Please please helpjejejnebwbww​

Please Please Helpjejejnebwbww

Answers

Answer 1

Answer:

C. 540 N

Explanation:

Let suppose that system formed by the athlete and the load are in equilibrium. By Newton's Laws of Motion, we use the moment equation with respect to the feet of the athlete to determine the upward force exerted by his two arms:

[tex]\Sigma M = -F\cdot r_{1} + m_{L}\cdot g \cdot r_{2} + m_{A}\cdot g \cdot r_{3} = 0[/tex]

[tex]F = \frac{(m_{L}\cdot r_{2} + m_{A}\cdot r_{3})\cdot g}{r_{1}}[/tex] (1)

Where:

[tex]m_{L}[/tex] - Mass of the load, in kilograms.

[tex]m_{A}[/tex] - Mass of the athlete, in kilograms.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]r_{1}[/tex], [tex]r_{2}[/tex], [tex]r_{3}[/tex] - Distances with respect to the feet, in meters.

[tex]F[/tex] - Upward force exerted by his two arms, in newtons.

If [tex]m_{L} = 6\,kg[/tex], [tex]r_{2} = 1.20\,m[/tex], [tex]m_{A} = 70\,kg[/tex], [tex]r_{3} = 0.90\,m[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]r_{1} = 1.30\,m[/tex], then the upward force is:

[tex]F = \frac{[(6\,kg)\cdot (1.20\,m)+(70\,kg)\cdot (0.90\,m)]\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{1.30\,m}[/tex]

[tex]F = 529.578\,N[/tex]

The upward force exerted by his two arms is 529.578 newtons. (Right answer: C)


Related Questions

Question 3 of 10
Which image shows an example of the strong nuclear force in
action?
A.
B.
C.
D.

Answers

Answer: The answer is B

Explanation:

There are 4 fundamental forces that hold matter together.

- Gravitational Force

- Electromagnetic Force

- Strong Nuclear Force

- Weak Nuclear Force

We have barely just scratched the info about nuclear forces but the reason why B is the answer to the question is that Strong nuclear force actually holds the protons and neutrons together in the nucleus of an atom, much like the picture in B.

Answer: B

Explanation:

Write the dimension of a / b in the x = at + bt2. Where x is the distance and t is the time?​

Answers

The dimension of a/b where x is the distance and t is the time is T

Given the expression

x = at + bt²

where

x is the distance

t is the time

Based on the homogeneity principle, the expression on the left-hand side must be equal to that on the right. Hence;

x = at

[tex]a = \frac{x}{t}[/tex]

Since x is the distance and distance is measured in metres, the dimension equivalent will be the length 'L'

Since t is the time and time is measured in seconds, the dimension equivalent will be the seconds 'T'

[tex]a=\frac{L}{T}[/tex]

Similarly;

x  = bt²

[tex]b=\frac{x}{t^2}\\b=\frac{L}{T^2}[/tex]

Next is to get a/b;

[tex]\frac{a}{b} = \frac{L}{T} \div \frac{L}{T^2}\\\frac{a}{b} = \frac{L}{T}*\frac{T^2}{L} \\\frac{a}{b} =\frac{T^2}{T}\\\frac{a}{b} =T[/tex]

Hence the dimension of a/b is T

solve two questions under inclined plane using Newton 2nd law​

Answers

Explanation:

If the mass of the inclined plane is large enough, could N ever be equal to mgcosθ. Reasons?

So far I've come up with: mgcosθ−N=ma meaning if N were to equal mgcosθ, ma=0. Since the surfaces are frictionless and since N is acting on the inclined plane too(it'll have a horizontal component), this isn't possible. Am I right? Where am I going wrong?

Which type of reactions usually happens slowest?

Answers

Answer:

option b is correct..................

Please help have due very soon?thank you

Answers

The answer is :78 I think

What is the voltage of the power source if a motor with a resistance of 20 2 draws a
current of 1.5 A?

Answers

Answer:

190v I believe

hope this helped a little and if it did pls mark brainiest :)

A bucket filled woth water seems light while it sinks into water.Also show their relation using formula

Answers

Answer: This phenomenon happens due to upthrust exerted by water.

Explanation:

We know that,

Liquid Pressure is directly proportional to the height of the vertical column in the liquid.(P∝h)

When a bucket filled water is sunk into the water container, there occur difference in the pressure in top and bottom of the water container. Due to this, water exerts an upward force on the bucket filled with water. This is called Uprthrust.

Upthrust on the bucket makes the bucket filled with water lose some of it's weight and causes apparent loss in weight.

Hence, the bucket filled with water seems light while it sinks into water.

give reason
Husking rice in a rice mill is faster than husking with dhiki

Answers

Answer:

Because rice mill is more advanced than dhiki.

It is the developed form of the dhiki.

