PLEASE HELP The United States spends over $20 billion a year on space exploration through NASA. Do you think that this has been worth the cost? In three to five sentences, provide two specific examples of things we have learned from space exploration, and explain how these examples influence your opinion.(4 points)

Answer:

A Inertia

Explanation:

Rhodium (Rh) is in period 5 on the periodic table. What does this tell you about this element ?

option - D

It has 5 energy levels/shells in its electron cloud.

With the information from the periodic table we can find that the correct statement is:

D. it is 5 energy level

The periodic table of the elements is a method of classifying the chemical elements based on their atomic number, it is divided into rows and columns

The rows are called the period and indicate the energy shell that is filled with electrons, all periods start with one electron and end when the shell is filled with 8 electrons.

The columns called groups correspond to elements that have the same number of electrons in their last shell, the chemical properties of the elements of the group are similar.

In this case we have an element the Rhodium, from period 5 and group VIIIB, when reviewing the period table it can be indicated that it has properties similar to cobalt and the inner layer is filled with two electors in its last layer.

When reviewing the different claims

a) False. The periodic table is not about molecules but about atoms

b) False. The metallic characteristics depend on the relationship between the number of electrons and the fermi level that is not indicated in the periodic table.

c) False. The number of protons is equal to the atomic number, in this case the rhodium has Z = 45, therefore it has 45 protons in the nucleus

d) True. It is at level 5 since the energy levels and the periods coincide.

In conclusion, with the information from the periodic table, we can find that the correct statement is:

D.  it is 5 energy level

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Answer:

Im pretty sure its B im very sorry if its wrong.

Answer:

0.318cm

Explanation:

The computation of the radius of the wheel is shown below:

As we know that

One revolution of the wheel = 2πr

Here r denotes the radius of the wheel

Now

5 revolutions of the wheel would be

= 2πr ×  5

= 10πr

So,

10πr = 10cm

Thus r = 1 ÷ π

= 0.318cm

The radius of the wheel will be r=0.318 cm

The radius is defined as the distance between the center of circle and the outer layer of the circle.

It is given in the question that

Revolutions of the wheel = 5

The length of the string =10 cm

Now the radius will be calculated as

One revolution of the wheel

= [tex]2\pi r[/tex]

Now 5 revolutions of the wheel would be

=  [tex]2\pi r\times 5=10\pi\ r[/tex]

Since the string has the length of 10 cm then

[tex]10\pi\ r=10[/tex]

[tex]r=\dfrac{10}{10\pi}[/tex]

[tex]r=0.318\ cm[/tex]

Thus the radius of the wheel will be r=0.318 cm

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Answer:

r =[tex]\frac{ 1 \pm \sqrt{ \frac{m}{M} } }{1 - \frac{m}{M} }[/tex]

Explanation:

Let's apply the universal gravitation law to the body (c), we use the indications 1 for the planet and 2 for the moon

          ∑ F = 0

           -F_{1c} + F_{2c} = 0

             F_{1c} = F_{2c}

let's write the force equations

             [tex]G \frac{m_c M}{r^2} = G \frac{m_c m}{(d-r)^2}[/tex]

where d is the distance between the planet and the moon.

              [tex]\frac{M}{r^2} = \frac{m}{(d-r)^2}[/tex]

             (d-r)² = [tex]\frac{m}{M} \ \ r^2[/tex]  

              d² - 2rd + r² = \frac{m}{M} \ \ r^2

              d² - 2rd + r² (1 - [tex]\frac{m}{M}[/tex]) = 0

              (1 - [tex]\frac{m}{M}[/tex])  r² - 2d r + d² = 0

we solve the second degree equation

              r = [2d ± [tex]\sqrt{ 4d^2 - 4 ( 1 - \frac{m}{M} ) }[/tex] ] / 2 (1- [tex]\frac{m}{M}[/tex])

              r = [2d ±  2d [tex]\sqrt{ \frac{m}{M} }[/tex]] / 2d (1- [tex]\frac{m}{M}[/tex])

              r =[tex]\frac{ 1 \pm \sqrt{ \frac{m}{M} } }{1 - \frac{m}{M} }[/tex]

there are two points for which the gravitational force is zero

The distance between object from planet will be "[tex]\frac{R}{[1+\sqrt{\frac{m}{M} } ]}[/tex]".

According to the question,

Let,

As we know,

→ [tex]Prerequisites-Gravitational \ force = \frac{GMm}{r^2}[/tex]

Now,

→ [tex]\frac{GMm_1}{x^2} = \frac{Gmm_1}{(R-x)^2}[/tex]

→ [tex]\frac{(R-x)^2}{x^2} = \frac{m}{M}[/tex]

→     [tex]\frac{R-x}{x} =\sqrt{\frac{m}{M} }[/tex]

→          [tex]x = \frac{R}{[1+ \sqrt{\frac{m}{M} } ]}[/tex]

Thus the answer above is appropriate.          

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Your question is a "non sequitur", which means "it doesn't follow".

Your "then" doesn't contradict your "If", so no mystery is implied.

