Please help solve ASAP!!!

Answer:

  y = -7x +8

Step-by-step explanation:

The slope-intercept form of the equation of a line is ...

  y = mx +b

where m represents the slope, and b represents the y-intercept. The y-intercept is the value of y when x=0. Here, you have m=-7 and b=8. Your equation is ...

  y = -7x +8

Answer:

~ x = 12 centimeters of the route on map ~

Step-by-step explanation:

Let us plan out our steps, and solve for each:

1. We can see that we have to determine the cm of the route on the map, so let us convert the 1.8 kilometers ⇒ centimeters:

1.8 km = 180,000 cm

2. Given the information, let us create a proportionality as such:

      1       =           15,000      ⇒   x - centimeters of the route on the map

      x                   180,000

3. Now let us cross multiply, and solve through simple algebra for x:

15,000 * x = 180,000,

x = 12 centimeters of the route on map

Did you ever figure this out. I need the answer for a test.

Answer:

Jumbo burger with fried is 75%

chicken with salad is 65%

Step-by-step explanation:

you first split the burger and sides. You add up the sides to find the salad. Then add up the sides and burgers

Answer:

What is the probability that he order a Jumbo Burger with Regular Fries or a Chicken Sandwich with a Salad? Make an area or tree diagram to help with the problem.

Answer to question: 20% for Jumbo Burger with Regular Fries and 10.5% for Chicken Sandwich with a Salad.

Step-by-step explanation:

You are going to find the probability that he order a Jumbo Burger with Regular Fries or a Chicken Sandwhich with a Salad by using a area model or a tree diagram. Although you ddin't ask me to solve it, I'm gonna help you with it anyways.

Sandwhiches:

50% - Jumbo Burger (JB)

30% - Chicken Sandwich (CS)

20% - Regular Burger (RB)

Sides:

40% - Curly Fries (CF)

35% - Salad (S)

25% - Regular Fries (RF)

Acronyms

Jumbo Burger (JB) + Curly Fries (CF) = JBCF

Jumbo Burger (JB) + Salad (S) = JBS

Jumbo Burger (JB) + Regular Fries (RF) = JBRF

Chicken Sandwich (CS) + Curly Fries (CF) = CSCF

Chicken Sandwich (CS) + Salad (S) = CSS

Chicken Sandwich (CS) + Regular Fries (RF) = CSRF

Regular Burger (RB) + Curly Fries (CF) = RBCF

Regular Burger (RB) + Salad (S) = RBS

Regular Burger (RB) + Regular Fries (RF) = RBRF

Probability of combinations:

JBCF = 0.5 x 0.4 = 0.20

JBS = 0.5 x 0.35 = 17.5

JBRF = 0.5 x 0.25 = 12.5

CSCF = 0.3 x 0.4 = 12

CSS = 0.3 x 0.35 = 10.5

CSRF = 0.3 x 0.25 = 7.5

RBCF = 0.2 x 0.4 = 8

RBS = 0.2 x 0.35 = 7

RBRF = 0.2 x 0.25 = 5

Your tree diagram should look something like this:

         CF(40%)- outcome - JBCF (20%)

          /  

(50%)JB ---  S(35%)-  outcome - JBS (17.5%)

           \            

           RF(25%)-  outcome - JBRF (12.5%)

         CF(40%)- outcome - CSCF (12%)

          /

(30%)CS ---  S(35%)- outcome - CSS (10.5%)

            \

            RF(25%)- outcome - CSRF (7.5%)

           CF(40%)- outcome - RBCF (8%)

           /

(20%)RB ---  S(35%)- outcome - RBS (7%)

          \

          RF(25%)- outcome - RBRF (5%)

Hope this helps because this took forever :D

Answer:

The mean will increase, after the outlier is removed.

