concentration. However, solution 2 contains only 20 g of salt dissolved in 500 ml of water, which implies that the concentration will be lower than solution 3. Therefore, solution number 3 has a higher concentration compared to solution 2.
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How much water will the measuring cup have if you poured 1/2 of it out?
Answers
In Rutherford experiment some alpha particles fired at a gold foil bounced backward as a result of ... A.reflection from the surfaces of gold atoms B.electrostatic repulsion by gold nuclei C.electrostatic repulsion by electronsD.all of the aboveE.none of the above
Answers
Answer:
B.electrostatic repulsion by gold nuclei
Explanation:
According to Rutherford's experiment, a thin gold foil was bombarded with alpha particles. Some of the particles passed through the foil undeviated, some were scattered through large angles while some bounced backwards.
It follows that the particles that bounced backwards must have encountered a massive particle of like charge.
The atom is composed of a nucleus which contains positively charged particles. Some of the alpha particles which are positively charged particles bounced back when they encountered the positively charged particles in the nucleus.
Answer: The correct option is B (electrostatic repulsion by gold nuclei).
Explanation:
In the Rutherford's experiment, he used positively charged particles called alpha particles to bombard an atom in order to find out what is inside the atom. Together with two other scientists, Geiger and Marsden, they used a narrow beam of alpha particles emitted from a radioactive source to bombard a thin gold foil. The scattering of the particles from the gold foil was detected by a movable zinc sulphide screen which could be rotated to various positions around the foil.
Each time an alpha particle hit the screen, a visible flash of light or scintillation was produced. This was observed by a microscope attached to the screen. It was then observed that some of the particles followed a straight path through the gold foil while a few where scattered in a backward direction. This was as a result of electrostatic repulsion by gold nuclei which occurs due to the greater part of the mass of the atom was concentrated in a minute nucleus with positive charge.
the text of oxygen gas in the laboratory
Answers
Explanation:in testing for oxygen a glowing splint is used.
the glowing splint is brought in the presence of the test tube containing the gas
the glowing splint rekindles or lights up showing that oxygen is present.
this is a positive test because oxygen supports burning or combustion
difference between Nitrogen 1 oxide and Oxygen
Answers
Answer:
one atom of oxygen is not equal to oxygen
please help with the attached picture question 21, 22, 23
Answers
Explanation:
21. The given molecule for cracking is tetradecane.
On cracking it forms one mole of decane (C10H22) and two moles of ethene gas.
The chemical equation is shown below:
[tex]C_1_4H_3_0->C_1_0H_2_2+2C_2H_4[/tex]
22. The essential condition for the formation of an ester is the reaction of alcohol and acid in presence of concentrated sulfuric acid.
Thus among the given options, the first option is the correct one.
23. Isomers of butanol are shown below:
It is 2-butanol.
The position of -OH group changes to the second carbon.
The world is made up of
Answers
Answer:
Explanation:
The world is made up of living beings .
help me please I will mark as brainliest for the first correct answer
Answers
Answer:
1. 3-methylpentane
2. 2-bromo-3-chloropentane
3. 2,2,4-trimethylpentane
Explanation:
1. CH3CH2CH(CH3)CH2CH3.
Methyl group is in the third carbon atom in the long chain. The organic compound has five(5) carbon atoms thus it is named as pentane.
Therefore the name of the compound is
3-methylpentane
2. CH3CH(Br)CH(Cl)CH2CH3
The compound has Chlorine and Bromine in the carbon chain. Chlorine is given as chloro-, Bromine is given as bromo, depending on the position in the carbon chain. Bromine is located in 2 carbon atom and chlorine is in third(3) carbon atom in the long chain. The long chain has five carbon atoms thus pentane.
Naming of the compound we begin with the on lowest in the alphabet. The name of the organic compound is therefore;
2-bromo-3-chloropentane
3. CH3CH(CH3)3CH(CH3)CH2CH3
In this long chained organic compound, methyl-group is found in 2,2 and 4th positions. Since this is still pentane, naming the organic compounds, we start with the one with the lowest carbon. Therefore this becomes;
2,2,4-trimethylpentane
I hope this helps you to know how to name the organic compounds.
write any two conditions at which a body of certain mass weightless
Answers
Answer:
A body becomes weightless in a zero-gravity scenario and when a force is applied to a body that is equal and opposite to the force of gravity. If the body is falling only under the influence of gravity.