Maybe you're trying to say that matter is somehow not conserved in the equation . . . 4Fe + 302 → 2Fe203 . But it is.  There are 4 Irons and 6 Oxygens on each side, so conservation is not violated here.

I looked up "rust" on Floogle, and got slapped with pages and pages of chemistry that I don't completely understand.  But what it's saying is that rusting is a very complex chemical process, AND it doesn't happen unless there's some water involved.

So the bottom line is that there's a lot more going on than simply

4Fe + 302 → 2Fe203 ,

there's water going in and out of the process at every stage, and when it's all over, you have rusty iron, and mass has been conserved.

Answer:

B. kinetic energy

Explanation:

Thermal energy (It’s a low form of energy ) is a form of kinetic energy as it is produced as a result of motion of particles either if they vibrate at their position or they move along longer paths.

Answer:

1.26 m/s

Explanation:

v=(2*pi*r)/T

v=(2*pi*2)/10

The  object is spun around in a circle of radius 2.0m with a period of 10.0s. Its velocity be 1.25 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Radius of the circle = 2.0 m.

Period of spinning of the object = 10.0 s.

So, angular velocity of the object be = 2π/10 radian/second.

So, magnitude of velocity be = radius × angular velocity

= 2.0 × 2π/10 m/s

= 1.25 m/s.

Hence, the magnitude of velocity of the object be 1.25 m/s.

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Answer:

a. True

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement by measuring the time required for sound to travel a set distance through a solid, a liquid, and a gas.

Mathematically, the speed of a sound is given by the formula:

[tex] Speed = wavelength * frequency [/tex]

Generally, the frequency of a sound wave determines the pitch of the sound that would be heard.

Diffraction occurs for all types of waves, including sound waves.

Answer:

256 N

Explanation:

formula of centripetal force = mv²/r

m= 2kg

v= 8m/s

r= 0.5m

mv²/r = 2×8²/0.5 = 256N

Answer:

a place where two bones come together is known as a join

Answer:

Hey mate.....

Explanation:

This is ur answer....

Joints – A place in the body where bones come together. Non-Moveable Joints (sometimes called fixed or fibrous) – A place in the body where two or more bones come together but do not move.

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Answer:

Δx = distance between central bright fringe and first bright fringe = 19.85 x 10⁻⁴ m = 1.985 mm

distance between central bright fringe and second dark fringe = 2.978 mm

Explanation:

We have the following data:

λ = wavelength of light = 641 nm = 6.41 x 10⁷ m

L = Distance of Screen from slits = 3.19 m

d = slit separation = 1.03 mm = 1.03 x 10⁻³ m

Δx = distance between consecutive bright fringes = fringe spacing = ?

Using formula:

[tex]\Delta x = \frac{\lambda L}{d}\\\\\Delta x = \frac{(6.41\ x\ 10^{-7}\ m)(3.19\ m)}{1.03\ x\ 10^{-3}\ m}[/tex]

Δx = distance between central bright fringe and first bright fringe = 19.85 x 10⁻⁴ m = 1.985 mm

distance between central bright fringe and second dark fringe = 1.5Δx

distance between central bright fringe and second dark fringe = (1.5)(1.985 mm)

distance between central bright fringe and second dark fringe = 2.978 mm

Answer:

534.8 meters

Explanation:

Use T=(2*pi*r)/v

560=(2*pi*r)/6

3360=2*pi*r

1680=pi*r

534.8 meters=radius

It takes 560s for a runner to complete one circular lap, moving at a speed of 6.00 m/s. The radius of a track is 534.7 m.

Mathematically, it can be calculated as follows :

distance = speed × time

The formula relating distance (d), speed (s), and time (t) is

d = st

First, Calculating the distance,

d = 560 s × 6 m·s⁻¹

  = 3360 m

When, Calculating the track radius,

The distance travelled is the circumference of a circle,

C = 2пr

r = 3360/2п

 = 534.7 m

The radius of the track is 534.7 m.

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Answer:

v = 2.57 m / s

Explanation:

For this exercise let's use conservation of energy

starting point. When it is at an angle of 30º

          Em₀ = K + U = ½ m v₁² + m g y₁

final point. Lowest position

          Em_f = K = ½ m v²

as there is no friction, the energy is conserved

          Em₀ = Em_f

          ½ m v₁² + m g y₁ = ½ m v²

Let's find the height(y₁), which is the length of the thread minus the projection (L ') of the 30º angle

         cos 30 = L ’/ L

         L ’= L cos 30

         y₁ = L -L '

          y₁ = L- L cos 30

we substitute

          ½ m v₁² + m g L (1- cos 30) = ½ m v²

           v = [tex]\sqrt{ v_1^2 +2gL(1-cos30 )}[/tex]

let's calculate

           v = [tex]\sqrt{ 2^2 + 2 \ 9.8 \ 1.0 (1- cos 30)}[/tex]

           v = 2.57 m / s

With rising heat, the steam pressure inside the pot builds up beyond atmospheric pressure, allowing the temperatures to rise well above boiling point. This design enables to save time, energy, and resources. The temperature inside a pressure cooker can well go beyond 110° C, which reduces the time needed to cook food.