Answer:

The equation is,

[tex]y = - \frac{4}{3}x - \frac{2}{3} [/tex]

Step-by-step explanation:

When a line is parallel to the other line, they will have the same gradient :

[tex]12x + 9y = 3[/tex]

[tex]9y = - 12x + 3[/tex]

[tex]y = - \frac{12}{9} x + \frac{3}{9} [/tex]

[tex]y = - \frac{4}{3} x + \frac{1}{3} [/tex]

We have already found the gradient. Next, we have to substitute the gradient and coordinates into the slope-form equation, y = mx + b :

[tex]y = mx + b[/tex]

Let m = -4/3,

Let x = -5,

Let y = 6,

[tex]6 = - \frac{ 4}{3} ( - 5) + b[/tex]

[tex]6 = \frac{20}{3} + b[/tex]

[tex]b = 6 - \frac{20}{3} [/tex]

[tex]b = - \frac{2}{3} [/tex]

Answer:

Step-by-step explanation:

total = 1 + 2 + 4 + 3 = 10

blue then blue = 2/10 * 2/10 = 1/5 * 1/5 = 1/25

green then red = 4/10 * 3/10 = 12/100 = 3/25

Answer:25 in^2

Step-by-step explanation:

d1=10 d2=5

area of rhombus=( d1 x d2)/2

Area of rhombus=(10x5)/2

area of rhombus=50/2

Area of rhombus=25 in^2

Answer:

(f - g)(x)= - 6 {x}^{2} - 8x + 9

(f - g)(-4!)= - 55

Step-by-step explanation:

[tex]f(x) = - 9 {x}^{2} - 2x, \: \: g(x) = - 3 {x}^{2} + 6x - 9 \\ (f - g)(x) = f(x) - g(x) \\ = - 9 {x}^{2} - 2x - (- 3 {x}^{2} + 6x - 9) \\ = - 9 {x}^{2} - 2x + 3 {x}^{2} - 6x + 9 \\ \purple{ \boxed{ \bold{(f - g)(x)= - 6 {x}^{2} - 8x + 9}}} \\ (f - g)( - 4)= - 6 {( -4 )}^{2} - 8( - 4) + 9 \\ = - 6 \times 16 + 32 + 9 \\ = - 96 + 41 \\ \red{ \boxed{ \bold{(f - g)( - 4)= - 55}}}[/tex]

Answer:

43.96

Step-by-step explanation:

ok so you use the formula: A= 3.14•r•2 next you plug in your values a=3.14•7•2 3.14•7= 28.98•2=43.96

Answer:

43.96

im dying on the question before that one it says "What issues are you having when it comes to area and circumference" you typed nothing really and here you are asking us whats the circles area lol

Step-by-step explanation:

Answer:

False

Step-by-step explanation:

Answer:

The probability that a club member picked randomly is female, given that the person prefers swimming on weekends, is 0.8 = 80%.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Prefers swimming on weekends.

Event B: Being female.

25% prefer swimming on weekends

This means that [tex]P(A) = 0.25[/tex]

It is found that 20% of the members in that city prefer swimming on weekends and are female

This means that [tex]P(A \cap B) = 0.2[/tex]

So

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2}{0.25} = 0.8[/tex]

The probability that a club member picked randomly is female, given that the person prefers swimming on weekends, is 0.8 = 80%.

Answer:

The value of the standardized test statistic for this significance test is -1.25.

Step-by-step explanation:

We are given that in a recent poll, 30 percent of adults said they wanted to "cut down or be free of gluten".

The researcher conducts a survey of a random sample of 25 students at her university and five of them say they want to at least reduce gluten.

Let p = population proportion of students wanting to reduce gluten at the university.

So, Null Hypothesis, [tex]H_0[/tex] : p = 30%      {means that the proportion wanting to reduce gluten at the university is the same as for all adults}

Alternate Hypothesis, [tex]H_A[/tex] : p < 30%     {means that a smaller proportion of students would say they want to reduce or be free of gluten}

The test statistics that would be used here One-sample z test for proportions;

                           T.S. =  [tex]\frac{\hat p-p}{\sqrt\frac{\hat p(1-\hat p)}{n} {} }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of students who would say they want to reduce or be free of gluten = [tex]\frac{5}{25}[/tex] = 0.20

            n = sample of students taken = 25

So, the test statistics  =  [tex]\frac{0.20-0.30}{\sqrt\frac{0.20(1-0.20)}{25} {} }[/tex]

                                     =  -1.25

The value of standardized z test statistic is -1.25.