Answer:
A body becomes weightless in a zero-gravity scenario and when a force is applied to a body that is equal and opposite to the force of gravity.If the body is falling only under the influence of gravity.
In the figure a cyclist moves A to B and then to C.he could also go through the shortest path AC. Depending on this fact solve the following questions: Find the length of AC .Find the displacement and total distance covered.
Answers
Answer:
hope it helps you see the attachment for further information
Describe weighted average
Answers
Answer:
Explained below
Explanation:
In simple average, we just add all the given data variables and divide it by the number of data given.
However, when it comes to weighted average, what we do is that we multiply each given variable by their weights and then divide the sum of that by the sum of the weights.
Thus, if the variables are denoted by x and their weights are denoted by y, then we have;
Weighted average = Σ(xy)/Σy
What is the mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water?
Answers
The mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water is 29.7%.
What is mass percent ?Mass percent is a means to describe a component in a specific combination or to convey a concentration. The mass percentage used to describe the solution composition indicates the mass of solute contained in a given mass of solution.
To determine the mass percent of an element in a compound, we divide the mass of the element in one mole of the compound by the compound's molar mass and multiply the result by 100.
Given:
Number of moles = 0.64 moles
Moles of sodium fluoride = Given mass/molar mass
0.64 moles = Mass / 42
Mass = 26.88gram
Mass % = Mass of solute/ mass of solution × 100
= 26.88/90.48 × 100
= 29.7 %
Thus, 29.7 % is the mass percent of a sodium fluoride solution prepared by dissolving 0.64 moles of sodium fluoride into 63.5 grams of water
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mention two factors which affect pressure due to liquid contained in a vessel
Answers
Answer:
depth of the liquid and nature of liquid affects the pressure due to liquid contained in a vessel
Answer:
Two factors influence the pressure of fluids. They are the depth of the fluid and its density. A fluid exerts more pressure at greater depths
Which among the following mixtures will show tyndal effect?
i) copper sulphate solution
ii) sand in water.
iii) milk.
iv) starch solution
Answers
Answer:
milk and starch solution are the colloids, hence these will show the tyndall effect
Answer:
milk and starch solution
Explanation:
Tyndall effect is shown by colloidal solutions. It is not shown by true solutions or suspensions.
Milk and starch solution are colloidal solutions. They show tyndall effect. On the other hand, common salt and copper sulphate solution are true solutions. They do not show tyndall effect.
High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to
purify chemical substances. The pressures used in this procedure range from around 500
kilopascals (500,000 Pa) to about 60,000 kPa (60,000,000 Pa). It is often convenient to know
the pressure in torr. If an HPLC procedure is running at a pressure of 3.20x10^8 Pa , what is its
running pressure in torr?
Express the pressure numerically in torr.
►
3.20 x 10^8 Pa = _____ torr
Answers
Answer:
2,400,000 torr (3 s.f.)
Explanation:
Convert the pressure from Pascal to atm first:
[tex]\boxed{1 \: atm = 101325 \:Pa }[/tex]
3.20 ×10⁸ Pa
= [(3.20 ×10⁸) ÷101325] atm
= 3158.2 atm (5 s.f.)
Convert atm to torr:
[tex]\boxed{1 \: atm = 760 \: torr}[/tex]
3158.2 atm
= (3158.2 ×760) torr
= 2400000 torr (3 s.f.)
Select the structure corresponding to trans-3-octene.
Answers
Answer: B
Explanation:
Answer:
The Correct Answer Is B.
How the amount of acid rain caused by the burning of fossil fuels can be reduced ?