Answer:

The correct answer is A) It is upright and 1.5m behind the mirror

Explanation:

Your reflection must be upright, meaning vertical/erect, and the distance will be the exact same. Also, the reflected ray appears as if it had traveled from an object located behind the mirror.

Answer:

a) 1.2 m/s

b) 0.350 m

c) 1.2 m/s

d) 0.250 m

Explanation:

a)

       [tex]v = \lambda * f (1)[/tex]

       [tex]v = \lambda * f = 6.0 m * 0.2 1/s = 1.2 m/s (3)[/tex]

b)

       ⇒ A = Δd/2 = 0.700m/2 = 0.350 m (4)

c)

d)

Kinetic energy decreases if either the mass or the velocity of the object decreases or if both decrease. and  Kinetic energy increases if either the mass or the velocity of the object increases or if both increase.

Explanation:

These statements explain the relationship between mass, velocity, and kinetic energy .i.e KE = ½mv², (3) Kinetic energy decreases if either the mass or the velocity of the object decreases or if b decrease. (4)Kinetic energy increases if either the mass or the velocity of the object decreases or if both decrease.

When a body has a mass of m kg and travels a velocity of v m/s then the kinetic energy is given by,

KE=1/2mv²

In the above relation, it is clearly shown that,

Kinetic energy is directly proportional to the mass of the body,

i.e

KE∝m

and also Kinetic energy directly varies with the square of the velocity of the body.

I.e

KE∝v²

Therefore, From the given expression we can conclude that when mass and velocity increased either one of them or both, the kinetic energy also gets increased.

And when mass and velocity decreased either one of them or both, the kinetic energy also gets decreased. Hence options (3) and (4) are correct.

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The dependent variable is academic performance while the independent variable is presence/absence of tutorial support.

The correct results are:

In every experiment, there is a dependent and independent variable as well as an experimental and a control group.

The experimental group receive the treatment while the control group do not receive the treatment. The independent variable is manipulated and its impact on the dependent variable is evaluated.

The control group are students who did not receive the tutorial support while the experimental group are students that received the tutorial support.

The dependent variable in this case is academic performance. Its outcome depends on the presence or absence of tutorial support (independent variable).

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Answer:

bb kettle

Explanation:

it transfres electricsl to kinetic

Answer:

a. 7.6 * 10^5 A/m^2

b. 5.6 * 10-^5 m/s

Explanation:

lol

Answer:

Gamma Rays have the highest frequencies

Explanation:

This is because Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies compared to the other light frequency. Radio waves, on the other hand, have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation which means the answer has to be gamma rays. Brainly Please!!!! Here are screenshots that may help

Answer:

B It is always increasing.

Explanation:

In Physics, entropy can be defined as the tendency or ability of a substance to reach maximum disorder i.e to be randomly distributed.

This ultimately implies that, entropy is a thermodynamic quantity that measures the degree of maximum disorder or randomness of a system.

The S.I unit used for the measurement of the degree of maximum order or randomness of a system is Joules per Kelvin (JK¯¹). An example of entropy is the mixing of ideal gases.

Generally, the entropy in an irreversible process always increases and as such the change in entropy has a positive value.

Hence, the entropy of the universe is always increasing because its energy flow is considered to be in a downward direction rather than upward i.e from a hot region to a cold region; making the energy to be evenly distributed.

Answer:

the bar is the top and bottem. the nucleas in the middle and the Spiral arm is the last space

Explanation:

Answer:

look pkch

Explanation:

Answer:

1. 2.5×10¯⁹ N

2. 3.33×10¯¹¹ m/s²

Explanation:

1. Determination of the force of attraction.

Mass of astronaut (M₁) = 75 Kg

Mass of spacecraft (M₂) = 125000 Kg

Distance apart (r) = 500 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force of attraction (F) =?

The force of attraction between the astronaut and his spacecraft can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 75 × 125000 / 500²

F = 2.5×10¯⁹ N

Thus, the force of attraction between the astronaut and his spacecraft is 2.5×10¯⁹ N

2. Determination of the acceleration of the astronaut.

Mass of astronaut (m) = 75 Kg

Force (F) = 2.5×10¯⁹ N

Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

2.5×10¯⁹ N = 75 × a

Divide both side by 75

a = 2.5×10¯⁹ / 75

a = 3.33×10¯¹¹ m/s²

Thus, the acceleration the astronaut is 3.33×10¯¹¹ m/s²

Answer:

Take shorter showers.

Throw newspapers in the trash can.

Answer:

v = 12.79 m/s

Explanation:

Given that,

The mass of a car, m = 1200 kg

Momentum of the car, p = 15 350 kg-m/s

We need to find the velocity of the car. We know that, the formula for the momentum of an object is given by :

p = mv

Where

v is the velocity of the bject

So,

[tex]v=\dfrac{p}{m}\\\\v=\dfrac{15350}{1200}\\\\v=12.79\ m/s[/tex]

So, the velocity of the car is 12.79 m/s.