Using the z-distribution, it is found that the value of the standardized test statistic for this significance test is:

D) –1.091

At the null hypothesis, we test if the proportion is of 0.3, that is:

[tex]H_0: p = 0.3[/tex]

At the alternative hypothesis, we test if the proportion is of less than 0.3, that is:

[tex]H_1: p < 0.3[/tex]

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

For this problem, the parameters are:

[tex]p = 0.3, n = 25, \overline{p} = \frac{5}{25} = 0.2[/tex]

Hence, the value of the test statistic is:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.2 - 0.3}{\sqrt{\frac{0.3(0.7)}{25}}}[/tex]

[tex]z = -1.091[/tex]

A similar problem is given at https://brainly.com/question/24166849

Answer:

x= 10

Step-by-step explanation:

1/5 x -2/3 = 4/3

Add 2/3 to each side

1/5x -2/3 +2/3 = 4/3 +2/3

1/5x = 6/3

1/5x = 2

Multiply each side by 5

1/5x * 5 = 2*5

x = 10

Answer:

If Raven's monthly payment were $125, the amount of the loan that she is considering taking out  would be less than $43,205.56.

Step-by-step explanation:

If you think about it this way it may be more simple. If the APR stays constant then a greater payment will result in a greater loan. The opposite is also true meaning a lesser payment will result in a lesser loan. If the amount Raven pays is greater than $145 then the loan will be greater than $43,205.56. If the amount she pays is less than $145 then the loan will be less than $43,205.56. Of the options, only one of these situations will be present. In my case, the correct option was a payment of $125 will result in a lesser loan than $43,205.56.

Answer:

If Raven's monthly payment were $125, the amount of the loan that she is considering taking out  would be less than $43,205.56.

Step-by-step explanation:

Answer:

[tex]z=\frac{0.0156-0.0471}{\sqrt{0.0303(1-0.0303)(\frac{1}{385}+\frac{1}{340})}}=-2.469[/tex]    

Now we can calculate the p value with this probability:

[tex]p_v =P(Z<-2.469)= 0.0068[/tex]    

Since the p value is a very low value and using any significance level 5% or 10% we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of customer complaints using the old dough is less than the proportion of customer complaints using the new dough.

Step-by-step explanation:

Information provided

[tex]X_{1}=6[/tex] represent the complaints with the old dough

[tex]X_{2}=16[/tex] represent the complaints with the new dough

[tex]n_{1}=385[/tex] sample 1 selected  

[tex]n_{2}=340[/tex] sample 2 selected  

[tex]p_{1}=\frac{6}{385}=0.0156[/tex] represent the proportion of complaints with the old dough

[tex]p_{2}=\frac{16}{340}=0.0471[/tex] represent the proportion of complaints with the new dough

[tex]\hat p[/tex] represent the pooled estimate of p

z would represent the statistic

[tex]p_v[/tex] represent the value

Hypothesis to test

We want to verify if the proportion of customer complaints using the old dough is less than the proportion of customer complaints using the new dough, the system of hypothesis would be:    

Null hypothesis:[tex]p_{1} \geq p_{2}[/tex]    

Alternative hypothesis:[tex]p_{1} < p_{2}[/tex]    

The statitsic is given by:

[tex]z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}[/tex]   (1)  

Where [tex]\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{6+16}{385+340}=0.0303[/tex]  

Replacing the info provided we got:

[tex]z=\frac{0.0156-0.0471}{\sqrt{0.0303(1-0.0303)(\frac{1}{385}+\frac{1}{340})}}=-2.469[/tex]    

Now we can calculate the p value with this probability:

[tex]p_v =P(Z<-2.469)= 0.0068[/tex]    

Since the p value is a very low value and using any significance level 5% or 10% we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of customer complaints using the old dough is less than the proportion of customer complaints using the new dough.

Answer:

Hope this helps pls mark brainliest

Answer:

Step-by-step explanation:

Twice the first equation can be added to the second to eliminate the variable y.

  2(3x -y) +(5x +2y) = 2(0) +(22)

  11x = 22 . . . . . . . the result of the combination

__

Solving this gives ...

  x = 2

Substituting into the first equation gives ...

  3(2) -y = 0

  y = 6

The solution is (x, y) = (2, 6).