Answers
Answer:
The amount of acid rain caused by the burning of fossil fuels can be reduced by creating nitrogen oxides in the process of burning coal and other fossil fuels, some power plants are changing the way they burn coal. A great way to reduce acid rain is to produce energy without using fossil fuels. Instead, people can use renewable energy sources, such as solar and wind power.
its not a question but i wanted to tell you guys that if you guyz like my answers then please don't forget to give like and follow at the same time. I am not forcing you to follow only if you guyz like my answer then like or follow. THANKS FOR READING..
Answers
Answer:
thank you for this oibnki
Answer:
Sure I'll go ahead and like your answers and follow you if that's what you wanted! :)
Explanation:
How many liters of carbon dioxide can be “scrubbed”, or removed, with 3.45 Liters of 0.10 M of lithium hydroxide solution?
Answers
Answer:
The correct answer is - 3.864 L of CO2.
Explanation:
In a chemical equation, the symbol that means "dissolved in water" is _____. (s) (l) (aq) (g)
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Specific heat capacity is _____.
greater for metal than for wood
the amount of heat required to raise the temperature of 1g of a substance 1 oC
represented by the symbol, Q
all of these
Answers
Answer:
all of this
Explanation:
A sample of gas has a volume of 20 cm³.The pressure is changed to 90 kPa at constant temperature,while the volume increases to 75 cm³.What was the original pressure of the gas?
Answers
Answer:
337.5kPa ~ 338kPa
Explanation:
Using the ideal gas law PV=nRT we have the following definitions from the problem:
V(initial) = 20cm³
P(initial) = ?kPa
V(final) = 75cm³
P(final) = 90kPa
Since we know that the number of moles of the sample did not change, nor did the temperature, nor does the ideal gas constant (R) we can rewrite this equation to state:
P(initial)V(initial) = nRT =P(final)V(final) ~ P(initial)V(initial) = P(final)V(final)
Rearranging this equation as we are solving for the initial pressure we find that:
P(initial) = (P(final)V(final))/V(initial)
P(initial) = ((90kPa)(75cm³))/20cm³
P(initial) = 337.5kPa ~ 338kPA
Cho các dung dịch: Glucozơ, glixerol, fomanđehit, etanol. Có thể dùng thuốc thử nào sau đây để phân biệt được cả 4 dung dịch trên?
A. Cu(OH)2; B. Dung dịch AgNO3 trong NH3;
C. Na kim loại; D. Nước brom.
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Answers
Answer:
chắc là câu B í
Explanation:
what do you mean by 1 joule work
Answers
Answer:
Joule is the SI unit of work. 1 Joule is amount of work done when a force of 1 Newton displaces a body through a distance of 1m in the direction of the force applied.
Can you help me on this. I will support your correct answer
Answers
Zinc+ sulphuric acid= Zinc sulphate
Magnesium chloride, Magnesium nitrate, magnesium sulphate
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Re-word this statement: Ionic Radii are changing as you move down the column because the atoms in lower rows have more energy levels, which makes the valence electrons farther from the nucleus, so it takes less energy for them to be pulled away.
The Ionic radii are changing as you move across a row because each element has one more proton, which increases the attraction of the nucleus.
Answers
Answer:
ty po hehe
Explanation:
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Answer the following questions based on the above graph(Electron affinity vs Atomic no.)
i)Why on moving from Li to Be, the value of electron gain enthalpy drops.
ii)Cl has a higher peak than fluorine. Explain.
iii)Why Fluorine has the highest value among its period members.
Answers
i) Be has a fully filled 2s level.
ii) This is because chlorine is larger than fluorine.
iii) Fluorine needs only one electron to attain the octet configuration.
Electron affinity is the ability of an electron to accept gaseous electrons to yield gaseous ions with a negative charge.
Electron affinity depends on the size of an atom. Larger atoms have a higher electron affinity because they are better able to accept electrons.
The drop between Li and Be is because the 2s orbital in Be is already fully filled while Li has incompletely filled 2s level. electrons do not easily go into the higher energy 2p level.
The higher peak of chlorine is because chlorine is larger than fluorine hence the electron affinity of fluorine is less than that of chlorine. The smaller the ion the lesser the electron affinity.
Fluorine has the highest electron affinity in period 2 because it needs only one electron to attain the octet structure.
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