6.
For a given prism the angle of incidence is changed from 0° and 90', the angle of deviation [ ]
b) decreases
c) first decreases and then increases
d) first increases and then decreases
a) increases

Answers

Answer:

increase

Explanation:

please mark as brainlyest

Answer

A.Increses

Explanation:

A ball is dropped from a height of 180m- Calculate the velocity of the ball when it strikes the ground

Answers

Answer:

6s , 60mls

Explanation:

hope this helps love

Answer:

0m/s

Explanation:

When the object strikes the ground, it then becomes in uniform motion and when an object is in uniform motion, the velocity is 0

What volume of silver metal will have a mass of exactly 2500.0 g? The density of silver is 10.50 g/cm3.

*Include your units!

Round your answer to the nearest tenth.

Answers

Explanation:

The density of silver is 10.5g/cm3

=2500.0g/10.5g/cm3

=238.09cm3

238.1cm3 to nearest tenth.

I hope my answer helps. Please mark as brainliest.

Calculate the upthrust on a object immersed in water if the object displace water of mass 2 kg.(g=9.8m/s²) ​

Answers

Thrust is force

Mass=2kgAcceleration due to gravity=g=9.8m/s^2

Using Newtons Second law

[tex]\boxed{\sf Force=Mass\times Acceleration}[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow Thrust=2(9.8)[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow Thrust=19.6N[/tex]

We have that the the upthrust on a object immersed in water is

[tex]U=19.6N[/tex]

From the Question we are told that

mass= 2kg

Gravity g=9.8m/s^2

Generally the equation for the upthrust  is mathematically given as

[tex]U=mg[/tex]

Therefore

[tex]U=2*9.8[/tex]

[tex]U=19.6N[/tex]

For more information on this visit

https://brainly.com/question/1519601

(6). A car travels in a straight line from city A to city B at a speed of 60kmh-1

. Then return

from city B to city A along the original route at a speed of 40kmh-1

. The distance between

the two cities is 120 km. What is the average speed of the vehicle?

1. 30kmh-1

2. 45kmh-1

3. 48kmh-1

4. 60kmh-1​

Answers

i think that the answer is 4. 60kmh!

If the resistance reading on a dmm’s meter face is 22.5 ohms and the range selector switch is set to the R x 100 range what’s the actual measured resistance of the circuit
A.22.5 kohms

B.2.25 mohms

C.2.25 kohms

D.225 ohms

Answers

Answer:

c

Explanation:

The mass of an object is 4kg and it has a density of 5gcm^-3. what is the volume ​

Answers

Answer:

density =   mass/ volume

5=4000/ volume

volume=4000/5

volume=800 cm^-3

People who get population education are also aware of health issues and environment education justify

Answers

I believe this statement is correct if not I am sorry

Observe the given figure and find the the gravitational force between m1 and m2.​

Answers

Answer:

The gravitational force between m₁ and m₂, is approximately 1.06789 × 10⁻⁶ N

Explanation:

The details of the given masses having gravitational attractive force between them are;

m₁ = 20 kg, r₁ = 10 cm = 0.1 m, m₂ = 50 kg, and r₂ = 15 cm = 0.15 m

The gravitational force between m₁ and m₂ is given by Newton's Law of gravitation as follows;

[tex]F =G \cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}[/tex]

Where;

F = The gravitational force between m₁ and m₂

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

r₂ = 0.1 m + 0.15 m = 0.25 m

Therefore, we have;

[tex]F = 6.67430 \times 10^{-11} \ N \cdot m^2/kg \times \dfrac{20 \ kg\times 50 \ kg}{(0.1 \ m+ 0.15 \ m)^{2}} \approx 1.06789 \times 10^{-6} \ N[/tex]

The gravitational force between m₁ and m₂, F ≈ 1.06789 × 10⁻⁶ N

what is the definition of unit?definition of unit?​

Answers

Answer:

The Reference standard with which we carry out the measurement of any physical quantity of the same kind is know as unit .

I HOPE I HELP YOU.

Answer:

The standard quantity which is used for the comparison with an unknown quantity is called unit.

Unit is a known or standard quantity in terms of which other physical quantities are measured.

for examples;kilogram,metre,second,etc.

Explanation:

hope it helps you

State Ohms law in easy words

Answers

Answer:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

A water heater marked 4 kW takes 4 minutes to heat 1 kg of water from 20 °C to 50 °C. The cost of electrical energy per kWh
is $0.120. What will be the total cost of energy consumption?

Answers

The total cost of the energy consumption for the given time period is $0.0364

The given parameters include;

power rating of the heater, P = 4 kW = 4000 Wtime taken to completely boil the water,[tex]t = 4 \min = 4 \min \times \frac{1 \ h}{60 \ \min} = 0.067 \ h[/tex]mass of the water, m = 1 kginitial temperature of the water, t₁ = 20 ⁰Cfinal temperature of the water, t₂ = 50 ⁰Cspecific heat capacity of water, c = 4200 J/kg⁰Ccost of electrical energy = $0.12

The total energy consumed in the process of heating the water;

Total electrical Energy  = Energy of the heater (kWh) + Energy of the heated water (kWh)

Energy of the heater (kWh) = power x time

                                = 4 kW x 0.067 h

                                 = 0.268 kWh

Energy of the heated water (J) = mcΔt

where;