Answer:

vertex is: (4,-9)

y intercept= (0,7)

roots= (1,0) and (7,0)

Step-by-step explanation:

so we can use factoring to solve this quadratic equation real quick:

x^2-7x-1x+7

x(x-7)

-1(x-7)

(x-1)(x-7)=0

x-1=0

x=1

x-7=0

x=7

(1,0) and (7,0) are the roots

axis of symmetry: 8/2=4

substitute axsis of symmetry in equation to get vertex:

4^2-8(4)+7

16-32+7

-16+7=-9

vertex is: (4,-9)

y intercept= (0,7)

roots= (1,0) and (7,0)

Hope this helps

Answer:

The question is about the least amount to charge each policyholder as premium

The least premium is $484

Step-by-step explanation:

The least amount of premium to charge for this policy is the sum of the expected values of outcome of both instances of policyholder dying before the age of 70 and living after the age of 70 years

expected value of dying before 70 years=payout*probability=$24,200*2%=$484

Expected of living after 70=payout*probability=$0*98%=$0

sum of expected values=$484+$0=$484

Note that payout is nil if policyholder lives beyond 70 years

The premium of $573 means that a profit of $89 is recorded

answer would be A because it u factor it out you will get your initial equation

Answer:

7cm²

Step-by-step explanation:

Explanation:

x = number of pouches

y = cost for having x number of pouches

To find the unit cost, divide y over x

For choices A through D we have the following unit costs

We see that 0.233 is the lowest unit cost, so therefore, Choice C is the lowest cost per pouch.

Answer:

[2,3)

Step-by-step explanation:

[0,1), [0,1),[0,1),[0,1)

[1,2), [1,2),[1,2),[1,2),[1,2),[1,2),[1,2),[1,2)

[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3),[2,3)

[3,4),[3,4),[3,4),[3,4),[3,4),[3,4),[3,4)

Answer:

35%

Step-by-step explanation:

The total number of cinema seats can seat 280 people. Since 98 people take up 98 seats of the cinema, they are taking up 98 cinema seats out of the 280 cinema seats originally available.

As a fraction this would be written as  [tex]\frac{98}{280}[/tex] .

What you want to do is then divide 98 by 280 or 98/280, to get 0.35.

To get the percentage of seats filled, you must multiply the decimal you get by 100.

So it should look like this and your result should be 35%.

[tex]\frac{98}{280} = 0.35 *100=35[/tex]%

Answer:24

Step-by-step explanation:

Height =4

Base=6

Area of parallelogram=base x height

Area of parallelogram=6 x 4

Area of parallelogram=24

Answer:

Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_d[/tex] = 0

Alternate Hypothesis, [tex]\mu_d\neq[/tex] 0    

Step-by-step explanation:

We are given that a local insurance agent randomly selected profiles for 10 of his clients and checked online price quotes for their policies.

Then, based on paired data on the 10 clients (the price he offered them and the corresponding online quote), he obtained t-statistic = 0.709 p-value = 0.248.

Here , we will use the concept of Paired data test statistics because the prices that the local insurance agent offered and the corresponding online quotes are from the same single data. These information has not been taken from the two independent samples.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_d[/tex] = 0    

Alternate Hypothesis, [tex]\mu_d\neq[/tex] 0    

Here, null hypothesis states that there is no difference between the price he offered them and the corresponding online quote.

On the other hand, alternate hypothesis states that there is difference between the price he offered them and the corresponding online quote.

Hence, this would be the correct null and alternative hypothesis.

Answer:2:1

Step-by-step explanation:

6.5:3.25

6.5/3.25=2/1

6.5:3.25=2:1

therefore n=2

Answer:

a) Null hypothesis:[tex]\mu \leq 120[/tex]  

Alternative hypothesis:[tex]\mu > 120[/tex]  

b) [tex]t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236[/tex]  

The degrees of freedom are given by:

[tex] df = n-1 = 80-1=79[/tex]

The p value for this case taking in count the alternative hypothesis would be:

[tex]p_v =P(t_{79}>2.236)=0.0141[/tex]  

Step-by-step explanation:

Information given

[tex]\bar X=130[/tex] represent the sample mean for the amount spent each shopper

[tex]s=40[/tex] represent the sample standard deviation

[tex]n=80[/tex] sample size  

[tex]\mu_o =120[/tex] represent the value to verify

t would represent the statistic    

[tex]p_v[/tex] represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 120[/tex]  

Alternative hypothesis:[tex]\mu > 120[/tex]  

The statistic for this case would be given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)  

Replacing the info given we got:

[tex]t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236[/tex]  

The degrees of freedom are given by:

[tex] df = n-1 = 80-1=79[/tex]

The p value for this case taking in count the alternative hypothesis would be:

[tex]p_v =P(t_{79}>2.236)=0.0141[/tex]