Δt is the change in temperature = t₂ - t₁

                                                      = 50 ⁰C  -  20 ⁰C = 30⁰C

Energy of the heated water (J) = 1 x 4200 x 30

                                               = 126,000 J

Electrical power of the heated water (Watts) = [tex]\frac{126,000 \ J}{4 \ \min} \times \frac{1 \min}{60 \ s} = 525 \ W[/tex]

Energy of the heated water (kWh) = [tex]\frac{525}{1000} \times 4\min\times \frac{1 \ hr}{60 \min} = 0.035 \ kWh[/tex]

Total electrical Energy  = 0.268 kWh  +  0.035 kWh

                                       = 0.303 kWh

The total cost of the energy consumed is calculated as;

[tex]Total \ cost = \frac{\$ \ 0.12}{kWh} \times 0.303 \ kWh = \$ \ 0.0364[/tex]

Therefore, the total cost of the energy consumption is $0.0364

To learn more about cost of electrical energy calculation, please visit: https://brainly.com/question/17924004

According to Hooke's law
(a) stress x strain = constant
(b) stress / strain = constant
(c) strain / stress = constant
(d) stress = strain

Answers

Answer:

According to Hook's law, we know,

strain/stress =Constant

Explanation: So, the ratio between stress and strain is always constant.

So, if stress is increased, then strain changes in that way so that this ratio always remains constant.

How do we find the weight of a beam

Answers

Answer:

Standard weight: We calculate the standard weight as follows: G = L * mweight, where L is the length of the beam calculated as the difference between the extreme points of the beam body along the direction of the beam axis, taking into account all features except holes.

Explanation:

I want Brainliest plz!!

: Lili

calculate the potential energy stored in a meta ball of mass of 80 kg kept at a height of 15m from the earth surface . What will be the potential energy when the metal ball is kept on the earth surface Take (g- 9.8 m/s] ​

Answers

Answer:

11760 J

Explanation:

cuz potential engery is PE = MHG

SO 80×15×9.8= 11760 J

Answer:

11769j

Explanation:

here,

mass(m)=80 kg

height(h)=15m

acceleration due to gravity(g)=9.8m/s^2

now,

potential energy = m×g×h

= 80×9.8×15

= 11760j

a stone attached to 1m long string is moving with the speed of 5ms in a circle find the centripetal acceleration of the stone​

Answers

Answer:

The centripetal acceleration of the stone is 5 m/s²

Explanation:

The length of the string to which the stone is attached, r = 1 m

The speed with which the string is rotated, v = 5 m/s

The centripetal acceleration, [tex]a_c[/tex], is given as follows;

[tex]a_c = \dfrac{v^2}{r}[/tex]

Therefore, the centripetal acceleration of the stone found as follows;

[tex]a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2[/tex]

The centripetal acceleration of the stone, [tex]a_c[/tex] = 5 m/s².

show how three identical 6 resistors must be connected tho have the following effective resistance values 9 and 4 ohms​

Answers

Answer:

connect two 9 ohms resistance in series now it becomes 18 ohm

light travels 3,00,000 km/s . Is it velocity or speed?​

Answers

Answer:

speed

Explanation:

according to your question, your answer is speed

The pressure at the ice point for a constant-volume gas thermometer is 4.81 x 10^4Pa.
While that at the steam point is 6.48 x 10^4 Pa.
What pressure would the thermometer indicate at 50°c?

Answers

Answer:

0 deg C = 4.81E4     pressure at 0 deg

100 deg C = 6.48E4     pressure at steam point

100 deg C - 50 deg C = (6.48 - 4.81) * 10^4 = 1.67E4 Pa

50 deg C = 50 / 100 * 1.67E4 + 4.81E4 = 5.65E4 Pa Just the halfway point between the two given pressures

What is the total distance covered during its complete motion? (CCT TYPE) *
2 points
350 km
20/3 km
50 km
40/3 km

What is the SI unit of speed? ( CCT type) *
2 points
m/s
mm/s
m/ss
None of the above

. In which period is the bus decelerating? (CCT type) *
2 points
0-5 min
8- 12 min
11-19 min
5-10 min

Only answer who knows, don't spam. because I am in hurry.​

Answers

Answer:

40/3

M/s

11-19

These are the answers

40/3
M/S
19-13
Hope it’s help you

Why do scientists not use US customary units when reporting their data?

Answers

One of the scientist's jobs is to report the results of his experiments to all the other scientists in the world.

There isn't a single real science shop anywhere in the world that uses the US customary system of units. Not one.

Even in the measly three countries that use it for measuring carpet, pumping gas, and weighing fish ... Myanmar, Liberia, an the USA ... the scientists do their work in the SI/MKS/metric system.

Starting from rest, two skaters push off against each other on smooth level ice, where friction is negligible. One is a woman and one is a man. The woman moves away with a velocity of 1.9 m/s relative to the ice. The mass of the woman is 46 kg, and the mass of the man is 88 kg. Assuming that the speed of light is 3.0 m/s, so that the relativistic momentum must be used, find the recoil velocity of the man relative to the ice.

Answers

I’m sorry i don’t know
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